How much weight can a timber wall carry?
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- Опубликовано: 2 фев 2022
- I show you an easy way to calculate the loadbearing capacity of a stud wall.
🚀Get the tables used in this video: geni.us/timbercalculation
What if you could easily calculate how much weight a stud timber wall will carry? It means you could create load bearing walls to carry just about anything you want. And you will be surprised when you watch this quick tutorial how easy it is to work out studwork load capacity using just a Sharpie pen and a calculator!
Check out my more in depth tutorial here: • The EASY WAY to do a T...
Timber calculations playlist: • Structural timber calc...
None of the information in this video should be deemed as advice. I cannot comment on your individual project, and you should contact a local structural engineer for advice before working on any loadbearing structure. 
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ℹGet the tables used in this video: geni.us/timbercalculation
LOVE IT! Thanks for using units and properly cancelling out...unit analysis helps me grasp things easier. THANK YOU!
Excellent. Your videos are so helpful Robin. Thanks for sharing
Very useful and straightforward.
Fantastic info. Ta for posting! 👍
coolest stuff as always
Hello @Robin
What I am trying to do is
I have bolted two timber joist C16 47 * 150 mm graded horizontal to each other in the wall with M12 196mm RawalBolt 6 in each timber to wall,
and then hang 10 joist on those two timbers with the help of the hangers and then cover the top with edges osb to create a ceiling. Now question is that How much weight two joist 47*150mm 3.6meter bolted to the wall with 10 joist 47*150mm 3.6 meter handing of the these two joist bolted in the wall can hold? WOuld it be Strong enough to live on that ceiing?
someone told me that either I should double the number of bolts or give a support with steel bar but my joiner thinks there is no need for it. any Sugessions? Thanks in advance. I would really appreciate if you can answer this
He'll not answer it as that's a money making job for an Engineer in this capitalist society 😂 c'mon Engineers paid for their degrees, let them earn back.
Fantastic video as usual!
The K12 factor of 0.23.... on the chart when you marked your dotted line, reads 0.26, where did the 0.23 come from please.
Hi Liam. It's an interpolation between the figures of 0.26 and 0.21, because the slenderness ratio of 38 didn't exactly fit.
@@RobindeJongh thank you, Robin. I understand now 👍
Thanks for the video Robin - very interesting.
However, I find it hard to believe that a piece of timber of this size can only support ~350Kg of mass (3.5kN force). Instinctively I would expect it to take a lot more force along its length before it failed. Can you please clarify for a non civil engineer (I'm an electronics and computing engineer) if this is the force at which you would expect the timber to fail or if it's more to do with regulations and perhaps deflection/compression dimensional changes? Surely it would take several times this much force to actually cause catastrophic failure of a piece of timber like this?
Hi Craig. Great questions! Firstly, it is the buckling that would cause it to fail. If the timber was held fully in position along its length in both directions then it would be capable of much more. This is the 0.23x factor. Secondly, there is a safety factor built in to the value for allowable stress.
@@RobindeJongh Thanks Robin. This is really useful. Can I check my understanding by asking a question related to Craig's? I have been modelling a similar stud wall where the critical axis is the minor axis. Am I correct in thinking that if the timber member is fully held in position along its length in the minor axis (e.g. by nailing sheathing to both sides of the wall with a structural panel of adequate strength) this would mean that the non-critical axis would then become the critial axis for buckling?
@@tlangdon12 Spot on!
@@RobindeJongh Thanks
Cool...tnx
What would you recommend; I want to hang a cafe racer on a shelf above my fireplace. Fire place is a bump out and cafe racer will be approx 350lb (157kg) 4.5ft feet.
Hey Scott, I had to look up what a "cafe racer" is 🤣 Actually this sounds like quite a challenge, because it's not only heavy but also its centre of gravity is away from the wall, meaning a large moment is produced. You might need some purpose made frame hidden in the wall. Why not beef up the ceiling and hang it?
hi Robin i have a lamenated timber bin 250mm x 100mm x 6.200mm length how much weight i can put on it thank you in advance
23,267.61 lbs
So are you saying we can hang 350kg off one stud with the right fixing? For example wall mounting a battery system.
The calculated strength assumes that the load is applied to the top of the wall. Hanging something off it would be an eccentric load, thus reducing the loadbearing capacity.
@@RobindeJongh makes sense. this would be a more practical number to know.
Also there must be a force where the screw will just rip out of the wood. Seems like it would be a complex calculation.
Great video Robin. So max weight would be 350kg per vertical. Assume from analysis that wall would tend to bow outwards as a failure mode then. Interesting you might generally use such size timber for non-structural partition, but assume you are illustrating the principle for larger sizes employed in structural scenarios. Interesting that is planed "2inch x 3inch" and standard CLS size should be 68mm x 38mm so either they sold you a bit short (or its shrunk since being planed). In the other plane the OSB or plasterboard would also help the nogins (and that would be true in a flooring scenario rather than the wall you are looking at in this video). Many thanks again.
Hi John. This is the 38x63 CLS stuff you get at Wickes and B&Q, so I thought I would see how much weight it can take. I've had the offcut lying around fo a while so it's probably bone dry and has shrunk!
@@RobindeJongh I thought it looked nicely seasoned
@@RobindeJongh I though 350 Kg was a good result for a relatively small cross-section.
Provided it doesn't bend and latterally supported. or else it can't withstand that much can it. So all the equations still need to pass including slenderness, buckling checks etc. Unfortunately analysis then design is not that simple is it, even for an engineer.
That’s precisely what the video shows. The value from the table takes slenderness into account.