ALEKS - Interconverting number of atoms and mass of compound (Example 1)

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  • Опубликовано: 8 ноя 2024

Комментарии • 18

  • @hwylsoliloquy2959
    @hwylsoliloquy2959 3 года назад +6

    THANKYOU SO MUCHHH!!! This method has saved me soo much timeee, you made everything easier to understand. YOURE THE BESTTT!!! STAY SAFE AND HEALTHYYY MY HERO

  • @reanna5158
    @reanna5158 4 года назад +2

    Thank you so much! This was the most helpful interconverting number of atoms and mass of compound I've seen. None of the other ones had this problem. I love how you explained that we needed to go from Chem formula to Na to MM. It was helpful to see it laid out like that.

    • @TheChemistryTutorChannel
      @TheChemistryTutorChannel  4 года назад +2

      I'm glad that you found the video useful! Don't hesitate to request more ALEKS videos that I can help with!

    • @reanna5158
      @reanna5158 4 года назад +1

      @@TheChemistryTutorChannel thank you yes! I am struggling on combustion analysis and would love some help. I'm not sure if you've made a video yet, but if not, that would be so helpful!

    • @TheChemistryTutorChannel
      @TheChemistryTutorChannel  4 года назад +2

      @@reanna5158 I can have a few example videos for the combustion analysis topic up first thing tomorrow. Be sure to subscribe so you won't miss them!

    • @reanna5158
      @reanna5158 4 года назад +1

      @@TheChemistryTutorChannel Subscribed! Thank you a ton

    • @TheChemistryTutorChannel
      @TheChemistryTutorChannel  4 года назад +1

      @@reanna5158 The Combustion Analysis video is posted!

  • @esma4379
    @esma4379 2 года назад +5

    i did the exact same way and got it wrong. It tells me the actual method was to divide the 1.0*10^9/6.022*10^23(avagadro's number). Then divide that number by the amount of hydrogen which is 10. Then multiply that number by the molar mass of B4H10 and thats the actual answer, which is pretty much the same as ur method??

  • @williamjennings7116
    @williamjennings7116 2 года назад

    howd that -15 come about? whatever i do i just get somee large number and nothing in the negatives. PLEASE HELP

    • @esma4379
      @esma4379 2 года назад

      type in ur problem on mathaway it usually gives the correct one

  • @unknown-ks3zv
    @unknown-ks3zv 2 года назад

    Thank you so much!

  • @viv1593
    @viv1593 2 года назад

    thanks !!

  • @darlincardoza2397
    @darlincardoza2397 3 года назад +1

    how did you get the -15?

    • @TheChemistryTutorChannel
      @TheChemistryTutorChannel  3 года назад +1

      10^-15 is the power I get once the calculations are completed. One thing that makes unit conversions difficult for students is putting it into the calculator! Sometimes, order of operations can get mixed up and your answer will be different from the correct one. Try multiplying 1.0 x 10^9 by everything across the top first, then hit enter. Then, divide by everything in the denominator of each conversion factor and hit enter to get the final answer.

    • @nathanael_seattle495
      @nathanael_seattle495 3 года назад

      @@TheChemistryTutorChannel I wish the multiplication was done slower and shown clearly..... I got a different exponent. Not sure what I did wrong.

    • @williamjennings7116
      @williamjennings7116 2 года назад

      i know its been a year later but have you figured out how to get that -15 ??

    • @Maria-jr4xy
      @Maria-jr4xy 9 месяцев назад

      @@williamjennings7116 still have not figured out that -15

    • @nicktrujillo4963
      @nicktrujillo4963 8 месяцев назад +1

      @@Maria-jr4xy I got 8.8546*10^-15. I think you're probably not putting it into your calculator correctly. When you use numbers in scientific notation, you have to put them in parentheses, otherwise the calculator will fudge up the order of operations. It should look like this:
      (1*10^9)/10= 100,000,000
      100,000,000/(6.022*10^23)= 1.66057788*10^-16
      (1.66057788*10^-16)*53.323= 8.85469943*10^-15 (then round to the correct sig figs)