FUN FACT: There's a wayyy easier way to solve final velocity of ball just before it hits the ground! If we consider the position of the object on top of the cliff and on the bottom (just before it hits the ground), both the positions will have the SAME total energy! (potential + kinetic energy will be same for both points). Thus, PE(initial) + KE (initial) = PE(final) + KE (final)... also dont worry about the m (mass) as it cancels out later on. this also works if an object is projected UPWARDS at a certain angle theta from the horizontal. HOPE THIS HELPS!!!!
i just learned more in 20 mins than in a month because of a godawful shitty professor who refuses to lecture and literally only has us attempt problems with no context in groups, with the only knowledge being studying a horrible confusing textbook
I'm sorry to hear that! Unfortunately, many universities put their professors in the very difficult position of having to teach classes with no training in education. Many of these folks view research as their real work, and would rather not be teaching at all. I'm glad the video helped, and hope you have better experiences with your professors going forward.
![2-D Vector Position & Velocity in Physics (Projectile Motion) - [1-4-1]](http://i.ytimg.com/vi/sJFwuFj8WUg/mqdefault.jpg)
Great tutorial, been having trouble understanding and this video definitely helped me a lot. Thank you !
FUN FACT: There's a wayyy easier way to solve final velocity of ball just before it hits the ground! If we consider the position of the object on top of the cliff and on the bottom (just before it hits the ground), both the positions will have the SAME total energy! (potential + kinetic energy will be same for both points). Thus, PE(initial) + KE (initial) = PE(final) + KE (final)... also dont worry about the m (mass) as it cancels out later on. this also works if an object is projected UPWARDS at a certain angle theta from the horizontal. HOPE THIS HELPS!!!!
it's like LasVegas lmaoo
square root of 0.306 is .55 not .53 ??
Thanks Daddy Newton🙏🙏
how are you getting -5.42m/s from (g x .53)???
In this case acceleration in the y-direction is equal to gravity so g would be -9.81m/s^2. After that you just multiply. Hope this helped!
Nathan Cheng -9.81 x .53 = -5.199m/s. Am I right or am I missing something
Nathan Cheng yes there is a miscalculation at 16:52
@@alexiskander7367 yep I was about to say that it should be 0.553 instead of 0.53 right?
Nathan Cheng no, he multiplied 9.81 x .53
And got the wrong answer at 16:52 that’s what I am saying
question 1 you have time is 0.55 seconds
i just learned more in 20 mins than in a month because of a godawful shitty professor who refuses to lecture and literally only has us attempt problems with no context in groups, with the only knowledge being studying a horrible confusing textbook
I'm sorry to hear that! Unfortunately, many universities put their professors in the very difficult position of having to teach classes with no training in education. Many of these folks view research as their real work, and would rather not be teaching at all. I'm glad the video helped, and hope you have better experiences with your professors going forward.