Physics: Viewer's Request: Mechanics #15: Energy Conservation
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- Опубликовано: 24 июл 2024
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We will solve: A “skier” slides down a 30 degree slope. When the “skier” reaches the bottom, it takes the same distance for the skier to stop as the length of the slope the “skier” came down. What is the coefficient of friction?
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• Physics: Viewer's Requ...
LMAO at the Dog(s) barking and how WIFE put up a picture at that time!!! .... meanwhile.. I enjoyed this video... well done Michel.. there's a certain pleasure derived from seeing how a problem is solved... I'm always that much smarter after watching your videos.. THANK YOU!
Glad you enjoyed it - Wife
I love the viewer request playlist
Very good problem with nicely explained solution.
You make great videos keep It up
Great sir
TEACHER ,
VERY GOOD MOVIES
Nice !
Thanks!
Oh I loved this exercise, actually my physics teacher put this one my final exam
And did you figure it out?
@@MichelvanBiezen Yep and It was amazing
Nice going!
@@MichelvanBiezen I've already done the physics exam on the Ebau exam in Spain and It went so smooth. Thank you for your content it has helped me a lot🤗
aerodynamics might play a part as the center of gravity moves back to the center of mass.[vertical]. Air Forced downward would reduce the COEF to zero. Like a hovercraft..
Excuse me sir. I don’t quite understand why E(lost flat) is positive on the right side. If that’s the case, shouldn’t E(lost hill) also be negative?
If energy is lost, then the final energy will be less than the initial energy. In order to equate the 2 sides, you must either subtract the lost energy from the left side or add it to the right side.
@@MichelvanBiezen Thank you very much! I think I finally understood the energy difference.
skiing on SPACE ! YES
Sir can you make video on angular momentum please
We have a whole playlist on angular momentum: PHYSICS 13.5 ANGULAR MOMENTUM You can find these from the home page of the channel.
@@MichelvanBiezen thankyou sir
I have been following your videos for a while and they helped me a lot particularly in Mechanics. I have an Exercise request concerning the handwheel (torque , momentum...etc). Please let me know , how can i contact you , so i can send you a picture of the exercise.
You can send it here in the comment section.
@@MichelvanBiezen Thanks for your reply and her i´ve tried to translate the exercise from German to english. a lot of Terms are different but i think i did well describing the Problem.
a Bucket attached with rope to shaft in form of a Cylinder which is also attached to a Handwheel in the Middle.
The mass of the Bucket is : 5,2 kg
radius of the Shaft is : 11 cm
moment of Inertia I_total = 0,75 kg.m^2
radius of the Handwheel is : 35cm
a) what force should be exerted on the Handwheel so that the Bucket will not move?
b) The handwheel is now released and the bucket is moved 10 m down, what Velocity does the Bucket have ?
C)what is the kinetic Energy of the Bucket and of the Shaft?
C) Time in The air of the bucket in 10m ditance down?
D) what is the Total implus ?
This is an interesting problem indeed. We'll shoot a video on it today.
On part d, impulse is always calculated ocular object which was not specified in the question. Thus I will calculate it on the bucket and on the shaft separately.
@@MichelvanBiezen Can't wait to see. Could you please tell me when are you going to post it??
Hi sir, Omar present...........
Ignoring aerodynamic drag of course, i.e., the skier was in a vacuum.
(hopefully with an oxygen tank)
You ignored the air resistance. Thats why all the resistance was attributed to mue
That is correct.
@@MichelvanBiezen Good to know, keep up the good work, I learn so much from your lectures. TYSM