Sir I am a student of AK Jha Sir in JRS Tutorials, Varanasi I want to tell you that your book is boon for every PMT and IIT aspirant. Our teachers respect you and we respect them. You are a living gem!
This is how I understood it: -- first imagine yourself looking down on this rotating plate from top of the center. Draw the particle, the grove and the plate. At this instant name a poin A which is fixed on the grove and coincides with the particle at this instant. Now draw the velocity vectors of A and particle, which will be same here. -- now imagine dt time has passed, the grove has rotated by d(theta) and in this time the block will move by dx in the direction of the velocity it earlier had. -- now you might be a bit worried here for several reasons: thinking that the particle should rotate instead of going straight but there is no force or there component in that direction so that isn't possible. Also note that there would be some dx space between the particle and the groove walls between which this dx displacement has happened.
The basic doubt here is about the frame of reference. If one looks at a particle on the rotating table in grounds frame, it shall not be radially outward only (as it is rotating). Also, there will be various other forces (forces and reaction on the groove). In that case ,ball moving in the groove carries no meaning if watched from grounds frame.
Yup, but if imagine the path that it would take about the axis, it would look kind of spiralling outwards, with increasing tangential linear velocity and also the outward velocity along groove.
I am amazed that nobody is saying that the particle is moving in a flat spiral ,,, which is visible from all frames,, table or outer frame both... If you can understand this then you can understand all the forces working on it. I am surprized that Verma ji himself could not make any clear answer on it in the last part of this discussion.
Exactly in ground frame it's a flat spiral. He just mentioned the radial equation but didn't explain the answer. What it means is that, in radial direction acceleration is rate of (rate of change of r) and an -ve acceleration like gravity = w^2 r . Which is also called perceived gravity. But in this gravity objects falls outward.
If Sir had explained in more detail, it would have been better. Sir said that even though the particle in the groove is moving away in the groove, no force is acting on it, when seen from the Ground frame. This needs to be elaborated more.
I understood why it was by drawing diagrams of this phenomena: -- first imagine yourself looking down on this rotating plate from top of the center. Draw the particle, the grove and the plate. At this instant name a poin A which is fixed on the grove and coincides with the particle at this instant. Now draw the velocity vectors of A and particle, which will be same here. -- now imagine dt time has passed, the grove has rotated by d(theta) and in this time the block will move by dx in the direction of the velocity it earlier had. -- now you might be a bit worried here for several reasons: thinking that the particle should rotate instead of going straight but there is no force or there component in that direction so that isn't possible. Also note that there would be some dx space between the particle and the groove walls between which this dx displacement has happened. --now after displacing particle by dx along its velocity which we drew earlier, we will draw the position of A -- A , which was coincident with particle earlier now won't be coinciding. The particle has went straight ahead by dx but the particle is constrained to rotate (since it is fixed with the groove wall). -- so after dt the particle would appear to have been separate from A i.e. slided radially in the groove. Now I think you understand what is happening now try to imagine why speed is increasing
@@rounitkamal2832 If possible, kindly draw the pic of your explanation on a paper, by saving it in google drive and pasting the link here.. It would be for the benefit of everyone.
@@rounitkamal2832that's what he's asking that howcome particle is moving away from the center of the table along the groove, if there's no such force acting on it....??
See bro, your question is absolutely intriguing..👍 Now this statement that you mentioned that sir had said is absolutely confusing. Becoz howcome a body would accelerate in the direction where no force seems to be acting on it. Therefore there's surely a component of net force acting on the particle in the direction away from center along the groove which remains uncancelled that's why the body's accelerating radially outwards. I hope you're getting my point. Now not only is the body accelerating radially but also with the increasing radius (i.e. it's distance from the center), it's linear velocity around the axis is too rapidly increasing. If you just trynna imagine the path of the particle about the axis, it would appear to be spiralling outwards away from the center. So this actually shows that there's surely a net force which is driving the particle all the way along the groove to furthest positions away from center. Now this force is a result of the table spinning at a constant angular velocity about it's axis. This is what's causing a net force to act having an uncancelled component in the radially outward direction along groove as the walls of the groove are absolutely frictionless, this no resistance to the particle in moving outwards.
I slept on your book as, pillow during my school days, interestingly I was interested in solving ur questions no matter board exams were of different subjects next day #livinglegend
Since time isnt involved, This could also be solved using conservation of Energy in a single step without the need of calculus. Intital rotational KE of the particle = final translational and rotational energy of the particle together. Although the classical approach by professor can be used even in the presence of a non conservative force. I always encourage my students to check for the feasibility of conservation priciples as long as time isnt involved
@@_mayank_trivedi Even if an object is at rest it needs a Force To CHANGE Its state of motion the object is already in motion in which it has zero velocity
I am a ca student having economics exam tomorrow.....i don't know why the hell I am watching this but enjoying at the same time though I am not able to understand a single word
Respected sir From ground frame there is no force but still partical moves. It is evident from the fact that after one complete rotation its x coordinate has changed. Is this because earth is itself non inertial although the non inertiality is much less . Ground frame which we are considering is itself non inertial and the movement of particle in ground frame is due to pseudo forces like corriolis force
we know that every object requires centripital force to move in cicular path But in this condition the particle is not getting any centripital force. So the particle will not move in circular path. And move outside the grove
samajh gaya ki particle circular motion nhi chalega magar uski speed bhad rhi hai mtlb accelaration toh hogi na wo acc. kiski wajeh se aa rhi hai batado plz
Sir I am unable to solve this question which is given in your book from the chapter 'Centre of Mass'. ' A square plate of edge d and a circular disc of diameter d are placed touching each other at the midpoint of an edge of the plate. Locate the centre of mass of the combination, assuming same mass per unit area of the same plates
It will be inside the square plate only. As You know that for a system of bodies, COM lies towards the heavy body. So when you calculate the area of square, you will get (d²) while for the Circular disc, it will be πd²/4 if its thickness is neglected. So on comparing both the values, you will find that the value of coefficient of d² i.e. π/4 is
There is formula for this I think Xcordinate of COM= A1×X1 + A2×X2/X1+X2 Where A1 and A2 ara of each shape X1 and X2 xcordinate COM of respective shape. Same formula for y cordinate
@@Shitai-4everyup you are right but the formula is slightly incorrect. X- coordinate of COM = {(A1×X1) + (A2×X2)}/(A1+A2) Where : A1 and A2 are the areas of square and circular plate respectively. X1 and X2 are the the X-Coordinates of their respective Geometric centres which are their own center of masses.
@@Trolex6969yes, it will be slightly left to the point at which circular plate touches the square plate, if the square plate is left to circular plate. And it will lie on the line joining their geometric centers as their mass density is the same.
Yes, there definitely there is a force called coriolis force (which by the way is a pseudo force). Search it on wikipedia.. Also, try to understand what happens when a military tank is fired or how sniper rifle's bullet traverses. Coriolis force makes them turn right or left defending upon which hemisphere it is traversing in. It's very interesting phenomenon.
@@iamalive2826 I understand that, that's why i had mentioned in my post above, that it's a pseudo force. When we observe a phenomena from non-inertial frame of reference, pseudo force is needed to explain the apparent motion. That is what i had meant when i wrote the above comment. Had i mentioned that there's no such thing as a coriolis force or centrifugal force on account of it being a non-real force, then that person would have thought.. hmm, then what is Sir talking about, and what is this whole page on wikipedia about titled "coriolis force or centrifugal force". So, to ease the acceptance of these concepts, it needs to be told in a way that becomes slightly less threatening or confusing to the viewer. Once he/she has understood those concepts, then he/she would be willing to see the difference between a real force and a pseudo force. However, in order to prevent any confusion, in the first line itself, in my original post, i did mention that it is a pseudo force, so as not to imply that it is a real force. I hope this clears my point of view.
I am student of Prateek Jain sir for IIT-JEE. Prateek sir tells us sometimes how HC Verma sir encouraged him in Physics while he was doing research work with Verma sir.
Thank you sir , thanks a lot 😀 for clearing my doubt 👍👍mazza aagya sir
Your question was selected keep it up
Corriolis force refer kijiye
Which coaching are u
@@physicsbrahma4149 there is already a vedio by sir
Congratulations
Sir I am a student of AK Jha Sir in JRS Tutorials, Varanasi I want to tell you that your book is boon for every PMT and IIT aspirant. Our teachers respect you and we respect them. You are a living gem!
I'm too in JRS tutorials....
Really
I study in sky tutorial
I also studied from jrs..for me jha sir is god
This is how I understood it: -- first imagine yourself looking down on this rotating plate from top of the center. Draw the particle, the grove and the plate. At this instant name a poin A which is fixed on the grove and coincides with the particle at this instant. Now draw the velocity vectors of A and particle, which will be same here.
-- now imagine dt time has passed, the grove has rotated by d(theta) and in this time the block will move by dx in the direction of the velocity it earlier had.
-- now you might be a bit worried here for several reasons: thinking that the particle should rotate instead of going straight but there is no force or there component in that direction so that isn't possible.
Also note that there would be some dx space between the particle and the groove walls between which this dx displacement has happened.
Thank you
how can you say that the block will move in the direction of is velocity by distance dx. please elaborate that.
Bro well tried but sense nahi ban rahi..
Brother if it moved a dx distnace it's direction of velocity is changing that is w×r which is changing instantaneously
teaching on green board.....huge respect sirji🙏🙏🙏🙏🙏🙏
WoW 😲 learning from the legendary author of the book
Thank you both Nihar and Sir......🙏
Bahut bahut badhai Congratulations 2 U Sir!
Mobile ke karan aapko lecture dete hue concept of Physics ke work out Example ko explain Kiya.
Doubt cleared.. Fantastic explanation thank you sir❤️
Sir Your explaining Concept is very Simple
Noone can beat his legacy
@@AamAadmiSamajwadiParty Shankar kalal
@@AamAadmiSamajwadiParty yup bro🤣🤣
@@VENOM-oz7ev Venom rahim
@@prabhatsingh6124
Prabhat bhabhi bsdk kuch bola tereko mene?
The basic doubt here is about the frame of reference. If one looks at a particle on the rotating table in grounds frame, it shall not be radially outward only (as it is rotating). Also, there will be various other forces (forces and reaction on the groove). In that case ,ball moving in the groove carries no meaning if watched from grounds frame.
Yup, but if imagine the path that it would take about the axis, it would look kind of spiralling outwards, with increasing tangential linear velocity and also the outward velocity along groove.
You are the boss of physics ⚛️
Imagine sir teaching you face to face.. wow
Such a humble teacher
I am amazed that nobody is saying that the particle is moving in a flat spiral ,,, which is visible from all frames,, table or outer frame both... If you can understand this then you can understand all the forces working on it.
I am surprized that Verma ji himself could not make any clear answer on it in the last part of this discussion.
Exactly in ground frame it's a flat spiral.
He just mentioned the radial equation but didn't explain the answer.
What it means is that, in radial direction acceleration is rate of (rate of change of r) and an -ve acceleration like gravity = w^2 r . Which is also called perceived gravity. But in this gravity objects falls outward.
@@JohnDoe-wi6nq wonderful..
If Sir had explained in more detail, it would have been better. Sir said that even though the particle in the groove is moving away in the groove, no force is acting on it, when seen from the Ground frame. This needs to be elaborated more.
I understood why it was by drawing diagrams of this phenomena:
-- first imagine yourself looking down on this rotating plate from top of the center. Draw the particle, the grove and the plate. At this instant name a poin A which is fixed on the grove and coincides with the particle at this instant. Now draw the velocity vectors of A and particle, which will be same here.
-- now imagine dt time has passed, the grove has rotated by d(theta) and in this time the block will move by dx in the direction of the velocity it earlier had.
-- now you might be a bit worried here for several reasons: thinking that the particle should rotate instead of going straight but there is no force or there component in that direction so that isn't possible.
Also note that there would be some dx space between the particle and the groove walls between which this dx displacement has happened.
--now after displacing particle by dx along its velocity which we drew earlier, we will draw the position of A
-- A , which was coincident with particle earlier now won't be coinciding. The particle has went straight ahead by dx but the particle is constrained to rotate (since it is fixed with the groove wall).
-- so after dt the particle would appear to have been separate from A i.e. slided radially in the groove.
Now I think you understand what is happening now try to imagine why speed is increasing
@@rounitkamal2832 If possible, kindly draw the pic of your explanation on a paper, by saving it in google drive and pasting the link here.. It would be for the benefit of everyone.
@@rounitkamal2832that's what he's asking that howcome particle is moving away from the center of the table along the groove, if there's no such force acting on it....??
See bro, your question is absolutely intriguing..👍
Now this statement that you mentioned that sir had said is absolutely confusing.
Becoz howcome a body would accelerate in the direction where no force seems to be acting on it. Therefore there's surely a component of net force acting on the particle in the direction away from center along the groove which remains uncancelled that's why the body's accelerating radially outwards. I hope you're getting my point.
Now not only is the body accelerating radially but also with the increasing radius (i.e. it's distance from the center), it's linear velocity around the axis is too rapidly increasing. If you just trynna imagine the path of the particle about the axis, it would appear to be spiralling outwards away from the center. So this actually shows that there's surely a net force which is driving the particle all the way along the groove to furthest positions away from center.
Now this force is a result of the table spinning at a constant angular velocity about it's axis. This is what's causing a net force to act having an uncancelled component in the radially outward direction along groove as the walls of the groove are absolutely frictionless, this no resistance to the particle in moving outwards.
Legend OF PHYSICS EVER HC VERMA SIR!
I slept on your book as, pillow during my school days, interestingly I was interested in solving ur questions no matter board exams were of different subjects next day #livinglegend
This video is truly a treasure of mathematics(it contains extremely valuable details).
I had the same doubt sir but now its totally clear thank you soo much
That Pseudo force is Equal to Normal reaction with groove that's the reason it being Stable
That's all what I needed😊
Sir l like your Hair style 🤩😘🔥😎🥳
Thank you sir maaza aa gaya
H. C sir
Panka
Since time isnt involved, This could also be solved using conservation of Energy in a single step without the need of calculus. Intital rotational KE of the particle = final translational and rotational energy of the particle together. Although the classical approach by professor can be used even in the presence of a non conservative force. I always encourage my students to check for the feasibility of conservation priciples as long as time isnt involved
Please give initial equation of conservation of energy
Nice explanation 👌
Sir, this means force is not the cause of motion ....but that change the whole perception of newtonian physics @HCverma
force is never cause of motion its the cause of change in motion
@@athvii that's the same thing...!
@@_mayank_trivedi nah
@@_mayank_trivedi Even if an object is at rest it needs a Force To CHANGE Its state of motion
the object is already in motion in which it has zero velocity
@@athvii how earth is moving around the sun?
This questions can also be done by WET
when in frame of rotation.
Sir app jee advanced level ki physics pada do youtube par maja aa jayega
PW ki challengers series dekh lo ek baar. Usme hai kaafi high level ke ques.
Long Hair... Looking adorable
I am a ca student having economics exam tomorrow.....i don't know why the hell I am watching this but enjoying at the same time though I am not able to understand a single word
Okk
Respected sir
From ground frame there is no force but still partical moves. It is evident from the fact that after one complete rotation its x coordinate has changed. Is this because earth is itself non inertial although the non inertiality is much less . Ground frame which we are considering is itself non inertial and the movement of particle in ground frame is due to pseudo forces like corriolis force
we know that every object requires centripital force to move in cicular path
But in this condition the particle is not getting any centripital force. So the particle will not move in circular path.
And move outside the grove
Is my answer correct sir ?
I think bro it is correct and ur logical is also correct here ❤❤❤
samajh gaya ki particle circular motion nhi chalega magar uski speed bhad rhi hai mtlb accelaration toh hogi na wo acc. kiski wajeh se aa rhi hai batado plz
Sir🙏 Please Eak baar Magnetic field ke bare me samjha dijiye. Class 10 in UP🙏🙏
Sir apke book me drift velocity [eE/2m]×tau hai par teachers eE/m × tou krwa rhe h please btaiye sir 🙏🙏🙏🙏🙏
❤❤❤❤❤❤❤concept of physics 🎉🎉🎉🎉🎉🎉🎉
Sir I am unable to solve this question which is given in your book from the chapter 'Centre of Mass'.
' A square plate of edge d and a circular disc of diameter d are placed touching each other at the midpoint of an edge of the plate. Locate the centre of mass of the combination, assuming same mass per unit area of the same plates
It will be inside the square plate only. As You know that for a system of bodies, COM lies towards the heavy body. So when you calculate the area of square, you will get (d²) while for the Circular disc, it will be πd²/4 if its thickness is neglected. So on comparing both the values, you will find that the value of coefficient of d² i.e. π/4 is
There is formula for this I think
Xcordinate of COM=
A1×X1 + A2×X2/X1+X2
Where A1 and A2 ara of each shape
X1 and X2 xcordinate COM of respective shape.
Same formula for y cordinate
@@Shitai-4everyup you are right but the formula is slightly incorrect.
X- coordinate of COM = {(A1×X1) + (A2×X2)}/(A1+A2)
Where : A1 and A2 are the areas of square and circular plate respectively.
X1 and X2 are the the X-Coordinates of their respective Geometric centres which are their own center of masses.
@@Trolex6969yes, it will be slightly left to the point at which circular plate touches the square plate, if the square plate is left to circular plate. And it will lie on the line joining their geometric centers as their mass density is the same.
Boss.Love you sir.💕
Sir is there any force called coriolis force as we look it from rotating frame ???
Yes, there definitely there is a force called coriolis force (which by the way is a pseudo force). Search it on wikipedia.. Also, try to understand what happens when a military tank is fired or how sniper rifle's bullet traverses. Coriolis force makes them turn right or left defending upon which hemisphere it is traversing in. It's very interesting phenomenon.
@@ThePhysicsTrain thanks actually I am IIT JEE aspirant and I had met with some question involving the use of this force in Iit pyq
@@ThePhysicsTrain pseudo force is not real force it just used for calculations
@@iamalive2826 I understand that, that's why i had mentioned in my post above, that it's a pseudo force. When we observe a phenomena from non-inertial frame of reference, pseudo force is needed to explain the apparent motion. That is what i had meant when i wrote the above comment. Had i mentioned that there's no such thing as a coriolis force or centrifugal force on account of it being a non-real force, then that person would have thought.. hmm, then what is Sir talking about, and what is this whole page on wikipedia about titled "coriolis force or centrifugal force". So, to ease the acceptance of these concepts, it needs to be told in a way that becomes slightly less threatening or confusing to the viewer. Once he/she has understood those concepts, then he/she would be willing to see the difference between a real force and a pseudo force. However, in order to prevent any confusion, in the first line itself, in my original post, i did mention that it is a pseudo force, so as not to imply that it is a real force. I hope this clears my point of view.
@@ThePhysicsTrain just never see things in non inertial frame😁
Sir please have a meet series with Sandeep Maheshwari sir
I am your biggest fan 🙏🥺💖
Centrifugal force is fictitious so how it is pushing the ball outwards in the rotating frame. Please explain Sir.
Sir hcv verma book is enough for jee advance please reply me sir🙏🙏
Nice hairstyle sir very unique
Hii love from mubai sirr ji
Sir where can I send you my question. And in what format?
Respected sir,
How a car move on 90 degree road is the noraml reaction help to move because i think mg is balanced by friction
Nice explanation sir 😍
Today first mst sir
Jai hind sir I am Ravi
I want to work on physics discover
Please help me
I am student of Prateek Jain sir for IIT-JEE. Prateek sir tells us sometimes how HC Verma sir encouraged him in Physics while he was doing research work with Verma sir.
what coaching?
@@itachu. unacademy
me too bro
@@itachu. Unacademy(Plus)
@@itachu. unacademy
Sir if we put a charge in vaccum and apply magnetic field on it what will be force on it and ive some other intresting concepts about it
Hcv sir is a genious
Good chela MERAA.. ✌✌✌
Gravity make by which particle?
Thanks sir 😀
A guess the particle from ground frame moves in a straight line
He is so lucky that he got his dought cleard by onerable hc verma sir
very nice viedo
The thing is in ground frame the ball will not just be moving out radially.
Am I right?
Yes, you are right in saying that..
Sir .
Which type of force attract towards centre of Earth💯💯💯💯💯💯💯💯💯💯💯💯💯💯
Gravitational Force
Sir physics ko kaise samjhen ki physics asan lage
Looks like a beautiful ravan
Sir why dipole moment direction is from negative to positive
Proud of bihar
Sir big fan
Sir when you will release bhautiki ki samajh part 2.? Please tell
Sir, coriolis acceleration par ek video banaiye
JEE adv 2016 question on same concept
I saw real Einstein ❤️❤️❤️
thank you sir😃
Sir is there any tangential for acting on it...?
Great.hlo
Yeah buddy 👍🏻
Respected sir in this question what is difference between rotating table frame and ground frame?
Sir please tell me a topic of law of inertia
Sir pl aap hindi me hi padhaye jisse ki hindi medium aur english medium dono ko fyda ho
Sir plz explain why sky is blue
Sir we are from south india we couldn't understand Hindi could you speak in English sir
Sir aapne ye saare que bnaya haj phir aap dekh dekh kr kyu pdh rhe hai ?
Sir physics ka sab numerical solve nahi hota ,jo topic padh liye uske baad bhi physics ka numerical nahi banta
Practice makes a man perfect. Setup your mind for hard and consistent work.
Ye question Maine kiya hai.
👍
Sir smooth table hai mtlb friction nahi hoga to koi force kaise aa sakti hai
Normal toh hoga
Sir bautiki ki samajh ka 2 vol publish kab hoga
Here just almost 33 comments I think they all are most beautiful mind
👍👍👍👌👌👌👌
Sir please explain point charge
❤️❤️
HC verma sir a
How to solve hc verma difficultie type question sir please advice sir
sir aap jee ke jiye ek coaching start Karo❤️❤️❤️❤️❤️
Sir can u please make lectures on some of the imp topics from physics of high school 🙏🙏
Sir please explain us about impulse
Impulse is all about momentum 🐥
Sir i am siddharth kumar from bihar ( darbangha ) sir please batadoon ki hcv verma book hai jee advance ke liye enough hai
😂
Sir hcv verma centre of mass killing question no. 61 aur 60 Batadige
Sir i have mailed you but not getting any response on my query.
Sir ji pranam
9:40 to 11:37 ,crux of video
How to make super conductor??
Force kyon lagta hai