Mechanical Engineering: Particle Equilibrium (7 of 19) Tension of Cables Attached to Hanging Object
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- Опубликовано: 19 июн 2015
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In this video I will calculate T1=?, T2=?, T3=? of a 500kg mass hanging from a ceiling.
Next video in the Particle Equilibrium series can be seen at:
• Mechanical Engineering...
Truly a gift to all those of us who leave physics class falling on our faces.
Hahahaha! We all been there. Glad we can help.
We learn this concepts in class 11 before engineering proud to be indian
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Bless your soul you amazing man! I have a test tomorrow and i get everything you are doing, keep going.
you passed?
This is amazing. Thank you SO much. I could understand in 10 minutes what I couldn't for months in other physics classes. Teaching is a skill on its own.
You're very welcome!
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Glad you find our videos helpful.
Thank you so much , i find all your videos very helpful since I’m taking AP physics and the teacher in school tries to explain things fast since we have a lot of material to cover and I often find myself lost in her lesson and it’s hard for me to keep up with her , one day i found your videos and ever since that day i depend on them whenever i need help . :) thank you very much 💕✨
Michel Biezen, i enjoyed watching and learning from your tutorials. Your Engineering tutorials are very good, and i like them. You did an excellent jobs of explaining concepts in a very entertaining , clear and understandable way . Many thanks for your tutorials.
I had such a big problem understanding this typical physics exam question. thanks to you i can now solve most of these questions in less than 4 mins. Hip hip hurra for you Professor.your explanations is so easy to follow.
I missed this on my physics 1 exam. Looking back on it I have no idea how I didn't understand it. Its so easy now
I swear to my teacher’s explanation was so complicated and I didn’t understand anything until I saw this vid and I have a test tomorrow thank u so much
I hope i found this earlier this is a great help you are amazing.....
If my prof is good as you i wont struggle understanding our lessons
Thank you so much for the person in this video.Im getting to know something new about Force hanging case.Hope for more such a great video in the future.
Wanted to say I came here to say looking for help to solve a challenge problem for my physics class only until I realized half way through that it was a trick answer. Still stayed for the excellent lesson, you’ve definitely helped me on my path Mr. van Biezen. Many thanks.
Thank you. Glad you found our videos. We have thousands of videos on physisc and engineering.
I was the whiz when we did this at school (in the 60s) but I moved in to chemistry and not gone near since. Too many years later and m son needs help with his homework. French school as well so it's in French God help me.
You might just have saved my life with this. Very well explained. Thank you.
So you had your kid when you were around 50?
@@thefridge5844 I'm 66 now, he is 18.
I haven't been able to understand this problems earlier but now everything is clear. It is only because of u. U r amazing. I also liked your bow
A very helpful video, i was just reviewing my class lecture and this video explained a lot. Thank you so much.
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More people have mentioned that. That you.
Some days ago i was ill and I couldn't come to school. I tried to study but didn't understand until I watched this video. Thank you so much for explaining. You saved my life
thank you so much. From South Africa. This sure will help for tomorrow's physics exam
fellow south african! i also have an exam tomorrow!!! ugh!
YESS!! Thank you verymuch!! I couldn't understand this from my sir but u easily explainedit !!!!! THANKS ALOT!
You sir are a genius. May god bless you!
You are The Boss , I am glad to watch your video ,you are amazing and i understood everything, even though My English is not good enough , thank you very much , made my day .
You just summarized my entire semester in 10 minutes. Thank you, Sir🥲.
Glad you found our videos,
Sir, you might hear this a lot of times or probably none but you're awesome sir. You have saved my life lol I hope you're doing well! And thanks a lot for this video!
We remember that when we were students we were at times very desperate to find anything that could help us understand the material. That is a big part of the reason why we are making these videos to help students today that are in the same position. Comments like yours tell us it is working. We are very glad they are of help to students. Thank you for your comment.
Professer Biezen, Thank you so much for doing these static videos I am a Mechatronic Engineering student and I have been enjoying many of your videos to help me along. I just so happen to be taking statics this summer and this playlist is what i have needed. I am also taking Ordinary Differential equations I hope you get a chance to do this as well. Again thanks for the content.
Johnny Canazon
Johnny,
You are welcome. I started differential equations as well as statics. Now I just need time (still working more than full time besides doing these videos) Good luck with your studies this summer.
thanks Prof! love the way u easify the question.. and we know giving knowledge I's just doubling your knowledge
sonic boom are you American ?
great vid! im currently in my final year of highschool, and due to the coronavirus im very bored so im practising for physics in college. watching this makes me feel dumb and clever at the same time😂
thank you so much your videos are really appreciated
Excellent tutorial. You make it so simple Sir.
Thank you very much professor. Really amazing lesson.
May God bless you, Sir. Your tutorial was really helpful.
Never studied mechanical engineering. But after watching your lessons, I feel that I missed a lot! So interesting! Tank you.
Thank you for this great example! I only encountered tension problems that only has t1 and t2 and are attached to the object, but this one has t1 and t2 and its connected to another string which is t3 that is attached to the object. 😊 Also subscribed and will be exploring your other physics videos. ❤️
Glad to have you as a new subscriber! We have over 9000 videos. Enjoy!
thanks for this amazing lecture!
I'm just wondering about ty1 sin 30. Are we assuming that a right angle gets formed by the angle between t1 and tx2 above it so that we can imagine a 30/60/90 triangle with ty1 opposite?
from africa kenya thanks almost graduating come next year channel has helped alot
Keep it going! Glad you found our videos.
You are truly brilliant...
Thank you very much! Helped me out a lot.
Great walkthrough. Thank you.
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This really helped Thank you!!
Great video, thanks man.
Sir can you explain equation relating to rope drum and load. Our project had faced issue since we supplied crane where it function on top of hill due to gravity parameters we couldn't find the exact load we carry out by crane. It runs on 25hp motor, which could lift 10ton , but at 5 ton itself the gears rotated opposite direction since the load seems heavier due gravity pull near Nepal hydro power generation project. It suppose to drill and lift deep to 78mts into mountain but at 9mts itself issue faced
woah, very helpful i must say. Definitely subscribing
the sound the marker does it's so good
Been watching your vids for a while, but just subscribed. I like the straightforward style you have. My only input would be based on how I like to do problems like this and that is to wait and obtain the final forms of the variables and equations and then do all the trig functions and other numbers and arithmetic. Great video however, I enjoy watching and seeing another style and explanation. :)
That is indeed the typical way in which one should solve physics problems (solve the equations first before substituting numbers), but there are a number of types of problems, where plugging in numbers earlier is advisable.
@@MichelvanBiezen :)
@@MichelvanBiezen I like the videos you've done where you take the moment of inertia of a pulley into account. I'd like to see one where you take the mass of the rope into account too.
thank you ever so much for this video. even 7 years later, people like me still find this useful! May Allah bless your soul.
Thank you. Glad you found our videos! 🙂
Nice video, clears my confusion.
Simply..u can use lami's theorem...
4900/sin(130)= T1/sin(110)=T2/sin(120)...
Solve this equation u can get T1& T2 value
it did not work. how?
Yes here you can use Lami's theorem, but you can't use it when you have an unknown force and angle that's why it is better to know how to resolve forces.
Thanks for your videos!!!! 🎉🎉🎉👍
Thankyou so much, great video!
Thanks. You’re a life saver
Thank you for your video! They are very useful first, and second you explain very well!
Thank you. Glad you find these helpful.
The lesson is pretty amazing I appreciate, For further knowledge, I'd like to know what's contributes to the large tensions in T1 and T2, whereas in normal situations, we would expect that summation of tensions in T1 and T2 will be equal to the tension in T3.
When the angles appoach zero degrees, the tensions will approach infinity. 🙂
Oh thank you so much now I solved all my problems really thank you, keep going
Happy to help
Best tutorial ever thanks 🙏
Thank you Professor, I would like to ask about a part of a question I saw in an IG textbook, the question starts as "A smooth bead is threaded on a light inextensible string, the ends of the string are attached to the ceilling, the bead is acted on by a horizontal force F and the bead is in equilibrium..... ", the point is that the answer assumes that the tension on both sides of the string are equal, why is this true?
Thanks
If the tension on the string was not the same on both ends, then there would be a net force acting on the string and the string would accelerate in the direction of the net force.
I love u thanks :) you are a great teacher
Thank you so much! After I saw some of your videos I got an A in Physic on the exam.
Excellent. Good job!
thankyouuu!!! im now understand how to solve this type question!! Really worth to watch
Glad it helped
Thank you Sir
I tried to solve a problem in my high school text which was like this i tried to use Lami theoram for equilibrium but i failed to find the angles it helped alot Sir
May God bless you
Great! Thank you. 🙂
Thanks that was so helpful
I UNDERSTOOD WELL THANKS.
Thanks so much sir, this stuff actually jumped in😁
Glad it helped!
Merci beaucoup !!! Vous m'avez vraiment aidé même si ce n'est pas ma langue ! C'est tout dire :) vous êtes très bon pour expliquer monsieur !
Merci bien
Thankyouuuu!!!!
I have been watching all of your physics problems, very well done videos at a good pase. Much appreciated, thanks for your hard work and dedication.
Many thanks for your nice comment. We appreciate it.
God bless you and all your relative
Thank you very much!
Very comprehensive instructions
This came in very useful!
Glad it was helpful!
Very helpful! Thank You!
nice and clean thank you
Thank you so so so much, you are a lifesaver!
Happy to help!
This is an old video but since the results showed there are inbalance between the force, does that mean its not in equilibrium? Since it supposed to be at 0 however in the end we got like 6,012N T1 and 5,540N on T2? Plus the 4900N below
There is no net force on the object. (Otherwise there would be an acceleration --> F = ma) Therefore all the forces in the x-direction add up to zero and all the forces in the y-direction add up to zero.
Thank you sir!
Dear sir I have been watching your videos and they have been very helpful.
I just have one question. What if the rope is not weightless(Like reality)? How can we incorporate the weight of rope into this equation if we know the weight/m?
Then you need to look at this playlist: MECHANICAL ENGINEERING 10: FORCES ON CABLES
super clear, thank you so much!
Glad it helped!
thank you.
wonderful!!!
very nice explain
Thank you so much!
Why is there a tension force equal to the the gravity force. Wouldn't that net in twice the force downward?
i dont understand what you plugged into the calculator that gave you the answer for t1 towards the end! please help!!
T1 = 4900N / 0.8152
Excellent better than the people lecuring and tutoring me
Thanks a lot!
thanks for helping bro
Thank you Sir 💙🎶
thank you from the bottom of my stupid heart
Thank you so much for this explanation
Welcome 😊
Thank you Sir!
good work it was hard but you made it very simple
Glad it helped
This is so interesting to me (now)... now that I'm trying to build a backyard zipline! I'm trying to figure out what the tension load is on the anchor points (to estimate deflection based on a post materials of choice). With AnchorA at the different height from AnchorB (to gain the 3% slope)... adding a sag in the cable to create a low point (and use gravity to slow down/brake the zipline)... the low point will NOT be in the middle. With the low point NOT in the middle, then the angles at the anchors will be different, so I think the equations you presented here would be applicable to finding the tension at each anchor points based on the low point (of the sag). Is my assumption correct? Can I apply these equations to my problem? Or does this only apply to a cable with anchor points that are level (as in your example)? If so... my other problem remains, which is how do I know where my low point will be (based on the heights on the anchors and the distance between the anchors)? Is there an equation to find that?
When it comes to a backyard zipline, trial and error will work the best. The less sag you have to higher the tension in the cable.
Michel van Biezen yes... That’s a good approach too. While I do have a tree at the starting anchor... I don’t have a tree at the opposite end, so I’ll need to install a post. This will require a sizable post hole, concrete and post itself (I imagine). And while I’d prefer to over build it anyway... I’m trying to at least find an objective reference point. I certain don’t want to under estimate the size of the post because redoing a post installation like that would almost be unbearable.
Anyway... I also thought this is a fun problem where I could actually apply math and physics to solve.
I would recommend doing a few calculations with various amount of sag and with various resulting angles. You would be surprised how much tension you will have when the sag is reduced.
You the best👑
Thank you !! Saved me a ton
You're welcome!
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Thank you.
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At 3:54, he meant to say T1x in the x-direction, not y. Just a happy little accident. :]
"Happy little acident..." Do you watch Bob Ross from "Joy of painting"? LOL. I (Mike van Biezen's wife) used to watch him on TV 25 years ago. Long before Bob Ross RUclips days.
@@MichelvanBiezen Heh. I wish. Bob Ross was before my time.
I hope I know this channel when I'm still an undergraduate student. 😌😌😌.
should the t1 or t2 be ALWAYS have more newtons than t3? or does it depend on the sines and cosines given?
I don't like to use "always" except in very few situations. Best to work it out and see what happens.
what a god. I am passing my exam bc of this
No god around here. But glad you found our videos and you found them helpful. 🙂