Probability - Free Formula Sheet: bit.ly/3zb22rW Final Exams and Video Playlists: www.video-tutor.net/ Next Video: ruclips.net/video/m0o-585xwW0/видео.html
"The organic chemistry tutor", you are too much! what i always wonder about you is that you are almost everywhere in the mathematically oriented courses. I thank God for blessing us through you! KEEP IT UP SIR, FOR YOUR WORK IS SAVING CONFUSED SOULS.
A life saver for someone helping get a high school student through probability and stats. You are a God-send. Thank you. And I wish you had been here when I was taking graduate stats. For real.
At 30:19 I was thinking to myself, "I wish he put all the formulas he used in one place". Less than 3 seconds later my wish was answered. Excellent video mate. Not once did I feel the need to rewind. Thank you
I am having an unexplainable amount of trouble with random variables as a whole, thank you SOOOOOO much for publishing this. You are God sent, I hope you have the most amazing day ever because you surely made mine better.
Thank god for this video! Finally got the right answer to my homework problem after maybe a million tries! Thanks for your hard work and easy to understand explanations!
Great lesson, only concern is that we're representing Geometric as a continuous curve though it should be discrete. Another approach for (c) and (d) using cumulative approach: (c) P(X
Yes,I a just thinking about that and realize something is wrong, In the video I don't understand the process but the cumulative process is good I think.
I've gain alot from this video,thank you so much...kindly do for me this question. Identical independent trials are carried out .The probability of successful outcome is P.On average five trials are required until a successful outcome occur. Find,(i) P (ii) the probability that you succeed for the first time in the fifth trial.
I know I'm late but after trying this problem for myself I got P=1/5 and the probability that you succeed for the first time in the fifth trial as 8.2%. Not 100% sure though.
For question 5, parts d&e, you get the "central region probability" of 1 - (1-q^n) - q^N = q^n - q^N where N>n such that the probability is positive definite
Exactly, P(a _< X _< b) = P(X _< b) - P(X _< a-1) = 1-q^b - (1-q^(a-1)) = q^(a-1) - q^b If X can be equal to "a" then you have to subtract 1 to only remove probability of outcomes before "a". but... P(a < X _< b) = P(X _< b) - P(X _< a) = 1-q^b - (1-q^a) = q^a - q^b
your explanation is great. But I have a doubt in 3 rd question. It is mentioned that every 10th person is a teacher but it is not mentioned anywhere that first 9 person are not teachers
I thought the same thing. If we don't care what the first 9 people are, then since encountering one person is an independent event, the probability that the 10th person we meet is a teacher is just 4%.
In the questions where asked to find P(X > x), why is the upper limit infinity instead of 100, since in the question it has been mentioned that 100 random samples were used for testing.
~8mins into the video, what is the explanation for mean = 1/p ? What does the mean refer to, and what does the variance/std deviation refer to in this case ?
Table of Contents: 1. Introduction (00:00:00 - 00:00:07) 2. Probability of Getting a Specific Outcome on the Fourth Try (00:00:07 - 00:01:55) 3. Formula for Calculating Geometric Distribution (00:01:55 - 00:02:11) 4. Probability of Seeing the First Blue Car on the Seventh Car (00:02:11 - 00:03:55) 5. Probability of Encountering a Teacher as the Tenth Person (00:03:55 - 00:07:36) 6. Mean, Variance, and Standard Deviation Calculation (00:07:36 - 00:09:06) 7. Probability of Selecting a Defective Tire as the Eighth Tire (00:09:06 - 00:10:48)
i love it how you write down so many digits after the 0... i thougt i was the only one in this world doing this.. at least i was the only on at my class xD
"1 - P(X≤14) - P(X≥31)" is a long and consuming way. Why not, instead and simply, subtracting the probability of (X≤14) from the whole probability of (X≤30): (1 - (0.98)³⁰) - (1 - (0.98)¹⁴) which is still equal to 0.20816. Likewise, instead of "1 - P(X≤20) - P(X>45)" we subtract the probability of (X≤20) from the whole probability of (X≤45): (1 - (0.98)⁴⁵) - (1 - (0.98)²⁰) which is equal to 0.26473 as well. In addition, a simpler way to deduce and remember why P(X>X) is equal to "q^x" is that P(X>X) and P(X≤X) are complements, if the probability of (X>X) is the probability that "X" and all initial trials preceding it fail "q^x" then the probability of the residual (X≤X) must be "1 - q^x" which is the same as saying the probability that all trials fail except "X" and what precedes it.
@@lifeinvestments3954 : it’s not a minor mistake. Each random variable describes a particular event. Geometric r.v count the number of trials needed to get the first success or the number of failures needed to get the first success. Note here that, the first success is running into the first teacher to be the 10th person we meet. Or you meet 9 people and they are all not teachers, then you finally meet the 10th person who is a teacher. Understand what r.v the video is about and it’s properties before you confuse yourself,
@@Keithustus : Bro, you don’t know shit, there is no mistake in the video. If you don’t understand something, ask. I am using this video as a review. I am an applied math grad. I had A- in prob, I assure you, anytime you think his video is a mistake, it is guaranteed you don’t understand what he is teaching. If you don’t understand, ask, don’t be ungrateful and shit on the video.Humble yourself and ask for explanation. I just explained the 10th person to be a teacher scenario to someone.
@@yaweli2968 it’s not a mistake in “the math” it’s a blatant mistake in SPEAKING about the math. If you talk with people who use math and not just those who study it, you’ll see the difference.
The 10th teacher solution you present is undercounting. 10 consecutive teaches is a valid example of a configuration where the 10th person is a teacher. You are solving for "the first" teacher being the 10th person you meet
It’s a geometric r.v for a reason.You know as well that the first 9 ain’t teachers, if that be the case, it will just be the prob of meeting a teacher to the 10th.
#3(a) should be just straight probability, not the formula. In the first two, the question was about the xth event being the first success, whereas in #3 the question is about the xth event simply being a success independent of the earlier samples.
23:50 you tried to get P(X > = 18), and stated that P(X>=18) = P(X >17) . This is a continuous distribution, so didn't you ignore that P(X>=18) should not include P( 17
You will probably think P(X>=18) should be P(X>=17.5) in the normal case with a correction factor, but the geometric is not continuous so it makes sense when you drop the “=“.
I had a doubt... In the 4th question, wouldnt the ques be based on binomial distribution? as it says a random sample of 100 tires is taken. N= 100 right?
Probability - Free Formula Sheet: bit.ly/3zb22rW
Final Exams and Video Playlists: www.video-tutor.net/
Next Video: ruclips.net/video/m0o-585xwW0/видео.html
"The organic chemistry tutor", you are too much!
what i always wonder about you is that you are almost everywhere in the mathematically oriented courses. I thank God for blessing us through you!
KEEP IT UP SIR, FOR YOUR WORK IS SAVING CONFUSED SOULS.
0:00 Q1: Geometric Distribution
2:22 Using a formula
3:59 Q2: Car Example.
6:09 Q3: Teacher
Mean, Variance and Standard Deviation
9:10 Q4: Tires
A life saver for someone helping get a high school student through probability and stats. You are a God-send. Thank you.
And I wish you had been here when I was taking graduate stats. For real.
Just joined University this year 😂
You cant imagine the amount of help I am getting from your videos 😢
Such amazing work .
At 30:19 I was thinking to myself, "I wish he put all the formulas he used in one place". Less than 3 seconds later my wish was answered. Excellent video mate. Not once did I feel the need to rewind. Thank you
You are absolutely right!
Thank you so much! Your video made the basics of statistics more clear than any other learning experience so far in my life. You are brilliant!
I am having an unexplainable amount of trouble with random variables as a whole, thank you SOOOOOO much for publishing this. You are God sent, I hope you have the most amazing day ever because you surely made mine better.
Dude, this channel really helped me in chem. You a real one.
This is so simple and yet my teacher couldn't explain it in 20 minutes. :D
Some people just not qualified to be teacher
My teacher explained it for 1 hour and somehow made it more confusing
Send your teacher this video!!
Of course he couldn't,,,,, this video is 32 minutes
Thank god for this video! Finally got the right answer to my homework problem after maybe a million tries! Thanks for your hard work and easy to understand explanations!
cant expect any better explanation than this!!!!! Such a lifesaver channel
Thanks Brother for this video i learn Too much from this nice technique getting us understand by questions
this video is so amazing, I came for Geometric Distribution explanation, I ended up finding heaven
Thank you, I know I am going to pass the coming exams because of you!!!
Great lesson, only concern is that we're representing Geometric as a continuous curve though it should be discrete.
Another approach for (c) and (d) using cumulative approach:
(c) P(X
Yes,I a just thinking about that and realize something is wrong, In the video I don't understand the process but the cumulative process is good I think.
I understand everything this guy explains!!!!!
Hi, I want to ask regarding the last question where we were looking for P (15
I've gain alot from this video,thank you so much...kindly do for me this question. Identical independent trials are carried out .The probability of successful outcome is P.On average five trials are required until a successful outcome occur.
Find,(i) P
(ii) the probability that you succeed for the first time in the fifth trial.
I know I'm late but after trying this problem for myself I got P=1/5 and the probability that you succeed for the first time in the fifth trial as 8.2%. Not 100% sure though.
@@Joe-un1tl Sorry for the late confirmation but I got the same thing as you so you are probably right.
For question 5, parts d&e, you get the "central region probability" of 1 - (1-q^n) - q^N = q^n - q^N where N>n such that the probability is positive definite
Exactly,
P(a _< X _< b) = P(X _< b) - P(X _< a-1) = 1-q^b - (1-q^(a-1)) = q^(a-1) - q^b
If X can be equal to "a" then you have to subtract 1 to only remove probability of outcomes before "a".
but...
P(a < X _< b) = P(X _< b) - P(X _< a) = 1-q^b - (1-q^a) = q^a - q^b
How much u make a year, you should make 10x that cause you’re the best teacher ever
The most wonderful explanation i have ever seen . Keep up the good work sir
Thanks!!!You gave me so much information that my teachers hadn’t covered in an 80-minute class🤣👍🏻
This man is a God send.
I don't know why when you said "I lost my train of thought" made me laugh so much.
Your work is saving me so much, thank you so much
3 yrs in high school and 2 yrs in college, thanx for carrying me man
your explanation is great. But I have a doubt in 3 rd question. It is mentioned that every 10th person is a teacher but it is not mentioned anywhere that first 9 person are not teachers
I thought the same thing. If we don't care what the first 9 people are, then since encountering one person is an independent event, the probability that the 10th person we meet is a teacher is just 4%.
Wish I had found the channel earlier. Its explained in such an easy manner.
Awesome 🎉 please do a video on hypergeometric distribution please 😢
This came just in time for my quiz tomorrow
This video saved my life❤❤❤
Gosh thanks for the guide. I have a test tomorrow and you just saved me!
Thank you. This'll help me get food on the table soon ✌️
God bless you, your channel is inspirational 😊
can you do a video on negative binomial distribution? there are no good tutorials
Thanks homie, my stats grade thanks you
you are better the my University teacher 😊
How to differentiate between geometric distribution questions and binomial distribution questions?
This is an excellent video. Very well explained.. great job.
I love you, organic chemistry tutor. I freaking love ya, man. You are to me as noob noob is to Rick Sanchez, only..you're a brilliant tutor.
this content helps me a lot bro
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You are the best of all the bests 💯💯💯
In the questions where asked to find P(X > x), why is the upper limit infinity instead of 100, since in the question it has been mentioned that 100 random samples were used for testing.
Any videos on
*Hypothesis Testing*
Or
*Confidence Intervals*
~8mins into the video, what is the explanation for mean = 1/p ? What does the mean refer to, and what does the variance/std deviation refer to in this case ?
Awesome formulas and great explaination
love how u say formula and calculator
You are a savior
One of the best explanation
Thank you sir
Appreciate it ❤️❤️❤️
Table of Contents:
1. Introduction (00:00:00 - 00:00:07)
2. Probability of Getting a Specific Outcome on the Fourth Try (00:00:07 - 00:01:55)
3. Formula for Calculating Geometric Distribution (00:01:55 - 00:02:11)
4. Probability of Seeing the First Blue Car on the Seventh Car (00:02:11 - 00:03:55)
5. Probability of Encountering a Teacher as the Tenth Person (00:03:55 - 00:07:36)
6. Mean, Variance, and Standard Deviation Calculation (00:07:36 - 00:09:06)
7. Probability of Selecting a Defective Tire as the Eighth Tire (00:09:06 - 00:10:48)
i love it how you write down so many digits after the 0... i thougt i was the only one in this world doing this.. at least i was the only on at my class xD
Question: At the 27min 33 secs, it says P of X greater or equal to 31 is P of
X greater than 30. I think it should be P of X smaller than 30?
Thank you for all you do 😊
Thank you so much, you're literally the best.
can you heart my comment shows that you're human.? cause I'm really impressed with the way you teach.. thank you, sir!
Thank you for this very clear explanation!
Regarding the tyre question, your sample is 100 tyres, so Q. (B) should be rephrased ‘among the first five tyres in the sample’
These videos always help me :)
beautifully explained as always!!! thank you
Thank you very very much brother u saved me from failing
best teacher !! 😊😊😊
Can you please help with hyper geometric distribution
I appreciate your effort sir
A question...X is a geometric P and to succeed in the second time your chance is 0.1275 suppose P>0.5 find
P(x>2)
P(x
Very tricky question, If were told X is a geometric P than P(x>0.5), P=12.75%, and what I believe the trick is here is to combine the P(X>2) and P(
"1 - P(X≤14) - P(X≥31)" is a long and consuming way. Why not, instead and simply, subtracting the probability of (X≤14) from the whole probability of (X≤30): (1 - (0.98)³⁰) - (1 - (0.98)¹⁴) which is still equal to 0.20816.
Likewise, instead of "1 - P(X≤20) - P(X>45)" we subtract the probability of (X≤20) from the whole probability of (X≤45): (1 - (0.98)⁴⁵) - (1 - (0.98)²⁰) which is equal to 0.26473 as well.
In addition, a simpler way to deduce and remember why P(X>X) is equal to "q^x" is that P(X>X) and P(X≤X) are complements, if the probability of (X>X) is the probability that "X" and all initial trials preceding it fail "q^x" then the probability of the residual (X≤X) must be "1 - q^x" which is the same as saying the probability that all trials fail except "X" and what precedes it.
This is the best video! Thank you!
Please 🙏 Is there any video regarding hypergeometric distribution?
This is awesome. Thanks for making me understand
you are the GOAT
This was so helpful, thank you so much!
Hi the video really helps me a lot but I need help with simplifying
Thanks for this amazing video. but I have a question, in Q3, why did you assume that the first 9 people I counted must not have any teacher!?
That was my concern but I think it's just a minor mistake
Same mistake in 4(a) too. That’s when I stopped watching this crap.
@@lifeinvestments3954 : it’s not a minor mistake. Each random variable describes a particular event. Geometric r.v count the number of trials needed to get the first success or the number of failures needed to get the first success. Note here that, the first success is running into the first teacher to be the 10th person we meet. Or you meet 9 people and they are all not teachers, then you finally meet the 10th person who is a teacher. Understand what r.v the video is about and it’s properties before you confuse yourself,
@@Keithustus : Bro, you don’t know shit, there is no mistake in the video. If you don’t understand something, ask. I am using this video as a review. I am an applied math grad. I had A- in prob, I assure you, anytime you think his video is a mistake, it is guaranteed you don’t understand what he is teaching. If you don’t understand, ask, don’t be ungrateful and shit on the video.Humble yourself and ask for explanation. I just explained the 10th person to be a teacher scenario to someone.
@@yaweli2968 it’s not a mistake in “the math” it’s a blatant mistake in SPEAKING about the math. If you talk with people who use math and not just those who study it, you’ll see the difference.
Am having my final Stat 112 exam today
Why mean is 1/p? What does "mean" represent here?
awesome explanation sir..
Hello may i ask, The Question Number 3 how can q= 0.96 the answer??
for region A , Why is it less than or equal to 14 instead of 15??
just a small doubt regarding q5 sub part c shouldn't x be 18 and not 17. thnx
Thank you so much❤
The 10th teacher solution you present is undercounting. 10 consecutive teaches is a valid example of a configuration where the 10th person is a teacher. You are solving for "the first" teacher being the 10th person you meet
It’s a geometric r.v for a reason.You know as well that the first 9 ain’t teachers, if that be the case, it will just be the prob of meeting a teacher to the 10th.
wait @29:12 , why are we doing x < or equal to 20 rather thanjust less than (& same for 45)?
Hi, regarding the formulas at the end of the video. Are those also applicable to binary distribution or exclusively to geometric distribution?
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Indeed we want to see the face. This man has really helped me. I wish I could meet him in person
@@derek949 Breaking Bad😂
You go wait tire
#3(a) should be just straight probability, not the formula. In the first two, the question was about the xth event being the first success, whereas in #3 the question is about the xth event simply being a success independent of the earlier samples.
Thank you very much !
Thanks for explanation❤
I really respect you,
Thank you
Awesome video
23:50 you tried to get P(X > = 18), and stated that P(X>=18) = P(X >17) . This is a continuous distribution, so didn't you ignore that P(X>=18) should not include P( 17
You will probably think P(X>=18) should be P(X>=17.5) in the normal case with a correction factor, but the geometric is not continuous so it makes sense when you drop the “=“.
Thank you so much
I had a doubt... In the 4th question, wouldnt the ques be based on binomial distribution? as it says a random sample of 100 tires is taken. N= 100 right?
as geometric distribution can have infinite trials
multinomial distribution please
with mean and variance.. please with examples
thank you so much
what if the second problem were ask us what the probability is of the 7th car to be the 2nd blue one ?
THANK YOUUUUU
Fun fact, the probability that you will meet a teacher after the second encounter, is higher than the probability of meeting a teacher after the 10th.
sorry finding the mean of a geometric distribution as finding the previous mean in the other video you gave as n*p ??