Hi, thank you for the tutorial of double-digest problem. But i was wondering while reading the book about it. So let me say, the number of sizes of restriction fragments digested by A enzyme is n the number of sizes of restriction fragments digested by B enzyme is m the number of sizes of restriction fragments digested by A+B enzyme is m+n-1(according to the book) And my question is why the size is m+n-1 when digest with A+B not m+n In video, i saw questions having both m+n and m+n-1 size for combination enzymes. I know this video posted a year ago.. i hope you received my message and reply my question. Thank you again.
I am getting very confused with this topic and there are only a few videos on restriction mapping could you please suggest a book with States these concepts very clearly please?
Thank you so much! But I have a question.. in the second problem, when both the enzymes are used, instead of assuming the remaining fragment to be of 0.8 kb, there could be two 0.4 kb fragments right? So which one should you consider there? Though the final mapping will still be the same
Super late with this, but in case you were still wondering, no. Since each enzyme only cuts twice, there can only be a maximum of four cuts. This means it's impossible for there to be two additional 0.4 kb fragments, as this would require a fifth cut.
I have a lab exam tomorrow with this. You saved my grade and explained it better than my college professor. THANK YOU!
I have a test on this tomorrow and you simplified it very well. Thank you
Thank you so much for this video! You made something that was really difficult for me to initially understand, into something easy. Thank you again!
WOW! You made this simple and straight forward. That is something I could not say about my professor. Thank you for that! :)
Thank you so much!Very easy to understand and very helpful!
oh my goshhh, thank you so much! i was literally struggling to grasp this and thought i was going to fail lol!
Love the questions. Best way of teaching. Many Thanks
love it. thanks a million
Thanks, very helpful indeed.
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Marvelous explanation, thank you.
very helpful!!! thanks so much!!!
Great explanation!
Hi, thank you for the tutorial of double-digest problem.
But i was wondering while reading the book about it.
So let me say,
the number of sizes of restriction fragments digested by A enzyme is n
the number of sizes of restriction fragments digested by B enzyme is m
the number of sizes of restriction fragments digested by A+B enzyme is m+n-1(according to the book)
And my question is why the size is m+n-1 when digest with A+B not m+n
In video, i saw questions having both m+n and m+n-1 size for combination enzymes.
I know this video posted a year ago..
i hope you received my message and reply my question.
Thank you again.
lucid explanation. it really built the concept on mapping. please keep producing more videos .
I am getting very confused with this topic and there are only a few videos on restriction mapping could you please suggest a book with States these concepts very clearly please?
Thank you so much! Love the accent hehe :3
Very nice explanation
Very good professor and very nice woman
Excellent
what if adding them up gives you more than 3? there will be an intermediate right how would you draw the map for that?
thanks!
Thank youuuu
Thanku soo much :p
thank u so much...!!! very useful
very helpful! But for the last problem, if I were to start with Eco R1, will it be a wrong approach?
no bcz both has two cuts so starting with anyone is ok
very nice
Thank you so much! But I have a question.. in the second problem, when both the enzymes are used, instead of assuming the remaining fragment to be of 0.8 kb, there could be two 0.4 kb fragments right? So which one should you consider there? Though the final mapping will still be the same
Super late with this, but in case you were still wondering, no. Since each enzyme only cuts twice, there can only be a maximum of four cuts. This means it's impossible for there to be two additional 0.4 kb fragments, as this would require a fifth cut.
thank you
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