Two Dimensional Motion (4 of 4) Horizontal Projection, Worked Example
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- Опубликовано: 26 авг 2024
- For two dimensional projectile motion shows how to determine the time in the air and the distance traveled for an object that is projected from a known height with a known initial velocity in the horizontal direction (x-direction).
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Not sure if you still read comments but these videos are very well done and extremely helpful. I hope you will continue to make them in the future and thank you.
More videos to come and yes I still read and try to respond to all of my comments. I appreciated yours very much.
I don't know if you still are around, but man, these four videos have been so helpful. Thanks for the great work and the simple explanations.
Glad I could help and thanks for the positive feedback!
Thank you sir so much for all your videos and different ways of questions to help us understand more.
Sir, I have one question about “time taken” . In this video you used the “time of y axis and considered it as the time taken for the whole projectile motion” .
But in your projectile motion (2 of 4 ) . You doubled the time of y-axis .
Is it because the question was find “total time” ?
When do we double the time of y-axis and when we don’t ? (in this vid you didn’t double the value of time in y axis$
I doubled the time in the video because we were calculating the time it takes for the object to reach its maximum height. But it also takes the same amount of time to come back down again. We know this is the case because we used 0 m/s as the final velocity.
@@stepbystepscience thank you so much Sir for replying to me and helping me in Physics. You are the best 🌹
The information in this video is presented in a very clear and concise manner making it easy to understand and fun to learn. Great job!
Glad it was helpful! Thanks for your positive comment.
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Thank you very much for the supportive comment.
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Glad to be helping out!
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I hope that you make it through physics, thanks for letting me know that my videos have been helpful. I means a lot to me when I get extended comments like yours. You can a listing of all my videos from my website, www.stepbystepscience.com
Good Afternoon Sir. and thank you very much for this.
First let me say this, i am new in the world of Physics and never thought i would understand it, up until today i got to understand 2D Kinematics in just 2 hours.
From chapter 1 - 5 in just 2 hours,
Thank you very much
You're very welcome, and best wishes to you.
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That's great, glad you found me!
My goal was to fully understand the lesson before going to bed and in less than 20 mins Alhamdulilah I fully understood thank you to the moon and back
Good night Moon, Thanks for the comment.
I'd been watching your videos for the past few hours and wow. Really, tysm. No words can express how thankful I am. I'd been struggling with kinematics for one month and a half now and your videos really help me. No one explain em better than you, at least imo. You're so cool! Again, tysm!
You are so welcome. And thank you for the very positive feedback. Much appreciated.
love your videos and am using all of them to study for entrance exam! great explanations in mapping out the variables!
+Giana Eileen Thanks for the comment. Sometimes it is hard to get though the whole thing in a organized manner in 10 minutes or less. Good luck withthe exams.
You can see a listing of all my videos form my website at www.stepbystepscience.com
this video is world class. Physics teachers, take note
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You're very welcome and greetings from Germany.
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RUclips can be very helpful, thanks for the comments.
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You're very welcome! Yes, I plan to keep making videos.
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Happy to help and thanks for commenting.
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Literally the best in the world
Very very nice of you to say so, thanks.
thank youfor taking the time to create this. you have helped many people!
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so you solve it with 2 dimension, Now i understand why acceleration in x direction is zero, You're really good at teaching! :)
+Exogen Design Again thanks for the very nice comments. I always try to think of what points are important to the understanding of the concepts and problems.
Brian Swarthout You don't know how much you've helped me, I'm an electrical engineering student, and physics is where I am weak at, basically this motion and forces thing, but after I've watched your video I started dealing with more complex problem in an Dynamics book by ferdinand singer and I've answered almost all the problem, I understand how velocity works and how to use formula with supporting theory of why i should use it, Thank you very much sir.
everything you explain is always well thought out and easy to explain I appreciate your vids
Glad you think so! Thanks very much.
Doc Brian,
Thanks for being so thorough Sir.
Cheers,
Bobby :)
Thank you for noticing and commenting.
You can see a listing of all my videos form my website at www.stepbystepscience.com
when this man helps me to understand the lessons quickly in just a few minutes vs when I listened to my 2 hours class and still don't understand hahaha. this really helped me
Thanks for the great comment.
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thank you for your video. It was extremely helpful for me.
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Thanks for the very nice comment.
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Thank you very much for all of your positive comments. You can see a listing of al my videos at www.stepbystepscience.com
I love the way you organize your presentation/explanation, it's simple, direct and understandable!
Ps. I think you used powerpoint presentation and that was a lot of animations, so much effort!
Thank you, thank you!
Thank you for the great comment. All of the presentations are done in Apple‘s Keynote.
You got a thumb up from me and I've been subscribed for a while now.
Thanks for letting me know.
You are perfect teacher You got a thumb up please solve more example about anything
Thanks for the great comment, right now I am working on a series of videos about momentum and collisions. Next up....capacitors and capacitance
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Thank you very much for saying so. You can see a complete listing of my videos at www.stepbystepscience.com
Good Explaination. @
Thanks
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Very well explained Sir
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thank u soooo much ,soooo so much
You are very welcome
Thank you so so so so so so so so so so much!!! It really helps!!!!!!!!!!!
You are very welcome, I am glad that you found the video to be helpful.
Thank you for explaining it real good im almost there but is the formula at 6:38 the second of Change in position Given the t=√2△Y÷a
Very nice video and very beautifully explained, but I have a question how to find initial velocity in x direction only if distance and height is given.
If you have the height then you can get the time to fall in the y-direction. The time in x-direction is the same as the time in the y-direction. Then just divide distance in the x-direction by the time. Doe that help?
Yes, thank you for explaining
Sir I have a request can you also teach foundation for 9th and 10th class as the questions are typical there.
Hearing form you soon on this request.
Not sure I understand your request... foundation for 9th and 10th class in what subject?
thank you for this!! :) it really helps me because we'll be competing after some days
You are very welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you so much
You're most welcome
@@stepbystepscience I do have 1 question id like to confirm though, my exam question was to find the angle of departure of the object at release from the top, once we know the distance travelled "x" and we already have the height, do we just use tan -1 opp/adj to get that angle ?
Thank youu !!!! 😄
You're welcome 😊
what if it asks to solve for velocity and angle?
Thank you so much!
Thanks a lot!
How i fond the angle
You're honestly fucking great. Thank you for the easy explanations.
Thanks for the watching and commenting...You can see a listing of all my videos at my website.....www.stepbystepscience.com
Thank you so so so much!!!
very helpful
Thanks!
I dont know if you will be able to read this comment. But I just want to ask, what if the given is in feet? Like 45 feet and 37 feet per second. How will it be solved? Thank you
It is done the same way. You just have to be consistent with your units. Use either metric units or English units. You can not combine them in the same problem.
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I wish you were our teacher haha
Lukas hallo Where do you go to school, I am in Berlin Germany. Thanks for commenting.
Brian Swarthout It's gymnasium in Lithuania, and these things are hard to learn.
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bruv ur mah niggah for helping me understand this.
why did he multiply velcity and time .and is there a formula for that.
At the end??? that comes from the basic equation that v = d / t. This is the equation you learn in 8th or 9th grade and is used when there is no acceleration.
why is gravity -9.81 and not just 9.81?
someone help me
people often just say that the acceleration due to gravity is 9.81 and that is not really wrong, but when you use it in calculations you have to include the negative sign. acceleration is a vector, the negative sign just means that it point down (in the negative direction). you have to include the negative signs in your calculations
@@stepbystepscience but if my distance is positive and so is my acceleration, i'm good, right?
My god hope i'll get a passing grade..... Thank you
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