Incline Plane Problems with Friction

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  • Опубликовано: 7 янв 2025

Комментарии • 29

  • @juniorcyans2988
    @juniorcyans2988 2 года назад +14

    I like the problems you used every time. Please keep updating often. It's been my habit to watch them almost every morning. Thank you very much!

  • @CliffordBacsarza
    @CliffordBacsarza 9 месяцев назад +1

    I like how you explain each concept clearly! Keep updating!

  • @ashcash4977
    @ashcash4977 Год назад +8

    For problem A, is there a reason you didn’t solve for the component vectors in the Y-direction? It seems you only did the X-direction for M1

    • @nsuauab
      @nsuauab Год назад +2

      Direction in which acc is acting, is the direction where components r broken...maybe that's the reason...

    • @umbriel7051
      @umbriel7051 2 месяца назад

      Cause they're just there so they're not accelerating and therefore not relevant (the mass isn't going up into the sky or being crushed into the triangle)

  • @oscarww3
    @oscarww3 Год назад +3

    Very clear way of explaining, Thanks.

  • @JimmyTyson-fm5zg
    @JimmyTyson-fm5zg 10 месяцев назад +1

    Nice explanation I've been watching alot of tutorials but a lot they like simple question but sir u are the best

  • @olivierniyonzima4191
    @olivierniyonzima4191 Год назад +1

    Teacher of the warld I like that keep it up dear👍

  • @mahsadarvishi
    @mahsadarvishi Месяц назад

    In 17:05 you considered motion downward but you also considered friction downward. I'm now confused

  • @HashemAljifri515
    @HashemAljifri515 Год назад +1

    23:50 there is something wrong here, the acceleration is negative because block m2 has a greater mass than m1. So the acceleration of the system should act downward .consequently, it should be m2g - T = (-)m2a rather . Thanks for this amazing explanation!

    • @yerb.
      @yerb. Год назад

      no its correct, m2 is heavier than m1 so m2g-T=m2a

    • @HashemAljifri515
      @HashemAljifri515 Год назад

      @@yerb. Are you psycho?? M2 has a greater mass than m1!! The trick is that the sin component of the gravity for m2 is less than the gravity of m1 so that's why my expectation was wrong....learn physics rationally rather than sticking to a physician,,, you won't do good if you think like this...

    • @yerb.
      @yerb. Год назад +1

      @@HashemAljifri515 you literally just repeated what I said. Calm down buddy you are taking gen physics

    • @yerb.
      @yerb. Год назад

      @@HashemAljifri515 also m2 has no sin component, it only has downward gravity acting on it… you are hilarious

    • @yerb.
      @yerb. Год назад

      @@HashemAljifri515 I feel like you have a language barrier yes m1 has frictional force and gravity acting on it: T-ukm1gcos30-m1gsin30, we are talking m2. Which is just m2g-T in this instance.

  • @samarthkulkarni3828
    @samarthkulkarni3828 4 месяца назад

    Why do you add a small line to the acceleration vector? What does it signify?

  • @edificationevangelism1083
    @edificationevangelism1083 10 месяцев назад

    What if the system has nonconstant acceleration? How would I find the value for m2 then? Thanks!

    • @edificationevangelism1083
      @edificationevangelism1083 10 месяцев назад

      I was given m1, the coefficient of friction, and acceleration and was asked to find m2 by my teacher

  • @EangVichhay
    @EangVichhay 3 месяца назад +1

    Very good

  • @NathanRuben-we9ee
    @NathanRuben-we9ee 6 месяцев назад

    Thanks so much it really helps

  • @notreallydavid
    @notreallydavid 9 месяцев назад

    inclineD plane!