+Erfanullah Mazloom Thanks very much. I'm pleased that they are clear enough for you to understand. This titration could easily be difficult to get your head around. Please spread the word! 🙂
This was soo helpful! I didn't get a thing before of why each step was happening and what was the purpose preventing me from doing the questions. But you explained and presented it so well! Amazing!!
+Mel tansz Cool! yes this is a complex titration. So much going on, I did wonder how to structure it so it could be understood. I am pleased it is clear enough, I really don't know until I get feedback like yours so thank you!
100% sure when other students watch it it'll automatically make sense! Compared to books where everything is so overwhelming this was a great visual aid and beautifully explained. Thanks again :)
Hello, before I begin your videos are amazing. Have you made any videos about analysis of brass to find percentage compositions of copper and zinc using a sodium thiosulphate titration? Thanks you.
Heyy thank you so much for these wonderful videos. I just wonder----Why do we need to use this specific method to work out the conc. of oxidizing agent??Can't we just use the one that haven been used to find out the conc. of reducing agent? Have read through the textbook but couldn't find any explanation.
Hi sir. I have a question. I saw a sentence in europe pharmaceutical monogram that is '0.1 N iodine equivalent 4.753 sodium thiosulphate'. How can ı calculate this 4.753. Can u help me please.
Amazingly Explained, but i do have one question regarding more calculations done in this particular redox titration If you had a question whose main aim was to find the metal ion that is attached to the iodate(v) how would one go about said calculation?
The 6.7×10^-4 moles of iodine is in a 3:1 ratio with the oxidizing agent we are trying to find the concentration of (iodine:iodate = 3:1). So to find the moles of the iodate ions you need to divide by 3
Hi! Sorry. I am a little confused when you got moles of iodine to be 6.7x10^-4, and then you related it back to 3I subscript 2. (Around 5:48) Isn't it because there are 3 moles of iodine in the, you should multiply 6.7x10^-4 three times??? And then divide by 3. Sorry I know this isn't correct but can you explain it?
Thank you so much. That was explained Beautifully. I finally understand what is the purpose of this titration. please solve one IAL paper of Edexcel unit 5 and unit 6.
Thank you, this is one of the hardest topics in Edexcel Unit 2 chemistry. One thing in particular, Edexcel in sodium thiosulfate titrations, they're introducing different things, like what they do is, make up a standard solution of 250cm^3 from like 25cm^3 of original solution and then ask us to find concentrations of the oxidising agents etc. Makes it all quite confusing.
+Saadz RS Yes there are a few steps. You just need to be methodical but understand why we are calculating things rather than just working out a load of numbers with no meaning. With regards to calculating conc of original solution you just need to multiply number of moles you have worked out in 25cm3 sample, multiply by 10 to find number of moles in original 250cm3 then divide this by the volume of the solution used to make the 250cm3. It's just like making a big jug of dilute orange juice from a more concentrated juice. You then pour out a sample in a glass to drink! The moles is just like the number of orange juice particles in the water!
saykusmeh bro No problem! Please share these videos to people you know who you think will also benefit too. If you are on twitter follow me @allerytutors to hear about what videos are being made before everyone else.
Thank you so much sir! I'm currently cramming for the autumn 2020 exams and your videos have been life saving!
me but a levels 2022
me but a levels 2023
@@joannadaniel9396 same:((((((((
me but a levels 2024
@@sarahalfarra9076how y feeling for paper 1 on Monday?
I like how concise and clear the video is.Thank you for explaining this to us Sir.
So nice of you
You are very good at explaining chemistry sir !!! I understand this bit of the so well now !!
+Erfanullah Mazloom Thanks very much. I'm pleased that they are clear enough for you to understand. This titration could easily be difficult to get your head around. Please spread the word! 🙂
Best explanation on the Internet for this titration.
THANK YOU VERY MUCH !! Mr.Chris
My A level exams are in week and this channel has been very helpful.
Thanks again !
You're welcome! Good luck with your exams.
ahmed can this be used for ocr?
This was soo helpful! I didn't get a thing before of why each step was happening and what was the purpose preventing me from doing the questions. But you explained and presented it so well! Amazing!!
+Mel tansz Cool! yes this is a complex titration. So much going on, I did wonder how to structure it so it could be understood. I am pleased it is clear enough, I really don't know until I get feedback like yours so thank you!
100% sure when other students watch it it'll automatically make sense! Compared to books where everything is so overwhelming this was a great visual aid and beautifully explained. Thanks again :)
this video explains the whole process clearly, i was confused before but i understand it now , thanks alot for the help !
+Haitham Hamila Brilliant! This can be a tough one to understand, so many things going on so I am pleased that I have explained it clearly enough.
thnx a lot!! i cant express my happiness.this was a very difficult lesson to me which u made very easy!!!
sir had an immaculate shave
lmao, agreed haha
You saved my freaking day. Thanks sir. I have AS Chemistry Exams today and was really puzzled with this subject. Thank you sir for helping me!
No problem. Hope the exam went well for you.
Oh the exams were super easy. Please keep making such videos!
Good good. Yes more uploaded and old ones revamped for September. Thanks for your support!
Anytime sir!
THANKU SO MUCH this video is amazing, so clearly explained, finally understand:))
You're welcome! Please share the vid.
I never understood titration because I found it difficult but this video was amazing, it was really helpful, thank you very much, sir.
I was puzzled with this process of titration but doing that using steps helped a lot.. tnx sir
+selina akhter No problem! 👍
absolutely amazing explanation, God Bless you for being so helpful
Thanks very much!
I know everyone else has said it but great video thanks for making them
You're welcome!
why is there a need to add the oxidising agent at 25cm3?😊
Why do you add the starch when the titration is close to the end point? Why not from the beginning?
YOU'RE SUCH AN AMAZING PERSON, GOD BLESS YOU
Hello, before I begin your videos are amazing. Have you made any videos about analysis of brass to find percentage compositions of copper and zinc using a sodium thiosulphate titration? Thanks you.
Thanks for that! No nothing on % composition of copper I'm afraid!
great informative video.. could you provide me some pdf links for volumetric analysis practical portiions for my thesis ?
Thank you so much! This topic was always hard to understand and I got it immediately with your explanation :)
Sir, you have oficially just saved my Adv H project :)
Thank you a lot for your help. Do we need to know this for AQA??
Have my chemistry paper one mock tomorrow (am in y13), thank you so much this is so helpful :)
This was really helpful! Idk if you’ve already done it but a video on determining iron content would be good :)
Thank you!!!!! Very well structured and explained!!!! Just subscribed!
Thanks for your support! Much appreciated, keep up the hard work!
Why do we add starch after I2 gets pale yellow and why not before?
Heyy thank you so much for these wonderful videos.
I just wonder----Why do we need to use this specific method to work out the conc. of oxidizing agent??Can't we just use the one that haven been used to find out the conc. of reducing agent?
Have read through the textbook but couldn't find any explanation.
Hi sir. I have a question. I saw a sentence in europe pharmaceutical monogram that is '0.1 N iodine equivalent 4.753 sodium thiosulphate'. How can ı calculate this 4.753. Can u help me please.
Awesome explanation, cheers mate
You're welcome!
This basically answer my experiment.. thanks 💚
You're welcome 😊
Your videos have been a massive help, thanks a lot!! :)
Bigman Ketz Brilliant! No problem. Please share my vids with others who you think will help them just as much.😊
why do the iodide ions have to be in excess?
Thank you very much! You literally save my chemistry P3!
Why we need add HCL and distilled water when we do the iodimetry
THANKS A LOT!
It's very common to get a question on this topic on the edexcel unit 3 paper.
Amazingly Explained, but i do have one question regarding more calculations done in this particular redox titration
If you had a question whose main aim was to find the metal ion that is attached to the iodate(v) how would one go about said calculation?
5:45 why do you divide by 3? I thought you'd have to multiply 6.7x10-4mol by 3 because there are 3I2 in the first equation?
The 6.7×10^-4 moles of iodine is in a 3:1 ratio with the oxidizing agent we are trying to find the concentration of (iodine:iodate = 3:1). So to find the moles of the iodate ions you need to divide by 3
Why is an excess of KI added??
Is this section needed for AQA? i noticed copper chemistry wasn't and this isn't in the textbook so i assume not?
+Dakota fireshard Yup this is not in AQA. For Edexcel and OCR as far as I am aware.
A Level Chemistry by Allery Tutors Thankyou :)
Do we have to know the equations for the new chemistry exam? or will they give us this? Thank you!
this is a dumb question but why do you not include potassium or sodium in the equations?
Are you still making OCR B year 2 videos
Vote on now. Vote via twitter twitter.com/allerytutors/status/1258408810714140672?s=20
THANK YOU VERY MUCH! I FINALLY UNDERSTOOD :)
+Theodore Tan You're welcome! Yes this a funny one to get your head round! Good luck with your exams!
would we have to know the equations bc the rest is fairly easy...
Amazingly explained!! Thanks alot!
Glad it was helpful!
what a wonderful explanation, thank you so much!
OMG THANK YOU!my unit 3 exam is on tuesday!Wish me a luck
Hi! Sorry. I am a little confused when you got moles of iodine to be 6.7x10^-4, and then you related it back to 3I subscript 2. (Around 5:48)
Isn't it because there are 3 moles of iodine in the, you should multiply 6.7x10^-4 three times??? And then divide by 3. Sorry I know this isn't correct but can you explain it?
Because 6.7x10^-4 is ONE mole of iodine, and the top equation is THREE moles of iodine
Nevermind. It just sort of intuitively clicked for me. Cheers mate, great video.
No problem! Please share the vid.
Hello,
nice explanation and may i have a video about peroxide value analysis like same existing explanation
Explain the formation of turbidity after equivilance
Can this be used for OCR??
Yes it can be used for OCR
Thank you so much. That was explained Beautifully. I finally understand what is the purpose of this titration.
please solve one IAL paper of Edexcel unit 5 and unit 6.
great video keep up the good work
Thanks very much! I certainly will. Please share, the more people use this channel the better! 😀
Why is it better to use distilled water instead of deioinised water why is distilled water more accurate?
a very similar calculation to this one came up on the OCR paper 1 this year.
very very helpful makes so much sense now!
Glad it helped!
great video mate, well explained;)
Thanks very much!
Hey, amazing video! I have a question, why do you have to add the starch when the solution turns pale yellow? Can't you add it right at the beginning?
Really loved the explanation!!!
You are a saviour! Thank you!!!
Thank you very very much. Truly appreciate this.
thank you for the video! Could you make a video on coulometry titration of Iodine with sodium thiosulfate?
This is so well explained! Thanks so much! :)
this video was extremely helpful thanks alot!
Thank you, this is one of the hardest topics in Edexcel Unit 2 chemistry.
One thing in particular, Edexcel in sodium thiosulfate titrations, they're introducing different things, like what they do is, make up a standard solution of 250cm^3 from like 25cm^3 of original solution and then ask us to find concentrations of the oxidising agents etc. Makes it all quite confusing.
+Saadz RS Yes there are a few steps. You just need to be methodical but understand why we are calculating things rather than just working out a load of numbers with no meaning. With regards to calculating conc of original solution you just need to multiply number of moles you have worked out in 25cm3 sample, multiply by 10 to find number of moles in original 250cm3 then divide this by the volume of the solution used to make the 250cm3. It's just like making a big jug of dilute orange juice from a more concentrated juice. You then pour out a sample in a glass to drink! The moles is just like the number of orange juice particles in the water!
+Allery Chemistry This was crazy lol; jug of orange juice hahaha! Unit 3B day-day-after tomorrow and this video just rescued me! Thank you so much :')
+Sadia Tahsin Yeh. I like orange juice! If the analogy worked then why not! Ha! Good luck with you impeding exams!
You are awesome, thank you Chris Harris!
This helped so much, bless you🙇
Thank you so much :)
No problem 😊
great explanation mate, helps a lot!!
Amazing explaination
Much Appreciated! Great channel
Can You do a video on Reactions Of Halogenoalkanes
+Fahad Imtiaz You are in luck! There is a whole playlist on this. ruclips.net/p/PLX4e2DxFRGQLaYEdVs-5kZbsVyTdILdjG
This was so helpful
+Jordan Tian F Excellent! Please share the vid.
Very Helpful ThankYou Sir
great lesson!
I'd recommend getting a bigger board . All the cramped writing can get someone easily frustrated especially with a topic like this .
Thank you Allery.
thanks a ton!
Brilliant
You are great! Thankyouu
thank you so much!
+MrBobsamosa Not a problem. Please help by spreading the word!
Thank you !
saykusmeh bro No problem! Please share these videos to people you know who you think will also benefit too. If you are on twitter follow me @allerytutors to hear about what videos are being made before everyone else.
Thanks, Sir!
Thank you, that helped!
***** Excellent. Good luck with your revision!
Bro is saving my A levels
amazing vid
thank you
Very helpful
Thank you legend
Thx
This helped sooo much thank you!
Please get a new mic! Thanks
+ARVX Yeh, looking into getting a radio mic now. :-)
bruv stop complaining
theres nothing wrong with this mic
Very bad
Thank you so much!!!
No worries!
@@AlleryChemistry Is this applicable to AQA?
Thank you so much!