Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html Full-Length Exams and Worksheets: www.patreon.com/MathScienceTutor/collections Next Video: ruclips.net/video/_H7ANeZ4iL8/видео.html
hello sir, i'm wondering what it's take and how long it's take for you to understand this stuff let along teach it clearly in the most simple way ever? I'm amazed. I want to understand stuff till I can explain it just like you did.
Say there is a molecule (a triene) in which a bulky base is used to to create a hoffman product via an E2 reaction. The first option will result in a cis disibstituted pi bond. The second option will result in a geminal disubstituted pi bond. There is also a trisubstituted pi bond possible towarss the middle of the alkene. Will the major product be the cis or geminal alkene? What drives this? Stability of the carbocathion? Steric hindrance? Stability of the end product?
The size i believe because its size is what determines the polarizability (ability to stabilize the charge). Therefore I- or Br- are better leaving groups than say F- and Cl-
The reason why the Hoffman product forms while e2 elimination of fluorine is due to enthalpy of the fluorine carbon and that's why it dont want to go easily at least that's what my profesor says
I have two orgo professors both highly respected in their fields, both had different reasoning. Consensus is that no one exactly knows, there’s 2-3 hypotheses as to why Fl- is Hoffman
If E2 is favored with a polar aprotic solvent is there a reason you use methanol for many of the solvent examples? Thanks for the video, super helpful for a quick MCAT review! Edit: type
The big, bulky base (tert-butoxide) cannot penetrate into the center of the molecule to deprotonate those Hydrogens (remember, the space-filling model: those electron clouds in the middle carbons are large). So, the only H the base can reach are the terminal ones on the end. Therefore, the Hoffman product forms, even though its technically less stable than Zaitsev. It is the only E2 reaction that can feasibly take place there.
But why does is the conjugated product formed? The MeO- doesn't know it has to make the conjugated product, it has no brain. Does the double bond already draw electron density from the a-CH bond to make it more likely to break before it happens?
Both the products are formed in the reaction the conjugated diene is majorly formed as it is more stable . the reactions occus so as the products have a lower Potential energy than the reactants is their is reconance then the stability of the alkene is more so this is the only reason why a cinjugated di ene is formed in major.
Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html
Full-Length Exams and Worksheets: www.patreon.com/MathScienceTutor/collections
Next Video: ruclips.net/video/_H7ANeZ4iL8/видео.html
not sure how my professors make it so complicated when you can clearly explain it to us in such clarity
zoned out of my three hour class and had no idea what was going on. Watched this 12 min video in class and now I'm ahead of everyone.
I swear most organic chemistry lectures are never understandable 😂
Yes you are correct! My
teacher does not teach in organized way. We learn simple concepts but given advanced problems lol
@@lmthagod328 😭
@@kylet6612My teacher too is like that 😭. Proof that we all live the same life 😂.
3 hours I've been zoning out my whole college life , lyf sucks for me .
I think you will save my life for my medical school entrance exam!! I really struggled in Organic Chemistry during finals!
Listen i am struggling. Chemistry was never my strongest science ! and i need this class to stay in my nursing program !
@@domoo2639 hope you succeed!
Thanks for clearly explaining the nooks and corners which are not that commonly taught. Really helpful!
Lmaoo sameeeee 😂😂😂
Oh my gosh I’ve been looking for the fluorine example everywhere! Thanks for explaining!
Best Organic Chemistry Tutor EVERRRRR! I love u man! I salute you!
So simple and straight to the point!
Thank you soo much helped me a lot for my 12th grade exams😀
A lot of thanks, Brother!
You cleared my prolong confusion.
hello sir, i'm wondering what it's take and how long it's take for you to understand this stuff let along teach it clearly in the most simple way ever? I'm amazed. I want to understand stuff till I can explain it just like you did.
You will, The key is to NEVER GIVE UP !!! You are capable of doing what he does, and so much more !!
Hi
I pray for this man alot
Thank's so much! quiz on this tomorrow, really helped : )
Same here now and it's midnight 😭
@@alessiailas4929 good luck!
@@alessiailas4929 1am 😅
I owe my life to you sir,
Thanks alot all my doubts is now cleared 😊
Say there is a molecule (a triene) in which a bulky base is used to to create a hoffman product via an E2 reaction.
The first option will result in a cis disibstituted pi bond.
The second option will result in a geminal disubstituted pi bond.
There is also a trisubstituted pi bond possible towarss the middle of the alkene.
Will the major product be the cis or geminal alkene? What drives this? Stability of the carbocathion? Steric hindrance? Stability of the end product?
didnt really explain what an e2 reaction is and how it works, do you have a video on that?
Thank you bro
Have a great day....
You're a lifesaver
now is hoffman product the minor or the major because once the minor was hoffman then the major was hoffman
what makes a good or bad leaving group?
The size i believe because its size is what determines the polarizability (ability to stabilize the charge). Therefore I- or Br- are better leaving groups than say F- and Cl-
The reason why the Hoffman product forms while e2 elimination of fluorine is due to enthalpy of the fluorine carbon and that's why it dont want to go easily at least that's what my profesor says
I have two orgo professors both highly respected in their fields, both had different reasoning. Consensus is that no one exactly knows, there’s 2-3 hypotheses as to why Fl- is Hoffman
Its excellent sir I learned a lot thank you so much sir
You are the BEST ! Thank you very much !
All doubt clear sir thnks❤
If E2 is favored with a polar aprotic solvent is there a reason you use methanol for many of the solvent examples? Thanks for the video, super helpful for a quick MCAT review! Edit: type
i was thinking the same thing! i was so confused
What about when its an alkyl group connected to a benzene ring, kinda need to know how to find the minor product there don't we....
Dude saved my finals for the 5th time
Helped a lot.. thanks
Thank you so much
Thank you once again.
Do i need to put the major product of the bad leaving group vice versa?
Any JEE/NEET aspirant☝️☝️☝️
Haa bhai, JEE 2025. Halo arenes and amines ke PYQ me bohot use hota hai E2 mechanism
super helpful.
just to know, in what grade /year do you learn this
me- 12th grade
Great explanation!
for -O-CH(CH)3, will its preference be 1>2>3 because of steric hindrance?
It will actually prefer 3>2>1 for E2 and E1
So in both the E1 and E2 reactions, both the minor and major product always form if possible?
Yes bcz both are regioselective ( can give major and minor products) and sterioselective ( can form cis and trans product) also.
Now I am maestro after 12min watching
Thank sir
Is it Saytzeff or Zaitsev??
both spellings are valid
Thanks !!!
god bless you
6:22 why is the major product Hoffman????
The big, bulky base (tert-butoxide) cannot penetrate into the center of the molecule to deprotonate those Hydrogens (remember, the space-filling model: those electron clouds in the middle carbons are large). So, the only H the base can reach are the terminal ones on the end. Therefore, the Hoffman product forms, even though its technically less stable than Zaitsev. It is the only E2 reaction that can feasibly take place there.
But why does is the conjugated product formed? The MeO- doesn't know it has to make the conjugated product, it has no brain.
Does the double bond already draw electron density from the a-CH bond to make it more likely to break before it happens?
Both the products are formed in the reaction the conjugated diene is majorly formed as it is more stable .
the reactions occus so as the products have a lower Potential energy than the reactants is their is reconance then the stability of the alkene is more so this is the only reason why a cinjugated di ene is formed in major.
Thanks nro
You are officially the final evolution of Bill Nye
bro cooked
Hi I am new quite so 0:08
I can’t understand you sorry this didn’t help
I hate organic it’s aweful