Alkene Reactions #1 - Narrated Answer Key

Here is a blank copy of the predict-the-product problem set: www.cpp.edu/~ls...
Here is a completed answer key: www.cpp.edu/~ls...
This is a predict-the-product problem set on alkene and alkene reactions (addition and reduction reactions).

[@yasmine2702]

Helped me so much in learning this chapter thank youuu!

[@nicolettesimonian2770]

why are u lying to urself

[@alexfrostbound4401]

Wonderful explanations!

[@parveshprashar2537]

Very awesome mam.Keep it up 👍😊

[@SS-pn7ss]

Great video, sums up a lot of ideas, thank u so much

[@yashdaryani8954]

for (I), wouldn't you have two compounds since both carbons are secondary carbons and so the bromine could either end up with carbon #3 or carbon #2 since they're equally stable?

[@THuuDo]

This is so helpful. Thank you!

[@justicegabriel9134]

Please explain how the structure came about

[@max3eey]

Please ask a question that makes sense

[@waheedgul9745]

Wonderful.......
God bless you.....

[@RT-ph2jm]

very informative! thanks!

[@sibahlendlovuenoughgirl5460]

First year thank you

[@harshpandey6311]

B will be syn or anti addition?

[@divyanshupal2460]

Thanks a lot ma'am .

[@Hipolito_S]

😂😂

[@divyanshupal2460]

Helped me in my revision

[@allesklar8636]

In problem D there is the formation of two tertiary carbocations. However the stabilization is the product of hyperconjugation. The position "1" with the methyl group gets stabilized by 3 C-H-bonds whereas in position "2" with the ethy group it should only get stabilized by 2 C-H-bonds since its -CH2-CH3. So im thinking that the more stable product ist the one wehre the Cl sits on Position "1". Am I thinking about this wrongly? Help or correction would be appreciated, thanks :)

[@Yourmom34577]

that's what I thought haha, I'm pretty sure it (the H) adds to the less substituted

[@BowlingwithMar]

Thank you so much omg

[@laurenbling5705]

Roci or racimic i can't see d handwriting

[@irmaanayancyramos3484]

For B, wouldn't it also be racemic?

[@Yourmom34577]

that's what I thought,

[@nastasiamijucic6791]

I don't think that the C with the OH and CH3 is a stereocenter, It Is only attached to 3 different groups not 4.

[@nathanneu6107]

@@nastasiamijucic6791 that was my thought also

[@VictorMutuku-cr7co]

Nice one

[@rameshgaurav4115]

In G 14:10 will there be no formation of hexane ?

[@nathanneu6107]

a little late, but yeah a hexane would form from rearrangement good catch lol

[@ShamithPrasad25]

no cuz cyclohexane is less stable than cyclopentane
if there was cyclohexane with a cation then yes with rearrangement it would turn into cyclopentane

[@chemistryourworld8261]

Nice

[@21geometrydash20]

what the fuck?