Harvard University Admission Question| Can You Solve For x? | Algeria

In this video, I'll be showing you step by step on how to solve this Harvard University Admission Problem using a simple trick.
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[@aryanuddin1903]

x=-6

[@mrinaldas9614]

At the the qusrtic stsge z&
Z^4 could have been replsced by k^2 (k =z^2).

[@SpencersAcademy]

Yeah. I had already made one substitution. I didn't want to introduce another substitution.

[@yurenchu]

(x+9)⁴ + (x+11)⁴ = 706
... let u = x+10 ...
(u-1)⁴ + (u+1)⁴ = 706
(u⁴ - 4u³ + 6u² - 4u + 1) + (u⁴ + 4u³ + 6u² + 4u + 1) = 706
2u⁴ + 12u² + 2 = 706
2u⁴ + 12u² = 704
u⁴ + 6u² = 352
u⁴ + 6u² + 9 = 361
(u² + 3)² = 19²
u² + 3 = ±19
u² = -3 + 19 OR u² = -3 - 19
u² = 16 OR u² = -22
u = ±4 OR u = ±i*√22
x+10 = -4 OR x+10 = +4 OR x+10 = -i*√22 OR x+10 = +i*√22
x = -14 OR x = -6 OR x = (-10 - i*√22) OR x = (-10 + i*√2)

[@SpencersAcademy]

Fantabulous heart 👏