@@LyndonLemos @LyndonLemos Instantaneous can be calculated via differentiation. i.e. its rate of change. This will give a figure which relates to the speed of the ball exactly when it is released. For the calculations, you basically calculate the equation of the line, given that we have 2 points. (0,0) and (13.13, 0.45). Equation when simplified would be: y = 1313/45x And then to differentiate we get: dy/dx=1313/45 meters per second Convert to km/hr: 105.04 km/hr I hope this helped, I'm not sure how well I explained it. If there was anything I didn't explain well I'm happy to try do a better job! Once again, really cool idea, handy to be able to work things out when we don't have money for speedguns and top equipment
![GEEK TIMË [OFFICIAL AUDIO]](http://i.ytimg.com/vi/ry-6RvkH880/mqdefault.jpg)
Cool idea, this is average speed over distance covered though, not instantaneous, which is what pros are measured by. Still cool vid bro
instantaneous = 105.04 km/hr
Appreciate the feedback back! Could you explain how the calculation differs for instantaneous?
@@LyndonLemos @LyndonLemos Instantaneous can be calculated via differentiation. i.e. its rate of change. This will give a figure which relates to the speed of the ball exactly when it is released.
For the calculations, you basically calculate the equation of the line, given that we have 2 points. (0,0) and (13.13, 0.45). Equation when simplified would be:
y = 1313/45x
And then to differentiate we get:
dy/dx=1313/45 meters per second
Convert to km/hr:
105.04 km/hr
I hope this helped, I'm not sure how well I explained it. If there was anything I didn't explain well I'm happy to try do a better job! Once again, really cool idea, handy to be able to work things out when we don't have money for speedguns and top equipment
Cold
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