Isn't PEP is 3C carbon molecule? Coz in step 2 the structure formula for PEP have only 2 carbons, there should be one -COOH molecule attached on the 1st carbon and the C=O bond should be C-0-H2PO3. please correct me if I'm wrong.
Thx for the nice lecture sir! And I saw an miswritten thing which is the double bond btw C and O of phosphoenolpyruvate on the 2nd step on the right side. Thx!
thanks for your wonderful lectures...i am a student from india...your way of teacher is very good....bless u wish u lots of health and wealth...keep goin
I think you're missing the orthophosphate generated from step 1 in the net reaction. That, and the pentavalent carbon draw in step 2 aside, this lecture is great.
Thank you for the explanation :) I have a doubt though. HCO3 is found in the rbc's but gluconeogenesis is carried out in hepatocytes. How are these correlated ? Thank you in advance :)
kindly, enlighten me on this: in step 10 of glycolysis, is pyruvate changed to pep? you said so in the beginning of this lecture. thanks. i love your lectures.
where does the HO go from the HOCO2-PO3 in step 1? Also in step 2 the CO2 is lost from the oxaloacetate, but where does the CO go from the second COO- group in oxaloacetate when transformed into Phosphoenolpyruvate?
I havent't understood why in step 1 phosphorylation is considered an exoergonic process, while in step 2 it is considered an endoergonic process. Thanks to whoever will answer!
PEP is the highest energy compound, so the phosphorylation of oxaloacetate that results in its formation would still be energetically unfavorable. This is my reasoning
This is a wonderful lecture and has really helped me. One note tho. I believe the structure u wrote for phosphoenolpyruvate is incorrect simply by the fact that carbon cannot have 5 bonds :)
Do you think you could have a few seconds at the beginning or end of your lecture where you are completely out of the frame? I'd like to screenshot you're board to study later. Thanks for the amazing videos, you are making grad biochem much easier for me!
During glycolysis if we have pyruvate shuttle to cross the inner membrane.. So during glucneogenesis why pyruvate does not cross the inner membrane of mitochondria to go outside.. Why it will convert itself to oxaloacetate? Plz reply
I'm a bit confused. Why is it that in the second step, oxaloacetate is being converted into PEP but the first of the two reactions shown start with pyruvate and the oxaloacetate acts as an intermediate?
it is energetically more favorable to first form the pyruvate to oxalacetate (also the step from phosphoenolpyruvate to pyruvate is irreversible) --> oxalacetate then acts as an intermediate and can be formed back to PEP which then reacts back the ways through the glycolysis to form glucose
If glycolysis takes place in the cytoplasm of the cell and the final step of glycolysis produces pyruvate(which is in the cytoplasm), how does the first step of gluconeogenesis takes place in the matrix of the mitochondria? or is the pyruvate that is produced in the cytoplasm from glycolysis transported into the matrix of the mitochondria?
![Skilla Baby - Misfit (Feat. Polo G) [Official Video]](http://i.ytimg.com/vi/IjsylSnNMyw/mqdefault.jpg)
I love your lectures - so clear, so concise, so helpful! 1000x better than Khan Academy :)
agreed
really better than Khan Academy. well i've not watched the same lesson from both cos once i come here, i'm sAtisfied.
AK lectures you are an absolute life saver thank you for everything that you do
This man is abnormally brilliant. I'm amazed. Keep it up.
the phosphoenolpyruvate in step 2 is drawn incorrectly. There are only 2 carbons, but should contain 3
instead of the central carbon having a carbonyl group it should be bonded to a carboxyl group.
Great videos though
Thank you so much ! I have an exam in about 15 days, and these lectures have been helping me a great deal. Your work has not been in vain !
Isn't PEP is 3C carbon molecule? Coz in step 2 the structure formula for PEP have only 2 carbons, there should be one -COOH molecule attached on the 1st carbon and the C=O bond should be C-0-H2PO3.
please correct me if I'm wrong.
Thank you so much. I really wish you happiness from all my heart!
Your videos are so helpful! Thanks a lot!
You are a wonderful tutor.
Thx for the nice lecture sir! And I saw an miswritten thing which is the double bond btw C and O of phosphoenolpyruvate on the 2nd step on the right side. Thx!
Thank you very much for the explanation!
Thank you so much, now this mechanism will be easier for me.
I love your lectures and much clearer.
u r the best!
I see a pentavalent carbon!! other than that, fantastic lecture as always. Keep it up!
you are the best ever.
excellent lecture!
thank you so much you are a hero
thanks for your wonderful lectures...i am a student from india...your way of teacher is very good....bless u wish u lots of health and wealth...keep goin
Best teacher of biochemistry .☺☺☺well explained sir ☺
Endless gratitude
Your lecture concept clear my doubts
I love you so much.
U are perfect...
Thankyouuu!💫
I enjoyed it
Wonderful lectures , assist in the study of lippincott (which can get really dry btw)
I think you're missing the orthophosphate generated from step 1 in the net reaction. That, and the pentavalent carbon draw in step 2 aside, this lecture is great.
If anyone can answer, where does the 2H+ come from in the first step?
Thank you for the explanation :)
I have a doubt though. HCO3 is found in the rbc's but gluconeogenesis is carried out in hepatocytes. How are these correlated ?
Thank you in advance :)
I agree. So much better than Khan academy!
kindly, enlighten me on this: in step 10 of glycolysis, is pyruvate changed to pep? you said so in the beginning of this lecture. thanks. i love your lectures.
I think it should be phosphoenolpyruvate (pep) to pyruvate
where does the HO go from the HOCO2-PO3 in step 1? Also in step 2 the CO2 is lost from the oxaloacetate, but where does the CO go from the second COO- group in oxaloacetate when transformed into Phosphoenolpyruvate?
thank you very much. i have an paper about in 3 days these lecture have been helping me.
I havent't understood why in step 1 phosphorylation is considered an exoergonic process, while in step 2 it is considered an endoergonic process. Thanks to whoever will answer!
PEP is the highest energy compound, so the phosphorylation of oxaloacetate that results in its formation would still be energetically unfavorable. This is my reasoning
So how does acetic acid prevent hunger and increase lipolysis?
This is a wonderful lecture and has really helped me. One note tho. I believe the structure u wrote for phosphoenolpyruvate is incorrect simply by the fact that carbon cannot have 5 bonds :)
coolnight987 Yes, it should contain a -COO group instead of the carbonyl group. Refer to my other lectures for its proper structure.
Do you think you could have a few seconds at the beginning or end of your lecture where you are completely out of the frame? I'd like to screenshot you're board to study later. Thanks for the amazing videos, you are making grad biochem much easier for me!
beyond comment
i dedicate the A i intend to get to you!
During glycolysis if we have pyruvate shuttle to cross the inner membrane.. So during glucneogenesis why pyruvate does not cross the inner membrane of mitochondria to go outside.. Why it will convert itself to oxaloacetate? Plz reply
I wanna know if there's any book contains this detailed informations??
Lehninger Principles of biochemistry
I'm a bit confused. Why is it that in the second step, oxaloacetate is being converted into PEP but the first of the two reactions shown start with pyruvate and the oxaloacetate acts as an intermediate?
it is energetically more favorable to first form the pyruvate to oxalacetate (also the step from phosphoenolpyruvate to pyruvate is irreversible) --> oxalacetate then acts as an intermediate and can be formed back to PEP which then reacts back the ways through the glycolysis to form glucose
Please can we get the soft copy of the notes you write on the board.PLEASE!!
my website...
lost for words buddy
Hi. I love your lectures. The PEP illustration is however incorrect, Sir. Thank you for these!
really???
If glycolysis takes place in the cytoplasm of the cell and the final step of glycolysis produces pyruvate(which is in the cytoplasm), how does the first step of gluconeogenesis takes place in the matrix of the mitochondria? or is the pyruvate that is produced in the cytoplasm from glycolysis transported into the matrix of the mitochondria?
The pyruvate can enter the mitochondria from the cytoplasm.
Pyruvate transported to mitochondria matrix via mitochonrial carrier to be decarpoxylated to acetyle co A for energt production
Why are you so smart?
PEP structure is missing a carbon
Your chemical structure for phosphoenolpyruvate is wrong....
Can you be my teacher
too much man, too much