Electric Field at the Center of a Square

Physics Ninja looks at a problem of calculating the electric field at the center
of a square. Point charges are placed at the 4 corners of the square the field from each charge is considered. The total electric field is the vector sum of the 4 fields.

[@user-mn8re8jp7v]

Please make more videos…Interest is growing and your explanations are really good!…Thank you! 🇺🇦🇨🇦

[@hooberdoober576]

Yep. Brings back memories. E&M at engineering school.. 1980. GO Univ. Alaska, Fairbanks|

[@sanskarbhusal1924]

Cleared my confusion. Thanks.

[@Chisti-vb8cr]

You helped me a lot in applied physics respect from Pakistan ❤

[@PhysicsNinja]

Happy to help

[@mywigdissolved7458]

thank u ! rly clean to look at and very understandable !

[@almulshivam]

Good evening Sir
Could you please upload the video of Electric Field and Electric Field Intensity?
Topic: Dielectric and Relative permittivity

[@AamrithaSR-ng4wq]

One doubt.... answer please.....
q3 is negative 5 and q2 is negative 5 .,then what is the direction of force on q2 due to q3 ?

[@hussamoulan2260]

Thanks sir and love from Pakistan 🇵🇰

[@mariamziad9379]

very helpful. thanks

[@manahelh.6104]

hello I have a suggestion that might make it more simple without having to use cos or x and y component. You could apply pythagorean theorum on one of the triangles of this square. In that way you don' t have to devide the length in 2 and wouldn't have to use a 45 degree angle or cos.

[@mossaffashahzad6312]

Just brilliant man

[@thatboyss5576]

I thought we use sin to find y-components ?

[@theultimatecoder3433]

Ye

[@olwethuzihlwele3741]

exactly my question

[@kurt4557]

im so cooked ;/

[@GloryMboya-g7g]

Plz there in total electric field more explaination

[@emonmollah9461]

Good work ☺️👍

[@zewditukergo7951]

Good video from pakistan❤

[@marcopaddanan7522]

correction for formula k= 9x10^9 N m^2/C^2

[@bereketyohanis9020]

thank you

[@fizixx]

Nice!

[@JilariousJamesGaming]

Bloody legend!

[@pheonix2710]

those who r preparing for jee 🌚🌝sees this question in exam