Thank you for consistently putting out all these videos. I appreciate you going back over the basics like this video. Im going to school to become a highschool chemistry teacher and i plan on using alot of your techniques so thank you again.
In India it's thought in high school in depth of application to it. Like we literally had 4 chapters linking to it. "Great Video And Awesome Explanation" Love from India🇮🇳😍
I get why markovnikov addition proceeds because a primary carbonation is unstable, but then what would be favorable about having anti-markovnikov addition and how would we know when those happen instead?
I am not an expert but During some reactions ( reactions which follow Anti Markonikov rule) free radicals are formed When we react butane(CH3CH2CH2CH3) with HBr and ROOR Br reacts first and forms a free radical as follows A Transition state is formed CH3CH2CH(Br)CH2• (here • represents free radical) Now the we will stabilise the free radical CH3CH2CH•CH2Br The free radical is more stabilised due to hyper conjugation hence now the H• atom will attack the free radical forming CH3CH2CH2CH2Br or 1 bromo butane Hope this helps 👍🏼
7:19 why does this reaction not include a hydride shift? You have explained earlier in the video that the more stable Carbocation is formed which is in this case a secondary carboncation. But now there is a secondary carbocation adjacent to a tertiary carbocation, wouldnt someone expect a hydride shift?
because when you go inside their mechanism, an actual free carbocation is never created, in the case of oxymercuration reaction, a cyclic carbocation is created where no rearrangement is possible, hence the tertiary carbocation is not formed
I love all your videos, and its really awesome, it seems like you have mastered all the known subjects, God Bless you and your family, I want to really understand the concept of how the reaction mechanism works.....
Can you do some videos on some more advanced concepts such as rearrangements, maybe some reactions such the Wittig reaction and other carbonyl reactions.
@@ayanleahmed1316 well it depends on your level. This channel has mainly been doing intro organic chemistry vids so the wittig would be quite advanced in comparison. Also explaining the stereochemical outcome isn’t simple.
@@ayanleahmed1316 That’s incorrect. You add a carbonyl compound to a phosphonium ylide not a phosphorane. And would you be able to explain the stereochemical outcome?
Hey, I've trouble to understand the reaction with on of your example with Hg(OAc)2. What does this Hg-molecule do (in detail)? Do you have a video that already covers this topic?
@@fruityliciousk2704 just wondering, so it is different from react with HBr which has a hydride shift that Br ion attacks tertiary carbocation instead?
The hydrogen atom is attached to the carbon atom with the larger number of hydrogens while the halogen (negative ion) is attached to the carbon atom with the lower number of hydrogens
markovnikov’s rule is just saying that the heavier atom will add to the more substituted carbon (a Br will add to a tertiary carbon over a secondary carbon)
I think on 1 minut and 45 seconds of the video, you said," the hydrogen is gonna go to this carbon, the one with the most number of CARBONS" I think you intended Say "hydrogen"
you said in two different markovnikov reactions that the H would go with the best sub carbon but then you said the H will go with the least sub carbon. Which is it?
He chose not to waste time drawing the second line indicating double bond. Very very strange and confusing. I do not know why this time saving thing was done.
I think it’s because the first compound (pent-2-ene) has a double bond where both carbons in the double bond are secondary, so the halogen (Br) has no preference to bond to, for either carbon in the double bond. That’s why the Br bonds 50% of the time to each carbon in the double bond. But for the second compound, but-1-ene, the double bond has a primary carbon and a secondary carbon, so the Br prefers to bond to the secondary carbon, which you understand follows Markovnikov’s rule.
This is so confusing to me. I don’t understand at all how to know what exactly the molecules with the arrow change the initial molecule to create different products.
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Thank you for consistently putting out all these videos. I appreciate you going back over the basics like this video. Im going to school to become a highschool chemistry teacher and i plan on using alot of your techniques so thank you again.
Ben Charlton copy car!!
I’m sad I don’t really watch these vids anymore because I’m done with chemistry for now but thanks for helping me get A’s!
We are done when I say we are done
thank you so much. this makes 100% sense now compared to my textbook 👌
In India it's thought in high school in depth of application to it. Like we literally had 4 chapters linking to it. "Great Video And Awesome Explanation"
Love from India🇮🇳😍
Taught*
And that's Indian education system! 🥺
@@xaej1he144 typo
*Taught*
Mr tutor ....
ur my best after my mother
I get why markovnikov addition proceeds because a primary carbonation is unstable, but then what would be favorable about having anti-markovnikov addition and how would we know when those happen instead?
That’s what I’m trying to figure out
I am not an expert but
During some reactions ( reactions which follow Anti
Markonikov rule) free radicals are formed
When we react butane(CH3CH2CH2CH3) with HBr and ROOR
Br reacts first and forms a free radical as follows
A Transition state is formed CH3CH2CH(Br)CH2• (here • represents free radical)
Now the we will stabilise the free radical
CH3CH2CH•CH2Br
The free radical is more stabilised due to hyper conjugation hence now the H• atom will attack the free radical forming
CH3CH2CH2CH2Br or 1 bromo butane
Hope this helps 👍🏼
u never disappoint bro
7:19 why does this reaction not include a hydride shift? You have explained earlier in the video that the more stable Carbocation is formed which is in this case a secondary carboncation. But now there is a secondary carbocation adjacent to a tertiary carbocation, wouldnt someone expect a hydride shift?
because when you go inside their mechanism, an actual free carbocation is never created, in the case of oxymercuration reaction, a cyclic carbocation is created where no rearrangement is possible, hence the tertiary carbocation is not formed
thank you sir organic has been hell for me since 11th grade.
So the hydrogen atoms wanna join the bois
I love all your videos, and its really awesome, it seems like you have mastered all the known subjects, God Bless you and your family, I want to really understand the concept of how the reaction mechanism works.....
Can you do some videos on some more advanced concepts such as rearrangements, maybe some reactions such the Wittig reaction and other carbonyl reactions.
Wittig reactions is simple
@@ayanleahmed1316 well it depends on your level. This channel has mainly been doing intro organic chemistry vids so the wittig would be quite advanced in comparison. Also explaining the stereochemical outcome isn’t simple.
@joshua , add a Carbonyl compound with phosphorane to form alkenes, this is a very simple way to prepare Double bond Hydrocarbons .
@@ayanleahmed1316 That’s incorrect. You add a carbonyl compound to a phosphonium ylide not a phosphorane. And would you be able to explain the stereochemical outcome?
THANKS A LOT SIR :>
Great revision, thanks
Bruh awsome channel🛐 you won my subscription🤭
Love from India 🇮🇳
My life savior!!!!
Excellent Explanation ❤
thank you so much ily!
Even if I jump in the cliff rn I really can't understand this lesson. AMEN
Hey, I've trouble to understand the reaction with on of your example with Hg(OAc)2. What does this Hg-molecule do (in detail)? Do you have a video that already covers this topic?
search for the oxymercuration demercuration video on his channel :)
search for the oxymercuration demercuration video on his channel :)
@@fruityliciousk2704 just wondering, so it is different from react with HBr which has a hydride shift that Br ion attacks tertiary carbocation instead?
How to know if it is anti markovnikov
If it has a peroxide,, i know im 2 years late 💀
@@circlefont you're just on time for me
i feel so dumb... i dont get this
me fr
The hydrogen atom is attached to the carbon atom with the larger number of hydrogens while the halogen (negative ion) is attached to the carbon atom with the lower number of hydrogens
You are not alone
He's explanation is complicated
markovnikov’s rule is just saying that the heavier atom will add to the more substituted carbon (a Br will add to a tertiary carbon over a secondary carbon)
I think on 1 minut and 45 seconds of the video, you said," the hydrogen is gonna go to this carbon, the one with the most number of CARBONS"
I think you intended Say "hydrogen"
Such a helpful video sir!!
5:45 Thank you, But seriously where did you find that OH. I mean that whole fraction has nothing to do with OH bruh.. Am I on the right video?
You are really great......I should admit that your voice is awesome... I'm simply addicted....
Where is the O-H group coming from in your examples?
All clear bro 👍
How do you know if you’re doing anti or not?
Someone said if there is hydrogen peroxide you are doing anti markovnikov
My orgo 1 final is in 3 days and you upload this.. can you read minds bro?
I love you man❤
thank you
Sir, are you a chemist?
good thing youtube nametags don't exist so we'll never know
Thanks a lot buddy 🙏🏻🙏🏻🙏🏻🙏🏻
you said in two different markovnikov reactions that the H would go with the best sub carbon but then you said the H will go with the least sub carbon. Which is it?
Why is there so much stuff in the reaction and how do we know what to use?
Only HBr and H3O+ will have addition at tertiary carbon rigy?
Thanks King!
Where is the double bond in pentane? There has to be one isn't it so? I mean in 1:17 minutes
He chose not to waste time drawing the second line indicating double bond.
Very very strange and confusing.
I do not know why this time saving thing was done.
When will you launch an astromy course..?
So why do you get a 50% 50% of Pent-3-ene and Pent-2ene ? I understood the second one because of Markovnikov's but why 50% for the first compound?
If you have an equal chance of getting either of two, in a macro scale, you get 50% of both. It's just probability.
I think it’s because the first compound (pent-2-ene) has a double bond where both carbons in the double bond are secondary, so the halogen (Br) has no preference to bond to, for either carbon in the double bond. That’s why the Br bonds 50% of the time to each carbon in the double bond. But for the second compound, but-1-ene, the double bond has a primary carbon and a secondary carbon, so the Br prefers to bond to the secondary carbon, which you understand follows Markovnikov’s rule.
What about pent-3-ene?👀😥
Respect 👍
I dont get why an not understanding this yet am writing my college exam three weeks from now.
This is so confusing to me. I don’t understand at all how to know what exactly the molecules with the arrow change the initial molecule to create different products.
You should watch his other videos
Basically, in a nutshell,
Nucleophile attack electrophile
commenting so more people see this
amazinggggggggggggggggggggggggggggggggggggggggg
МАРКОВНИКОВ КРУТОЙ МУЖИК БЫЛ!
Thank you you videos are very useful
🤔
I like science stress no problem 👍
Fr bro thats my rule
🙏🏻
Lol, does anyone else feel like he’s the Wizard in the Wizard of Oz? Can we see you? Lol
Hi
🤗
You teach well, thank you. But you speak a bit fast.
Nibondha chepavura
nenu koda atlanti confusion lo unnanu. chivariki neeku ardamainda?
Thanklsssss broooooo
Can you please marry me and teach me everything you know thank you 😄
Thank you