Theoretically, the initial energy can equal the final kinetic energy if there is no change in potential energy and there is no energy lost due to friction
@MichelvanBiezen sir my main doubt is that if the object was in a uniform circular motion then its kinectic energy is fixed.....but potential energy is not fixed as it changes height....so how total energy will be conserved then....and sir you said in your 1st reply that theoritically its possible that total eney is fixed if there is no change in potential enegy....but my question is practically potential energy must be changed as height changes.......so how total in every point will be conserved then???
@@MichelvanBiezen Hi sir, I have three doubts 1. The initial velocity is 22.14 m/s, is this initial velocity is required for all type of masses ? (for eg: 1kg, 2kg, etc.) 2. Why work done on the system is 0 ? 3. The final energy equation should be calculated at the same point where it started right ? Why it is calculated when it reaches top ? Thanks, Suhabavan.
1) Yes the velocity is mass independent (mass does not appear in the equation) 2) There is only a change in the KE and PE which is already accounted for. No force is acting on the system during the motion. 3) No, the energy equation can be used from any starting point to any stopping point.
Hello Michael sir it's my request to you that please explain this question 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏 [A disc of radius 0.2 meters is rolling with slipping on a flat horizontal surface. It's angular velocity ω=10rad/sec and velocity of its centre of mass=4m/s and it's centre is 'C' and its lowest contact point is'O'. Where does the instantaneous centre of rotation is located??]
Thanks Professor. I always look forward to your videos. Keep up the good work. How about calculating the required energy of a roller coaster cart with 6 people (estimate mass)....
Hi sir, I have three doubts 1. The initial velocity is 22.14 m/s, is this initial velocity is required for all type of masses ? (for eg: 1kg, 2kg, etc.) 2. Why work done on the system is 0 ? 3. The final energy equation should be calculated at the same point where it started right ? Why it is calculated when it reaches top ? Thanks, Suhabavan.
1) Yes the velocity is mass independent (mass does not appear in the equation) 2) There is only a change in the KE and PE which is already accounted for. No force is acting on the system during the motion. 3) No, the energy equation can be used from any starting point to any stopping point.
1) velocity is independent of mass here as you can see at any point velocity only depends on g and R 2) work done is zero as no external work is done ....as we are considering an ideal system where there is no air resistance etc ...so no external work is required to keep it moving 3) since energy is conserved we can consider any two and label them initial or final ...but since we are interested in the velocity at the top most point so that’s why it is that way ... Hope it helps👍🏻
@@MichelvanBiezen Thank you so much sir for your reply☺. I understood 2nd and 3rd points clearly. But still I'm not getting 1st point, suppose 500kg of mass is tied with the rope, then how come the initial velocity 22.14 m/s is enough to push the 500kg of mass upward. Sir my kind request, can you explain 1st point again with the diagram in your next viewer's request class?
You will need more force to move the more massive object, but the initial velocity is the same for any mass KEo = PE f (1/2)mv^2 = mgh and therefore the mass cancels
Can you please tell me why moving force of object is not in the circul touching direction. Because i think if a-acceleration is in this direction F should also be.
The object is just given an initial velocity when it is in the lowest position. After that, it is allowed to move without any interaction with an outside force.
nice problem and solution.... I enjoy the dialogue afterward when you and "The Wife" talk about the video.. She makes an interesting point, that is, WHAT should Vo be if you want to stop the ball at the TOP ???.. There must be a velocity that keeps the string Taut and yet arrives at the top with Zero Horizontal Velocity.... interesting.. :) (Okay, I checked it out and the limiting factor IS Rg .. and since those are constants they can't be varied. So, it looks like you could never get Vf = to zero at the top and still have the String Taut.. ) :)
@@MichelvanBiezen by the way Michel, how's this video for determining Conservation of Momentum? :D You'd think these Ship Pilots would have known better? Check it out.. facebook.com/alex.stewart.9421/videos/2725755084193201/
@@MichelvanBiezen Yes I've read the chapter about Power, Work, and Energy in my textbook and it talks about Conservative and Non-conservative Forces but I couldn't say that I understand the concepts perfectly.
Sir if initial velocity is equal to final velocity...then will energy conservation law work????...please tell🙏
Theoretically, the initial energy can equal the final kinetic energy if there is no change in potential energy and there is no energy lost due to friction
@MichelvanBiezen but sir why potential energy will not change...explain please
I don't understand your question since the potential energy changes (the object changes height)
@MichelvanBiezen sir my main doubt is that if the object was in a uniform circular motion then its kinectic energy is fixed.....but potential energy is not fixed as it changes height....so how total energy will be conserved then....and sir you said in your 1st reply that theoritically its possible that total eney is fixed if there is no change in potential enegy....but my question is practically potential energy must be changed as height changes.......so how total in every point will be conserved then???
That girl asked the exact question I was thinking. Super great response!
Why did we not account for the tention force in the rope? or is there no rope?
The tension in the rope does not do any work, since the motion of the object is perpendicular to the direction of the tension.
I see the mass cancels out, but does it matter if the mass is 1 pound or mass is 1 billion pounds?
Very nice video, I'm just wondering how you can count with a force that doesn't exist (the centrifugal force). How does that work?
At 5:20 shouldn't R = 2L not L,I thought R was the diameter not the radius?
The centripetal force and associated velocity uses the radius in the equations
@@MichelvanBiezen Hi sir, I have three doubts
1. The initial velocity is 22.14 m/s, is this initial velocity is required for all type of masses ? (for eg: 1kg, 2kg, etc.)
2. Why work done on the system is 0 ?
3. The final energy equation should be calculated at the same point where it started right ? Why it is calculated when it reaches top ?
Thanks,
Suhabavan.
1) Yes the velocity is mass independent (mass does not appear in the equation)
2) There is only a change in the KE and PE which is already accounted for. No force is acting on the system during the motion.
3) No, the energy equation can be used from any starting point to any stopping point.
Hello Michael sir it's my request to you that please explain this question 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
[A disc of radius 0.2 meters is rolling with slipping on a flat horizontal surface. It's angular velocity ω=10rad/sec and velocity of its centre of mass=4m/s and it's centre is 'C' and its lowest contact point is'O'. Where does the instantaneous centre of rotation is located??]
Thanks Professor. I always look forward to your videos. Keep up the good work. How about calculating the required energy of a roller coaster cart with 6 people (estimate mass)....
beautiful classic problem
Indeed!
Hi sir, I have three doubts
1. The initial velocity is 22.14 m/s, is this initial velocity is required for all type of masses ? (for eg: 1kg, 2kg, etc.)
2. Why work done on the system is 0 ?
3. The final energy equation should be calculated at the same point where it started right ? Why it is calculated when it reaches top ?
Thanks,
Suhabavan.
1) Yes the velocity is mass independent (mass does not appear in the equation)
2) There is only a change in the KE and PE which is already accounted for. No force is acting on the system during the motion.
3) No, the energy equation can be used from any starting point to any stopping point.
1) velocity is independent of mass here as you can see at any point velocity only depends on g and R
2) work done is zero as no external work is done ....as we are considering an ideal system where there is no air resistance etc ...so no external work is required to keep it moving
3) since energy is conserved we can consider any two and label them initial or final ...but since we are interested in the velocity at the top most point so that’s why it is that way ...
Hope it helps👍🏻
@@MichelvanBiezen Thank you so much sir for your reply☺. I understood 2nd and 3rd points clearly. But still I'm not getting 1st point, suppose 500kg of mass is tied with the rope, then how come the initial velocity 22.14 m/s is enough to push the 500kg of mass upward.
Sir my kind request, can you explain 1st point again with the diagram in your next viewer's request class?
@@nyasajain837 Thank you for the info☺👍
You will need more force to move the more massive object, but the initial velocity is the same for any mass KEo = PE f (1/2)mv^2 = mgh and therefore the mass cancels
Can you please tell me why moving force of object is not in the circul touching direction. Because i think if a-acceleration is in this direction F should also be.
The object is just given an initial velocity when it is in the lowest position. After that, it is allowed to move without any interaction with an outside force.
Iam a Fan of you , Michael
nice problem and solution.... I enjoy the dialogue afterward when you and "The Wife" talk about the video.. She makes an interesting point, that is, WHAT should Vo be if you want to stop the ball at the TOP ???.. There must be a velocity that keeps the string Taut and yet arrives at the top with Zero Horizontal Velocity.... interesting.. :) (Okay, I checked it out and the limiting factor IS Rg .. and since those are constants they can't be varied. So, it looks like you could never get Vf = to zero at the top and still have the String Taut.. ) :)
Yes sir.
@@MichelvanBiezen by the way Michel, how's this video for determining Conservation of Momentum? :D You'd think these Ship Pilots would have known better? Check it out.. facebook.com/alex.stewart.9421/videos/2725755084193201/
could you do some qn's based on this
We have many examples on the conservation of energy on this channel. Do you have a specific question in mind?
Sir please tell me how to ask my doubts as viewers request???🙏🙏
Right here in the comments section of the videos.
@@MichelvanBiezen thank you sir
Hello Michel! How about a video on Conservative Force and Non-conservative force which removes kinetic energy from the system? Thanks!
That is a good suggestion. That still causes a lot of confusion. I made a note of it, in order to make a video on the topic.
@@MichelvanBiezen Yes I've read the chapter about Power, Work, and Energy in my textbook and it talks about Conservative and Non-conservative Forces but I couldn't say that I understand the concepts perfectly.
shouldn't R = 2L not L,I thought R was the diameter not the radius?
The radius is the distance from the center of the circle to the edge of the circle. That is the same as the length of the rope in this example.
Hi sir, Omar present............
My physics teacher also used this one in the exam xD