Net Force Physics Problems With Frictional Force and Acceleration
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- Опубликовано: 2 сен 2017
- This physics video tutorial explains how to find the net force acting on an object in the horizontal direction. Problems include kinetic frictional force, calculating acceleration using force & mass, and kinematics problems such as finding the distance travel, calculating the final speed or the time it takes to travel. A knowledge of free body diagrams and a basic understanding of newton's laws of motion is required such as newton's 2nd law of motion. This video contains plenty of examples and practice problems as well as the formulas & equations needed to solve it.
Free Body Diagrams:
• Free Body Diagrams - T...
Normal Force Problems:
• Normal Force Physics P...
Elevator Physics Problem:
• Elevator Physics Probl...
What Is a Normal Force?
• Physics - What Is a No...
Static Friction and Kinetic Friction:
• Static Friction and Ki...
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Contact Forces:
• Calculating Contact Fo...
Tension Force Problems:
• Tension Force Physics ...
Types of Forces:
• How Many Different Typ...
Inclined Planes:
• Introduction to Inclin...
Simple Machines:
• Simple Machines - The ...
______________________________
The 4 Fundamental Forces:
• The Four Fundamental F...
Centripetal Acceleration:
• Introduction to Centri...
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I learn more in a 12 min video than in 3 hours of lectures per week
TRUUU
cuz we only learn when we want or need to XD
This guy is simple, my physics professor makes it seem like we need to do way more than what's actually needed. This guy just helped release a lot of stress the day before the exam.
Yes
yes that's how much school wastes our time lol
WHY CAN'T I UNDERSTAND PHYSICS!!???! Great video BUT MY BRAIN IS TOO DUMB TO COMPREHEND ANY OF THIS
Physics is beyond equations it is imagination try visualizing each problem then you can understand the actual concept .
Visit mindset learn extra
Yo for reAl like right now am trying to solve a problem with only two weights (50kg and 80kg) it has no friction ..... calculate the speed .... me ....THE FUCK
Relate af😂😂😂
He's skipping the steps of wiring out the formulas and units. If you do that, it's more tedious, but much easier to follow. It's also the correct way to do it. He's also ignoring sigfigs, etc.
For my later use
0:11 :(part A) horizontal force and friction example (finding net horizontal force)
2:53 : (part B) acceleration, time, initial speed=0 (finding distance)
4:22 : (part A) frictional force (N), force horizontal (calc net horizontal force)
6:50 : (part B) calc acceleration
7:45 : (part C) final speed after a distance
8:52 : initial speed, final speed, time value (finding acceleration)
I still don’t understand love that
what do u even mean
game movie 😂🤣
same
Lmaoooo i forgot i even said that 😹😭. I don’t even remember learning this
@@valeriamartinez5301 lmao
I know it's just a practice problem, but I'm trying to imagine a 5kg box getting dragged on the ground for over 3km in a span of 15 seconds
Ikrrrrrr 😂😂😂😂
Nyooooom
well it did not state that it was being dragged by a human so..
@@schist_ I never thought this would be done by a human. It's going 720km/hour. Do you know how fast this is?
@@Losshe oh ok, I thought ur talking about human dragging that thing fast, but ok
This really helped me, thank you so much, my Fiancé has started redoing some school subjects and she’s been really struggling with this and so I wanted to help. You have helped me understand and now I can help her 🙌🏻
My physics teacher has a hard time teaching in english so its not easy to understand this subject with her. I feel thankful for you
physics is difficult enough as it is to understand, someone should not be teaching it in a language they arent fluent in. dang i feel u.
@@dbuc4671 my teacher is NOT fluent at all
Thanks, this may actually help me on my physics exam tomorrow!
@mr arican why do you keep asking this
the questions would be out of the world
Same!
@@gypsyfritzvalmores1468 For real
S-Tier tutor, he explains things so clearl Love this man, half my understanding on the coursework in mathematics/physics is thanks to him.
who is S-tier??
My final physics exam is after 6hrs and I have just started this unit you made it easier to understand thanks alot
I understand this but i just dont know when and how to use the formula
You really exerted plenty of effort here. Even though I am still 11 years old, I now have a little information about this. Thank you The Organic Chemistry Tutor
Hi matt
@@shumeiliu5242 Hey shumei liu
@@thelonely1938 su p
Woaaahhh Just today I understand this thing.... just wow. Thank you so much for the crystal clear explanation
I can't tell you how much I appreciate this... You are a savior.
THANK YOU!!!!!! AFTER A MONTH OF LEARNING THIS YOUR VIDEO FINALLY PUT ALL THE PIECES TOGETHER AND IT CLICKED! I OWE YOU MY LIFE!
My teacher took 3hrs class for this and you took only 12 mins
It's amazing
Brings back memories. Thanks
This channel is the best in the world I have been trying to understand this from my lectures for two days with no hope but here in few minutes I could understand the picture please carry on , and give us some examples when there is more forces on y axes as well so we can understand how it will work altogether thanks for your support
Force does not exist physically like an object with mass. Force, as we know it, turns out to be nothing more than an expression to express an idea like one would use the word "Love" to express once feelings. Force or Net Force is not the initial cause of motion. Energy (applied energy) is the origin of motion and not Force. Example: Choose an object of your choices and without applying the energy from within you, try to push and pull by applying "only" the Force or Net Force. Meaning that Energy (applied energy) is the origin of motion and not "Force". Once Energy (E) is applied, it creates what is known as Momentum (p). When this Momentum (p), which is mass and velocity, comes in contact with an object(s), it makes a surface contact that will enable you to push and pull. Energy (E) and Momentum (p) or "Ep", are not to be confused with Kinetic Energy in any way. Without Energy, there is no Momentum. Without Momentum, there is no surface contact on an object(s) to push, pull, work, shaping objects, motion, gravity, magnetism, radiation, etc. Momentum does not and cannot exist without the applied Energy that creates it. Energy and Momentum or "Ep", is the only common denominator that links all fundamental forces of nature. Without Ep, all fundamental forces of nature would be inert or non-existence. ~Guadalupe Guerra
Thanks a lot, now i understand the difference between ΣFx and ΣF
Nice and calming explanation bro. Keep going on ❤
Thanks so much I am going to have a test tomorrow and I finally understand now. I want to give a noble prize to you ❤🙏👏
You're the only reason why I love math now :DDDD
I learned something in like 12 minutes and actually learned something than sitting in a classroom where the teacher just lectures for half an hour, saying things that doesnt make sense. Thank you!
I just learned more in this 12 min video then I did in 5 55 min lessons at school wtf you just saved my life
Bro same
ty for this video i passed my summative test^^
this channel is keeping me alive in college
I am a bit confused though, does it mean that the force acting in the Y direction that's the vertical direction is the resultant force?
Thank you so much for your help! I used this to study for my physics test :)
Thanks sooooo much it's so easy to understand and your voice just makes it easier to understand
Wonderfully well explained, thank you for that.
Hey man thank you very much👍🏼🤝
Thanks it really help me in my quiz
To the people who can’t understand, Write with him!
Write what he’s writing and it might make sense, I do this with all his videos and I understand it quite alot
Who else watching this one day before the test?
Yup
Ay you got notes ?
Meeeeeee
Thank you so much for saving me on my test bro.
I was very confused from 2 days but after watching ur video all of my doubts are cleared🥲 .
Thanks bro for ur help
2 week quarantined had me confused. Thanks for the recap man !!!!
How is it 9 months later? ;,)
@@blossomslittleplace8934 it was cool. I passed the class but made a 2 on the ap test lmao
I think I had an A
@@zaysensationalvibes2120 Oooo nice work Zay! ^^
I hope this videos may help me to understand cause I was the only dumb one in my class while everyone finished the work in 5 mins saying that it SO EASY!!!!!
Thanks 👍 I might actually pass tommorow
U are better than my teacher
Thank you
Isn't it 8400N for the force exerted by the car and the net force is 8400N - 3500N (frictional force) which is 4900N? So, I think the average force would be equal to 5950N. Please let me know your thoughts about this. Thanks!
BTW, I really appreciate your vids. :)
i think your right. let me know
This guy carries all students
Question 2. the 12kg box actually feels an upward force exerted by the surface, the value is - 57.4 Newton (yes, minus 57.4 N) if a 350 Newton force acting on it at an angle of 30 degrees to the horizontal level. It means, the box has been actually lifted from the surface, therefore all the subsequent calculations of the horizontal net force, the acceleration, and the final speed after 200 meters will be invalid.
yes but actually no. You are right if you're only talking about the picture he drew, in that some force would have to hold the box to the surface for it to keep traveling only horizontally (rather then a "negative upwards force" It's probably easier to call it as a positive downwards force, eg gravity, similar to how friction is a positive backwards force, not a "negative forwards force" [even though mathematically they are the same thing of course]).
Notice though that the actual question includes no mention of a surface, or definition of the frictional force as a RESULT of drag on a surface. Therefor, for the purposes of solving the question, the box is floating in liquid, air, or space and the frictional force will be continuously working on the box from all sides, not just from a surface. So in respect to the net horizontal force, in the video is absolutely correct.
You're also right however that the acceleration and final speed are incorrect unless we assume that there is some force (eg gravity) that is stopping the box from moving upwards. Otherwise the acceleration and traveling would happen diagonally; the frictional force would be the same (assumed from the word "constant" and no mention of it only being horizontal horizontal) but we'd need to calculate with the original 350 N. I get a = 19.17 m/s(squared) and Vf = 87.57m/s for this
ima need another one
you have saved many lives including me many times ;-;
thank you so much
NICE VIDEO
Great teacher
Thank you so much
The problem with the 12 kg box pulled to the right by a 350 N force at 30 degrees above the horizontal contains a contradiction in the initial conditions. The scalar component of the downward normal force (i.e., the force that is supposed to be pressing the box against the surface) in this case is (12 kg)(9.8 m/s^2)sin(-90 deg) + (350 N)sin(30 deg) = 57.4 N, which is a positive quantity. It means that there will not be a sliding motion along the surface, since the latter requires that the scalar component of the downward normal force be negative. In other words, if you pull a 12 kg box with a force of 350 N at 30 degree angle, the box will take off the surface. Thus, the problem, as stated has no physical meaning, and the solution provided is not correct, I'm afraid.
thank you so much!!
AP Physics is being poop, you helped fix my problem in 2 minutes
Dude you are life physics saver
this is actually very helpful, thank you
good job buddy you have helped many students from failing the exams
Sir ma'am, for Qn2 ur answer is wrong part b). The tensional force exerts a vertical force upwards of 175N. Since the weight of the 12kg block is 117.6N. Thus there would be a net vertical force exerted onto the block of 57.4N. With this and the net horizontal force acting on the block, there would be a resultant force of 308.51N (3s.f). Acceleration is therefore 25.7m/s^2 (3s.f).
That box is moving 3 km in 15 seconds? That's insane
😂😂😂😂
Thanks a lot!!!
Thank you!
Great video. Thank you!
can you answer this plss..the velocity of an object at a time is given by v=4.0+2.0t.
find the magnitude of force acting on the object of mass=4.0kg
find the kinetic energy of an object of a mass-4.0kg and time 3.0t
setting the initial position x=0.0m of an object at time t=0.0s calculate the time (t>0.0s) at the position x=21m of the object?
Thank you so much for this videos...definitely it could help me to study this lessons so much..😇
Thanks a lot
You are so smart. I'm good at Physics but AP Physics is a little challenge for me. I need a 5 on the exam and I believe that you and my prep book will allow me to get a 5. 😃
did u get a 5
@@adios04 lol no
@@beautyandbrains1695 then what did u get lol
@@adios04 a two. But it was my fault for not studying as hard. I had a good teacher.
@@beautyandbrains1695 oh, i'm taking the class rn so i was just wondering
What if the friction force is more than the applied force would the net force be 0?
The box wouldn’t move
A video on how to find friction force
I don't know if you will see this but @6:33 can you please tell me what the net force would be because I worked it out but I am not sure if I am right.
Koko - Could someone help Koko out here, please?
When calculating net force why don't you calculate the weight of the block??
Great video but so many missing links. Like I didn't understand when the acceleration was squared and when it wasn't. And when initial velocity was also squared and it wasnt
sir please upload some videos regarding range and domain of function
There are tens of videos on his channel on those topics. Search on google " Range,Domain of function organic chemistry."
Are you god? like you have saved me through physics
Thank youuu
I need this and i know
If the force of friction isn’t specified, but the applied force is, can we still solve for the net force?
5:25 hello just wanna ask if the quetion did not provide the friction force then how to calculate the friction force?
If it happen on smooth horizontal surface?, no friction, how to calculate??
u would just put in zero Newtons for your value for friction and do the same exact process in this video.
for the acceleration of the second problem you divided the newton by 12 kg, wouldnt you have to convert the kg to 120 newtons? Just asking, kind of confused.
Am I the only 21 year old who still needs to know how and when to use this formula😩
You are not alone man....
yes
Thank you sir 🙏🏻
just a question about number 2, the force of 350 N at an angle of 30 degrees is enough force to lift the box from the ground, so the acceleration should have a horizontal and vertical component; am I missing something?
This author doesn't pay attention to things like that so he often makes mistakes. If it flew in the air, that friction would cease, yes. He doesn't even track sigfigs. Not a good teacher after all, other than the general concepts
@@VeritasEtAequitashow abou u be the teacher and start uploading video instead of hating a man that helped millions of people
is the force of gravity not needed in the problem?
i understand it though the problem in my textbook is just different
Tell me how ,
Fx = cos ∆
Fy = sin ∆
So draw a line pointing up at a angle that looks like this, this is the force vector.
/
/
/
/
Now turn it into a right triangle
/|
/ |
/ |
/θ_|
Remember Soh cah toa
Sin θ is opposite/force vector
Cos θ is adjacent/force vector
Solve for the opposite and adjacent to find fx and fy
Why can't I rewrite the expression in the first problem as: f-F? Does the greater force always go first?
Because we consider the force acting in the direction of motion as positive
Very nice explanation...just you should use 's' as a symbol for displacement...you are using 'd' for distance...this is not wrong but in equations of motion ...'s' is used...so not for confusion it should used...☺️🤗😊
why do i understand chemistry better than physics
Excellent channel my friend, this if fire content hermano, I don’t want to seem rude but why is the channel called the organic chemistry tutor
I shouldve been just "The Tutor" 💀
@@phantominside6497 😂 💯
I like ya cut G
Why did you find final velocity instead of solving for T and finding speed (distance/time)??? For question #2
Your 2nd problem has a math error. You said 350*cos(30) is 303.1, it is actually around 54...What am I doing wrong?
your calcu is wrong. mine is 303.1
A bicycle and its rider together have a mass of 80 kg. If the bicycle's speed is 6 m/s, how much force is needed to bring it to a stop in 4 seconds?
120 N
I have a test in like an hour and brain empty no thought
how did it go
@@p00t I ended up having an anxiety attack and my teacher let me reschedule 💪
@@p00t LMAO
Suvat equation >_>
3:34 hey directioners
I need to know how to do pushing....
how bot the How much force is needed to accelerate a 85 kg rider and his 220 kg motor scooter at 3 m/s2?
I have no idea what is going on
GOAT