Once you said it took you a while to get this, i knew i was at the right place. Cos people like you know how to explain it in the simplest of terms since you have been in our position before. Thank you. DOn't stop what your're doing
If the ring is perfectly conducting/metallic then yes it will have uniform charge distribution regardless of how we charged it. Unfortunately I couldn’t find any videos showing field due to a ring irl.
Hello friend, the video is very good, but I have a question with a similar exercise: I need to find the electric field at a known midpoint of 2 charged circular loops like the ones in the video (each with a different charge, both positive). I have to apply the formula that you show in the video for each of the circular loops, and then my question is: Should I add or subtract each of the results to obtain the electric field at that point? (taking into account that both charges are positive). Thank you so much
Which type of gussian surface we will take in order to find E field due to a hollow capsule like object which have both hemisphere and cylindrical symmetry?
i have an exam tomorrow, please help!! how come in the first problem you integrated with respect to Q? when doing the same problem but with a vertical rod instead of a ring, i integrated with respect to y using lambda = Q/Y dQ = lambda * dY and plugging that in for q, which is how i was taught. because, they say, Q is not a geometric quantity. why did you integrate with dQ? how do i know when to integrate with respect to Q or Y? does the ring not still have a charge density lambda = Q/(2piR)?
Once you said it took you a while to get this, i knew i was at the right place. Cos people like you know how to explain it in the simplest of terms since you have been in our position before. Thank you. DOn't stop what your're doing
sir you ended my nightmare about these topics. Best of luck for you and your family in the New Year 🎁🎀🎄🎄
I liked how well this was explained I just started learning about this and it helps a lot.
Thank you!
omg these saved my life please keep making videos like this thank you so much
Will do!
Absolutely fantastic teaching
Omg, the best explanation i had see so far!
Thank you so much, this was such a saver. Keep on coming more content!
i was your 420th like, youre welcome....
also thank yoooou, these vids are the bees earlobes
Would the total charge Q be the area of the disk, if so why would it be the area & not the volume?
5:01, Why can we assume angle theta will be the same for any dq on the ring? If dq was to be exactly on the x axis, wouldn't theta be 0?
So if you have a semi circle? I ended up integrating with respect to sin theta since dq would change as theta increases
Are there any experiments video showing electric field due to ring? And is the ring always going to get uniformly charged if we try to charge it
If the ring is perfectly conducting/metallic then yes it will have uniform charge distribution regardless of how we charged it. Unfortunately I couldn’t find any videos showing field due to a ring irl.
How did you modify the new limits?, any video or explanation on that.
Doesn't x change depending on the distance of the point we're choosing to calculate the electric filed for?
Hello friend, the video is very good, but I have a question with a similar exercise:
I need to find the electric field at a known midpoint of 2 charged circular loops like the ones in the video (each with a different charge, both positive).
I have to apply the formula that you show in the video for each of the circular loops, and then my question is:
Should I add or subtract each of the results to obtain the electric field at that point? (taking into account that both charges are positive). Thank you so much
Which type of gussian surface we will take in order to find E field due to a hollow capsule like object which have both hemisphere and cylindrical symmetry?
you the goat meehn! new fan
Thank you!
Thank you sir
i have an exam tomorrow, please help!!
how come in the first problem you integrated with respect to Q? when doing the same problem but with a vertical rod instead of a ring, i integrated with respect to y using
lambda = Q/Y
dQ = lambda * dY
and plugging that in for q, which is how i was taught. because, they say, Q is not a geometric quantity. why did you integrate with dQ? how do i know when to integrate with respect to Q or Y? does the ring not still have a charge density lambda = Q/(2piR)?
why is your point source formula kQ/r^2 instead of kQ/r? I have conflicting info in my notes from class
Kq/r2 is electric field and kq/r is electrical potential, not the same
Is it possible find that Electric Field using the electric field of a line?
the ring is finite, but for calculate the electric field of a finite line we have to use the gauss law
Had a bad day due to this topic evicirating me in a quiz
Amazing!
thank u!!
what a legend
Thanks man
Wow
huh.
Thank you so much, this was such a saver. Keep on coming more content!
Glad it helped!