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College Fluid Mechanics
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Добавлен 18 мар 2020
Hello! My name is Rasim Guldiken. I am a Professor of the Mechanical Engineering Department and the Associate Dean for Academic Affairs of the College of Engineering at the University of South Florida, located in beautiful Tampa, Florida.
I have taught fluid mechanics, thermodynamics, and engineering mathematics-related courses 41 times to 2700+ B.S., M.S., and Ph.D. students for the last 15 years. For my teaching initiatives, I have been recognized with several awards, including the SAE Ralph Teetor Educational Award, USF Academic Excellent Award, and USF University-Wide Outstanding Undergraduate Teaching Award. My engineering education interests lie in open courseware for courses, metacognitive activities, and flipped learning.
This material is based upon work supported by the National Science Foundation (NSF) under Grant No. 2019664. Any opinions, findings, conclusions, or recommendations expressed in this material are mine and do not necessarily reflect the views of the NSF.
I have taught fluid mechanics, thermodynamics, and engineering mathematics-related courses 41 times to 2700+ B.S., M.S., and Ph.D. students for the last 15 years. For my teaching initiatives, I have been recognized with several awards, including the SAE Ralph Teetor Educational Award, USF Academic Excellent Award, and USF University-Wide Outstanding Undergraduate Teaching Award. My engineering education interests lie in open courseware for courses, metacognitive activities, and flipped learning.
This material is based upon work supported by the National Science Foundation (NSF) under Grant No. 2019664. Any opinions, findings, conclusions, or recommendations expressed in this material are mine and do not necessarily reflect the views of the NSF.
Thermo 7.9: Isentropic Efficiency of Turbines, Compressors and Pumps
Thermo 7.9: Isentropic Efficiency of Turbines, Compressors and Pumps
Просмотров: 3 290
Видео
Thermo 7.8: Isentropic Efficiency of Nozzles
Просмотров 2,7 тыс.3 года назад
Thermo 7.8: Isentropic Efficiency of Nozzles
Thermo 7.7: Entropy Change - Isentropic Processes of Ideal Gases
Просмотров 7613 года назад
Thermo 7.7: Entropy Change - Isentropic Processes of Ideal Gases
Thermo 7.6: Entropy Change - Ideal Gases
Просмотров 5503 года назад
Thermo 7.6: Entropy Change - Ideal Gases
Thermo 7.5: Entropy Change - Liquids and Solids
Просмотров 7963 года назад
Thermo 7.5: Entropy Change - Liquids and Solids
Thermo 7.4: First and Second Tds relationships (Gibbs Equations)
Просмотров 1,5 тыс.3 года назад
Thermo 7.4: First and Second Tds relationships (Gibbs Equations)
Thermo 7.3: Entropy Change - Pure Substances
Просмотров 9003 года назад
Thermo 7.3: Entropy Change - Pure Substances
Thermo 7.2: Entropy Increase Principle
Просмотров 6593 года назад
Thermo 7.2: Entropy Increase Principle
Thermo 7.1: Entropy and Clausius Inequality
Просмотров 1,6 тыс.3 года назад
Thermo 7.1: Entropy and Clausius Inequality
Thermo 6.7: Carnot Cycle, 2 Solved Example Problems
Просмотров 3,4 тыс.3 года назад
Thermo 6.7: Carnot Cycle, 2 Solved Example Problems
Thermo 6.6: Carnot Cycle, Carnot Heat Engine, Carnot Efficiency
Просмотров 4573 года назад
Thermo 6.6: Carnot Cycle, Carnot Heat Engine, Carnot Efficiency
Thermo 6.4 - Refrigeration Cycle - 2 solved example problems
Просмотров 5123 года назад
Thermo 6.4 - Refrigeration Cycle - 2 solved example problems
Thermo 6.3 - Second Law of Thermodynamics; Refrigeration Cycle; Clausius Statement
Просмотров 7923 года назад
Thermo 6.3 - Second Law of Thermodynamics; Refrigeration Cycle; Clausius Statement
Thermo 6.2 - Heat Engine - Solved Example Problem
Просмотров 6253 года назад
Thermo 6.2 - Heat Engine - Solved Example Problem
Thermo 6.1 - Second Law of Thermodynamics; Heat Engine; Kelvin-Planck Statement
Просмотров 1,2 тыс.3 года назад
Thermo 6.1 - Second Law of Thermodynamics; Heat Engine; Kelvin-Planck Statement
Thermo 5.4 - Nozzles and Diffusers - Two Solved Example Problems
Просмотров 2,8 тыс.3 года назад
Thermo 5.4 - Nozzles and Diffusers - Two Solved Example Problems
Thermo 5.8 - Heat Exchangers - Solved Example Problem
Просмотров 1,2 тыс.3 года назад
Thermo 5.8 - Heat Exchangers - Solved Example Problem
Thermo 5.7 - Throttling Devices - Solved Example Problem
Просмотров 1,4 тыс.3 года назад
Thermo 5.7 - Throttling Devices - Solved Example Problem
Thermo 5.6 - Compressors and Pumps - Solved Example Problem
Просмотров 9033 года назад
Thermo 5.6 - Compressors and Pumps - Solved Example Problem
Thermo 5.5 - Turbines - Solved Example Problem
Просмотров 7353 года назад
Thermo 5.5 - Turbines - Solved Example Problem
Thermo 5.3 - Flow Work (Energy) and Conservation Energy for Open Systems
Просмотров 6493 года назад
Thermo 5.3 - Flow Work (Energy) and Conservation Energy for Open Systems
Thermo 5.2 - Conservation Mass for Open Systems
Просмотров 7553 года назад
Thermo 5.2 - Conservation Mass for Open Systems
Thermo 5.1 - Conservation Mass and Energy for Open Systems - Intro
Просмотров 1,6 тыс.3 года назад
Thermo 5.1 - Conservation Mass and Energy for Open Systems - Intro
Thermo 4.11 - Specific Heat of Liquids and Solids - Solved Example Problem
Просмотров 4883 года назад
Thermo 4.11 - Specific Heat of Liquids and Solids - Solved Example Problem
Thermo 4.10 - Specific Heat of Ideal Gases - Solved Example Problem II
Просмотров 6453 года назад
Thermo 4.10 - Specific Heat of Ideal Gases - Solved Example Problem II
Thermo 4.9 - Specific Heat of Ideal Gases - Solved Example Problem I
Просмотров 7873 года назад
Thermo 4.9 - Specific Heat of Ideal Gases - Solved Example Problem I
Thermo 4.8 - Specific Heat of Ideal Gases, Liquids, and Solids.
Просмотров 1,5 тыс.3 года назад
Thermo 4.8 - Specific Heat of Ideal Gases, Liquids, and Solids.
Thermo 4.7 - Energy Analysis for Closed System - Solved Example
Просмотров 2 тыс.3 года назад
Thermo 4.7 - Energy Analysis for Closed System - Solved Example
Thermo 4.6 - Energy Analysis for Closed System
Просмотров 1,7 тыс.3 года назад
Thermo 4.6 - Energy Analysis for Closed System
Why are you assuming laminar flow?
Because the Reynolds number=100
Love the mirror image triangle!
My dots get crossed!
I am also confused why you didnt include atmospheric pressure, compared to the first problem you did that was looking for the specific gravity of oil.
Think of this as a water tank (or a bucket, if you will). Adding opposing forces to the tank (Patm.Area) will cancel each other. So you can include Patm, but you need to include from outside pushing in as well.
because of your module from 1 to 12, i passed my final exam Dr, thank you very much, god bless you
You made my day!
I am also confused how you got 4PiR, if you're referring to an inner and outer diameter
The thickness of the ring is negligible, hence 2PiR for inside of the ring touching the fluid + 2PiR for outside of the ring touching the fluid= 4PiR
Learn in my 39😊
Great to hear. Keep going!
Displament thickness boundary mathematical derivation
both solutions you have given are impractical in the real world for most wind/water tunnels
Agreed! Thats one of the points I am making in this video. Just because math says you can doesnt mean you will be able to in real life. Best of success in your studies.
I used linear interpolation because it is approximately linear across a small difference. On the FE I will likely skip linear interpolation for the sake of speed and time management, but is this an appropriate solution if I felt I needed to use it.
Sounds great. You have to do what you have to do. It is good to strategize before taking the FE. Smart.
Why do you use the velocity of the top plate relative to the bottom plate? Would we not use the velocity of the top plate alone, because the fluid is still, so the velocity of the top plate relative to the fluid would just be the top plates velocity, or is it assumed the fluid is moving with the bottom plate?
Good question. Yes, because of the no-slip condition, the first fluid particle touching the bottom plate will move 1m/s toward the left. Also, if it makes you more comfortable, you can think of this question as the bottom plate is stationary and the top plate is moving at 3 m/s (2-(-1)) to the right. The final answer will be the same.
Thank you a good explanation. isn't an=0 then, because you said sinnpi is zero.
Not having pressure was a large omission.
Please note that that "cube" is the size of one of your hairs, as this is a differential analysis. Hence, the pressure change is negligible for a small size and reasonable assumption in real life.
why dont you do m=n for bn? the same way it was done for an where it became cos^2
how does the bernoulli equation affect manometry
This is a good question. If you insert V=0 into the Bernoulli's equation (fluid in a manometer is stationary), and manipulate the remaining terms, you get DeltaP=rho*g*h, which is the same equation presented here. So, Bernoulli's equation is a very powerful concept to learn in fluid mechanics
I works for that system you have created. But how can you extrapolate that inequality for any system?
Thank you sir, great video!
Just spent ages trying to find my mistake when manually working out the first pi term (8:50). Turns out I turned a + into a - for absolutely no reason. Tip for anyone who might be stuck: remember to double check your signs!
amazing explain thank you sir
What a explanation, it is very clear. Thank you so much sir.
adamsın
Great
This channel is very valuble
why didnt we use the a-5 table for p=0.4Mpa in between 300K and 400K to get u2 and the same for u1 but its directly from the table for 0.2 Mpa and 200K ? TY FOR THE EFFORT U HELPED ME ALOT
Please how do you write on the laptop
This is an Ipad I am writing on, not laptop.
Türkiye'den selamlar hocam
Your videos have clarity, Doctor. Very well
7:45 I diedddd😭 this lecture is so helpful thank you!!
Salamat,Pogi. Hulog ka ng langit!
this may be 4 years old but its still very useful for my final in 2 days. ty
My school over thought how to teach this. You’re a life saver and made it way more simple. Thank you
this was helpful thank you
the concept is so confusing !!!
Most students dont find this concept that bad, it actually increases my exam averages, so just review the concepts a few times, you will be fine. Best of luck
@@CollegeFluidMechanics i fiinished the course already, im relieved!
Thankss
thank you sir
abi her yerinden öpüyorum kralsın
Such an underrated channel. Many thanks for the excellent content!
great videos. Thanks for sharing!
Do you have a pdf for your notes its so helpful
Yes, I do. It is posted the website: www.collegefluidmechanics.com/
Great video! watching before my fluid final
goat
ulan madem türksün türkçe konuşsana yoksa fetocumusun
Great Reviews and great Explanation, Writing my FE today. Fingers crossed.
I am curious, Wouldn't the L defined in the FE handbook as "Length over which pressure drop occurs" be the vertical distance AKA 10 sin(30)?
L is the length of pipe. Vertical distance in a situation like this is accounted for in Bernoulli’s equation, where it is represented by the difference between the two points of height z1 and z2.
Very helful! thank you
Hi. Shouldnt the Re number be 3×10^4 in the moody chart? In that case, the f should be around 0.048.
yes I was getting the same so I was also a bit confused
what anice presentation!!! thank u
Thanks I learned a lot from it
@6:02 why are the areas divided by 4?
sorry for the late answer, but its bc hes using the diameter instead of radius. area of a circle is (pi)(r^2) but thats also equivalent to (pi/4)(d^2)
Dear Professor, just discovered your channel. I don't study fluid mechanics but i watched some of your videos and loved them. Thanks. Best. AC