Electric Field Due to a Line of Charge - Finite Length - Physics Practice Problems
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- Опубликовано: 27 дек 2024
- This physics video tutorial explains how to calculate the electric field due to a line of charge of finite length. It also explains the concept of linear charge density and how to calculate it using an equation that contains the total charge and length of the rod.. It shows you how to evaluate the definite integrals using calculus techniques such as U-substitution and trigonometric substitution in order to derive the formula to calculate the net electric field along the x axis and along the y-axis. This video contains a few examples and practice problems.
Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
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Every engineering student is being taught singlehandedly by this legend.
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@@Urbanstrangler He was only meant to learn Organic Chemistry but he went further
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50+ hours watching The Organic Chemistry Tutor
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I appreciate your passion for learning but if its for physics than i can't say much, you are one of a kind
Totally commendable
I think it was awesome that you took the time to integrate out the proof instead of providing the solution. Really helped me conceptualize everything better than my professors teachings
school is awful. Only thing I'm doing is paying those bastards for a piece of paper.
@@copperwater8456 school is good for you to have a syllibus or can see better path or target, but not a good place to study / learn
and just like that, enrolling physics 2 this semester in uni isn't regrettable anymore
Yess i took this lecture and i was lost
How did the exams go?
@@domantas973 did great! managed to get an A on Physics II, i also happened to transfer universities. used to do software engineering in my home country now i do mechatronics engineering abroad. Thank you for checking up
@@kasiorap how did u get an A 😩
@@shalinyvaleny2091 learning how the formulas work and how to use them in the situations that they should be applied in is key, also practice makes perfect! good luck in your exams! wish you the best of luck
at 15:39 when you moved the x out in front of the integral, shouldn't it be a 1/x since it was in the denominator?
yeah. i noted the same
He corrected it after that already
I'm confused about this part too😂
Because it is treated as a constant and we are integrating with respect to theta that,s why he moved it out as a constant
the point that was not clear to the whole class of 96 students
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Love understand more in a single day than an entire year of university lectures.
I'm about to give this topic up, then I searched. In my mind, "I'm sure he has a video for this. I'm sure of it." Then I saw your vid. So thank you very much! Great help as alwaysss.
Same with me lol
I started crying lol cuz I can't understand the same topic from my textbook* but he made me understand very easily
*edited some spelling
at 15:36 should you not put 1/x to the front instead of x?
Great video you didn't skip any steps and explained it all ty I was stuck on integration for ever until your video showed me there was trig sub in this problem
This guy is single handedly carrying my grade in 3 of my classes this semester
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Good on you for showing how to solve the integral. My physics professors either said "look it up in an integral table" or they solved it in their head...
I’m so dumb...who the hell thought integration is a good idea
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It is not that you are lunatic or dumb whatever; it is that you are heedless and reckless about why things operate the way they do. 😊
It's simple
@@mohamadsherif701 yet in calculus class, I got 45 out of 100!
Simple indeed!!
so good of an idea they thought it would be good to teach everyone else
at 15:45 wouldn't it be 1/x times the integral and not x times the integral?
Kyungseo Moon replied to Michael Adjei's comment below; he corrects it at 17:45. It is 1/x
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It is really helpful. Especially for our international student. It is very clear and step by step! thank you very much!
Thank you for being able to clearly teach this in English!
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I realised you are on earth at 35:01
The dog.......
I don't know how to thank you enough sir ❤
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Now this is difficult, but giving up is not an option ,especially if you have JG as your tutor.
Am I the only one with a crazy enough prof that wants the proof of the final electric field problem on the answer sheet? why do I even need to memorise proofs in a physics class?
Quick question, at 21:06 , why is 2 in front of k? Isn’t it supposed to be k times 2a(lambda)? Or did I miss something?
At 7:08 how he got the equation for dEx was by understanding that x/r is proportional to dEx/ dE. Therefor:
dEx/dE = x/r
dEx/dE = cos(theta)
dEx = dE (cos(theta))
thank you man - U pinned what i was looking for :)
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I benefeted more and
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The world's best teacher thanks
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Who says physics is still difficult with all this explanation?❤
Yo man, thanks so much for this in depth explanation. Really helped my understanding.
what if the point upon which we want to find the electric field (point b) is not directly in front of the center of the finite rod, but is in front of the start of the rod. How do we find the electric field it there?
Thank God, you are here sir ❤
Very nice, however I am struggling with the situation where the point P in not on the x axis. This means that the charged rod is not centered under P. The y components of E do not cancel and the x components are not symmetrical either. This is a much more difficult calculation and one that I have not seen anyone do. Could you extend this lesson to the more general case of an electric field at some point over any place of a charged line?
Hi, i dont understand why we take derivative? How does it help?
And are calculating the Force the whole rod is pushing to p، ، it just a little part of it?
Please factorizing x out of the integral was suppose to be 1/x not x multiplied by the whole integral please I don't why you multiplied x to the whole integration to get x cos it would been 1/x cos please explain
I guess he corrected x cos to 1/x (cos) at 17:45, he made a mistake
@@kyungseomoon6538 that's right, thank you
Couldn't you place a gouse shape around the rod and use gouse law instead? Like a cylinder for example?
Yes that would work
It's gauss's law
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quick question, at 16:52 when he sub dy and y values in integral, shouldn't his limits also change? why did he not write the limits for integral, x integrate cos(theta) d(theta)
I'm probably too late but his original limits were in terms of y, so no they do not need to change
@@Tommyometer thanks hahaha. i took that mod 2 years ago.
15:38 shouldn't it be 1/x in front of the integration symbol, not x?
Thanks a lot , it's very important chapter and not everyone can explain it, it's challenging.
Thanks brother I used the integral and now derived it for a wire not same length on both the side ....
1000th like from me
Hey can you also take up the case where the point of observation (that is where we are supposed to find out the electric field) is not symmetrically placed , like what happens when the Y-component does not cancel out???
I believe that your comment (more of a question I believe) is very valid. To the best of understanding, the method shown only works for finding the electric field from a distance x from the center of the line charge. The y-components of the electric field for other points do not cancel as you pointed out. More complex integration is needed. In the numerical example near the end of the video, it asks specifically the electric field 80 cm away from the center of the rod.
this is really helpful, thank you!
What if the rod is on the x axis? Would you have to use sin = 2a/r?
at the 9 minute mark, i stopped and realized that this WHOLE half hour video was just to explain ONE single problem and ONE fucking crazy ass integral smgdh
dear brother thank you very much for the work you have done to explain to us clearly j aime tes video
God bless you for this explanation
This is great! Could you please do one for a point that's not at the center?
That would be stupidly difficult homie leave that to the computers to compute
ik this comment is 3 years old and ur probably already an engineer that does this for breakfast, but in the video he explains how you can find Ex and Ey for a point not in the center using integration and then you can take the vector sum to find the field intensity vector
I know nowt so found this very informative, many thanks.
when sheet of charge is finite along z-direction from -z1 to +z1 and infinite along y-direction.find electric field intensity when we take point on x-axis??
in 13:30, the derivative of y on the left hand side should be dy/dt but we just wrote it as the differential of y, dy. And then replaced it aswell in the integration. Am i missing something?
pretty sure it's dy = xsec^2(θ) dθ (with respect to θ) , not just dy.
Do you have a video of distribution of charges: electric field and electric potential?
I had a similar question but the line of charge was a dipole, how would i got about solving?
physics vol 2 halliday resnick krane, that book right? phuck it big time xd
@@mentor1324 haha straight up
My professor never mentioned that point P next to the the middle of the line, so It was hard for me to get why Ey is 0
i like this explanation especially on integration part
Is the linear charge density symbol the same as that of lambda?
very important formula to calculate electric field on a distance to calculate electromagnetic wave which is an antenna communication
this is really awesome
Dude. Thanks.
Thank you so much!
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In the final integral (19:00) it should actually be x^2 on the bottom
Thanks a lot mr!
Can't this be simplified by using a cylinder as A, and using EA=q/epsilon(0)?
I think so but you are required to learn the prehistoric method by teachers.
Yeah a gaussian cylinder would be way easier, but most professors teach this before getting into Gaussian stuff
Thank you once again.
(15:42) There is a mistake when solving for the integration..... you can't take out x but have to take out 1/x
yes and he fixed the mistake in 17:44
The video is great but, if you imagine E in y component is 0 only in case of equatorial line
is this video in a playlist??
can anyone help me where did he get K=9 x 10^9?? im a bit lost
15:43 I think you made a mistake, it's supposed to be 1/x , not x
You are awesome. Thanks!
Thanks a lot.
It really helped me to understand the topic :)
thank you so much bro
now do one with point P at the end and above some y distance of the rod(which lies on x axis)
When he solved the definite integral, wasn’t he supposed to also change the limits of the integral?
no cause he went from terms of x/y to terms of u and back to terms of x/y so you don't need to. If you keep it in terms of u then yes
Thank you 😊🤲🏽
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The Organic Chemistry Tutor thank you so much man you're the best
Can someone explain to me why did he use trigonometry suddenly? Im so confused by that!
look up trig substitution, its a technique for solving integrals
THANK YOU
I think you got your Q wrong in the last problem. Off by a magnitude of power. I got 1.26E(-8)
well explained
How can I improve my integration ???
Mr Ellipse watch professor leonards videos
I concur about Professor Leonards videos. He’s an awesome teacher!
What is a segmat give me definition I didn't understand
tks very much
thankyou so much
Damn that integration was the one of the hardest so far or I forgot idk
Thank you sir...
this is a dumb question but where does the 2a come from?
the length of the rod was defined as a to -a with the middle as the origin between them. When the integration was done, the a and -a were bounds in the integral, so when doing the upper bound - bottom bound, we do a - -a = 2a
Annu Shankar thank you so much!!
Exam saver.
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thanks king
may allah bless your mind
sec= 1/ cos ?
Yep.... Reciprocal of cosine is secant or vice versa
Thank you!!!!!!!!!
ps: this is the 100th comment.
is it just me or is the volume on this video via laptop insanely hard to hear...
These topics are starting to get complex
You're not going to need to do this in class he's just showing the derivation.