Had this exact doubt 4 years ago, I'm so glad I worked it out in 4 hours the exact same way he did! Today I'm fully satisfied of my solution, all thanks to you, Sir!
Sir I am one of your students who attended your Workshop On Innovative Science Seminar. West Bengal, South Dinajpur. This seminar was held from Balurghat Lalit Mohan Adarsh High School. Thanks sir for all your valuable comments.❤️
According to the question asked, my explanation would be that when we try to increase the speed of that stone string contraption, you are increasing the angular velocity by which the stone rotates, due to this increased angular velocity the centripetal acceleration increases which basically means the the centripetal force I.e. tension in this case increases. Due to increase in angular velocity, you are providing the stone angular acceleration, and due to this angular acceleration the tangential acceleration increases, which increases the velocity. Therefore the perpendicular force does not have anything to do with increasing the velocity but just the fact that it is being spun faster will increase the tangential velocity. Increased tension in the string is a by product of increased angular velocity, many times if the rock is spun too fast, the string breaks and the rock goes flying tangentially. The string breaking signifies that there was an increase in tension force which went beyond the capacity of the string and eventually broke the string. Thanks.
I literally had this exact same doubt, and my friends weren't able to give a satisfactory answer as well, but this was an excellent explanation, thank you so much sir!
sir your dedication about the physics is very great and me and many more students are inspired from your attitude towards physics and definition because of you sir india will reach great height in the field of physics your book is sacred as giita for me loce you alot sir
If you consider tangential acceleration too, means accelerated circular motion... V(vec) = (mag)(v cap). Here "mag" = magnitude of velocity and "v cap" is the direction and "v(vec)" means velocity vector... And if we differentiate it wrt time you'll get dV(vec)/dt=[d(mag)/dt](v cap)+[d(v cap)/dt](mag) And you relate this equation with a (vec) = a(along velocity) + a(normal to velocity vector) ... You'll get Normal component of net acceleration= [d(v cap)/dt](mag).. this shows then the rate of change of direction of velocity vector multiplies by the magnitude of velocity give the normal component of the net acceleration...it also shows that, normal component only changes the direction of velocity vector..
I'm watching your every videos and hitting the "like" bottom, not because I'm a student but to me liking your videos and playing for no reason is my kind of "Guru dakshina" when i was in class 11 i failed in first unit test in physics but later i purchased Concept of Physics and got 81 in board exam. I have studied in Jawahar Navodaya Vidyalaya in the year 2013, Kaash uss daur mein RUclips jaisi platform aaj ke jaisa popular hoti toh shayad 95+ mujhe milta aap se woh concept direct RUclips jaisi platform mein mil jata 😢 phir bhi apko naman sir ji 🙏
Sir we are waiting for new course on electricity and magnetism Current electricity,,emi and ac etc ..... please 🙏 launch third part of electrodynamics 🙏🙏🙏🙏
How we travelled in time in future or past if we go more than light of speed and why we considered speed of light in time travel. Time travel me speed of light ka kya relation. Oo formula mujhe bhi pata hai but in real life speed of light ka time travel se kya relation hai please make a video on this
As per the law, mgh÷R = mv^2 ÷ R Or PE = KE Also we know Total energy (mv^2) Therefore on a circular motion mv^2 is always equal to PE+KE Hence Uniform circular motion Centrifugal force is equal to centripetal force but KE is always (1/2)mv^2. Cos 45 = sin45 = (1/√2) Velocity.cos45 = direction v^2 ÷ 2 = direction
The fact that speed doesn't change upon a perpendicular force remains true for both the situations discussed: uniform circular motion as well as projectile motion. The confusion is with the velocity vector which, under a perpendicular force, may undergo a change in its original direction and so on and so forth with time. And, lots of thanks to HC Verma sir for clarifications on this issue.❤
My question is " Does a charge undergoing acceleration within a gravitational field emit radiation? " I have been thinking about this situation for quite some time since my 11th grade and could not come up with any possible answer. I have also asked this to many physics teachers and professors but could not get a satisfactory response. According to classical electromagnetism, an accelerating charge emits electromagnetic radiation. However this scenario touches upon the intersection of two fundamental theories in physics-electromagnetism and general relativity.
We can also prove this by dot procuct and some basic calculus... Like we can quantify this statement - " An acceleration vector that has a positive component along the direction kf the velocity will increase the speed... Acceleration vector is perpendicular to velocity, it's componenet along the velocity is zero" We will use two dinension for simplicity ... Speed (s) = |Velocity|= √Vx²+Vy² Where Vx and Vy are components arr velocity vector .. Using chain rule and then product rule and then the chain rule gives .. ds/dt =1/2√Vx²+Vy² (2Vx dVx/dt + 2Vy dVy/dt) ds/dt= 1/s × (velocity vector) dot (Acceleration vector) From this we can see that if velocity and acceleration are perpendicular, v.a=0 (dot product is zero) So rate of change of speed wrt time = 0 ...
Hello Sir My name Vaibhav Kumar Upadhyay Today you come to Mahuja, Our Village . I felt very happy. Thank you Sir Did you liked our projects? Earthquake detector.
In an Young’s double slit experiment , the slits are kept 1mm apart and a monochromatic light of wavelength 0.5mm is used to illuminate the slits . A screen is placed 1 m away from the slits . What will be the distance of - a) 1st bright b) 1st dark c) 2nd bright
Sir next time whenever you make a video to answer any question then please give us a chance to think and comment by asking the que on one day and answering it next day
An other explainition is that , we know according to work energy theoram that when work is done on a body it change the k.E of the body if there is no work then there will be no change in k.E and hence no chang in velocity. This the case here in this question when force is toward center and velocity is along tangent then displacment is also along velocity thus there is angle of 90 between force and displacment and work done is zero therefore change in k.E is zero and hence change in velocity is zero in terms of magnitued
Sir I am the student from where you did graduation - Patna Science College. I meet you in 2013 When you come to see my poster of black hole in competition. And said this is something different you have projected, but your chandrashekher limit value to being a black hole is wrong. I remember that moment. 😊
Guru ji.. lot's of love and respect for you❤ Plz.. start jee and advanced concepts series 😢 We needs your help we can't feel physics many more 😢 Plz it's humble request 🙏🏻🙏🏻 plzz sir 😢
But I have a doubt,should not the Direction of horizontal component of velocity change as gravity acts perpendicular to it.I am not talking about the magnitude of horizontal velocity,it will remain constant but its direction should change.Please anyone clear my doubt 🙏
A force acting perpendicular to a particle's velocity can change its direction but not its speed. This is because only the component of a force in the direction of velocity affects the speed of the particle. When the force is perpendicular to the motion, it creates centripetal acceleration, changing only the direction, so the particle moves in a curved path, such as in circular motion, while maintaining constant speed.
Sir during pre exam of 10th a question have asked in my exam that if the refraction doesn't occur in two different medium then the value of angle incidents and angle refraction will be the question was too easy that both are = 0⁰ but as we know that sin i /sinr= refractive index so from this sin i / sinr should equal to 1 but sin 0 equal to 0 and 0/0 is undefined
Can we also use this video's logic to explain what gives the centripedal acceleration in the "ring on spinning rod problem" that we do in questions, as normal is always perpendicular to the motion of the ring and their is no friction in the rod.
Sir I ask a question to my teachers that , "What happens if we connect a conductor to a positive terminal of battery onley ? Can we say that the conductor is positively charged at this situation? if yes, then it means that current will flow in the wire which join conductor to the positive terminal of battery. But how it's possible because if current flow in wire the potential of positive terminal of battery will decrease and electric field also decrease between the plates of battery and in this situation driving force will pull the electrone frome positive plate to negative plate after this we get equilibrium condition. But the terminal potential difference of battery will increase with respect to initial situation when no conductor connecting with positive terminal of battery ". Sir My physics teacher give me the answer but my inerself not satisfying. Please sir help me and solve my this problem .. 🙏🙏
Sir I am rishikesh Anand and I have doubt that if two blocks are keep one above another then pull/push upper block can it possible that lower block move fastest then upper block if friction is present between two blocks
Sir I'm Abaneesh Mohapatra from odisha Rourkela of class 9 , I have a doubt In a concept of fluid mechanics I.e. A beaker is filled with water and a ice cube is partially floating in it and a coin is placed over it , after the ice melt, the water level decreases (why?) Thank you
Because the coin is on ice cube 🧊 and due to coin weight the ice 🧊 taking much space of water and when the ice 🧊 got melt than the water take lesser spane than the ice 🧊 and water level got decreases
seee the beaker is fully filled so when ice cube is placed a type of force called buoyont force act on it now for fully submerging or melting u can take here it must displace equal water from the beaker and hence there is no change inwater level as water has been displaced out but the coin here displaces the extra water and hence water level decreases as ofc coin is not participating in the quantity of water level
Gahre concepts hindi mein itne saral tarike se.
Pranam shreeman, jeete rahiye 🙏
Had this exact doubt 4 years ago, I'm so glad I worked it out in 4 hours the exact same way he did! Today I'm fully satisfied of my solution, all thanks to you, Sir!
Well done and keep shining! 👍
Legendary Explanation 🙏 by Legendary Teacher 🙂
Sir I am one of your students who attended your Workshop On Innovative Science Seminar. West Bengal, South Dinajpur. This seminar was held from Balurghat Lalit Mohan Adarsh High School. Thanks sir for all your valuable comments.❤️
Accha mota ram
sir THIS IS EXACTLY MY DOUBT IN WHOLE PHYSICS I LEARNT TILL NOW THANK YOU
According to the question asked, my explanation would be that when we try to increase the speed of that stone string contraption, you are increasing the angular velocity by which the stone rotates, due to this increased angular velocity the centripetal acceleration increases which basically means the the centripetal force I.e. tension in this case increases. Due to increase in angular velocity, you are providing the stone angular acceleration, and due to this angular acceleration the tangential acceleration increases, which increases the velocity. Therefore the perpendicular force does not have anything to do with increasing the velocity but just the fact that it is being spun faster will increase the tangential velocity. Increased tension in the string is a by product of increased angular velocity, many times if the rock is spun too fast, the string breaks and the rock goes flying tangentially. The string breaking signifies that there was an increase in tension force which went beyond the capacity of the string and eventually broke the string.
Thanks.
I literally had this exact same doubt, and my friends weren't able to give a satisfactory answer as well, but this was an excellent explanation, thank you so much sir!
Truly a living legend! 🙏
Sir की दीर्घायु के लिए दुआ, really extraordinary
❤IIT KANPUR ❤
Why?
Dickridin❤️❤️❤️
@@medicalstudies2356💀🤣🤣
@@medicalstudies2356found the jeeneetard
My brother in iit k
sir your dedication about the physics is very great and me and many more students are inspired from your attitude towards physics and definition because of you sir india will reach great height in the field of physics your book is sacred as giita for me loce you alot sir
I'm mbbs student..still I'm watching your videos.The way of explaining concepts of physics it's great...
Physics is the ultimate science of the universe
@@whykoksno
@@medicalstudies2356 then what is?
If you consider tangential acceleration too, means accelerated circular motion...
V(vec) = (mag)(v cap). Here "mag" = magnitude of velocity and "v cap" is the direction and "v(vec)" means velocity vector...
And if we differentiate it wrt time you'll get
dV(vec)/dt=[d(mag)/dt](v cap)+[d(v cap)/dt](mag)
And you relate this equation with a (vec) = a(along velocity) + a(normal to velocity vector)
... You'll get
Normal component of net acceleration=
[d(v cap)/dt](mag).. this shows then the rate of change of direction of velocity vector multiplies by the magnitude of velocity give the normal component of the net acceleration...it also shows that, normal component only changes the direction of velocity vector..
🌝🌝🤯
Huh Are you making this simple or complex😂
@@PradipRuj-b3iidk :/
@@Ahrx_ermabsolutely making it complex but clearer . This is mentioned in sir's book .
Very good explanation saralta se hi physics samajhne me asani hoti hai
thanks sir your explanation is fantastic🙏🙏🙏
I had same doubt since last year, thanks for this amazing explanation, sir!
Same doubt... amazing explanation sir!
I'm watching your every videos and hitting the "like" bottom, not because I'm a student but to me liking your videos and playing for no reason is my kind of "Guru dakshina" when i was in class 11 i failed in first unit test in physics but later i purchased Concept of Physics and got 81 in board exam.
I have studied in Jawahar Navodaya Vidyalaya in the year 2013, Kaash uss daur mein RUclips jaisi platform aaj ke jaisa popular hoti toh shayad 95+ mujhe milta aap se woh concept direct RUclips jaisi platform mein mil jata 😢 phir bhi apko naman sir ji 🙏
Many people maybe genious but they cant teach efficiently. But He is genious. As well as a great teacher. Lots of love❤ and respect to you sir!🙏🙏
Very true!
Sir we are waiting for new course on electricity and magnetism
Current electricity,,emi and ac etc ..... please 🙏 launch third part of electrodynamics 🙏🙏🙏🙏
Pure soul with zero haters❤
Hii 👋🏻
How we travelled in time in future or past if we go more than light of speed and why we considered speed of light in time travel. Time travel me speed of light ka kya relation. Oo formula mujhe bhi pata hai but in real life speed of light ka time travel se kya relation hai please make a video on this
Had not thik about it before!!
So satisfactory explanation❤
Aap bhi best hai 👍 aur rajwant sir bhi ❤💎 love u rajwant sir ❤
Thank u so much sir u r my inspiration ❤
धन्यवाद सर बला मूळे वेग वाढतो, कमी होतो,लंब असेल वेगाची दिशा बदलली पाहिजे छान स्पष्टीकरण दिलात त्याबद्दल धन्यवाद
Couldn't realise this video was 10 minutes long!!
Great Explaining sir
8:12 wah sir wah ! Kya baat kahi hai 😂
Lekin aik baat yaad rakhna😅
As per the law,
mgh÷R = mv^2 ÷ R
Or PE = KE
Also we know
Total energy (mv^2)
Therefore on a circular motion
mv^2 is always equal to PE+KE
Hence
Uniform circular motion
Centrifugal force is equal to centripetal force but KE is always (1/2)mv^2.
Cos 45 = sin45 = (1/√2)
Velocity.cos45 = direction
v^2 ÷ 2 = direction
The fact that speed doesn't change upon a perpendicular force remains true for both the situations discussed: uniform circular motion as well as projectile motion. The confusion is with the velocity vector which, under a perpendicular force, may undergo a change in its original direction and so on and so forth with time.
And, lots of thanks to HC Verma sir for clarifications on this issue.❤
Feeling proud after solving this question
My question is " Does a charge undergoing acceleration within a gravitational field emit radiation? " I have been thinking about this situation for quite some time since my 11th grade and could not come up with any possible answer. I have also asked this to many physics teachers and professors but could not get a satisfactory response. According to classical electromagnetism, an accelerating charge emits electromagnetic radiation. However this scenario touches upon the intersection of two fundamental theories in physics-electromagnetism and general relativity.
Thank you so much sir😊
Now my doubt is crystal cleared
Here are one more legend in the earth 🌎
There should be no confusion at all now as explained so precisely by your goodself sir.
Living embodiment of Physics 😊
We can also prove this by dot procuct and some basic calculus...
Like we can quantify this statement - " An acceleration vector that has a positive component along the direction kf the velocity will increase the speed... Acceleration vector is perpendicular to velocity, it's componenet along the velocity is zero"
We will use two dinension for simplicity ...
Speed (s) = |Velocity|= √Vx²+Vy²
Where Vx and Vy are components arr velocity vector .. Using chain rule and then product rule and then the chain rule gives ..
ds/dt =1/2√Vx²+Vy² (2Vx dVx/dt + 2Vy dVy/dt)
ds/dt= 1/s × (velocity vector) dot (Acceleration vector)
From this we can see that if velocity and acceleration are perpendicular, v.a=0 (dot product is zero)
So rate of change of speed wrt time = 0 ...
Hello Sir
My name Vaibhav Kumar Upadhyay
Today you come to Mahuja, Our Village . I felt very happy.
Thank you Sir
Did you liked our projects?
Earthquake detector.
In an Young’s double slit experiment , the slits are kept 1mm apart and a monochromatic light of wavelength 0.5mm is used to illuminate the slits . A screen is placed 1 m away from the slits . What will be the distance of -
a) 1st bright
b) 1st dark
c) 2nd bright
Pronam world greatest wish mama. Joy sreeRadhay Krishna...
Very nice explanation sir❤
7:31 the force which acting towards the center of circular path is called centrifugal force
Aap kahan the gyani baba
Kam se kam naam to sahi bata do
*CentriPETAL force
Amazing explanation sir! Thanks.
Sir next time whenever you make a video to answer any question then please give us a chance to think and comment by asking the que on one day and answering it next day
Video pause kar ke agle din dekh le
Long live legend H.C. Verma sir 😊❤
An other explainition is that , we know according to work energy theoram that when work is done on a body it change the k.E of the body if there is no work then there will be no change in k.E and hence no chang in velocity.
This the case here in this question when force is toward center and velocity is along tangent then displacment is also along velocity thus there is angle of 90 between force and displacment and work done is zero therefore change in k.E is zero and hence change in velocity is zero in terms of magnitued
Hcv sir op❤❤❤❤
Very very nice explanation sir 🙏
thanks sir u always make us explore physics in different ways.
Sir I am the student from where you did graduation - Patna Science College. I meet you in 2013 When you come to see my poster of black hole in competition. And said this is something different you have projected, but your chandrashekher limit value to being a black hole is wrong. I remember that moment. 😊
Huh but he did graduation from iit
LEGEND H C VERMA
Wow sir,
You're looking like Newton.. similar hairstyle❤
Thankyou sir
Awesome explanation sir
Wonderful explanation
Wowwww ❤
Guru ji.. lot's of love and respect for you❤
Plz.. start jee and advanced concepts series 😢
We needs your help we can't feel physics many more 😢
Plz it's humble request 🙏🏻🙏🏻 plzz sir 😢
sir ek video bna do angular momentum ke upar pls
❤ thanks sirji
Nice explanation sir❤
Amazing explanation sir ❤
Love you sor jii❤
But I have a doubt,should not the Direction of horizontal component of velocity change as gravity acts perpendicular to it.I am not talking about the magnitude of horizontal velocity,it will remain constant but its direction should change.Please anyone clear my doubt 🙏
A force acting perpendicular to a particle's velocity can change its direction but not its speed. This is because only the component of a force in the direction of velocity affects the speed of the particle. When the force is perpendicular to the motion, it creates centripetal acceleration, changing only the direction, so the particle moves in a curved path, such as in circular motion, while maintaining constant speed.
Best explanation sir👑
Loved the explanation...
Thank u so much ji❤
Guru ji baal kata lete,kitne acche lagte❤
And same is the concept for cyclotron,when perpendicular force increase the velocity of electron also increases in circular direction.
Guru ji👏👏👏
Sir during pre exam of 10th a question have asked in my exam that if the refraction doesn't occur in two different medium then the value of angle incidents and angle refraction will be the question was too easy that both are = 0⁰ but as we know that sin i /sinr= refractive index so from this sin i / sinr should equal to 1 but sin 0 equal to 0 and 0/0 is undefined
Amazing discussion
Thank you sir
No 1 physics master blaster hc verma sir 💪
Can we also use this video's logic to explain what gives the centripedal acceleration in the "ring on spinning rod problem" that we do in questions, as normal is always perpendicular to the motion of the ring and their is no friction in the rod.
Thank you
We miss you sir please come with new course in bsc physics course
Living legend 🙏
Namste guru ji
Thanks🙏 sir ji
Sir ham aap se baat kaise kar sakate hai ❤
Namaste sir ji
🙏🙏 thanks
Aapki jada help ho gayi mujhe
❤❤❤❤❤
Good
Sir I ask a question to my teachers that , "What happens if we connect a conductor to a positive terminal of battery onley ? Can we say that the conductor is positively charged at this situation? if yes, then it means that current will flow in the wire which join conductor to the positive terminal of battery. But how it's possible because if current flow in wire the potential of positive terminal of battery will decrease and electric field also decrease between the plates of battery and in this situation driving force will pull the electrone frome positive plate to negative plate after this we get equilibrium condition. But the terminal potential difference of battery will increase with respect to initial situation when no conductor connecting with positive terminal of battery ". Sir My physics teacher give me the answer but my inerself not satisfying. Please sir help me and solve my this problem .. 🙏🙏
Sir please make a video jee all topics ❤❤
Nice video
Sir is looking like Bhishma Pitamah of Physics.
Sir,aap 11th ,12th ka physics ka class dijiye u tube pe....
IIT KANPUR ❤❤
Physical is ♥️
Sir 12th ke sare chapters ke one shot de dijiye please ❤
Love HCV
Sir ❤
দারুন ,
Sir please solve the controversial chimney problem of JEE.
Sir I am rishikesh Anand and I have doubt that if two blocks are keep one above another then pull/push upper block can it possible that lower block move fastest then upper block if friction is present between two blocks
Sir I'm Abaneesh Mohapatra from odisha Rourkela of class 9 , I have a doubt In a concept of fluid mechanics
I.e.
A beaker is filled with water and a ice cube is partially floating in it and a coin is placed over it , after the ice melt, the water level decreases (why?)
Thank you
Because ice has greater volume than water
@@krishnagupta33452 no but even after the ice melts the water lever doesnt change
hey i got the solution.. its too long to type in chat, hit me up if u want the picture
Because the coin is on ice cube 🧊 and due to coin weight the ice 🧊 taking much space of water and when the ice 🧊 got melt than the water take lesser spane than the ice 🧊 and water level got decreases
seee the beaker is fully filled so when ice cube is placed a type of force called buoyont force act on it now for fully submerging or melting u can take here it must displace equal water from the beaker and hence there is no change inwater level as water has been displaced out but the coin here displaces the extra water and hence water level decreases as ofc coin is not participating in the quantity of water level