Physics: Viewer's Request: Mechanics #32: Coefficient of Restitution
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- Опубликовано: 6 окт 2024
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Given: the coefficient of restitution of a ball=0.7.
Find: what height=? will the ball bounce if it is dropped from a height=10m.
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• Physics: Viewer's Requ...
"And that is how its done" was defiantly a mic drop moment thank you this summed up what i needed to know perfectly
the coefficient of restitution is more like the degree of elasticity of an object. e=1 means therefore that your object is 100% elastic and will eventually have the same amount of kinetic energy as outcome as you've put in to
That is a good way to look at it.
Thanks very much watching this at 6am (did not sleep yet) but still understood everything
Time to get some sleep!
Been here when I was in my second year of college, and I'm back again while reviewing for my mechanical engineering board exams, you've helped me so much, thank you! ❤
All the best on your board exams. 🙂
The way it simplifies to such a short equation is beautiful
Glad you liked it. 🙂
Car frames are crooked so that head-on collisions are absorbed by the car. Not the passengers using their heads to fly through the windshields. Just the seat belts are not enough and the airbags, when they work, have issues But the material itself helps determine "e". i.e. A rubber ball vs a clay ball, Where is that factor?
Wow, you are wonderful.
One question from myside plz.
One person forgot his 4 Digit ATM pin but he remembers 4 things about his ATM pin...
1) First Digit is half of Third digit
2) sum of second and third digit is 8
3) Fourth digit is multiple of first & second digit
4) All four digits sum is 12.
So,
Generate the formula to build the ATM PIN.
He remembers 4 odd facts but doesn't remember the 4 digits...
Tell him to focus on the more important details next time!
@@blankblank103 This is world of Mathematics,
Anything could happen here 🤣🤣🤣🤔🤔🤔
4080, or what is the question ?
@@kingplunger6033 I asked the generator to generate this answer...
Thanks for this simple yet excellent explanations!
You're very welcome! 🙂
Sir hat-off never seen a famous 1 year old video on internet with 0 dislikes.
Thank you
They split the atom and sped the plane; conditioned air and deaden pain but to this day they must announce they're not sure what makes rubber bounce
Sir. I like your videos very much. You explain concepts in a much easier way to understand. Can I ask you a few questions about least action principal. We try to minimise the time for an action. For example light will choose the shortest time path from one medium to another medium. But why we choose time not other quantity. Can how can an object know which path is the shortest automatically. For example if we are on land and want to go to a point in the sea. We swim and run. But without trying out all different path,s, one can automatically know I have to follow sneil’s law. This puzzles me for years and would love to know why and how.
We have a whole playlist on the principle of least action: PHYSICS 70 PRINCIPLE OF LEAST ACTION: ADVANCED
Mmmmmhhh!
😂😂😂☝easy to understand and mug up in my memory bank😂😂😂😎🔥
Can you explain please nuclear physics
We have videos on nuclear physics in this playlist: PHYSICS 64 NUCLEAR PHYSICS
keep up the good work. love u from Zimbabwe
Thank you. Welcome to the channel!
Hi sir, Omar present..........................
Hello Sir, Great Lecture and great content as always. I was wondering if you do tutoring for business math?
Yes we do: Here are the playlists: BUSINESS MATH 1 - INTRODUCTION BUSINESS MATH 2 FINANCE MATH BUSINESS MATH 3 - LINEAR PROGRAMMING GENERAL BUSINESS MATH - THE SIMPLEX METHOD PROBABILITY & STATISTICS 3 - MARKOV CHAINS
@@MichelvanBiezen I'm taking Finance Math and would like to get tutoring. Could you please give me your email address because I couldn't find it on lectureonline.com, so we can talk about the details?
sir how to calculate force applied by ball on ground in this case?
We would need to know the duration of contact, which we don't in this problem.
Thank you so much 😊
You're welcome 😊
Thank you very much sir for your knowledge
It's my pleasure
Thank youuuuuuuuuu!
You are welcome.
Hello Sir, great lecturw as always. My question how did you know to square both sides?
Typically we square both sides to eliminate the radical sign.
Hi sir! do you have video regarding coefficients of restitution when both height are known but the coefficient and velocity after impact is unknown?
Not sure. We have a playlist on the coefficient of restitution PHYSICS 9.6 MOMENTUM AND COEFFICIENT OF RESTITUTION
@@MichelvanBiezen thank you sir for your videos! It helped me a lot. I already watched your videos sir. Thanks a lot :)
Sir can u do something for Olympiad physics, like for F=Ma contest ?
At this time we don't have the time. (We can only do so much every week). We hope to get to that eventually.
@@MichelvanBiezen OK thanks sir
Awesome 👏 content
Thank you 🙌
What can I see except thank you
Sir please help with spherical polar coordinates
Take a look at these playlists: PHYSICS 67 ADVANCED ELECTRICITY & MAGNETISM and PHYSICS 67.1 ADVANCED E&M VECTORS and also in the calculus 3 videos on this channel
@@MichelvanBiezen thank you sir
@@MichelvanBiezen sir can you tell us something about Dirac delta function
g o o d
Hi Michel,
My name is Yuliya, I represent The URAIT Publishing House, one of the leading higher and secondary education publishers in Russia.
With your written consent we’ll be happy to include your RUclips channel videos in our targeted list of the best educational video content.
Your video links will be placed on the margins of the books on our educational platform www.urait.ru, www.biblio-online.ru, and our users will follow the links to your RUclips channel to watch videos on the specific subjects.
I'll be waiting for your response!
Looking forward to our cooperation.
Best regards,
Yuliya Samoylova
Publishing Expert
e-mail: expert@urait.ru
Hi Yuliya. As long as the videos are watched through RUclips, that is perfectly fine. All the best.
@@MichelvanBiezen Unfortunately, without the written permission of the channel owner, we are not entitled to post external links to your channel.
Where can I send more information?
@@MichelvanBiezen Hello Miсhel.
We will be glad to cooperate, tell me where to send the permit?
@@MichelvanBiezen Unfortunately, without the written permission of the channel owner, we are not entitled to post external links to your channel.
Where can I send more information?