Work Energy Problem - Sliding Down a Ramp

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  • Опубликовано: 6 янв 2025

Комментарии • 18

  • @dawitdesalegn17
    @dawitdesalegn17 8 месяцев назад +8

    your teaching method is very good

  • @SILE75
    @SILE75 7 месяцев назад +2

    Thank you so much Physics ninja I have a similar 7 marks question,now I know how to do it.

  • @moon-ec4us
    @moon-ec4us 9 месяцев назад +4

    14:02 is it okay if i said
    fd=∆k
    Which means Mgd=1/2mv^2
    Which means
    gd =1/2v^2
    Then substitute with the values i know
    To get d

    • @tipi5953
      @tipi5953 7 дней назад

      isn't that basically the work energy theorem

  • @angeloorteza155
    @angeloorteza155 Год назад +2

    what if there is another ramp on the end

  • @sergeyborodin9211
    @sergeyborodin9211 Год назад +4

    Would that be easier for the ramp part to calculate the resulting/net force and then calculate work done on the ramp as a product of the net force over distance1 ?...thanks for ur videos!!

    • @PhysicsNinja
      @PhysicsNinja  Год назад +5

      There are many ways to solve this problem. You either find the work done by each force or you find the work done by the net force, they are the same.

    • @sergeyborodin9211
      @sergeyborodin9211 Год назад

      @@PhysicsNinja thanks again for ur videos! Some old farts like myself use them as part of recupiration)) cheers!

  • @klong1972
    @klong1972 Год назад +1

    How about repeating using conservation of mechanical energy?

  • @ytman-lq2mj
    @ytman-lq2mj 8 месяцев назад +4

    I’m getting 14.147 m by using a different method that’s worked in the past (energy transformations). Weird.

  • @Aizensosuke12345
    @Aizensosuke12345 24 дня назад

    Hey! Is it possible to solve this using a pure dynamics and kinematics approach? I tried it and got a similar answer.

    • @PhysicsNinja
      @PhysicsNinja  24 дня назад

      Yes, find accelation using newton’s 2nd law, then use kinematic equations

  • @fizixx
    @fizixx Год назад

    There's one I'd like to see.
    A block of mass of 4 kg being pulled up a frictionless ramp by a constant force of 6 N. The ramp is 5 m high and 75 m long. If the block has some initial velocity, let's just say 3 m/s, what is the speed at the top of the ramp? I've made-up all these numbers. This isn't a homework problem or anything.

  • @pleuvoirzz1546
    @pleuvoirzz1546 3 месяца назад

    When you substituted d1 for h/sintheta, you cancelled mgsintheta to mgh but I don't think that's correct because sin theta and h/ sin theta are not being multiplied. Sin is a ratio i.e, it's sin OF theta. Eng is not my first language but I hope you understood my doubt. Could you please answer if I'm missing something?

  • @NifteFilm-nn3nn
    @NifteFilm-nn3nn Месяц назад +1

    Hi professor how to get effective in physics

  • @mohamadfazli5575
    @mohamadfazli5575 5 месяцев назад +1

    Can't see your writing st all

    • @kessgoddey
      @kessgoddey 5 месяцев назад

      pls where do you get this questions from. I love them and I am studying for A level physics. pls recommend a good textbook with good questions like this