My sincere congrats for the detailed explanation on the motor selection; it's reassuring to find that there still are some decent material not solely based on unbiased simplifications! I have a question tough, would you mind helping me out if possible? If the conevyor belt is designed to be pre-tensioned and mounted on top of rollers, in order for an object to move, there must be no slipping between the roller and the belt, right? Hence, the friction is the force pushing the objects forward on the belt and is not a resisting force, meaning there is no pulling force, likewise you mentioned at 11:02. In that case, the only torque is due to the inertia, correct? Does that mean that, when the object has achieved its final velocity, all power given by the motor is spent by friction on bearing, gears and others? Thanks in advance for the video, have a nice day!
Thanks Joao Garcia, Lets discus! Point 1: There must be no slipping between the roller and belt, right? - Yes, it would be better if it is not slippery, but practically zero slip is not possible as you know. Point 2: Friction pushing the object forward on the belt and is not a resisting force- Yes absolutely right. Your last point, all power given by the motor is spend by friction on bearing, gears and other after reaching final velocity- This is complicate, yes this is 100% true that motor required torque will decrease after reaching final velocity means at zero acceleration. but as we are moving a belt, so there will be always a belt rolling friction, (thick belt means more rolling fiction), also there is not only roller MOI, but there is also transferring object and belt itself MOI which always being influce by gravity, as you said, motor is spending by friction on bearing, gears and others, so this term other is going to always much larger as compare to bearing friction.
@@mastermechanicaldesign Thanks for the response, it makes sense: wile it's true there must be no slip and hence the friction is not a dissipative force at first, it's hard to guarantee no slip, which is hence the dissapative force when the final velocity is achieved. Therefore, while it's not correct stating there is not dissipative friction, it's also not correct stating the pulling dissipative force is F_pull = (load_weight) * friction_coef. , right? Unless we consider "friction_coef." beign much smaller than the actual kinematic friction coefficient. For rxample, rather than adopting 0.2, we take 0,05. Do you thing that's a reasonable approach? The losses in bearings, gears and other I'll consider by using their efficiencies as 99% or 98%, for example. Once more, thanks for the responses, for the video and for the commitment on the subject!
Let's think in this way, 1. To move the belt, a strong frictional grip between rollers and belt is required, stronger the frictional griper of roller will give better will be result in terms of slip resistance, (So, sometimes we do knurl over rollers surface for better grip) in other word, frictional force between roller and belt should be more than frictional force of belt with conveyor's other parts (belt bottom support) with the load over belt. means, Friction force between roller and belt (depends on amount of belt tension, roller contact arc with belt and static co-efficient for friction between rollers and belt) should be grater then frictional force of belt (loaded with material) and belt support plate, 2. At starting frictional force of belt (loaded with material) and belt support plate will be high, and once belt start moving static co-efficient of frication will decrease to kinematic co-efficient friction. 3. Now, motor capacity should be cable to accelerate the belt from its static friction because we started the motor at zero velocity. 4. Friction between roller and belt is different than friction between belt support and belt, our aim should be increasing the friction between roller and belt for no slip. whereas our aim should be drecrece the friction between belt and belt suport, for easy pulling the belt, 5. Now, bearing friction is something that we should not consider in any calculation, you can consider as zero friction (in general) 6. So, for motor selection, these are following load you should consider. A. Frictional pull force between belt with load and belt support, B. Belt rolling friction (or you can say belt rolling resistance or belt drag over the rollers) -Which is actually difficult to calculate. C. MOI of all the rollers, gear box, motor and the load over the belt.
@@mastermechanicaldesign Awesome! It makes sense for me now. I don’t know how to thank you enough for the time and response! Once more, congrats for the content and commitment! You’ve got a subscriber for sure :)
You mention the 2nd method is better because it can calculate situations when there is no belt support and so no friction, but the first step at 14:26 you use the pulling force 1614.7N calculated using friction in the step before. How would you calculate this pull force if there was no belt support?
Thank you 😊😊 Mainly Pulling force for motor, will increase, Cosine component of frictional force (Vector physics) will be added in total pulling force. 👍 I will make detail video on include conveyor calculation also, very soon.
At 7:26 how the pull force value calculated..? (Pull Force = 1614.7Newton as per your calculation in video) Total Mass is 411.5kg, g = 9.81m/sec sq. COF is 0.2 Pull force = COF x Total Mass x Gravity Constant >> 0.2x411.5x9.81 ==>> 807.363. (according to my calculation) Please correct me if i am missing something.
Same doubt bro.....Got any solution for this??? Also at 15:35 MOI for 2 rollers = 0.25x15x(0.0225)^2x2 = 0.0038 kg/m^2 might come, but I guess wrongly mentioned as 0.0018 kg/m^2....Correct me also....I am also having the doubts.......
I would clarify the no friction part. I think what you were saying was the first part was the load to move the belt and load at constant speed then the second part was to start the belt from rest to the set speed which would require the diameter of the rollers. Is this correct?
Yes that's what I'm trying to say.. when we will start the conveyor from rest. An extra torque will be required to move the belt because of MOI of everything.
1. Gearbox power loss - consider gearbox efficiency 90% for helical worm gearboxes 2. FOS for MOI- If you are considering every component MOI (belt, load, rollers) then you don't need to consider any extra FOS.
Very good and informative videos bro ... thankyou.. i need one clarification, how do select dia of the roller? Is there any standards? And torque based on MOI is it finding for all the drives?..
There is no such standard, but yes roller diameter should be sufficient to roll the belt properly. Means if we take a thick belt then we should consider a large diameter. Also we should try to keep the roller diameter minimum to reduce the MOI Third yes strength but it depends on length and tension on the roller (no significant concern)
Offcourse considering MOI will give you close value. But if the application is light, rollers are small, then its okay to ignore MOI calculation, just consider significant SOF, but not too much. Its also a problem (deeply explained in video)
appreciate for immediate reply I think for a long conveyor, the number of roller will high that mean total MOI also High and the equation will give the high value of power
Please make a video of shaft deaign, and also give the information about allowable shear tensile streess and strength and allowable bending moment and fatigue failure and what will be the safe value from protecting above point
According to me, diameter of roller should be according to belt thickness and belt material, like allowable minimum bending radius of belt top of that we should keep the roller diameter minimum just to keep MOI of rollers minimum also to save cost
@@mastermechanicaldesign it depends on the length of the belt too? for example I am designing a 10 meters belt with the same material you used in the video, how much diameter do you recommend to use for the roller?
Sir... In moment of inertia method, to find moment of inertia torque for gearbox and motor, you selected the values related to 1hp motor and 10:1 ratio gearbox from datasheet. But how you choose the motor power and gearbox ratio before calculating it. Please explain that part.
The first basics of roller selection should be strength Second is space (how much space available height wise) Third is bigger rollers diameter means - High belt speed. So you can choose accordingly by reverse calculation.
sir, how did you select MOI for gearbox from catalogue? its not clear. and also when selscting a motor, why did you select from "4P 1500min-1" catagory?
Really I got nice knowledge about the selection of motor and gearbox, thank you so much........ Still having some doubts from this video @ 16:03 MOI of an object in linear motion is 0.208 Kgm^2.....But actual calculation as per the mentioned formula 20.165 Kgm^2 coming.....Correct me If I am wrong........
This is actually a range (a rough estimation) because acceleration depends on how much the initial load is over the motor. I have taken this from a research paper from ABB laboratory
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor
HI, Its very simple, 1. power consummation is equal to your conveyor motor required power. 2. 1 unit electricity is equal to 1 kW per hour. Let say your conveyor required motor power is 2 kW. Means your electricity consumption is 2 kW per hour means 2 Unit. -- for motor power calculation, refer formula of this video.
Sir thank you so much i am always wanted to become a machine designer your video help me a lot. Regarding conveyor belt design you talk about MOI OF ROLLER . But if anyone used troughed idlers instead of instead of flat idlers then how i found his moment of inertia of in
I'm so glad 😊 Trough rolls - as these are also rollers but at an angle. So we can also calculate the MOI same as roller. Don't need to be too exact. Just consider approximations at higher side.
Not exactly. But i would say whatever I have explained is pure physics, like power formula, speed, MOI etc. Plus for data reference i have given is from manufacturers catalogue. Which you can verify. However if you need specific parts validation, then i can provide. In terms of formula.
@ 7:29 when you are calculating Force You have written 411.5 X 9.81x0.2 which equals to 807 only how you got 1614.7 as answer please reply @mastermechanicaldesign
hi sir, in the 20:26 second final velocity u gave 146.5 mm/sec but u didnt mentioned how it came there can u please explain it to me, Thanks for sharing the great video as usual awesome great content
Let me first finish this bearing calculation series. Also i have used a powered roller only once in my experience. So it will take some time to research. I hope you understand me.
1)If I have flat belt conveyor with drive pulley and driven but both are different diameter then belt speed is change or not 2)same question for timing belt
Belt speed will always depend on driver pulley. If both pulleys are the same dia. Both will rotate at the same speed. If driven pulleys is smaller, will run faster. If driven pulleys bigger, will run slower. Belt speed will be same.
@@mastermechanicaldesign 1. For flat belt is same belt speed if we change diameter 2 but belt speed changes in timing belt if both pulley teeth are different
Can you make a video to design a motorised trolley which is moving on wheel and rail track, with loading capacity of 40 ton. For given speed 20m/min, calculate gearbox, wheel dia, motor power, ?
Sir ek question hai for example if customer need 100 part in one minute at the end of conveyor then what should be belt speed...means how we will calculate belt speed???
Hi Praveen very interesting question ❓ Here belt speed will also depend on part length. And gap between each parts Let say part length is 100 mm at a gap of 50 mm. Mean conveyor belt should travel 150 mm for one part delivery. And as given 100 part per minute. Mean 100x150 mm per minute 15000 mm per minute, 15 meter per minute. Please let me know if I'm making mistake in calculation 😅
Thanks for giving calculations for Conveyor Belt Power.. I want to suggest that kindly make a video about Selection of Power Transmission Belt Drive or No. of belt.. in which Counter pulley System.
No. Load will remain over the belt. Conveyor without belt support - Yes for short distance and light weight material transfer like plastic parts we don't give support below the belt. But this is not the main purpose of this video with this example I just want to say. If you don't support the belt then it doesn't mean that required torque will become zero. There will be a MOI of rollers and other items. "Watch the entire video otherwise you will be confused, I'm not confused"
Good information and much appreciated your efforts but kindly recheck the considerations for calculations as they seem little offset from actuals, as there is no much difference for the motor KW but when it comes to judge what can be done with other parameters to decide some intermittent operations that you get across while introducing other process based on selecting rpm’s and force flow process, might mislead to wrong assumptions though. All the way nicely explained
Hi Bharathrm, Thank you so much. yes, there is little calculations typing errors with example. But concept and formulas are right. Just bear with me. mistyping will eliminate completely with time. trying to build a cross check community.
Calculations concept will be exactly the same, Just include the force cosine component as per conveyor gradient angle, (Like in sliding Friction, MOI of belt and load)
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
My sincere congrats for the detailed explanation on the motor selection; it's reassuring to find that there still are some decent material not solely based on unbiased simplifications! I have a question tough, would you mind helping me out if possible?
If the conevyor belt is designed to be pre-tensioned and mounted on top of rollers, in order for an object to move, there must be no slipping between the roller and the belt, right? Hence, the friction is the force pushing the objects forward on the belt and is not a resisting force, meaning there is no pulling force, likewise you mentioned at 11:02. In that case, the only torque is due to the inertia, correct? Does that mean that, when the object has achieved its final velocity, all power given by the motor is spent by friction on bearing, gears and others? Thanks in advance for the video, have a nice day!
Thanks Joao Garcia, Lets discus!
Point 1: There must be no slipping between the roller and belt, right? - Yes, it would be better if it is not slippery, but practically zero slip is not possible as you know.
Point 2: Friction pushing the object forward on the belt and is not a resisting force- Yes absolutely right.
Your last point, all power given by the motor is spend by friction on bearing, gears and other after reaching final velocity- This is complicate, yes this is 100% true that motor required torque will decrease after reaching final velocity means at zero acceleration. but as we are moving a belt, so there will be always a belt rolling friction, (thick belt means more rolling fiction), also there is not only roller MOI, but there is also transferring object and belt itself MOI which always being influce by gravity, as you said, motor is spending by friction on bearing, gears and others, so this term other is going to always much larger as compare to bearing friction.
@@mastermechanicaldesign Thanks for the response, it makes sense: wile it's true there must be no slip and hence the friction is not a dissipative force at first, it's hard to guarantee no slip, which is hence the dissapative force when the final velocity is achieved.
Therefore, while it's not correct stating there is not dissipative friction, it's also not correct stating the pulling dissipative force is F_pull = (load_weight) * friction_coef. , right? Unless we consider "friction_coef." beign much smaller than the actual kinematic friction coefficient. For rxample, rather than adopting 0.2, we take 0,05. Do you thing that's a reasonable approach?
The losses in bearings, gears and other I'll consider by using their efficiencies as 99% or 98%, for example.
Once more, thanks for the responses, for the video and for the commitment on the subject!
Let's think in this way,
1. To move the belt, a strong frictional grip between rollers and belt is required, stronger the frictional griper of roller will give better will be result in terms of slip resistance,
(So, sometimes we do knurl over rollers surface for better grip)
in other word, frictional force between roller and belt should be more than frictional force of belt with conveyor's other parts (belt bottom support) with the load over belt.
means,
Friction force between roller and belt (depends on amount of belt tension, roller contact arc with belt and static co-efficient for friction between rollers and belt) should be grater then frictional force of belt (loaded with material) and belt support plate,
2. At starting frictional force of belt (loaded with material) and belt support plate will be high, and once belt start moving static co-efficient of frication will decrease to kinematic co-efficient friction.
3. Now, motor capacity should be cable to accelerate the belt from its static friction because we started the motor at zero velocity.
4. Friction between roller and belt is different than friction between belt support and belt, our aim should be increasing the friction between roller and belt for no slip. whereas our aim should be drecrece the friction between belt and belt suport, for easy pulling the belt,
5. Now, bearing friction is something that we should not consider in any calculation, you can consider as zero friction (in general)
6. So, for motor selection, these are following load you should consider.
A. Frictional pull force between belt with load and belt support,
B. Belt rolling friction (or you can say belt rolling resistance or belt drag over the rollers) -Which is actually difficult to calculate.
C. MOI of all the rollers, gear box, motor and the load over the belt.
@@mastermechanicaldesign Awesome! It makes sense for me now. I don’t know how to thank you enough for the time and response!
Once more, congrats for the content and commitment! You’ve got a subscriber for sure :)
This is a very good video for the conveyor design, we need more video like this, thanks sir
You mention the 2nd method is better because it can calculate situations when there is no belt support and so no friction, but the first step at 14:26 you use the pulling force 1614.7N calculated using friction in the step before. How would you calculate this pull force if there was no belt support?
Well Done Sir,
As An Engineer I can say that your Channel will help most of Person who belongs to Machine Design field 👍
I'm so glad 😊
Its a great explanation sir but i have a dout in calculation
0.2*9.8*411.5 = 806.4
how do you get 1614
Dear sir,
Very very classical tutorial...
Thank you so much rahul 😊
u r a good engineer as wel teacher.
Thank you so much
Excellent tutorial, created a spreadsheet from this for future conveyor designs. What additional do we add if the conveyor is inclined?
Thank you 😊😊
Mainly Pulling force for motor, will increase, Cosine component of frictional force (Vector physics) will be added in total pulling force. 👍 I will make detail video on include conveyor calculation also, very soon.
At 7:26 how the pull force value calculated..? (Pull Force = 1614.7Newton as per your calculation in video)
Total Mass is 411.5kg, g = 9.81m/sec sq. COF is 0.2
Pull force = COF x Total Mass x Gravity Constant >> 0.2x411.5x9.81 ==>> 807.363. (according to my calculation)
Please correct me if i am missing something.
Same doubt bro.....Got any solution for this??? Also at 15:35 MOI for 2 rollers = 0.25x15x(0.0225)^2x2 = 0.0038 kg/m^2 might come, but I guess wrongly mentioned as 0.0018 kg/m^2....Correct me also....I am also having the doubts.......
@@selvasenthil1997 Yes. Method is OK just correct the calculations.
This is the best video i have seen on the subject. Very well explained. Thank you.
I would clarify the no friction part. I think what you were saying was the first part was the load to move the belt and load at constant speed then the second part was to start the belt from rest to the set speed which would require the diameter of the rollers. Is this correct?
Yes that's what I'm trying to say.. when we will start the conveyor from rest. An extra torque will be required to move the belt because of MOI of everything.
@@mastermechanicaldesign thanks helps ALOT to know the nuance and can tackle other issues like if it was at an incline.
Very nice explanation sir.
1) What is the power loss in gear box?
2) What is the factor of safety consider the moment of inertia of the belt load?
1. Gearbox power loss - consider gearbox efficiency 90% for helical worm gearboxes
2. FOS for MOI- If you are considering every component MOI (belt, load, rollers) then you don't need to consider any extra FOS.
Very good and informative videos bro ... thankyou.. i need one clarification, how do select dia of the roller? Is there any standards? And torque based on MOI is it finding for all the drives?..
There is no such standard, but yes roller diameter should be sufficient to roll the belt properly. Means if we take a thick belt then we should consider a large diameter.
Also we should try to keep the roller diameter minimum to reduce the MOI
Third yes strength but it depends on length and tension on the roller (no significant concern)
Thankyou ❤
Hi which one is best to consider for doing the calculation, moment of inertia or without?
Offcourse considering MOI will give you close value. But if the application is light, rollers are small, then its okay to ignore MOI calculation, just consider significant SOF, but not too much. Its also a problem (deeply explained in video)
appreciate for immediate reply I think for a long conveyor, the number of roller will high that mean total MOI also High and the equation will give the high value of power
Yes exactly
Please make a video of shaft deaign, and also give the information about allowable shear tensile streess and strength and allowable bending moment and fatigue failure and what will be the safe value from protecting above point
Noted Atish,
Is the diameter of the roller according to the motor or is it the design for the belt?
According to me, diameter of roller should be according to belt thickness and belt material, like allowable minimum bending radius of belt
top of that we should keep the roller diameter minimum just to keep MOI of rollers minimum also to save cost
@@mastermechanicaldesign it depends on the length of the belt too? for example I am designing a 10 meters belt with the same material you used in the video, how much diameter do you recommend to use for the roller?
Really classic explanation about conveyor ..
How to select the motor for driven purpose of a machine from one place to another can you able to prepare a video for that
How do you want to drive.. Like on wheels or pick and drop. I mean I'm not fully understanding your requirement
Can you able to share your WhatsApp num so that I can share the image of that machine so you can easily understand
Sir... In moment of inertia method, to find moment of inertia torque for gearbox and motor, you selected the values related to 1hp motor and 10:1 ratio gearbox from datasheet. But how you choose the motor power and gearbox ratio before calculating it. Please explain that part.
That's a great question! I'll make sure to clarify that part in a future video.
15:07 the formula should be 1/2 mR^2 , right?
Hi jasesin, There is a typo mistake (correct 1/2mr2) 😑
@@mastermechanicaldesign thanks for the prompt response. I appreciate it.
@@mastermechanicaldesignany links how to correctly size/select the roller diameter?
The first basics of roller selection should be strength
Second is space (how much space available height wise)
Third is bigger rollers diameter means - High belt speed. So you can choose accordingly by reverse calculation.
sir, how did you select MOI for gearbox from catalogue? its not clear. and also when selscting a motor, why did you select from "4P 1500min-1" catagory?
For motor selection start from 18:02
Gearbox MOI - Find J value in catalogue 16:25
Really I got nice knowledge about the selection of motor and gearbox, thank you so much........ Still having some doubts from this video @ 16:03 MOI of an object in linear motion is 0.208 Kgm^2.....But actual calculation as per the mentioned formula 20.165 Kgm^2 coming.....Correct me If I am wrong........
Hey, yeah there are some typo mistakes, your calculation are correct.
Hello. Thank you for the video. Where did you get the acceleration times from? "0-2 seconds for 1/5 hp" etc.
This is actually a range (a rough estimation) because acceleration depends on how much the initial load is over the motor. I have taken this from a research paper from ABB laboratory
Excellent Explanation dude!! Keep it up
9:49 can you explain where you get 1 meter?
It's a simple mathematical step, first calculated for 1 unit (1 meter)
And then for total length 20 meter
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor
HI, Its very simple,
1. power consummation is equal to your conveyor motor required power.
2. 1 unit electricity is equal to 1 kW per hour.
Let say your conveyor required motor power is 2 kW.
Means your electricity consumption is 2 kW per hour means 2 Unit.
-- for motor power calculation, refer formula of this video.
@@mastermechanicaldesign
the installed power is not the consumed power
Yes, as i said, power consumption is equal to the required power to operate the conveyor (point 1)
Best explanation video
Very well explained sir.
Please make moment of inertia topic.
Sure!!
Good explanation, which book you followed for these concepts?
there are no such books, I do study from manufacture detailed datasheets or research papers
For some calculated power for an mechanical application, can we selecte AC induction motor or Bldc motor..? Or both for same power requirement?
Yes power required will be same for all types of motors
good and detailed explanation. thks❤️
Hello sir, can you please give us the link from where you got the belt table? thank you so much
drive.google.com/file/d/1j4Ve0GKd1DWazmZe0ha41LC1eB5FeKxN/view?usp=sharing
@@mastermechanicaldesign thank you sir!
You are just awesome bro, very wel explained,It is one of the biggest doubt I had, thanks for your valuable time and effort
It's my pleasure
Really video is great please make more such videos if possible please make video for designing of special purpose machine
Omg..thank you sir..i was finding these calculations but you made very easy….thank you
Glad to hear that 😊😊
Where can i find the source of that table of density ?
In the belt Manufacturers catalogue, I have given the example from MISUMI's catalogue
You download it from video discription.
@@mastermechanicaldesign thanks 🙏. I need help, i want the gearbox MOI for 0.55 kW. How do I look for it in the catalog tables?
Yes, 16:17
Please make video on Moment of inertia
Noted !!
Roller conveyor calculation par video banaye.
powered roller conveyor
Okay, Noted!!
Can you elaborate inclined convayor.
I'll make a video on it
Do you know how to calculate curve conversor?
You mean inclined conveyor?
@@mastermechanicaldesign Curve conversor....
Sir thank you so much i am always wanted to become a machine designer your video help me a lot. Regarding conveyor belt design you talk about MOI OF ROLLER . But if anyone used troughed idlers instead of instead of flat idlers then how i found his moment of inertia of in
I'm so glad 😊
Trough rolls - as these are also rollers but at an angle. So we can also calculate the MOI same as roller. Don't need to be too exact. Just consider approximations at higher side.
If the conveyor has an inclination what steps should be added?
Hi, Aniket, In an inclined conveyor we have to consider a cosine value (angle value) in mass, which will add up into conveyor pull force
Is there any documents or validation documents for your calculation
Not exactly. But i would say whatever I have explained is pure physics, like power formula, speed, MOI etc. Plus for data reference i have given is from manufacturers catalogue. Which you can verify.
However if you need specific parts validation, then i can provide. In terms of formula.
Really great video. Well done!
@ 7:29 when you are calculating Force You have written 411.5 X 9.81x0.2 which equals to 807 only how you got 1614.7 as answer please reply @mastermechanicaldesign
There are some calculation typo mistakes. Your calculation is right
Please explain once the Servo press calculation and selection
Hi Suresh, Servo motor selection calculation ??
hi sir, in the 20:26 second final velocity u gave 146.5 mm/sec but u didnt mentioned how it came there can u please explain it to me, Thanks for sharing the great video as usual awesome great content
Its selected motor final speed- watch from 19:50
You welcome Srinivasan
@@mastermechanicaldesign Thanks a lot sir😍
Thanks for very good explanation. Please make video for the selection of gearbox for indexing table application
Yes sure!! noted
Excellent lecture bro, can u pls explain the calculation of acceleration time in detail
Ok noted !!
Hi Sir can I ask where did you get or what book did that table of density came from?
Hi, this table is taken from MISUMI (an automation products manufacturer)
Very good explanation.....Thank you so much ...find it vey useful....Can you please make a video on Moment of inertia?
Will try
Your work is fantastic. At the 7.29 mark, you show Friction force = 1614.7 N I calculated 806.54? What did I miss please
There are some mathematical calculation mistakes from my side
Bro how to calculate cycle time for automation can you make video any following procedure
Okay I'll try Dhana
Roller chain conveyor calculation ka video banaye...
Sure Vinayak, Noted!!
Aayush Bhai waiting for Roller Conveyor Calculation.
Powered roller chain conveyor calculation par video banaye.
Let me first finish this bearing calculation series. Also i have used a powered roller only once in my experience. So it will take some time to research. I hope you understand me.
Thanks for sharing good information. If possible please do about power roller conveyor design calculations
Sure, I will
You are great sir ❤
COULD U PLEASE LET ME KNOW HOW TO CHOOSE MOTOR FOR Z OR INCLINE CONVEYOR.
Yes, pull force become Pull force X cos A . (A - inclination angle)
Awesome knowledge shared by you sir😊
How to calculate modular belt conveyor
Thank🙏 you sir. Please make video on moment of inertia
Sure, Coming soon
1)If I have flat belt conveyor with drive pulley and driven but both are different diameter then belt speed is change or not
2)same question for timing belt
Belt speed will always depend on driver pulley. If both pulleys are the same dia. Both will rotate at the same speed. If driven pulleys is smaller, will run faster. If driven pulleys bigger, will run slower. Belt speed will be same.
@@mastermechanicaldesign 1. For flat belt is same belt speed if we change diameter
2 but belt speed changes in timing belt if both pulley teeth are different
Can you make a video to design a motorised trolley which is moving on wheel and rail track, with loading capacity of 40 ton. For given speed 20m/min, calculate gearbox, wheel dia, motor power, ?
Yeah sure
Yes waiting for this video.
Awsome video sir ❤❤
Thank you jay 😊😊
very nice, small suggestion mass of belt value changed.
Yes, you are right.
Sir i want to now whole process of selection regarding gantry system vertical and horizontal movement with rack and pinion mechanism
Okay 👌 Noted, Complete series
Mostly valuable information sir thankyou.
Most welcome
you are awesome man
You too. Thank you 😊
Dear sir moi torque roller -0.25*15*(0.0225)2*2 value 0.0018 not available. Valve comes to 0.0037 please State whether this answer is correct or not
Hi Swapnil, Yes there is few calculation mistyping in my video. So Your calculation should be correct 👍
Sir ek question hai for example if customer need 100 part in one minute at the end of conveyor then what should be belt speed...means how we will calculate belt speed???
Hi Praveen very interesting question ❓
Here belt speed will also depend on part length. And gap between each parts
Let say part length is 100 mm at a gap of 50 mm. Mean conveyor belt should travel 150 mm for one part delivery.
And as given 100 part per minute.
Mean 100x150 mm per minute
15000 mm per minute, 15 meter per minute.
Please let me know if I'm making mistake in calculation 😅
please make a version of chain driven roller conveyors this video is great :D
Sure, Noted 👍
Thanks for giving calculations for Conveyor Belt Power.. I want to suggest that kindly make a video about Selection of Power Transmission Belt Drive or No. of belt.. in which Counter pulley System.
Noted, I would be better to do this within a transmission design series
How to select standaed belt length
Belt length having no such standard. you can order calculated length
Thanks master,how to calculate chain conveyor
I will make video on it, for sure
Great sir make such videos regards mechanical design selection, calculation, Power train, gear ,shaft , pulley,motor selection etc
Sure 😊, thank you so
If u remove the belt support
Whete will u keep the Loan ?
In Air ??
No. Load will remain over the belt. Conveyor without belt support - Yes for short distance and light weight material transfer like plastic parts we don't give support below the belt. But this is not the main purpose of this video with this example I just want to say. If you don't support the belt then it doesn't mean that required torque will become zero. There will be a MOI of rollers and other items.
"Watch the entire video otherwise you will be confused, I'm not confused"
Sir please make a video on moment of inertia in detail and how to use it in design.
Sure I will
This video is for my level technical expertise. Thanks ❤❤❤
I'm glad 😊
Good information and much appreciated your efforts but kindly recheck the considerations for calculations as they seem little offset from actuals, as there is no much difference for the motor KW but when it comes to judge what can be done with other parameters to decide some intermittent operations that you get across while introducing other process based on selecting rpm’s and force flow process, might mislead to wrong assumptions though. All the way nicely explained
Hi Bharathrm, Thank you so much. yes, there is little calculations typing errors with example. But concept and formulas are right. Just bear with me. mistyping will eliminate completely with time. trying to build a cross check community.
Can you provide the entire transcript of calculation in pdf..as my simple guide in conveyor belt calculation.thanks in advance
Okay 👍, Yes it would be useful
I have a question, whether the formula above can determine a DC motor for a conveyor?😅
Conveyor driving capacity. Like torque and speed will be the same for all types of motor
@@mastermechanicaldesign Thank you sir, for replying to my question😁
Thank you sharing the knowledge
please make video on how to design slat conveyor.
Noted
Please tell us indepth about welding symbols its types and methods
Sure Fenil, noted. In content list
Please make a video on power roller conveyor design
Plz share topic movement of inertia
Sure!!
Very good video , thanks Master
Hi Ayush,waiting for Powered roller chain conveyor calculation video
It will take some time. First we will complete bearings sizing and calculation parts
THANK YOU SO MUCH SIR, FOR SHARING KNOWLEDGE....
You are most welcome
Kindly Make a video on calculation of axial and radial load for bearing selection.
Sure dhiraj, Complete bearing series is planned.
Can you upload the video of Trajectory calculation with Example
Yes, I'll upload on another channel, physical channel, not created yet. I'll let you know
Yes, I'll upload on another channel, physical channel, not created yet. I'll let you know
Yes, I'll upload on another channel, physical channel, not created yet. I'll let you know
Yes, I'll upload on another channel, physical channel, not created yet. I'll let you know
sir we required your complet assembly desigen for study perpose
Share your email id. I'll send you link
Pls make a video of moment of inertia
Noted ☺️
गुरु बिन मंगल फेरते गुरु बिन करते दान
गुरु बिन सब निष्फल गया, वाचो वेद पुराण
Sir please make a video on rack and pinion with gear box selection
Noted Subham 😊
Calculation for gradient conveyor?
Calculations concept will be exactly the same, Just include the force cosine component as per conveyor gradient angle, (Like in sliding Friction, MOI of belt and load)
how to have its transfer function?
Why is the loading torque smaller than the starting torque in this video?
Could you share time stamp
It was so amazing explanation 👏
Thank you bhai
Most welcome 😊
Need detail video regarding welding types , bearing selection and type gear and pully teeth calculation all those topics in separate detail video
Sure 👍