Much appreciated Sir😊 v1=10..(1) (V2-10)/1+v2/1+(v2-v3)/1=0....(2) (V3-v2)/1+(v3)/1+(v3-v1)/1=0.....(3) 3v2-v3=10....(2). (2)*3 -v2+3v3=10...(3) 9v2-3v3=30..(2) So 8v2=40,v2=5v V3=5v and then I=v3/1=5/1=5A (30sec)
you don't need "the remaining" at node 1 because the other 2 nodes will utilize the V1=10v value in their equations, thereby each equation will have 2 unknowns (V2 and V3). 2 equations with 2 unknowns can be solved.
@@AC0_0From the bottom node we see a potential increase at V1, 0v -> 10v. In this case we know the voltage of V1 so we're not assuming current flow from it, instead we're assuming the flow of current from the other 2 unknown voltages.
Sir plz 🙏upload videos on network Syenthesis.... I tried very much to get videos on this unit on youTube but nobody has uploaded satisfactory videos... Ur videos are always helpful and Understandable plz upload some videos on this.
Because there was a Voltage source connected between the node v1 and the reference node (0v). So instead of writing the equation, we can directly write the value of v1. As nodal analysis is the process of finding the value of voltage present at nodes.
sir i have a doubt. if we multiple by 3 in eq-3, it will become 6v3-3v2=30 then adding with eq-3 it will become (6v3-3v2-+3v2-v3=40), now, equating it i have found 5v3=40 therefore v3=8v.. is this correct answer ?
Without attending any class in school nor any lecture, I master nodal analysis like my name thanks to neso academy
May God bless you !!
Much appreciated Sir😊
v1=10..(1)
(V2-10)/1+v2/1+(v2-v3)/1=0....(2)
(V3-v2)/1+(v3)/1+(v3-v1)/1=0.....(3)
3v2-v3=10....(2). (2)*3
-v2+3v3=10...(3)
9v2-3v3=30..(2)
So 8v2=40,v2=5v
V3=5v and then I=v3/1=5/1=5A
(30sec)
Tq...
Keep Growing.....Guys💛
How would you go about the question if you did not assume each node was the higher potential?
Where is the remaing eqns at node 1?
If it included and calcied answer is 2.5 A . Why this difference?
i am wondering about the same thing too. can you please explain sir?
I'm also confused
But correct answer.. Check by Applying kvl
20÷8 ....2×4 =8 strike 8 by 4 and then 4*5 =20 strike 20 by 4 ( I think he used this method )
you don't need "the remaining" at node 1 because the other 2 nodes will utilize the V1=10v value in their equations, thereby each equation will have 2 unknowns (V2 and V3). 2 equations with 2 unknowns can be solved.
At node 3 eq are ...
(V3 -V1)/R5 -I + V3/R4=0
Sir pls tell if its correct?
@nesoacademy at node 3 : The equation should be V3-V1 + V3-V2 + I =0 ??
Are trying to say when assigning current directions ,you choose any direction
Thank you sir ❤️
Enhanced the value
How did you get the I=5A ?
why we are considering only 1 variable in node 1m bcoz there are more 3 lines left??
Sorry sir but the last step is pretty fast It took me a lot of effort 😢to understand even so thank you veryuch
why is V1 not -10V, because we assume V1 as a large voltage , so current leaves V1 which opposes the direction of current at the 10V?
same question, can u help?
Help
@@AC0_0From the bottom node we see a potential increase at V1, 0v -> 10v. In this case we know the voltage of V1 so we're not assuming current flow from it, instead we're assuming the flow of current from the other 2 unknown voltages.
Sir you are great
Sir plz 🙏upload videos on network Syenthesis.... I tried very much to get videos on this unit on youTube but nobody has uploaded satisfactory videos... Ur videos are always helpful and Understandable plz upload some videos on this.
thank you sir,,plz upload more videos on dis subject.....thanx in advance sir.....
thank you
why do you multiply by 3 and add 2? 8;26
When will you again continue signals & systems? Just curious to know, no offence!
Sir please make a full video on Microprocessor and Microcontroller as soon as possible.plz sir..
thanks a lot sir plz try to upload full syllabus
U r awesome sir
incredible
good job for case 1 but where is case 2??
its in another vide...and the link of that video is ruclips.net/video/UOHvCU2br1k/видео.html
Legend..
❤️❤️❤️
Why do we assume all the currents leaving the node 🙄🤔
the math will work out in the end with the finished equations. the assumption is arbitrary when just setting up the equations.
🙏❣
Why we didn't write full equation at node v1
Because there was a Voltage source connected between the node v1 and the reference node (0v). So instead of writing the equation, we can directly write the value of v1. As nodal analysis is the process of finding the value of voltage present at nodes.
😢😢😢😢
Where The R has gone then ....???
It is one.. He didn't calculate it
sir i have a doubt.
if we multiple by 3 in eq-3, it will become 6v3-3v2=30
then adding with eq-3 it will become (6v3-3v2-+3v2-v3=40),
now, equating it i have found 5v3=40
therefore v3=8v..
is this correct answer ?
Same doubt bhayya
Ryt
why we are considering only 1 variable in node 1m bcoz there are more 3 lines left
it will be 9v3 not 6v3, so 8v3 =40 => v3=5
Thank you