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thank you very much 🎉
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5^x=20x=log20/log5=1+log4/log5=1+2log2/log5
x=log20/log5=(log5+2log2)/log5=1+2log2/log5x≈1+(2×0.301)/0.699≈1301/699≈1.861Deviation is about 0.00013×5^(1301/699)≈59.99
Samash, what do you intent to show by your solution and the deviation of 0.0001. Having even a deviation of 0.00000001 doesn’t equate to 60 = 60. Please do come again, thanks
5^x=20log 5^x=log20x log5 =log(5×2^2)x=(log5+log2^2)//log5x=1+2 log5(2)
✌️
5×=20×=4Լագոնիկ ոճ
😁
thank you very much 🎉
You're welcome 😊
5^x=20
x=log20/log5
=1+log4/log5
=1+2log2/log5
x=log20/log5=(log5+2log2)/log5=1+2log2/log5
x≈1+(2×0.301)/0.699≈1301/699≈1.861
Deviation is about 0.0001
3×5^(1301/699)≈59.99
Samash, what do you intent to show by your solution and the deviation of 0.0001. Having even a deviation of 0.00000001 doesn’t equate to 60 = 60. Please do come again, thanks
5^x=20
log 5^x=log20
x log5 =log(5×2^2)
x=(log5+log2^2)/
/log5
x=1+2 log5(2)
✌️
5×=20
×=4Լագոնիկ ոճ
😁