please teach the question, river has average velocity of 0.7m/s and has a reoxygenation constant 0.4 d-1. At the point of which organic pollutant is discharged, it is saturated with oxygen at 10mg/L.. Below the outfall the ultimate demand for oxygen is found to be 14mg/L and the Kr= 0.2 d-1. And Kd =0.14 d-1. What would be the pollutant concentration 8 Km downstream? Mention the assumptions made for solving this problem. Assume if any data is needed. (The Streeter - Phelps equation is given in the last page with usual notations) [
Thank you very much for sharing! Very nice and clear illustration. Just one comment: it is not very clear to me by saying sulfuric acid oxidizes something, which is different from what is written in the slide (13:29) where the oxidizing agent in the COD measurement is dichromate while sulfuric acid provides the acidic condition (i.e., H+) that allows the reaction to occur.
Thanks so much! Got upset with other videos on the same topic and felt happy after seeing yours. Great clarity.
Thank you for the very clear explanation. Really appreciate it.
Thank you so much . You made the BOD topic easy for me.
Such amazing clarity.
Amazing thank you very much
Beautiful
very accurate explanation and very informative. Thanks.
Nice lesson, thanks a lot
you’re the best 👍🏼👍🏼👍🏼
thankyou so much!
Great video thanks for sharing
Excellent content
please teach the question, river has average velocity of 0.7m/s and has a reoxygenation constant 0.4 d-1.
At the point of which organic pollutant is discharged, it is saturated with oxygen at
10mg/L.. Below the outfall the ultimate demand for oxygen is found to be 14mg/L and the
Kr= 0.2 d-1. And Kd =0.14 d-1. What would be the pollutant concentration 8 Km downstream?
Mention the assumptions made for solving this problem. Assume if any data is needed.
(The Streeter - Phelps equation is given in the last page with usual notations)
[
Thank you very much for sharing! Very nice and clear illustration. Just one comment: it is not very clear to me by saying sulfuric acid oxidizes something, which is different from what is written in the slide (13:29) where the oxidizing agent in the COD measurement is dichromate while sulfuric acid provides the acidic condition (i.e., H+) that allows the reaction to occur.
Thanks for the clarification. I appreciate the feedback.
@@belindasturm352 What happens to the 6 moles of oxygen? You take "180 * 32" but it's 1 mole glu per 6 mole of oxygen. So should you times 32 by 6?
nice and cool lecture
Nice lesson
Perfect example....nice clarification....
Thanks....
In TOD 32/180 = 0.167 not 1.67 mam there is bit confusion
Good explanation and easy to understand. Thank you.
Thanks for the positive feedback!
good and simple explain
very good
Explicit explanations, thank you