Hello Amit, thank you for the analysis. I have one more comment about the wpe, wpe = 1/CL*(RFBtot||RL||rdspass), say in higher frequency, the Cc would short the gate and drain of MP, the pass devices, result in E node equivalent R = 1/gmpass. So in this case, wpe = gmpass/CL. This is usually be used as 2 stage amplifier 2nd pole analysis.
Thanks! Keep making more "intuition" videos. I feel like we gain valuable knowledge and skills when it comes to intuition, rather than crunching math. It would be nice to continue and explain how the transfer function would like long along with the phase shift. Primarily, It would be nice to see what a RHP or LHP affect the phase margin.
Thank you Sir 😊 Simple Conpect Very interesting Ldo with feedback Types of the v_v,serial _Parell (voltage Amp ,the B=r2/r1+r2 is also +,Av no feedfack is + ) With Cc to achieve the circuit compensation ❤ for Rz the only Zero in the Ldo circuit vo/vi =1-gmpassRz-gmpass(1/SCc)= Vo=0 and then 1=gmpassRz+gmpass(1/SCc)..(1) 1=gmpass(Rz+1/SCc)..(1) (1/gmpass)-Rz=1/SCc..(1) 1/S=(Cc/gmpass)-CcRz..(1) So Wz=1/[(1/gmpass)-Rz)]Cc....Answer🤔 Of all the pole contributions in this circuit, there are only two pole contributions. One pole is the capacitance effect of the first pole vo1, and the other pole is vo2. The improve poles are too close. Add Cc to make the effect difference between the two poles.🤔
Nice explanation!Thank you brother again🙏
thank you brother, nice explanation
I'm not able to understand sir. How can I understand working of transistors and mosfets ? Any reference videos sir? Thank you,
Hello Amit, thank you for the analysis. I have one more comment about the wpe, wpe = 1/CL*(RFBtot||RL||rdspass), say in higher frequency, the Cc would short the gate and drain of MP, the pass devices, result in E node equivalent R = 1/gmpass. So in this case, wpe = gmpass/CL. This is usually be used as 2 stage amplifier 2nd pole analysis.
Hi... Isnt for point A .. Req= 1/gm10?
yes
Yes, you are right
Thanks! Keep making more "intuition" videos. I feel like we gain valuable knowledge and skills when it comes to intuition, rather than crunching math.
It would be nice to continue and explain how the transfer function would like long along with the phase shift. Primarily, It would be nice to see what a RHP or LHP affect the phase margin.
Nice analysis !!
Thank you Sir 😊 Simple Conpect
Very interesting Ldo with feedback Types of the v_v,serial _Parell (voltage Amp ,the B=r2/r1+r2 is also +,Av no feedfack is + ) With Cc to achieve the circuit compensation ❤
for Rz the only Zero in the Ldo circuit
vo/vi
=1-gmpassRz-gmpass(1/SCc)=
Vo=0 and then 1=gmpassRz+gmpass(1/SCc)..(1)
1=gmpass(Rz+1/SCc)..(1)
(1/gmpass)-Rz=1/SCc..(1)
1/S=(Cc/gmpass)-CcRz..(1)
So Wz=1/[(1/gmpass)-Rz)]Cc....Answer🤔
Of all the pole contributions
in this circuit, there are only two pole contributions. One pole is the capacitance effect of the first pole vo1, and the other pole is vo2. The improve poles are too close. Add Cc to make the effect difference between the two poles.🤔