HCF and LCM - Shortcuts & Tricks for Placement Tests, Job Interviews & Exams
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- Опубликовано: 9 июл 2024
- Crack the quantitative aptitude section of Placement Test or Job Interview at any company with shortcuts & tricks on HCF and LCM. Extremely helpful to crack entrance exams like MBA, Banking - IBPS, SBI, UPSC, SSC, Railways etc.
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www.careerride.com/
#HCFAndLCM #QuantitativeAptitude #PlacementTest
0:00 Quantitative Aptitude
5:31 LCM Least Common Multiple
10:33 Quickly find LCM & HCF
25:37 What greatest number divides 17, 42 and 93 and leaves remainders 4, 3 and 15, respectively?
30:20 What least number when divided by 36, 24 and 16 leaves 11 as remainder in each case?
39:53 The ratio of two numbers is 5:6 and their LCM is 480, then their HCF is
44:31 What largest number will divide 47,35 and 27 leaving same remainder in each case? What will be the common remainder?
46:59 There are 3 equilateral triangles with sides 114 cm, 76 cm and 152 cm. What maximum size scale can measure them exactly?
52:39 5 clocks ring automatically at intervals of 12 minutes, 8 minutes, 3 minutes, 4 minutes and 10 minutes, respectively. In 8 hours from the moment they start, how many times will they ring
57:03 3 cyclists cycle along the circumference of a jungle. They complete one round in 27 minutes, 45 minutes and 63 minutes respectively. Since they start together, when will they meet again
58:46 Manoj wants to paste wallpaper on wall of his room. The wall is 4 meters and 50 cm in length and 3 meters and 50 cm in height. But the wall should be covered completely only by square pieces of wallpaper having same size. What is the number of maximum sized wallpaper squares needed to cover the walls
Practice Questions on "HCF and LCM" available at:
www.careerride.com/mcq/problems-on-h-c-f-and-l-c-m-quantitative-aptitude-mcq-questions-13.aspx
Upload video for number system
Thank you soo much sir
Sir link is not opening
Q6 was wrong check it once
Sir 135/5=27
Second question is wrong.
Ans is 12/1350
(135/5=27 not 29)
Ans. 24/1350
👍
@@suniln5542 24 can't divide 36 so 12 is right.
my ansr also 12/1350
Help pls. Can it still be simplified to 2/225? Or should it just be 12/1350?
Thank you for a great session and helping us to gain knowledge.
But in second question it should be 27 as a divisor for 135, so the answer obtained is 12/ 1350.
12/4050
correct
Yes there is a correction in final answer.
yes i also got this answer
12/1350
Friendly way of teaching just like teaching in classroom.Thank you so much sir from bottom of heart for such lovely tutorials.
i appreciate the hardwork you have put in this video to make the concepts clear. In second question the LCM of denominator is 1350. so that the ans is 12/1350.
Yeah broo
Well said bro in a polite way
wah ehsaan kiye bata kar ata hai to khud karlo ek to free mein chanel bata rha hai upar se usko bhi rectify kar rhe hai
Indeed.. litrally I tried for 2-3 times and I got the same 25*27*2 = 1350
Yes true
The answer for question 2 is, 12/1350 because LCM = 1350 and HCF = 12.
Yess
Yeah that's what made me doubt the answer
Exactly ☺️☺️
I cross checked myself thinking that I gone wrong while simplifying for 10 minutes 🤣🤣
He made mistake in calculating 5*27 =135 but he said 5*29=135
51:47 When you put x= 4 to X^2-8X+15 it will never be 0.
Just this one playlist and all topics are thoroughly covered with variety of questions
Thank you so much
There were some mistakes in the exedcution but the concepts and methods dicussed were very accurate and good. Well done
this channel was recommended by our institute really awesome videos i feel instead paying fees in my institute would have watched your videos before
The best thing in your teaching is that you start from the very basic and then go for tricks so that the base become stronger.... thankyou so much for your efforts ❤️
Yes
Excellently explained!!! Commendable job 👏👏👏
In 2nd question of finding hcf of 36/75, 48/150, 72/135 .
LCM of (75, 150,135) = 1350 because all those are divisible by 15. So the answer is 12/1350.
12/1350
@@rambabupalla959 please ask mee 7 question why lcm is 480
@@bhuvidhana Bro 480 is given pls read que carefully
I am really thankful for your efforts of helping students.I learnt a great deal from you,as I was struggling before finding your channel
best class i ever attended...of hcf and lcm
Sir you are amazing , you find awesome alternatives to cancilisation of any problem in just a minute..❣️
Thanqew for your wonderful teaching!😻
The methods, tricks are so wonderful!!
But the main thing is you have a catchy voice!! Very pleasant!!!😍🎶
This channel is free to understand concept but still ur society is not seeing the good side still sending comments on the small multiplication mistake.For those people i would like to say "SAALE AGAR ITNI HI ATA HAI TO KHUD KAR LE"
Yes I am seeing ur comment after two years but this is the fact😂 when you are doing great things noone appreciate you but if u have done a small mistake society will always criticise u
you : 49:40 that 19th table
my brain: we don't do that here
Thank you so much sir..🙏for providing content which is very helpful for competitive exams and ur explanation is awesome👏 so satisfied vth ur classes sir..😊
If anyone wants to understand what just happened in 44:30 question no 9.
suppose, the common remainder is k and HCF is x.
47 = ax + k
35 = bx + k
27 = cx + k
we cant calculate HCF x of 47, 35, 27 because we don't know the remainder k
so 47 - 35 = 12 = (a-b)x , 35 - 27 = 8 = (b-c)x , 27 - 47 = -20 = (c-a)x
and HCF of all this 12, 8 and 20 has HCF x and it is free from remainder k
Sir the way you teach
You make all Difficult sums so easy
Thanks a lot sir
Awesome , just awesone . Best and simplest video you're gonna find on HCF/LCM.
Ye mera favorite channel hai I love this channel bcz mujhe yahan se bahut kuchh sikhne mil rah hai thank you sir
thank you very much sir !! this video helped me a lot
Sir,ur teaching is very useful to us.And,in the 2nd sum,I think the lcm of 135 is 27
Great Explanation! Thankyou so much sir.
Best channel.....this video solve my all doubts👍
Thankyou so much sir...I understood very well👍🏼
Really
The way you teach sir has developed a interest in me in studying it ....thanks a lot
hey can i continue with this channel for apptitude
Thank u 👍 very much sir. I found this video very helpful. Keep making such videos❤️
Enjoyed a lot by learning...thanks for this video..☺️
CareerRide is my new learning platform. Great Going .. pls don't change the way of teaching. many channels cover in just 10 to 15 min which helps nothing.
loved this video.. starting from basics and covered each type of question. Thanks alot
Thanks for covering different types of problems. It helped me a lot...Can you please explain general method for the last method coz I am getting answer different from the option verification. Again, Thanks a lot..... you are better than my Aptitude Sir.
Cant express my gratitude through mere words.....thanku so much sir
Thankyou so much, this was my weak topic from start of my school year till date when I am in engineering and I was ashamed to admit it, but because of your videos, I have understood the topic completely and can solve its questions correctly. Thankyou Sir and CarrerRide.
Thank You for your efforts, Sir. In Q3, the remainder of 93/13 is not 15 as 13 * 7 = 91 and we get the remainder as 2. I think there is a problem with the question as HCF would be 13 only when the remainders are 4, 3, 2. Please correct me if I am wrong.
You are right. I think question is misprint. Remainder would be 2 not 15.
Yes. Bro.. I just checked now
Yes question is wrongly printed
Correct 💯😅
it may be some tricky question made to confuse us
I absolutely enjoyed this session 😄❤️
Thankuu so much sir for such an awesome video. Waiting more to come like this👌
Thank you sooo much sir.Gonna suggest this wonderful channel to all my peers.Keep making such videos:)
So nice of you. Thank you!
Excellent Work!!!❤️ there was just Calculation error in Q2 but approach was appreciable
Ya, LCM of denominator is 450 right?
Every question is beautifully explained..thank u so much 😊
You're welcome, Bipasha! Glad that you found the content useful. Stay connected :)
Hyyyy
You are excellent.May God bless you ❤️
your videos are the reason i am able to solve aptitude questions .thank you very much keep up the good work!!!!
You're welcome, Ameer. Thank you for writing in. Your comments motivate us to do better. Do take a look at our Logical Reasoning videos as well. Stay connected and please subscribe for new videos :)
Sir very nice, need more new sums.....in each chapters....humble request
who so ever is coming across the video don't leave it because it's of 1hr 10 min i completely assure you that it will help you a lot thank you for the knowledge 🤗
Thanks for assuring other viewers, Hritika. Appreciate it :)
I appreciate d hardwork u hv put in this video to make d concept clear ..thankuuu sooo much ❤ it helps me a lot lot lot lot plz one request can u plz teach English grammar..i doo silly mistake & go wrong with that plz think about this
Excellent videos, thank u soo much for these videos. it's really helpfull🙏🙏🙏
Thank you sir these videos are very helpful and you explanation is very good !!
But i have a doubt in question 11. I can be wrong so please correct me. When you put the value of x=4 in the equation they are not equal to zero. It would be correct if the equation was (x^2)-8x+16 instead of (x^2)-8x+15. And again thank you for your efforts.
K= 15/4
No need to equate.. simply put x=4 in x^2-kx-1
But when we put 'x=4' in two equations ,
we get '-1' in both the equations
-1=-1 .
To find 'k' we equate both the equations that means both the equations has same value.
So, i think for that question equation
answers should be equal instead of equations equal to '0'.
But hcf is also a factor.. so it should divide perfectly.. i.e. remainder = 0 ,, so why equate
@@karansiriya7796
Yes
Actually ( X-4) is not HCF to those equations..
But in the question they given
If (X-4) is HCF to those equations then what is K value?...
So when we put X= 4 in the both
equations they must get satisfied..
That means when X=4 both equations get equal value.
So putting X=4 in both equations
by equating we get K=4
According to question we have to find K value and they asked if X-4 is HCF then what is K value..
Ohh.. ok.. I got it.. just a little mistake in video.. "equations = 0" ,, instead directly equate..
Thanks 👍
It was a nice video but Question 2: LCM is 1350 (75,150,135).
Yes, Bcoz here by mistake he took 29 in place of 27. i.e. 135/5= 27.
Thiyagu yes u r correct
Yes sir it's not 29
Yes
Yess ua crct
Awesome session, absolutely satisfying.
Thanks a lot sir your voice is magic and easily understand
Thank you sirrr
Please sir will you make number on system videos also it's my request
The explaination is really wonderful. Me just want a few things. It is not a must to find HCF when greatest is mention. We have to check whether it is written "divided by" or "divides" in the question alongwith. For example, in a question like" find the greatest no of 3 digit which when divided by 6, 9, 12 leaves 3 as remainder in each case". Here we have find the LCM of the nos. and then carry on the other steps as required. Actually I derive it after practicing few problems of HCF and LCM.
But in all the qs discussed, where greatest no was mentioned wether along with divided or divides - HCF WAS USED....CAN U EXPLAIN...
When will we use lcm when greatest no is mentioned...i don't understand
@CareerRide sir can u plz explain
@@Agl_Mansha789 Yes although Greatest was mentioned but it's asking to find the dividend as divisiors are given.
GCD will find the factor of divisor itself which will be wrong so we find LCM then add the remainder
@@Agl_Mansha789 So say simply if question says to find:-
Divisor (Divides) - GCD/HCF
Dividend (Divide by) - LCM
your complete session is just wonderful....
Excellent explanation.. Sir thank you so much..
Such an amazing explanation by u sir.....got it like that I'll never forget it ....thanks for ur efforts for us....👌👌
Thank you sir ! Thank you so much for teaching. Now I placed CTS company with the help of your videos and your teaching. Great job sir.
That's a fantastic news, Arun. Congratulations. Thank you for coming back and letting us know. All the best. :)
Sir, your way of teaching is superb.
Superb, thank so much sir, it's very useful 😍🥰😘
Clarrified my doubt how to decide whether LCM or HCF
Thank you sir
I studied this video for more than 2 weeks sir. You are so awesome sir. Thank you sir and CARRER RIDE for updating this. Thankyou...
Most welcome :).
Do take the advantage of our interview videos as well.
@@CareerRideOfficial Surely
Great hardwork.Thank you sir
thank u sir...... such a explanation....
Sir Q(11) is wrong . (x-4 ) is not the factor of (x2-8x+15) . so, (x-4) can't be HCF of both equations . Hope you correct it Sir.
Exactly
Is here the question wrong only or the method and concept are also wrong?
@@OvishaSanyal The methodology is correct, but the question is wrong.
your communication skill is too good.....
Beautifully explained.❤️
Ooo God.......atleast at the end someone came up with best explanatory vedio.....😊 thanks ...
At 36:35
least number to find...
The differance is same value can be subtracted
The differance is different what should be do
Definitely ur hardwork is appreciable but there is an error in question 3 solution....Please have a look
thank you so much...explanation was crisp and clear
Thankyou very much sir.
Super sir, very helpful
finally, I choose the best platform to learn aptitude...Thank you for the best content
You're welcome :)
U r the best Teacher ... Thanks for making this video
Literally this is a nyc video and full of information.... nyc playlist (most wanted)
In question 12 we will add 1 to the answer so it will become 5 cuz we also count the bell which rang just before .
Question says....from the moment they start...not the moment they rang together
Well this is correct
Very helpful. Respect from Pakistan
India always helps u...
It supports me alot to prepare fir campus, tq so much sir making it..keep on doing like this
Yo're welcome, Harshita! Stay connected :)
It's a extraordinary explanation sir,Very easy to understand
It is a bit clumsy. But very excellent
explanation and very important problems selected
11th question:if both the equations are equal to 0,why can't we substitute X=4 directly in eq 2
The equations are not equal to 0. Both the equations will be equal to each other if 4 is substituted in them.
@@kowshikatmakuri4193 why??
I think question is wrong because if we divide x^2 - 8x + 15 by x - 4
It is not completely divisible so it is not the factor there must be mistake in equations
Bro you literally cleared my concepts thnks alot
Thanks sir u r explanation made us confident in hcf and lcm...... I always follow your channel for my studies
It's my pleasure.Stay connected :)
For Q3, if you consider a=bq+r, then you have 17=bq1+4, 42=bq2+3, and 93=bq3+15. Clearly, bq1=13. Since 13 is a prime number, q1 must be 1. But b is also the HFC, so the answer is 13.
But 93%13=2.
In the question, it's 15 (which is again 13+2). So I am a bit confused if the question is correct or not.
Pls explain 93 divided by 13 leaves reminder 15.🤔
Check out at minute 29:51.
Yeah when 93 divided by 13 we get reaminder as 2 not 15
93/13 reminder 15
if u think that way you won't be able to solve these questions..because to leave remainder 15 a number must be greater than 15..and less than than 17...because first number is 17..so only 16 but that will leave remainder as 1 which is not asked in question....so his answer is correct....
Thank you so much sir.....👏👏👏
Thank you for your great work sir
39:33 how came answer would be 1461...
When 1461 is divided by 12 the answer will be quotient 121 and reminder be 9
If u take one less ,i.e add 12 to 9 then it will be 21... How else a no. Like 12 can leave remainder 21??
Please make classes on Data interpretation and sufficiency
+1
Nicely explain.... Thanks 🙏 so much , it help me to clear all my doubts..
Thank you for this video 😊
Excellent. Mind blowing sir. Really very interesting video.. all types coverd in easy method.. ♥️♥️🎉🎉🎉.. even paid channel will not give this type explanation
You're welcome! :)
How can be the remainder of 13 be greater than 13...in the 3rd question the remainder should be 2 i.e. 13 * 7 = 91
93 = 13 * 7 + 2
yes
Thank u sir for the excellent explanation of lcm and hcf . got to know the east method to solve for the inertance
I solemnly appreciate your efforts sir. Very helpful honestly!
Divisibility
Inverse
Geometry, Coordinate Geometry
Clocks & Calendar
Logarithms
Algebra
pls make video on above quant topics as these also come for campus placement aptitude tests
i.) Calendar Video: ruclips.net/video/oxc4G14nyUY/видео.html
ii.) Clocks: ruclips.net/video/edEvlh0tqzk/видео.html
iii.) Logarithms: ruclips.net/video/w-7mbazOx6o/видео.html
Sir
In 11th question , I can't understand how k is become 4.
Will you please explain it.
Yes, even I too have the same doubt
If (x-4)=0 then x=4
Equate both the equations
then substitute'x= 4' in those equations then we get
16-32+15=16-4k-1
-1=15-4k
4k=15+1
4k=16
K=16/4
'K=4'.
Even i have the same doubt, x=4 doesn't give 0 in first equation
Superb sir
Good effort
Thanks for vdo
Tqs for ur lovely teachings sir