THANK YOU SO, SO MUCH!! I didnt understand this topic when it was taught in class and later gave up for a yr but now we're doing it again and i figured I had to deal with it sooner or later. With your video, I FINALLY understood the concept and can now solve questions on my own. Really grateful, man.
Thank you so much! That was an extremely clear explanation. For the problem I was solving, the total acceleration was already given to me for three identical blocks being pulled to the right with a force of 55 N. It asked for the tension of a string but it's the same throughout since the blocks are identical. I got the answer now :)
Really confused at the beginning when you made separate equations for the blocks, so I paused, and singled out all tension variable, and substituted them until they fit in block m1 equation with the Fa. Ended up as Fa = a (m1+m2+m3). Now it makes much more sense. But as you can see, as I un paused, so they somewhat the same thing. I was confused whether the tension was the same in all the ropes.
Simple trick: T1: (5+8)×300/5+8+2 13×300/15 3900/15 =260 For those who want to save some time F=ma That means a=f/total mass Tension= (m1+m2)×force/total mass (specific for the case of T1)
Thank you sir. Our sir taught us how to two boxes question and gave us three boxes question to try and i wanted to solve, from ur video I understood and solve it ❤ and Love from India ❤
THANK U SO MUCH I FINALLY UNDERSTOOD THIS LESSON because my class teacher is an old man and i dont understand anything he says cuz he is missing teeth and he is half asleep while "teaching" TYSM!
What would be the max. tension on each cable at the moment it overcomes the frictional force on those blocks? Can you assign friction coefficient and do an example?
hi, may I clarify that to solve the acceleration of the 3 blocks, you can just treat the 3 blocks as a system, then find acceleration using equation F=total mass x acceleration ?
What if we got the answer 59.62N as the answer? As in: Fa= (Ba+Bb+Bc)*a 300N=(5kg+8kg+2kg)*a a=300N/15kg a=20m/s^2 Tension on Tc: Tc=Bc*(g+a) Tc= 2kg*(9.81m/s^2 + 20m/s^2) Tc=2kg*29.81m/s^2 Tc=59.62N tension in the string between blocks A, B and C = 59.62 N My question is what is the difference?
I'm really confused you didn't put any frictional force on the forces acting horizontal cause according to my teacher whenever there's an applied force there's going to be a frictional force unless it's frictionless,but you didn't mentioned that it's frictionless that is why I'm lost.
Why does the original force drop between the bodies? I've asked on physics stack exchange and my professor but no satisfactory answer so far. If one force is exerted in the first place why does it drop towards the end of the system?
THANK YOU, this clarified everything for me with these problems
Thanks for comment! Happy to help.
wow, you're a really gifted teacher. the clarity and simplicity of your approach to problems is super helpful. thank you!
THANK YOU SO, SO MUCH!! I didnt understand this topic when it was taught in class and later gave up for a yr but now we're doing it again and i figured I had to deal with it sooner or later. With your video, I FINALLY understood the concept and can now solve questions on my own. Really grateful, man.
That’s great to hear. Good luck on your exams! Comments like this are the reason I make videos.
Oh man this helped so much with tension problems and general. Helped me figure out solving blocks on planes too! Great explanations and breakdown
What a beautiful solution to a great problem.
Absolute nice way of teaching
What a great sir you clarify all my doubts on Newton's law of motion
I watch your each and every video
Love from India ❤❤
Omg this is the single reason ill pass my physics exam tmrw, TYSM
Thank you so much! That was an extremely clear explanation. For the problem I was solving, the total acceleration was already given to me for three identical blocks being pulled to the right with a force of 55 N. It asked for the tension of a string but it's the same throughout since the blocks are identical. I got the answer now :)
Good job Lillian!
you have no idea how helpful this was, stresing over first year uni rn, this video from five years ago was a godsend
hahaha same. What's the chances of us being in the same uni?
@@blueshorts88200.276%
Great explanation. Thanks for your work explaining Newton’s laws.
My pleasure!
Really confused at the beginning when you made separate equations for the blocks, so I paused, and singled out all tension variable, and substituted them until they fit in block m1 equation with the Fa. Ended up as Fa = a (m1+m2+m3). Now it makes much more sense. But as you can see, as I un paused, so they somewhat the same thing. I was confused whether the tension was the same in all the ropes.
Very good explanation to teach the mathematical expressions for tension. 👍
Thanks!!! This helps so much, ur explanation was much better than my teacher’s!
oh my god THANK YOU SO MUCH for this video. I was struggling so much but you explained it so well.
Glad it helped!
Thankyou sir, I am very confused how to solve this type question but after saw your video my doubt are clear thankyou sir I am from india
so helpful, my problem was with 4 objects and still this video helped me get all of the right answers for my question. thank you.
Awesome!! You got this.
@@PhysicsNinja now im trying to do another with two objects but im stuck
thank you u made me believe in myself as i didnt quite since i did the same thing but u made me be confident for similar questions
awesome job! you've got this.
Simple trick:
T1:
(5+8)×300/5+8+2
13×300/15
3900/15
=260
For those who want to save some time
F=ma
That means a=f/total mass
Tension= (m1+m2)×force/total mass
(specific for the case of T1)
Thank u so much sir well explained 😅i have a test on this next week been studying very hard ❤ I will tell all my friends about this video
Nice explanation
This was like the easiest question in my jee syllabus
Thanks so much dude! This helped me really understand this topic!
daddy cracked at teaching. i appreciate u
Beautifully explained
This was just what I needed..Thank you
Glad I could help
Superb... I love physics... pls post some videos with inclined plane, free body diagram
Superb explanation.. And thanks to answers sir
i wish you were my physics teacher
Great presentation. Very clear. Thanks!
tysm sir i was finding it difficult to solve these now i understood tysm
good stuff bro im not even capping no cap
Thank you I lost 5 marks in my previous exam due to this.
Thanks 😊 from India
Very clearly explained
Love from India....Thanks a lot ! 😊
Subscribers from India ❤️❤️
Sir I have a doubt that why did you take the tension force of 5 kg block T2 . Why it is not T1 .
By the great explanation
Thanks from India 🇮🇳
Sir I have a doubt that why did you take the tension force of 5 kg block T2 . Why it is not T1 .
By the great explanation
Thanks from India 🇮🇳
Sir I have a doubt that why did you take the tension force of 5 kg block T2 . Why it is not T1 .
By the great explanation
Thanks from India 🇮🇳
@@dbuc4671 why did u copy me
@@praazhnaashre1629 idk
Made so easy:)
Thank youuuu!
Thank you sir. Our sir taught us how to two boxes question and gave us three boxes question to try and i wanted to solve, from ur video I understood and solve it ❤ and Love from India ❤
You just made my life a ton easier
It is very useful for study and speak is very wonderful
Thank you Sir
Thank you for teaching this. It was really clear
Amazing Video
Thank u ❤️❤️
You are better than my teacher😁😁😁
this video saved me from failing my hw
THANK U SO MUCH I FINALLY UNDERSTOOD THIS LESSON because my class teacher is an old man and i dont understand anything he says cuz he is missing teeth and he is half asleep while "teaching" TYSM!
Glad it helped!
In which class this topic is studied??????
Thank you so much! You literally saved me :')
superb sir..
thanks for this amazing video...
Being from India and understood this topic from u only is such a good feeling
U are a great physics teach and Ty so much 🌹
This was great! Thanks
Thank you very very much sir it helped me very much ☺️☺️
Outstanding video sir.
You made this soo easy! Thankyou🤗
Sir ur wonderful
Really really thxx for helping me...... 🙂🙂🙂
Thank you it solved my problem❤️
Thank you so much 😭❤
You're so welcome!
That was beautiful
What would be the max. tension on each cable at the moment it overcomes the frictional force on those blocks? Can you assign friction coefficient and do an example?
hi, may I clarify that to solve the acceleration of the 3 blocks, you can just treat the 3 blocks as a system, then find acceleration using equation F=total mass x acceleration ?
Yes that works!
@@PhysicsNinja thanks a lot! your video really made these kind of questions so much easier to solve!
Superb sir
Thank you
What if we got the answer 59.62N as the answer?
As in:
Fa= (Ba+Bb+Bc)*a
300N=(5kg+8kg+2kg)*a
a=300N/15kg
a=20m/s^2
Tension on Tc:
Tc=Bc*(g+a)
Tc= 2kg*(9.81m/s^2 + 20m/s^2)
Tc=2kg*29.81m/s^2
Tc=59.62N
tension in the string between blocks A, B and C = 59.62 N
My question is what is the difference?
Thank you sooo much for helping me with this concept😊😊
Gratitude from India 🇮🇳🇮🇳🇮🇳🇮🇳🪷🪷
My pleasure 😊
Thank you!
If the blocks have different friction constant ,so what will be the tension fore ?
oh it's really helpful for my problem. thanks.
amazing. thank you.
God bless u sir thank u very much!❤
So nice of you
Thanks 👍👍👍👍👍 sir
Thank u soooo much!
Very good video!
The pro elimination trick rocked sir 👌
Sir if force is not given then how to find acceleration
U forgot about friction? What did you specify the normal force for?
Thank you very much
Thanks!!
Thankyou for this it helped...!
is there a video about the Tension in the Strings with the friction force as well?
I'm really confused you didn't put any frictional force on the forces acting horizontal cause according to my teacher whenever there's an applied force there's going to be a frictional force unless it's frictionless,but you didn't mentioned that it's frictionless that is why I'm lost.
Thanks ninja....
we love you
Uh I have a question. Could I treat the 8kg and 2kg block as one thing and derive the equasion from newton's second law: 300-T2=10(a)?
Thank you 😭❤️
Indeed you are a physics Ninja,👏👏👏👏
bro is currently cuddling while watching this. help me
That’s kinda gay bro?
You gay?
More than good
can you do it for vertical suspension
Thankyou very very muchh sir❤️🙏😀
Great❤️
Love from india❤
will u plz explain me athing why there is tension t1 equal and possite tension t2
Why do the second two blocks have the same tension?
different strings will have different tensions, same strings have the same tension
❤thanks
Why does the original force drop between the bodies? I've asked on physics stack exchange and my professor but no satisfactory answer so far.
If one force is exerted in the first place why does it drop towards the end of the system?
Because they don’t pull as much mass. The second only pulls 2 blocks, the third tension only pulls 1 block
Did I forget the friction of the blocks with the table?
Why did u not consider force of friction acting on both blocks?
if it's not mentioned, we assume it's frictionless.
Is there education system in foreign like indiaaa?