Physics Ninja looks at an Honors Physics problem of launching a projectile horizontally. The total flight time, distance traveled, and final velocity are calculated.
Finally! Now I understand why the acceleration is zero in the x direction! And even, I should have put it together on my own, now I understand why that means the x direction velocity stays the same too!
I handed my physics notes from last year to a friend that's a year younger, forgetting that I'm probably going to need it lol. At least I know that I have some of the best resources (aka this youtube channel)
how would I find the angle at which the projectile (in the question I'm stuck with its a cannon ball hitting a ship) collides with the ground/object and the resultant velocity of the cannon ball hitting the ship?
You need to find vx and vy just when the projectile will hit the ground. vx=vox and vy=voy-gt. use the time when it hits the ground. Once you know both components of velocity you can use trigonometry to find the angle. tan(theta)=vy/vx and solve for the angle theta=atan(vy/vx). Hope this helps!
1. A ball is projected horizontally from the edge of the table that is 1.00 m high, and it strikes the floor at point 1.20 m from the base of the table. a. What is the initial speed of the ball? b. How high is the ball above the floor when its velocity vector makes a 45.0˚angle with the horizontal? please help in b
When the velocity vector makes a 45 degree with the horizontal, it means that the horizontal component and the vertical component of the velocity at that point is equal (tangent of 45 degrees is 1/1 =1). The velocity from part a is 2.67 m/s. This is always the horizontal component. At 45 degrees, this is also the vertical component. Use the kinematic equation using this value of the y-velocity, you get a height of 0.3637 meters from the top of the table. Since the table is 1 meter high, 1 minus 0.3637 equals 0.636 meters above the floor.
Real ones know how it feels when you solve the question first and then watch the video and get the correct answers. Little motivation boosts fr fr
whoever unliked this video has 24 chromosomes cus this was the most clear and simple explanation of a horizontal projectile throw
I am a student in KFUPM and really your videos are very helpful in our physics courses>> thank you
Best explanation!
This helped me a lot! Thank you so much sir🙏🏻❤️
You are really amazing.
The way how you explain it and how clearly you did it 🙏. Thank you and keep up the good works 👍
So nice of you
thank you for saving my life i really needed this.. TYSM I CANT THANK YOU ENOUGH
I was following along fine until you got to trigonemtery. I understand that too, but why isnt the equation done with the hypotenuse?
This tutorial is so simple and clear🤩 Thank you sir💖
Finally! Now I understand why the acceleration is zero in the x direction! And even, I should have put it together on my own, now I understand why that means the x direction velocity stays the same too!
You may also watch my video
How to find the height?
How did he get the 2 in the bottom
why was time not doubled? thanks
what about a single stage rocket?
Perfect explanation 😍 thank you
very easy to follow and understand thank you
Thank you sir this was really helpful
why does vy turn positive?? wouldnt -9.8(1.75) be negative? a bit confusing
ooops, i forgot the -ve sign... sorry about that. Velocity is down, which i defined as the negative direction.
Thanks 👍. I understood it because u took your time
I handed my physics notes from last year to a friend that's a year younger, forgetting that I'm probably going to need it lol. At least I know that I have some of the best resources (aka this youtube channel)
damn i need to find the initial velocity :(
Great video
I dont get why g=-9.81 ? if its moving downwards cuz of gravitational acceleration , shouldnt it be +9.81 ?
shouldnt the g be negetive?
thank u sir
When finding time the ball remains in the air the formula should be y=ut-1/2g(t*t).... therefore the answer will be 3.09s
Bruh you made it a lot harder than I had to be
Good explanation
Useful video
Do more on projectile
Thanks! Check out my other videos on projectile motion.
Physics Ninja can u show how to simplify quadratic equation and get time t values?
how would I find the angle at which the projectile (in the question I'm stuck with its a cannon ball hitting a ship) collides with the ground/object and the resultant velocity of the cannon ball hitting the ship?
You need to find vx and vy just when the projectile will hit the ground. vx=vox and vy=voy-gt. use the time when it hits the ground. Once you know both components of velocity you can use trigonometry to find the angle. tan(theta)=vy/vx and solve for the angle theta=atan(vy/vx). Hope this helps!
For the Vy you multiplied negative times positive. Is Vy not negative?
yea i was also just super confused about that... his mistake.
1. A ball is projected horizontally from the edge of the table that is 1.00 m high, and it strikes the floor at point 1.20 m from the base of the table.
a. What is the initial speed of the ball?
b. How high is the ball above the floor when its velocity vector makes a 45.0˚angle with the horizontal? please help in b
When the velocity vector makes a 45 degree with the horizontal, it means that the horizontal component and the vertical component of the velocity at that point is equal (tangent of 45 degrees is 1/1 =1). The velocity from part a is 2.67 m/s. This is always the horizontal component. At 45 degrees, this is also the vertical component. Use the kinematic equation using this value of the y-velocity, you get a height of 0.3637 meters from the top of the table. Since the table is 1 meter high, 1 minus 0.3637 equals 0.636 meters above the floor.
Is this the answer you got?
oh my gosh thank you so much u saved me
is it possible to use work-energy therem here to find v?
Yes of course
@@PhysicsNinja thank you !!!!
Ur a lifesaver
Thank youuuuuu
you make a mistake because the question has a velocity of 20m/s and the law t equal to root 2H/g work with no initial velocity
Tqvm u save my brain today
Thanks a lot sir
You got this!
Ok well ik what grade I’m getting tmr 😂😅
GOOD PHYSICS NINJA EXAMPLE==ZERO BABBLING INSTRUCTOR VIDEO++INSTEAD EASY 2 VIEW GEOMETRY 2 HELP SOLVE PUZZLES.
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