that is legendary @Michel van Biezen, and i dont mean Fermats Theorem, i mean your working through the proof in a clear and concise way, thank you so much, beauty in maths!
Thanks, but one suggestion. Employing the quadradic equation unduly complicates things. Instead, just move the terms with a b^2 to one side, factor out the b^2, divide both sides by the remainder, take the square root of both sides, cross-multiple, divide both sides by b, multiple both sides by 1/a, and viola. Also, please accept my PayPal contribution toward the purchase of a vertical sliding whiteboard. Thanks again.
You are the best! Thanks for making this so easy to understand.
You are welcome.
This is so wonderful way and you relive my stress but the video is not clear to be seen, so anyway try to improve my dear.
Thanks! This video is helpful for me.
Glad you found our videos and you find them helpful. 🙂
can you a video on which you'll how it is possible to get the laws of Newton with the Hamilton principle?
We have some Hamiltonian and Lagrangian mechanics videos, but plan to add more when we get a chance.
Michel van Biezen,that would be great-thank you very much
Loved it but it was. HANDFUL!. Appreciate your efforts very much both of you.
Our pleasure!
Glad you enjoyed it!
it is also possible to make a similar video to get the Snell law,I've seen a review of it on maa
We are putting it on the list of videos to make. (good suggestion).
that is legendary @Michel van Biezen, and i dont mean Fermats Theorem, i mean your working through the proof in a clear and concise way, thank you so much, beauty in maths!
Glad you liked it!
Thank you so much! Your videos are so helpful!
Only problem is that it’s not true. Read Feynman’s book QED page 43.
Thanks, but one suggestion. Employing the quadradic equation unduly complicates things. Instead, just move the terms with a b^2 to one side, factor out the b^2, divide both sides by the remainder, take the square root of both sides, cross-multiple, divide both sides by b, multiple both sides by 1/a, and viola. Also, please accept my PayPal contribution toward the purchase of a vertical sliding whiteboard. Thanks again.
nice
beautiful
What if you take the other answer given by the quadratic? Then theta 1 is not equal to theta 2!
Sir does the ray only take a path with least time or can it correspond with path with max time