You can solve it by taking the initial qty. of milk as (4x/5) also. In that case you'll have to take the whole qty. as (x). And if you assume the whole qty. to be (5x), then the initial qty. of milk would be 4x.
The way u teach is commendable sir...I mean every channel only tells the answer but u tell in diff methods and above all u help us do them faster without the use of pen.....amazing lectures ..plzx keep uploading
first question can be solved by alligation also : Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water ) So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 ) So , in x-40 litres of mixture we add 40 litres of pure water In mixture there is 1/5 pure water In water theres 5/5 pure water After mixing both we get 2/5 of pure water So , m+w. w 1/5. 5/5 2/5 X-40 : 40 =. 5/5-2/5 : 2/5-1/5 So , x-40 : 40 = 3:1 Thus x-40 = 120 and x = 160 ( intial quantity of mixture ) We can do others with same method too
I have never immersed myself in any activity other than watching these videos and trying to solve every question. The concepts and the way of teaching are exemplary.
No. The water increased by 1unit(1-->2) in ratio and by 32L(minus8L and add40L) in the mixture i.e, 1 unit corresponds to 32L. so initial milk= 4*32=128L and initial water= 1*32= 32L
@@indelible-23 Yes we can solve it. I tried it and was getting the original solution to be 120 ltrs. (Got mixture and water using alligation as 3:1, since water was 1 therefore mixture would be 3 x 40 = 120). But the question has stated that we removed 40 ltr of the solution and added 40 ltr of water. So technically the 120 ltr we calculated was missing 40 ltrs that was removed (As in alligation we calculate how much of the average was due to liquid 1 (Milk + Water Mix) and liquid 2 (Only water).) Once I added the 40 ltrs that was removed (120 + 40 = 160) and did the ratio to find water and milk, I got the right answer.
first question can be solved by alligation also : Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water ) So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 ) So , in x-40 litres of mixture we add 40 litres of pure water In mixture there is 1/5 pure water In water theres 5/5 pure water After mixing both we get 2/5 of pure water So , m+w. w 1/5. 5/5 2/5 X-40 : 40 =. 5/5-2/5 : 2/5-1/5 So , x-40 : 40 = 3:1 Thus x-40 = 120 and x = 160 ( intial quantity of mixture ) We can do others with same method too
While using alligation method, we get ratio of (milk+water)soln to water as 3:1, water added is 40ltr so 1 unit represent 40ltr, therefore 3 units of (milk+water)soln represents 120ltr, but ans should be 160ltr instead of 120ltr, can anyone help with this?
40 litres of the mixture was replaced by 40 litres of water. Therefore 40L of water mixture was added to 120L of mixture. Hence the total becomes (120+40)L
You're answer is right, 120 Ltrs was original mixture is the answer. But since initially 40 ltrs of that mixture was remove, hence we have to add that back. Therefore total is 120L + 40L = 160 Ltrs You can review the below video to revisit a similar question being solved using alligations. ruclips.net/video/qQcGkxuf4ws/видео.html&ab_channel=Rodha
Sir suppose in 4th question of milk and water - If the total of both the ratio does not match and we equate it after taking lcm and then to that ratio can we multiply with 1 & 4 to find result? Thanks in advance
In part (b) of Milk water que. If we distribute 180L mixture in all three vessels in 3:4:5 and then solve for each vessel according to ratio i am getting 88:92 M:W in vessel D. can anybody tell what mistake in my way?
We took 60 Ltr as the LCM hence each vessel have 60 ltr mixture of Milk and water i.e A : B : C = 60 : 60 : 60 Now it'll become 1 : 1 : 1 I hope you understand Brother ((:
I am not sure but in alligation we mix 2 type of stuff to get a resultant.. But here in 1st ques 40l of mixture is 'replaced' with water. Correct me if i am wrong. Thanku
I think we use 2 types of stuff in an allegation like 1.runs and wickets 2.students and amount collection 3.concentration and volume 4.cost and items e.t.c correct if I'm wrong....
If we alligate (M+W) and W, we get a ratio of M:W of 3:1 in the alligated mixture. W is only being added to the alligated mixture and M is not being reduced
@@romanthchowan1578 Start by taking both solutions in terms of % of either water or Milk. I am taking % Milk. We know that Solution I is 40% Milk(because 2 out of 5 parts milk) and solution II is 60% milk. It is given that the solutions are mixed in ratio 1:4. Assume the resultant solution has x% milk. By Allegation Method (60-x) / (x-40) = 1 / 4. Solve this you will get x = 56%. This implies the resultant solution is 56 parts milk and 44 parts water. simplifying ratio => 56:44 = 14:11.
@Sim Sidhanti While using alligation method, we get ratio of (milk+water)soln to water as 3:1, water added is 40ltr so 1 unit represent 40ltr, therefore 3 units of (milk+water)soln represents 120ltr, but ans should be 160ltr instead of 120ltr
I am not sure but in alligation we mix 2 type of stuff to get a resultant.. But here in 1st ques 40l of mixture is 'replaced' with water. Correct me if i am wrong. Thanku
Take any one concentration..for example Water Conc. Ratio . Water is 1 parts in initial and 100 percent pure water is mixed to get 2 parts in the mixture.. convert the parts into percentrage.. Therefore initial amount of water = 20 percent mixed with 100 percent will give you an weighted average of 40 percent...solve by alligation method and you will get the final ratio as 3:1 . Now 40 litres of water divided by 5 [ 3+2} will give you 8 . Now one part = 8 litres...Therefore . 40-8 = 32 litres.. SO one part of water = 32 litres and 4 parts of milk -= 128 litres. I hope this is right...If I'm wrong correct me
@@snehatsamuel30 1 part is not equal 8lt But, weight ratio= 3:1 1 unit =40 lt water (acc to concept what we added to the milk. ) To reach to initial level we have to subtract 8lt of water from this 40 lt.Back process It comes 32 lt. Now what was the initial ratio M:W 4:1 here this 1 unit =32lt. Question is solve I hope it is right....
The concept of Profit and Loss Questions have been explained in full detail in the below link in the most simple and innovative manner. ruclips.net/video/sK6SkqSI_Tc/видео.html
Take any one liquid, say milk. In the first mixture, it is 40 percent and in the second mixture it is 60 percent. Solve and you will get milk concentration as 56 percent. And hence the M:W ratio as 14:11. :))
The first question cannot be solved using alligation since there is also a reduction in M as the question mentions *replaced* If we alligate (M+W) and W, we get a ratio of M:W of 3:1 in the alligated mixture. W is only being added and M is not being reduced. Hope this helps those who had the same question as me.
first question can be solved by alligation also : Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water ) So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 ) So , in x-40 litres of mixture we add 40 litres of pure water In mixture there is 1/5 pure water In water theres 5/5 pure water After mixing both we get 2/5 of pure water So , m+w. w 1/5. 5/5 2/5 X-40 : 40 =. 5/5-2/5 : 2/5-1/5 So , x-40 : 40 = 3:1 Thus x-40 = 120 and x = 160 ( intial quantity of mixture ) We can do others with same method too
I can say the ans is 100% correct. Eg- let us take first container as 40 and 60 and second as 60 and 40....1unit in first container is 20(8+12) and 4 units of 2nd container is 80(48+32)... And total milk:water = 56:44 and when we divide by 4 we'll get 14:11
In 40L mix 32 was milk and diff in case of milk is 1 that's why he took it as 32. Because in new mixture we have additional 40L water so don't take unit with respect to water Edit- if 40L of milk was added instead of water then we would take 8. Hope that was helpful
can anyone relate...that feeling of solving the question correctly for the FIRST time before sir does...just incomparable
I do
love that feeling
💯🙌🏻
And the joy is unimaginable being a weak student at mathematics
In 2 question the ratio is actually 352:368 which further gets to 22:23
he corrected it
15:48 sum of Milk :- 72+180+100 = 352 (372 mentioned)
Bro how did you watch this full video because i am facing a lot of problem in playing this video, it gets stuck always
@@Abhijeetkr_2211 i am watching it on its playlist, really the course content is well.
16:06 ratio will be 22:23
@@riteshsrivastav7598 Amateurs 😂
@@sumitad5271 isnt it 88:92
Genius. It’s not about speaking something extraordinary but explaining the rote concepts the simplest of ways
In question 1 why initial quantity of milk is not 4/5*x as milk and water are in ratio of 4:1 so milk will be 4/5*x
You can solve it by taking the initial qty. of milk as (4x/5) also. In that case you'll have to take the whole qty. as (x). And if you assume the whole qty. to be (5x), then the initial qty. of milk would be 4x.
The way u teach is commendable sir...I mean every channel only tells the answer but u tell in diff methods and above all u help us do them faster without the use of pen.....amazing lectures ..plzx keep uploading
I can't thank you enough for these lectures, Ravi sir. I'm using your videos for CSAT. You're a gem for students!
This channel is truly a gem.
first question can be solved by alligation also :
Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water )
So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 )
So , in x-40 litres of mixture we add 40 litres of pure water
In mixture there is 1/5 pure water
In water theres 5/5 pure water
After mixing both we get 2/5 of pure water
So , m+w. w
1/5. 5/5
2/5
X-40 : 40 =. 5/5-2/5 : 2/5-1/5
So , x-40 : 40 = 3:1
Thus x-40 = 120 and x = 160 ( intial quantity of mixture )
We can do others with same method too
I have never immersed myself in any activity other than watching these videos and trying to solve every question. The concepts and the way of teaching are exemplary.
Thanks
16:04 answer is 88:92
22:23 😂
@@anubhavkumartiwary8417 ek hi baat h boss
Thank you Sir for deliberately committing mistakes so that we are assured that you’re human just like us 😂
Please keep the volume of entire video as high as it is of introduction of channel
sir ur really a god of CAT EXAM
Correct answer for part b is 22:23
Yeah correct. 93:92 will give total qty to be 185ltr but actually it has to be 180ltr only. So the ratio is 88:92 or in simpler form 22:23👍👍
watch the complete video
@@ajinkyaawachar5686 Amateurs 😂
8:20,Sir,if we consider the change in qty and ratio of water instead of that of milk.
The total qty of both milk as well as water are different.
No. The water increased by 1unit(1-->2) in ratio and by 32L(minus8L and add40L) in the mixture i.e, 1 unit corresponds to 32L. so initial milk= 4*32=128L and initial water= 1*32= 32L
@@sakshisharma9397 yess...well explained
@@sakshisharma9397 thanks!
3:50 how to do this question by method of alligation ? i am trying but not able to get the answer
May be we can't solve it by using alligation method. Coz we are adding and removing too.
If we can please tell me how
@@indelible-23 Yes we can solve it.
I tried it and was getting the original solution to be 120 ltrs. (Got mixture and water using alligation as 3:1, since water was 1 therefore mixture would be 3 x 40 = 120).
But the question has stated that we removed 40 ltr of the solution and added 40 ltr of water.
So technically the 120 ltr we calculated was missing 40 ltrs that was removed (As in alligation we calculate how much of the average was due to liquid 1 (Milk + Water Mix) and liquid 2 (Only water).)
Once I added the 40 ltrs that was removed (120 + 40 = 160) and did the ratio to find water and milk, I got the right answer.
first question can be solved by alligation also :
Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water )
So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 )
So , in x-40 litres of mixture we add 40 litres of pure water
In mixture there is 1/5 pure water
In water theres 5/5 pure water
After mixing both we get 2/5 of pure water
So , m+w. w
1/5. 5/5
2/5
X-40 : 40 =. 5/5-2/5 : 2/5-1/5
So , x-40 : 40 = 3:1
Thus x-40 = 120 and x = 160 ( intial quantity of mixture )
We can do others with same method too
@@ryzen7-wp7gscan you tell how to solve pyq cat 2023 shift 1 question using alligation 😅
It's from the topic of alligation and mixture itself
1 st one through..sir Poissons ratio!! easily done thanku sir❤️❤️❤️
Sir plz chck the calculation in second question. 372 replaced by 352
17:05 check for answer b
6:23 how ratio reflects the question
Sometimes idle also do mistake 16.23 ...
From past 2 month you are my idle
Leader sir ......
Huge respect from prayagraj 🙏🙏🙏
ideal*
13:21 in this question's 2nd part why did sir equalize the volume again? ques mai toh ratio ko 3:4:5 mai banana hai
Wo ratio ABC ka diya hai bhai batana to ratio vessel D ka hi hai milk aur water ka
Can anyone tell how to identify whether to solve question with alligation and whether with ratios ?
+1
you can actually solve that with alligation also , remove the 40 l and maintain the same ratio , then you will get the lengths and weights ration
Thank u sir🙏🙏
Thank you so much sir.❤❤
What a teaching level sir
Just awesome 👌
At 8:28 can someone tell me how to do with water ? I got the milk one while doing with water didn't get the appropriate ans
Since ratio is 4:1 where 1 unit equals 32. 1 unit of water is 32L and 4 units of milk give 128L
For water first we have taken 8L out and put 40L in. So, for 1 unit = -8+40= 32L
Thank you guruji ❤
Amazing concept videos.
guys dont forget to like his vids
excellent mentor thank you, sir
While using alligation method, we get ratio of (milk+water)soln to water as 3:1, water added is 40ltr so 1 unit represent 40ltr, therefore 3 units of (milk+water)soln represents 120ltr, but ans should be 160ltr instead of 120ltr, can anyone help with this?
40 litres of the mixture was replaced by 40 litres of water. Therefore 40L of water mixture was added to 120L of mixture. Hence the total becomes (120+40)L
Same doubt... If anyone can clear this out please..
You're answer is right, 120 Ltrs was original mixture is the answer. But since initially 40 ltrs of that mixture was remove, hence we have to add that back. Therefore total is 120L + 40L = 160 Ltrs
You can review the below video to revisit a similar question being solved using alligations.
ruclips.net/video/qQcGkxuf4ws/видео.html&ab_channel=Rodha
how did you calculate the ratio by allegation method?
@@piyushmundra7511can you please clear my doubt? how did he calculate 3:1 ratio by using allegation method
sir you are anand kumar for us 🙏🙏🙏🙏🙏🙏
Classes are really good, but volume is very low.
immense thanq
thankuuu sirrrr
20:37 anyone having different answers? If u take a:b:c
sir , can you please help how can we solve 1st ques by 2nd method if taking water as reference for unit ?
12:00 in this qsn cant we write in upon like (2/3+3/1+1/2) so we will get ratio as 39:10?
No, because addition of each ratio is not same. 2+3=5, 3+1=4 and 1+2=3. Addition represents that what total is the ratio is calculated upon.
Thank you Sir!!!
Why 1 unit milk is 32 ???
We removed 8L of water and then added 40L. So 1 unit of water will be 40-8 = 32L.
can we prepare for 2023 cat from this playlist?
Superb sir, you are superb......
In the 1st que 2nd method 1 unit water means 8L sir , Not 32L.
yaah that's n\my doubt too....
@@tejasvisaini1120 yeah.
We removed 8L of water and then added 40L of water again. Result: 32L of water added. So 1 unit change = 32L
😢
Sir you are the besttttttttt😭😭😭♥️
😘😘😘
Sir can we use Alligations and mixtures concept
Sir suppose in 4th question of milk and water - If the total of both the ratio does not match and we equate it after taking lcm and then to that ratio can we multiply with 1 & 4 to find result?
Thanks in advance
Yes
revising
for SNAP 2024
How to solver last question using allegation method
In part (b) of Milk water que. If we distribute 180L mixture in all three vessels in 3:4:5 and then solve for each vessel according to ratio i am getting 88:92 M:W in vessel D. can anybody tell what mistake in my way?
Got right answer.
Sir please your voice is very low
Please make it loud so we can hear easily
are volume bada na fir
Use earphones birooo
@Abhijeet S oh god LMAO
Plz tell me anyone why ratio becomes 1:1:1
We took 60 Ltr as the LCM hence each vessel have 60 ltr mixture of Milk and water i.e A : B : C = 60 : 60 : 60 Now it'll become 1 : 1 : 1 I hope you understand Brother ((:
thanks sir
In the1st qns we can also use allegation isn’t it.
I am not sure but in alligation we mix 2 type of stuff to get a resultant.. But here in 1st ques 40l of mixture is 'replaced' with water.
Correct me if i am wrong. Thanku
@@siddhantdhyani4541 You can take 1st Type as 80% milk / 20% water and the 2nd Type as 0% Milk / 100% Water
Quantities can be Q-40 and 40 to get initial quantity of mixture
I think we use 2 types of stuff in an allegation like 1.runs and wickets 2.students and amount collection 3.concentration and volume 4.cost and items e.t.c correct if I'm wrong....
@@vishalmidha_musicaholic can you solve it pls
Sir how to do last ques with alligation method , i tried but do not get answer
If we alligate (M+W) and W, we get a ratio of M:W of 3:1 in the alligated mixture. W is only being added to the alligated mixture and M is not being reduced
Sir i think 7:39 the mixture of milk will be 8*1 = 8
Cat 2023 aspirants like here
Thanq sir
can I really trust this free series for cat?
Can we solve the last question by distance method?
Yes, absolutely. By allegation method aswell
@@vishalmidha_musicaholic how?? pls help
@@romanthchowan1578 Start by taking both solutions in terms of % of either water or Milk. I am taking % Milk. We know that Solution I is 40% Milk(because 2 out of 5 parts milk) and solution II is 60% milk. It is given that the solutions are mixed in ratio 1:4. Assume the resultant solution has x% milk. By Allegation Method (60-x) / (x-40) = 1 / 4. Solve this you will get x = 56%. This implies the resultant solution is 56 parts milk and 44 parts water. simplifying ratio => 56:44 = 14:11.
How to solve first question with this method?
Sir you are great but video ki sound thodi zyada rkha karo
how to do the first question of this video by alligation method?
@Sim Sidhanti While using alligation method, we get ratio of (milk+water)soln to water as 3:1, water added is 40ltr so 1 unit represent 40ltr, therefore 3 units of (milk+water)soln represents 120ltr, but ans should be 160ltr instead of 120ltr
how am i not supposed to get confused among the methods to solve the first question knowing it can be solved by ratios or alligation and whatnot
now that's where you have multiple swords , choose your best.
How to solve 1st question using allegation?
I am not sure but in alligation we mix 2 type of stuff to get a resultant.. But here in 1st ques 40l of mixture is 'replaced' with water.
Correct me if i am wrong. Thanku
Take any one concentration..for example Water Conc. Ratio .
Water is 1 parts in initial and 100 percent pure water is mixed to get 2 parts in the mixture.. convert the parts into percentrage.. Therefore initial amount of water = 20 percent mixed with 100 percent will give you an weighted average of 40 percent...solve by alligation method and you will get the final ratio as 3:1 . Now 40 litres of water divided by 5 [ 3+2} will give you 8 . Now one part = 8 litres...Therefore . 40-8 = 32 litres.. SO one part of water = 32 litres and 4 parts of milk -= 128 litres. I hope this is right...If I'm wrong correct me
@@snehatsamuel30 1 part is not equal 8lt
But, weight ratio= 3:1
1 unit =40 lt water (acc to concept what we added to the milk. )
To reach to initial level we have to subtract 8lt of water from this 40 lt.Back process
It comes 32 lt.
Now what was the initial ratio M:W 4:1 here this 1 unit =32lt. Question is solve
I hope it is right....
@@ranjanagehlot9631 what do you mean by "to reach to initial level". Can you please explain?
@@ranjanagehlot9631 and what was the use of finding the ratio "3:1"
sir most of the videos are low sound its very difficult to hear you properly.
The concept of Profit and Loss Questions have been explained in full detail in the below link in the most simple and innovative manner.
ruclips.net/video/sK6SkqSI_Tc/видео.html
Listen in earphone on full volume...it sounds perfect
Sir, volume bohot low hai
why we are not taking the 1 unit of water 8 lit???
We can tak 1 unit decrease in milk is due toh 32 mil removed from it. Right
Similarly 1 unit increase in water is due to 40-8 ( additional water)
sir u teaching style is awsm but u r not audible , if possible kindly increase video voice , plzzzzzzzzzzzzz
appreciate
8:30
How to solve the last question with Alligation...
Take any one liquid, say milk. In the first mixture, it is 40 percent and in the second mixture it is 60 percent. Solve and you will get milk concentration as 56 percent. And hence the M:W ratio as 14:11. :))
@@shiprasingh6360 yes, you are right.
Speak in a higher pitch, please!
can I really crack cat by taking your lecture seriously?
Can't understand what u r saying, means u don't find this sufficient??
Pls explain
zeRODHAA
The first question cannot be solved using alligation since there is also a reduction in M as the question mentions *replaced*
If we alligate (M+W) and W, we get a ratio of M:W of 3:1 in the alligated mixture. W is only being added and M is not being reduced.
Hope this helps those who had the same question as me.
first question can be solved by alligation also :
Lets suppose starting quantity of mixture is x with m : w = 4:1 ( m for milk , w for water )
So after removing 40 litres of mixture we get x-40 litres ( ratio will still be same ie 4:1 )
So , in x-40 litres of mixture we add 40 litres of pure water
In mixture there is 1/5 pure water
In water theres 5/5 pure water
After mixing both we get 2/5 of pure water
So , m+w. w
1/5. 5/5
2/5
X-40 : 40 =. 5/5-2/5 : 2/5-1/5
So , x-40 : 40 = 3:1
Thus x-40 = 120 and x = 160 ( intial quantity of mixture )
We can do others with same method too
The last solution is wrong ... You can't determine the final quantity as because nothing of the quantity of containers are given ..
Then what is the right answer ?
Yaah correct... If assuming both quantities as same then and is 14:11
We aren't getting the final quantity, if you notice, we are getting the ratio of milk is to water.
I can say the ans is 100% correct. Eg- let us take first container as 40 and 60 and second as 60 and 40....1unit in first container is 20(8+12) and 4 units of 2nd container is 80(48+32)... And total milk:water = 56:44 and when we divide by 4 we'll get 14:11
Question is incomplete
In first ques. second method why are we multiplying the ratio of water with 32 which represent 1 unit of milk ?
Can someone explain in 2nd method 1st question why sir took 32 as a unit for water also, it should be 8 na and 8x1.. confusing 😭
In 40L mix 32 was milk and diff in case of milk is 1 that's why he took it as 32. Because in new mixture we have additional 40L water so don't take unit with respect to water
Edit- if 40L of milk was added instead of water then we would take 8. Hope that was helpful
@@kavyapande4886 cant read your reply properly? can you ellaborate !
is this a mute video.
No.
???
Thankyou sir
There is a problem in almost all the videos, videos are getting struck and only will out is to leave that part of the video and move further.
Yes bro they need to fix it. I thought that my net connection is slow😂😂
What are you talking about guys??
All the videos are working fine for me including this one 🙄 its not stucking anywhere for me
@@siddhantdhyani4541 That's because the issue existed an year ago 🙄 and now everything's in its place.
Sir I asked u a lot of times to mention ur WhatsApp group link.
Could u please mention it sir?
Dont have whatsapp group now. I ll share telegram link in community tab
Thank you sir 🙏
Thankyou sir
Thank you sir
Thank you sir