How to Find the Cable Tension Forces - Static Equilibrium - Equilibrium Problem 3

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  • Опубликовано: 27 янв 2025
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    In this video, we find the tension in the cables shown due to the applied force on the system. This problem is solved using static equilibrium and the property that all forces, internal and external, must cancel and counteract each other so all forces sum to be zero.
    Problem statement:
    Two cables are tied together at C and loaded as shown. Determine the tension in AC and BC.
    Problem walkthrough steps:
    Draw a free body diagram
    Look at each force separately, known and unknown
    Find or determine the x and y directional forces for each of the known and unknown forces in variable form
    Sum all the x directional forces together. Then sum all the y directional forces together
    Solve for the unknown forces. Can use multiple processes to solve for 2 equations 2 unknowns (if this happens)
    Check answers
    Topics of this problem include:
    Free Body Diagram (FBD)
    Solve a statics equilibrium problem with multiple unknowns
    Determining equilibrium
    2 unknown forces
    2 unknown vectors
    X and Y Components
    Summation of forces in the x and y directions
    Vector Addition
    Force combination
    Vector combination
    Vector Mechanics
    Forces in right triangles
    Orthogonal vectors
    Determining tension forces
    Summing forces to be zero
    Beer Johnston problem 2.33
    Engineering statics
    2D equilibrium problem 3
    College level
    Professor Engineer
    Professor_Engineer

Комментарии •

  • @Professor_Engineer
    @Professor_Engineer  Год назад +2

    Thanks for watching! Don't forget to like this video, subscribe to the channel, and leave a positive comment below! Also, if this video was helpful, please use the link to view the next problem in this Static Equilibrium Series:
    ruclips.net/video/U41vsiX2do8/видео.html

  • @stoffeundeis5208
    @stoffeundeis5208 3 месяца назад +1

    THATS AMAZIG. Please keep going. The german engeneer static videos are very dry and dont use numbers. That's why I am looking for english videos, and yours is just perfect. Thank you!

  • @HarryKaufman-go2nx
    @HarryKaufman-go2nx Год назад +1

    Glad I found this channel. So helpful👍

  • @mayghazi8210
    @mayghazi8210 8 дней назад

    Thank youuuu!!

  • @alitr-tf1dc
    @alitr-tf1dc 3 месяца назад +1

    thanks a lot 💙

  • @sirig03
    @sirig03 Год назад +2

    Thank you so much

  • @Marv_33
    @Marv_33 Год назад +1

    thanks for the great explanation I will use this channel and shared with some of my current classmates.

  • @sandrashappell6754
    @sandrashappell6754 Месяц назад

    Why didn't you include the gravitational force on 300? Is it just a choice? Does including it just change the unit such as newtons?

    • @Professor_Engineer
      @Professor_Engineer  14 дней назад +1

      Since this problem is in US Customary Units, we do not include the acceleration of gravity on weights in units of force such as pounds (lbs), kips (k) or tons. In the SI system, we need to include/multiply by the acceleration of gravity on masses such as kilograms (kg) to convert these masses into forces, which would be Newtons. In US Customary Units, if we were given a mass, which would be in units of slugs, then we would have to multiply by the acceleration of gravity. So, in short, when in force units do not multiply by the acceleration of gravity. I hope this helps.

  • @scisev
    @scisev Год назад

    aren’t the angles wrong? shouldn’t it be 90-20 and 90-40

    • @Professor_Engineer
      @Professor_Engineer  Год назад +2

      The angles shown are correct. And hopefully this explanation helps, think of the cable as a transversal line going through the solid black horizontal line at point A where the 40 degrees is measured and going through the x-axis at point C where I drew the free body diagram. Because that solid horizontal line and the x-axis on the FBD are parallel to each other, any line crossing both of these parallel lines will be transversal. Thus, the angle between the parallel line and the transversal line (on the interior side of the crossing) will be equal at each end. Basically, if the line of the cable is 40 degrees of the horizontal at one location, it will be that same 40 degrees off the horizontal at another location. If you need a better explanation, let me know. Hopefully this helped.