Physics 9.6 Coefficient of Restitution (1 of 9) What is Coefficient of Restitution? 1

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  • Опубликовано: 28 ноя 2024

Комментарии • 42

  • @oneinabillion654
    @oneinabillion654 Год назад +1

    You can relate this to the derivation of "Relative speed of approach = Relative speed of separation" for elastic collision using conservation of momentum and energy to make the coefficient more understandable.

  • @kalibos
    @kalibos 8 лет назад +9

    Awesome, thanks Michael, I was just about to see if you had any videos on this.
    And a more general thank you for having such a comprehensive syllabus available to us.

  • @channelutility3002
    @channelutility3002 2 года назад +2

    Thank God this is concise

    • @MichelvanBiezen
      @MichelvanBiezen  2 года назад +2

      Glad you found our videos and you find them useful. 🙂

    • @channelutility3002
      @channelutility3002 2 года назад +2

      @@MichelvanBiezen Are you German

    • @MichelvanBiezen
      @MichelvanBiezen  2 года назад +3

      Originally I am from Belgium. I immigrated to the United States and now live near Los Angeles.

    • @dansman1729
      @dansman1729 Месяц назад +1

      ​@@MichelvanBiezenThank God for Immigration! I still can't believe some people are trying to stop it...

  • @physics20246
    @physics20246 3 месяца назад

    Excellent Sir

  • @emcc5444
    @emcc5444 Год назад +1

    Where does all the momentum from the ball go if the ball doesn't bounce up with the same velocity, and momentum should be conserved?

    • @MichelvanBiezen
      @MichelvanBiezen  Год назад +1

      It is the same principle as when you throw a snowball against a wall and it sticks (doesn't bounce back). Is the momentum conserved? The answer MUST be YES. So where did that momentum go? It went to the Earth. (Since the Earth is so big, you can't measure it, but that is where it went).

    • @emcc5444
      @emcc5444 Год назад +1

      @@MichelvanBiezen man, thanks a lot sir, you're a life saver

  • @faizasikandar6050
    @faizasikandar6050 5 лет назад

    Hero of physics

  • @ohvjayaweera3253
    @ohvjayaweera3253 3 года назад +2

    Wonderful teaching Sir thank you

  • @bakchodi-v2b
    @bakchodi-v2b 6 лет назад +1

    What is COR value for collision between steel and steel?

  • @generalrocksteady9948
    @generalrocksteady9948 3 года назад +1

    Why is the initial vel. Before collision 0. Shouldnt it be _/(-2gh) ??

    • @MichelvanBiezen
      @MichelvanBiezen  3 года назад +2

      The "0" is for the other surface the ball collides with (the surface of the floor) for which the velocity is zero. (as explained in the video)

  • @shwetatiwari6480
    @shwetatiwari6480 5 лет назад +1

    Great English teacher.

  • @mohammadtalib3510
    @mohammadtalib3510 7 лет назад +2

    Amazing sir ..!!?
    You described in verry simple manner !!!
    Thank you sir!!

  • @rt6701
    @rt6701 7 лет назад +3

    Sir, this playlist is awesome...but could you do collisions in a more detailed way?

    • @MichelvanBiezen
      @MichelvanBiezen  7 лет назад +3

      Look at the following playlists for more videos on momentum: PHYSICS 9.5 INTRODUCTION TO MOMENTUM PHYSICS 10 IMPULSE AND MOMENTUM

    • @rt6701
      @rt6701 7 лет назад +1

      Okay sir!!!Thanks!!!

  • @purushothamreddy2392
    @purushothamreddy2392 5 лет назад +1

    Thanks! Professor .....

  • @kisakyetitus3006
    @kisakyetitus3006 3 года назад +1

    Thank you, I loved the video.

  • @PrakashPandey-xj8co
    @PrakashPandey-xj8co 7 лет назад +1

    Sir, it would be helpful if you upload a video of bullet fired from gun of certain velocity and then passed through block due to which the block moved a certain amount of distance 'x'. we have to find the coefficient of kinetic friction between the block and surface.

    • @MichelvanBiezen
      @MichelvanBiezen  7 лет назад +1

      You can find those videos in this playlist: PHYSICS 10 IMPULSE AND MOMENTUM

    • @PrakashPandey-xj8co
      @PrakashPandey-xj8co 7 лет назад +1

      Michel van Biezen sir the video you suggested helped me, but my doubt is that bullet doesn't remains inside the block, it passes out with some velocity and the block moves. We have to find the coefficient of kinetic friction between the block and surface.

    • @MichelvanBiezen
      @MichelvanBiezen  7 лет назад +1

      That problem is solved in the exact same way. You use conservation of momentum for the collision portion and then you use the conservation of energy for the second portion when the block slides over the surface.

    • @PrakashPandey-xj8co
      @PrakashPandey-xj8co 7 лет назад +1

      Michel van Biezen got it. Thanks sir...... You are best. Your video helps a lot....!!

  • @jmkew9498
    @jmkew9498 4 года назад

    Thanks sir. Clear explanation

  • @anupamojha9343
    @anupamojha9343 3 года назад

    I m from India and there are many books who does not cares about magnitude of rel velocity . So I was confused from two months . I thought e can have + /- sign

  • @joanpareja3313
    @joanpareja3313 6 лет назад +1

    This is awesome! Thank you so much!

  • @ceit.estella
    @ceit.estella 3 года назад

    Sir, please upload lecture videos about coefficient of restitution for oblique impacts. Thank you, sir. 😊

  • @Lakitu1446
    @Lakitu1446 7 лет назад +2

    Omg thank you very much ;-)

  • @ye8075
    @ye8075 6 лет назад +4

    Great bow-tie

  • @faizasikandar6050
    @faizasikandar6050 5 лет назад

    Salute

  • @yuen818
    @yuen818 6 лет назад +1

    Wait. Isnt 1/2 supposed to be negative?

    • @MichelvanBiezen
      @MichelvanBiezen  6 лет назад +1

      Note that we used absolute value signs. (that is why the negative sign is not there)

    • @confused_one_
      @confused_one_ 4 года назад

      No they have put modulus, means only positive values could be taken

  • @RajkumarGupta-oi6es
    @RajkumarGupta-oi6es 3 года назад +1

    I can't understand your language