Tension Force Physics Problems
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- Опубликовано: 16 окт 2024
- This physics video tutorial explains how to solve tension force problems. It explains how to calculate the tension force in a rope for a object descending with a downward acceleration using newton's laws of motion. it also discusses how to use free body diagrams and the weight force to calculate the tension force in two ropes at different angles. There's another tension force physics problem that asks you to calculate the tension in two cables / ropes where one rope is in the horizontal direction and the second rope is at an angle.
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Is it okay for you to add the full video here too for those who have RUclips membership?
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Thanks a lot man you are a saviour. I was literally finding this topic difficult to comprehend but after watching this video it became so easy to solve tension problem.
What the heck. I was literally going to search up this practice problem and then I see that you uploaded it 2 hours ago...H-how did you know that I needed this exact video? LOL, even the question I got wrong (which is why I'm searching it up) is almost identical to JG's first question. xD
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Fr
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thanks for this video! I usually see the video that's made by you and I benefit from it. In this video I stopped worrying about tension problem because of you. thank you so much once again my teacher.
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Finally I found a video on force tension. Thanks!
In my school they just taught me the formula of tension force which is T = M(g+a) but they never taught me how it was interacting with y axis.. and like Sum-of-F(y) or those. Actually formula just enables us to do maths tht are capable of solving with just that formula. If u know one formula then you can do just one type of math. But we need to learn the root of it. The basis of it. Thanks to your teaching I can understand formulas better and I dont have waste my energy in memorizing them. I can just create my own favourable formula if I have to. Thanks a lot. You deserve a lot more recognition.
Thank you once again for another excellent video on Tension Force in Physics.
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closer to the end, with the last free body diagram, that made a lot of sense how it works since you lose the track when working with equations and numbers and taking a look at the picture helps a lot to clarify whats going on
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at 2:24 , shouldn't we use -9.8 as acceleration because gravity acts downwards and we are taking the upwards direction as positive?
Late answer, but here's the explanation:
It's because on 0:57 he set the sum of the forces to be ΣF = T - W, so he already put the minus sign here on the weight force where gravity is. You could set it to be ΣF = T + W, so it would be ΣF = T + (50 * (-9.8))N, as adding a negative number is the same as subtracting, the result would be the same.
we use -ve as direction
9.8 is a downward acceleration so it must be -9.8 and because of this we calculate 2.3 - 9.8 which is equal to 5.5 and then multiply it by 50 and that is equal to 275
yes i was thinking that too. It confused me to get 275 for the tension because then the box would not be lifted. I don't understand why he added the accelerations together for 1a and then subtracted the accelerations for 1b if both the accelerations in b are going in the same direction ?
The acceleration is 9.8 due to gravity. Upward acceleration will be -9.8 because it is going against the gravity.
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Hi, i genuinely am lost. If the accelerations are in different directions, aren't we supposed to subtract and if in the same direction, add?(first example)
Chai
yeah if you use gravity which goes down as a positive vector then he should have done 9.8-2.3 in the first example
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In the first problem, wouldn't gravity be negative here since you used up as positive and down as negative?
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At 2:26 shouldn’t it be (2.3-9.8) or (-9.8+2.3) because 9.8 is the force of gravity and gravity is pulling downwards and the acceleration is going upwards?
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equilibrium, find the tensions T,, T2, and T, in the ropes.
the ropes make angles unknown with the horizontal. If the system is in
A bag of cement of weight 300 N hangs from three ropes as shown in the figure below.
Hello sir, thank you for your videos, it's enlightening !
I have a problem rolling in my mind and I'd love to bounce it off to someone like you.
Let's say I have 500kg suspended to a rope at 3m high.
I'd like to know what resistance, force or tension (i'm not sure) it would take to slow its fall to a crawl like 3m/10 hour.
If you have the time to answer this little problem i have, i'd be very happy !
Thank you again sir !
Assuming the block starts from rest (u=0), there's no air resistance.
m = 500 kg
s = 3m v = 3m/10hr
s = vt
t = s/v = 3 × 10/3 = 36000 s
s= ut + at²
a = s/t² = 3/36000² m/s²
F = ma = 500 × 3/36000²
(Downward force needs to be 500 × 3/36000² N)
W = mg = 500 × 10 = 500 × 3/36000²
-Fnet = T - W
T = -Fnet + W = -500 × 3/36000² + 5000 N
If you pull the block with this force, you'll get your desired result.
What do you use to write on?
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Please I need help with this question 🤕
A uniform plank “AB” of mass 3kg and length 16metres is suspended at the ends of two inelastic strings AP and BQ where P and Q are two fixed points on the celling such that angle PAB =150 and angle QBA=120.
The plAnk is held in equilibrium in a horizontal position with the string taut by a vertical upward force”F acting at a point C 5metre from the end A
Find the tension in the string F
g=10m/s^2
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Please tell what's the difference between cord and string? And how to solve cord questions??
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If you had a volume with uniform density but it was oddly-shaped meaning it has more mass on one side and the ropes are at the same angle. One rope is at the smaller side and another at the bigger side, would that mean the rope at the bigger side has more tension?
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But I have a question I'd like to be cleared I noticed that w weight didn't have effect on the horizontal axis x why?
Weight is Fg (mass×acceleration due to gravity), that is the force of gravity acting on an object. Gravity only acts downwards (sorry its a late reply )
Always know what we needs
ik im 2 years late but this explanation is better then my teachers
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finally got the hang of it
hey i understand what you did to tension for the two ropes in the second question HOWEVER wouldn't it be incorrect as the weight is being help by two strings, there for diving the weight by 2, then using sin 588/2 = 294.3, 294.3sin(60) 294.3sin(30)?????? i have a midterm tomorrow please help. i got your answer originally but it doesn't make sense as to why i would not divide the mas by two
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