Can we apply this to find the loss in kinetic energy when a ball renounce on surface of earth, since you are saying this case is not C.O.M frame collusion case?
In a sense it is still a C.O.M case, but one of the masses is Earth, and therefore it would be very difficult to measure the change in momemtum of the Earth.
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great video mate u helped me get a degree in oxford. thank u over the years
Congratulations!
thank you
Can we apply this to find the loss in kinetic energy when a ball renounce on surface of earth, since you are saying this case is not C.O.M frame collusion case?
In a sense it is still a C.O.M case, but one of the masses is Earth, and therefore it would be very difficult to measure the change in momemtum of the Earth.
@@MichelvanBiezen ,nice , thanks for explaining Sir😊
Nice presentation
Sir, I have a stupid question. Can we say C is eqal to V final squared divided by V initial squared?
Wouldn't, (1-C^2 ) be equal to the ratio of energy lost (Eo-Ef) to the initial energy (Eo)
yes
I’m a little confused, if you take the square root of both sides wouldnt C be C^1/2 instead of C^2?
Are you referring to v = sqrt (2gh)? We substituted there, we did not take the square root of both sides.
No at 4:26 when you stated we can sqrt both sides of the equation and we end up with C^2 = H(f)/H(i)
If I said "square root" I meant to say "square" since that is what I did.