Ap scores just came out today.... and I just passed with a 3. I owe a lot of that to you. I had almost no idea what I was doing for most of the year, every new lesson in this class seemed incomprehensible. However with the AP test approaching, I decided to try to cram as much info to credit for the class. That's exactly what I did when I found your channel. Very understandable explanations with interactive questions was exactly what I needed. I learned just enough to get credit, and was even intrigued by the material. I am certain I would've found another review channel were I to keep looking, however I don't think it would have been as beneficial as yours. Again, I thank you from the bottom of my heart!
I'm confused about the question at 31:00, wouldn't they be equal because .01molKSO x 2/1= .02molHNO and .02MolHNO x 1/2 = .01 making the mole ratios equal? Or does the coefficient already represent the number of moles
I'm not sure where you're getting your # of mols from, but the # of mols for a solution is given the M(Molarity) * L(Volume). In this case K2SO3 is (0.1*0.1) and HNO3 is (0.2*0.1). The mol ratio between K2SO3 and HNO3 is a 1:2 ratio, meaning for every 1 mol of K2SO3 present, 2 mol HNO3 is needed. In this case, 0.01 mol K2SO3 is present and 0.02 mol HNO3 is needed. Option C is correct because it gives a correct stoichiometric ratio for the reactants and the products (0.02 mol K2SO3 and 0.04 mol HNO3) and (0.02 mol K2SO3 for 0.02 mol SO2 or 0.04 mol HNO3 for 0.02 mol SO2). We can make an assumption that this doubles the amount of volume because in PV=nRT, V and n are directly proportional and the question told us that P and T are constant, meaning a change in the factor of n means the same change in factor of V and in this case # of mols of SO2 was doubled, therefore V is doubled.
This context is a acid-base reaction, so the proton from HF (H+) is donated to the OH molecule. This results in H2O being formed and a spectator molecule that results from the leftover atoms (Na and F -> NaF).
It should be noted however, that she got it wrong in this case because HF is a weak acid and does not dissociate and therefore HF should stay together in the final reaction, netting HF + OH- --> F-+ H2O
![ARGENTINA vs. CHILE [3-0] | RESUMEN | ELIMINATORIAS SUDAMERICANAS | FECHA 7](http://i.ytimg.com/vi/De3AWmXzhuA/mqdefault.jpg)
Ap scores just came out today.... and I just passed with a 3. I owe a lot of that to you. I had almost no idea what I was doing for most of the year, every new lesson in this class seemed incomprehensible. However with the AP test approaching, I decided to try to cram as much info to credit for the class. That's exactly what I did when I found your channel. Very understandable explanations with interactive questions was exactly what I needed. I learned just enough to get credit, and was even intrigued by the material. I am certain I would've found another review channel were I to keep looking, however I don't think it would have been as beneficial as yours. Again, I thank you from the bottom of my heart!
Congrats that you passed it!! And thank you so much for coming back and commenting on my channel!!
hey! i love your videos and was wondering when you're gonna release videos for unit 5?
Hey, when are you realising Unit 5?
huh
what happened? you just never did the other 5 units
@@val-zv3ko look at live streams
14:04 shouldn’t the answer be D since HF doesn’t dissociate
Ohhhhh I just realized that I made the mistake. Thank you for noticing it. You're right. It's D.
UNIT TEST TMR LETS GOOO
:) just got to this one after reviewing your other videos, thanks again!
At 42:45, the question asked for C5H5N, not HCL, so wouldn't it be A?
Yes, you're right 😂 my bad
Slay queen content
are there any cram ap chem unit 5?
I'm confused about the question at 31:00, wouldn't they be equal because .01molKSO x 2/1= .02molHNO and .02MolHNO x 1/2 = .01 making the mole ratios equal? Or does the coefficient already represent the number of moles
I'm not sure where you're getting your # of mols from, but the # of mols for a solution is given the M(Molarity) * L(Volume). In this case K2SO3 is (0.1*0.1) and HNO3 is (0.2*0.1). The mol ratio between K2SO3 and HNO3 is a 1:2 ratio, meaning for every 1 mol of K2SO3 present, 2 mol HNO3 is needed. In this case, 0.01 mol K2SO3 is present and 0.02 mol HNO3 is needed. Option C is correct because it gives a correct stoichiometric ratio for the reactants and the products (0.02 mol K2SO3 and 0.04 mol HNO3) and (0.02 mol K2SO3 for 0.02 mol SO2 or 0.04 mol HNO3 for 0.02 mol SO2). We can make an assumption that this doubles the amount of volume because in PV=nRT, V and n are directly proportional and the question told us that P and T are constant, meaning a change in the factor of n means the same change in factor of V and in this case # of mols of SO2 was doubled, therefore V is doubled.
@@mr.snuffulmuffin6954 sorry already took the AP chem test but I did figure out how to do it
Hi how did u know to put h20 and NaF in the products? In 14:07
This context is a acid-base reaction, so the proton from HF (H+) is donated to the OH molecule. This results in H2O being formed and a spectator molecule that results from the leftover atoms (Na and F -> NaF).
It should be noted however, that she got it wrong in this case because HF is a weak acid and does not dissociate and therefore HF should stay together in the final reaction, netting HF + OH- --> F-+ H2O
when will you be releasing unit 6?
Please check out the livestream videos for Unit6
at 42:44 isn't it bronsted-lowry base not acid?
Yes it is
Very true, that was a mistake as she was referring the acid to HCl
Yes, it should be, they accidentally thought the question asked for HCl... i think
cram ap chem in 1 day before finals
Good luck on your final
@@academic-coach-youhyun thank you it went terribly cuz of last minute studying lmao but at least i knew what i was doing so chance of partial credit