2D Kinematics Problem Solving Examples

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  • Опубликовано: 14 авг 2019

Комментарии • 17

  • @warwick802
    @warwick802 Год назад +20

    This is for grade 11 and I'm in college studying this before a big test. Your Newton's Laws and Kinematics videos helped me more than my professors mickey mouse powerpoints. Blessings!

  • @brickman7814
    @brickman7814 Год назад +6

    You really have the courage to use sharpie on this

  • @saraahmed632
    @saraahmed632 3 года назад +8

    Thank you so much for this video! I'm in my first year at university studying physics and you have helped me so much.

  • @tobethehead
    @tobethehead Год назад +11

    Last answer isn't it meant to be the y component divided by the x?

  • @lalalana6939
    @lalalana6939 Год назад +3

    Thank youuu so much for this, it has helped me so much

  • @missn.a.ndlovu3322
    @missn.a.ndlovu3322 2 года назад +3

    Thank you I understand everything from the video.

  • @xbz24
    @xbz24 Месяц назад

    what is the frame of reference you are using for the first example

  • @rixxir7768
    @rixxir7768 Месяц назад

    Could you use the X direction to find time?

  • @__Joki__
    @__Joki__ 3 года назад +3

    I’m a bit confused on why we don’t do anything about the Time component for the first question? The only known variables were the acceleration and V1X, does T not matter because the acceleration was zero and multiplying the two would be zero regardless?

    • @annekegretton5453
      @annekegretton5453  3 года назад +2

      Great question Julius! It is totally possible calculate Δt from the information given in that first problem. You can use the equation y_2 = y_1 + v_{1y}Δt + 0.5aΔt^2 to solve for time (don't forget you'll need the quadratic formula to solve it!). However, since the question doesn't ask us to calculate time, there's really no need to waste your time (pun intended) solving for it.
      The awesome thing about the kinematics equation we used here, (v_2)^2 = (v_1)^2 + 2a(y_2 - y_1), is that it actually _comes from_ that quadratic-looking kinematics equation with time in it, but it allows you to jump straight to calculating final velocities without having to first solve for time.
      I hope that helps!

    • @__Joki__
      @__Joki__ 3 года назад +1

      @@annekegretton5453 Thank you for your response, it helped a ton!!

  • @wildwonders-uo9ey
    @wildwonders-uo9ey 8 месяцев назад

    Thank you