Perfect!! You are a blessing!! I have never had chemistry in my life and my teacher goes so fast like if we are supposed to know this already and then she says, "Stop me if you get lost." then she continues rambling on and on and on while I am stuck way back when. She gives us no time to ask before she jumps and works out the problem herself and goes on and on and on and on and I am like WHAT????? What is that?! I wanted to cry earlier out of frustration and I decided to just youtube it to see if maybe that will explain it better than her and the book. So, I decided to click on yours and THANK GOD I DID!!! LIFE SAVER! You explain with great detail and that is just awesome!
Melissa Ramirez Glad that you found the video helpful. I am not sure why a teacher would make it any harder then it has to be and yes textbooks can be a bit hard to read. Thanks for commenting and good luck in the future.
I don't know why either..now I'm super confident I'll get an A or B. Maybe a B since I haven't been doing well. I have a question though. There was a question that got me confused. It asks how many atoms are in 121g of Ca. I know you do have to convert and all that and eventually you get 3.02mol(6.02x10^23)atoms. I kept getting 1.82x10^25 atoms for the answer, but the correct answer was a power less, it was 1.82x10^24 atoms. How come the calculator said to the 25th power and the correct answer was to the 24th power? A power less?
Even if I put 6.02x10E23 it gives me to the 24? There's something wrong with my calculator. I'll just mentally subtract one from the exponent then. Thank you!
+Jaime Guzman Great, I try to go through everything step by step, in fact....You can see a listing of all my videos at my website, www.stepbystepscience.com
Very helpful. I have a review quiz tomorrow over this in my chemistry class, and this was exactly what I needed in order to remember all of my forgotten information😂
Bummer that the prof could not figure it out, glad that you found the video helpful. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you for explaining this clearly. Your video was easy to follow and I was able to get everything g you side. In class it's hard to take notes from teacher because she really fast so your video was a lot easy because your goinh slower. Thanks.
Step-by-Step Science thanks. Do you only do chemisy? So for pryjng, but are you a teacher or studying?? I'm taking an AP basic chem class and your video covered onw of my subscription subjects so I figured you might be.
Now I am teaching physics from 7 thru 12 grade and maths for the 8 grade. For the past 6 years I have been working at a small private school in Berlin Germany. I have taught some chemistry before.
I understand the process up to the point where we divide the molar values by the smallest molar values. I want to understand the process and not just memorize it so could you please explain how we can just divide the molar values to find the empirical formula?
Wait, you can't assume 100 grams if they provide a total grams of 180.16. Don't you need to multiply 180.16 by all the given percentages first to get the grams of each element, then do the grams to moles calculation?
+lvbearboy 180.16 is the molar mass of the compound, not the mass of the sample. The percent composition will be the same irregardless of the mass of the sample.
Thank you very much for making this video. However, I was wondering what would happen if, after dividing the amount of moles for each element by the lowest number, one of the numbers ended in a decimal such as .5 where you wouldn't be able to round up or down. I know that the empirical formula only contains whole numbers so how would you go about writing the empirical formula for this instance? Thanks again, Whitney
I’m confused about how you were able to get the 30g / mol. I know you said from the periodic table but can you please explain to me where on the periodic table I would find it??
carbon's molecular weight (on the periodic table) says "12.001" or 12 Hydrogen's molecular weight (on the periodic table) says "1.008" or 1 [In the problem, it says H2, so double this (2) Oxygen's molecular weight (on the periodic table) says "15.999" or 16 C=12 H2=2 O=16 Added together = 30. So you now have the 30g, I hope this helped!
The molar mass of 1 carbon (12g), 2 hydrogens (1g +1g) and 1 oxygen (16g) from the empirical fomula. Does that help? You can a listing of all my videos from my website, www.stepbystepscience.com
Thank you, my channel is actually mostly physics. You can see a listing of all my videos by topic at my website, www.stepbystepscience.com ilecture online also has a lot of good physics videos.
and what if i have this problem... compound has the following mass composition: 53.33% carbon, 11.11% hydrogen and 35.56% oxygen. Its molar mass is 90amu.
+TriHardHero Thanks for the comment. I try to go through everything step by step…in fact…you can see a listing of all my videos at my website, www.stepbystepscience.com
The molar mass of 1 carbon (12g), 2 hydrogens (1g +1g) and 1 oxygen (16g) from the empirical fomula. Does that help? You can a listing of all my videos from my website, www.stepbystepscience.com
I watched this video and I am still confused on how to do molecular formula. How did you even get 30g and on my test they don’t even give you the molecular weight just the percentages of each element
You just explained in 8 minutes what my teacher can't explain in an entire semester. You just earned a like, thank you so much for the work!
Great to hear. You're very welcome!
Perfect!! You are a blessing!! I have never had chemistry in my life and my teacher goes so fast like if we are supposed to know this already and then she says, "Stop me if you get lost." then she continues rambling on and on and on while I am stuck way back when. She gives us no time to ask before she jumps and works out the problem herself and goes on and on and on and on and I am like WHAT????? What is that?! I wanted to cry earlier out of frustration and I decided to just youtube it to see if maybe that will explain it better than her and the book. So, I decided to click on yours and THANK GOD I DID!!! LIFE SAVER! You explain with great detail and that is just awesome!
Melissa Ramirez Glad that you found the video helpful. I am not sure why a teacher would make it any harder then it has to be and yes textbooks can be a bit hard to read. Thanks for commenting and good luck in the future.
I don't know why either..now I'm super confident I'll get an A or B. Maybe a B since I haven't been doing well. I have a question though. There was a question that got me confused. It asks how many atoms are in 121g of Ca. I know you do have to convert and all that and eventually you get 3.02mol(6.02x10^23)atoms. I kept getting 1.82x10^25 atoms for the answer, but the correct answer was a power less, it was 1.82x10^24 atoms. How come the calculator said to the 25th power and the correct answer was to the 24th power? A power less?
Melissa Ramirez Sorry but I also get 1.82x10^24. You must be entering something wrong on your calculator, probably it has to do with the exponent.
Hmm. Interesting because that's the second time it's happened to me? You put 3.02x6.02x10E23 right?
Even if I put 6.02x10E23 it gives me to the 24? There's something wrong with my calculator. I'll just mentally subtract one from the exponent then. Thank you!
i hope you know just how important you and your effective teaching methods are. you just saved my grade THANK YOU
That is very nice of you to say, thanks for letting me know!
This was really helpful! My teacher never explains anything to us..
Thank you for the positive comment. What do these never explaining anything teachers do all day in their classes.
My teacher never explains us anything 2.
My teacher is the same!!!!!
Rachel Carlson same with my teacher lol
My teacher just linked this video instead of explaining it...
I'm taking an online course and they describe this process with one example and no steps. This helps out tremendously.
Great that you found the video helpful and thanks for letting me know. You can see a listing of all my videos at www.stepbystepscience.com
Thanks for your help. I am studying for a test that's tomorrow! Your video was surprisingly helpful, keep it up.
This helped me a lot, I'm really struggling in chemistry but this made it easier to understand.
+Kima Sohma Likes Anime Great, thanks for commenting. You can see a listing of all my videos at my website, www.stepbystepscience.com
i have a test today and i didnt understand anything at all but this tutorial really helped me understand thank you so much for this!!!!!!
You are very welcome, I hope the test goes well. You can see a listing of all my videos at www.stepbystepscience.com
This is a perfect example, exactly what i needed. Straight to the point!
+Jaime Guzman Great, I try to go through everything step by step, in fact....You can see a listing of all my videos at my website, www.stepbystepscience.com
thank you so much......you the only one who dont teach this topic confusing.....thank you again sir
Very helpful. I have a review quiz tomorrow over this in my chemistry class, and this was exactly what I needed in order to remember all of my forgotten information😂
Great, hope the quiz goes well.
Your chemistry videos have been very helpful to me this year. Thank you!
that is great and thanks for commenting
great that you find them helpful, thanks for commenting.
Thanks again! Whenever I need help, I watch your videos.
Thank you very much for watching and letting me know.
YOU JUST SAVED MY LIFE
Props to you dude this explained it better than my teacher thanks so much
Thanks for the comment....you can also see a listing of all my videos by topic at www.stepbystepscience.com
Hello! I'm studying AS levels and this explanation is so clear! really glad i came across ur explanation! ty
Thanks for the comment. I try to go through everything step by step.
You can see a listing of all my videos at www.stepbystepscience.com
Thanks for posting this. It is very helpful and well explained.
An oldie but a goodie, thanks for letting me know. You can see a listing of all my videos at www.stepbystepscience.com
I'd like to thank you sooo much im in 1st year of chemistry, and i'm not going to take ap becauee of my teacher.
you're awesome!
Chipo Sandwich Thank you very much for the positive comment. Sorry that you won't be taking AP next year.
THANK YOU!! VERY HELPFUL AND EASY TO UNDERSTAND!!
Thanks for watching and commenting.
This helped me out SO much. Thanks.
Glad it helped!
Thanks a lot I found it really helpful and very easy to understand.
I do not understand what you mean by /sci/ and /b/. ???
thank you soooooooooooooooooooooooooooooo much helped me soo much for finals!
this was SOOO helpful :) i did my problem as you did yours
Great, that is the way it is supposed to work.
How did u get the mole?
Glad it helped out!!
This video was insanely helpful man thank you so much
Glad it helped and thanks for the comment.
You are very welcome!
Incredibly helpful, thanks!
Why did I even bother to go to class. The Prof himself couldn't even figure this out. Thanks step-by-step Science.
Bummer that the prof could not figure it out, glad that you found the video helpful. You can see a listing of all my videos at my website, www.stepbystepscience.com
Determine the empirical formula for a compound that contains C, H and O. It contains 52.14% C and 34.73% O by mass.
Group of answer choice
Uhh this was a few months ago? Did you ever get your answer?
Thank u so much sir.good teaching methods u have.god bless u..
You are welcome.
Thank you so much! You're awesome at teaching
Saviour. Really helpful
Glad it helped!
Saved My Lab thank you
Excellent and thanks for the comment
Thank you for explaining this clearly. Your video was easy to follow and I was able to get everything g you side. In class it's hard to take notes from teacher because she really fast so your video was a lot easy because your goinh slower. Thanks.
Glad that you find the videos helpful. You can see a listing of all my videos a my website, www.stepbystepscience.com
Step-by-Step Science thanks. Do you only do chemisy? So for pryjng, but are you a teacher or studying?? I'm taking an AP basic chem class and your video covered onw of my subscription subjects so I figured you might be.
Now I am teaching physics from 7 thru 12 grade and maths for the 8 grade. For the past 6 years I have been working at a small private school in Berlin Germany. I have taught some chemistry before.
That sounds like a lot of work. Being a teacher isn't easy, do you work in the U.S now or are you still in German?
zack Vandermude In Germany now and yes it gets busy. Also it looks like you have a German last name. The mouth/openning (Munde) of the Vander.
You are a lifesaver!
Thank you, glad to hear it!
This helped me so much!! Thank you! :)
I understand the process up to the point where we divide the molar values by the smallest molar values. I want to understand the process and not just memorize it so could you please explain how we can just divide the molar values to find the empirical formula?
How did he get 30 for empirical weight?
Glendaly lopez I got u fam, it's Carbon+Oxygen+hydrogen
But 12+16+1=29...Is it mandatory to round up?
No, he has 2 Hydrogens in the formula, so its 12+16+2(1) = 30
its C+2(H)+0 =12+2(1.008)+16=30.01
It helped me a lot. Thanks
Step-by-Step Science
• 1 second ago
You are very welcome, thanks for taking the time to comment.
How would you do this if you aren't given the total mass?? Pls. College exam is tomorrow.
Wait, you can't assume 100 grams if they provide a total grams of 180.16. Don't you need to multiply 180.16 by all the given percentages first to get the grams of each element, then do the grams to moles calculation?
+lvbearboy 180.16 is the molar mass of the compound, not the mass of the sample. The percent composition will be the same irregardless of the mass of the sample.
Thank you very much for making this video. However, I was wondering what would happen if, after dividing the amount of moles for each element by the lowest number, one of the numbers ended in a decimal such as .5 where you wouldn't be able to round up or down. I know that the empirical formula only contains whole numbers so how would you go about writing the empirical formula for this instance?
Thanks again,
Whitney
Whitney Souery if you divide and one of them is .5, multiply all of them by 2. Same if you get .3, multiply all of them by 3 for the correct ratio
Is the end compound actually glucose?!
It helps me a lot Thank you 🤠
Happy to help, you're very welcome.
What if the smallest molar value doesn't give you a whole number when divided by another particular molar value?
that's where I'm stuck too but I think you have to then multiply all by a number that turns then into a whole
I’m confused about how you were able to get the 30g / mol. I know you said from the periodic table but can you please explain to me where on the periodic table I would find it??
carbon's molecular weight (on the periodic table) says "12.001" or 12
Hydrogen's molecular weight (on the periodic table) says "1.008" or 1 [In the problem, it says H2, so double this (2)
Oxygen's molecular weight (on the periodic table) says "15.999" or 16
C=12
H2=2
O=16
Added together = 30. So you now have the 30g, I hope this helped!
Isn't it faster/easier to find the molecular formula 1st, since the empirical formula is usually obvious from there? Thanks.
+Nathan Parrish Can you find the molecular formula first? You can see a listing of all my videos at my website, www.stepbystepscience.com
how you can solve if you get a point by dividing the molar value by the lowest molar value
Amazing! I often struggle with chemistry, thanks for the help
+Zoso 345 You are very welcome...
You can see a listing of all my videos at my website, www.stepbystepscience.com
Hey= sir how did you know to divide when converting grams to mol? Because in this video you really didn't go into depth about that concern.
Uhm sir I didn't get it how does the empirical weight turns to be 30 g 1mol? Thanks
+ｒｙｓｋｔｈ you look on the periodic table and add up the weights of the elements from the empirical formula.
+WrathPhalanx Thanks for responding. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you so much
what would happen it i were to put this in /sci/ and /b/?
Question, How did you get 30 as the Empirical Weight?
The molar mass of 1 carbon (12g), 2 hydrogens (1g +1g) and 1 oxygen (16g) from the empirical fomula. Does that help? You can a listing of all my videos from my website, www.stepbystepscience.com
that equals 20, not 30
12+2+16=30 :)
You are the best.
Valentina Téllez That is very kind of you, thanks for commenting
You gained another subscriber :)
And thank you very much for that.
Great video helped me a lot thank you sir.
You are very welcome.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Take the percentage and divide by atomic weight at the beginning
what if one of the components is ash from municipal solid waste?
This was sooo helpful..thanks
Thanks this helped a lot!
Glucose?
WORTH WATCHING
THANK U
SIR CAN U SUGGEST ME PHYSICS CHANNELS FOR CLASS 11
PLEASE PLEASE PLEASE
Thank you, my channel is actually mostly physics.
You can see a listing of all my videos by topic at my website, www.stepbystepscience.com
ilecture online also has a lot of good physics videos.
okay
thank u very much
+Step-by-Step Science so basically u can find an empirical and molecular formula from just one percent composition with the molar mass right?
and what if i have this problem... compound has the following mass composition: 53.33% carbon, 11.11% hydrogen and 35.56% oxygen. Its molar mass is 90amu.
Thankyou this was very helpful!
@Porcia Hall, Thank you for commenting, glad you found the video helpful.
Thanks heaps, helped a lot :) i appreciate how you simply put it as do this and this :)
+TriHardHero Thanks for the comment. I try to go through everything step by step…in fact…you can see a listing of all my videos at my website, www.stepbystepscience.com
Thanks :)
Great video
Thank you!
Thanks sooo much i finally understand chemistry;)
This was great
+Isi Hummetli Thanks for the comment, You can see a listing of all my videos at my website, www.stepbystepscience.com
Oh thanks.I will look through
Do you have any video about mass and molar concentration ?
I believe that I do not, sorry.
Okay dude, thanks
Helped a lot thanks
This helped a lot thank you very much
Great video 👍🏼
Thanks for commenting.
Thad vid is old but helps allot thank you
How ddi you get 30 for empirical weight ?
The molar mass of 1 carbon (12g), 2 hydrogens (1g +1g) and 1 oxygen (16g) from the empirical fomula. Does that help? You can a listing of all my videos from my website, www.stepbystepscience.com
bless
your
soul
No blessing necassary, just trying to help out a bit where I can. Also You can see a listing of all my vidoes at www.stepbystepscience.com
My chem teacher is a funny old man but he is not a well rounded educater and it is videos like these that help me out so thanks
Thanks for the comments
From where that 30 came???
I watched this video and I am still confused on how to do molecular formula. How did you even get 30g and on my test they don’t even give you the molecular weight just the percentages of each element
It helped so much carry on
You are very welcome, thank you very much for watching and commenting.
OMG!!! I finally get it!!!!! thank you!!!!!!!
Claudia Penaranda Awesome, thanks for commenting!
Thank you very helpful!
it was helpful thank you
Thank you so much! Super helpful
Perfect
Thanks for saying so!
How would I solve this if it said “the molecular mass is 180.16”
Oof this was 2 yrs ago😬😬 hope you found your answer
How to calculate molarity
I do not think I have a video for that.
Thank you soo much sir ...
thanks really much, helped me
but there is no given mw just the percentage..
Thank you😍
You are very welcome, thanks for watching and commenting.
dude god bless you I was so confused
dude, great that you got it figured out and thanks for the comment.
Thank you
gerne!
Thank you so much!!!
I dont get how to get the ew
thank you so much!!!!!
the atoms do not add up
Merci beaucoup!
You are very welcome.
So helpful thank you!!!! :)
Thank you :) really clear
+VestigeVogue Thanks for the positive comment.You can see a listing of all my videos at my website, www.stepbystepscience.com
thank you so much