Great video explaining these reactions! My professor tends to lose me by going into too much detail and forgetting that we are not all professionals in OCHEM. This video gives me exactly what I need to know about each reaction in a simplified manner! Thank you!
So many professors forget that the reason they have students is that it is their job to teach chemistry to those who don't yet know it! I'm glad my videos are able to fill in where your professor is unable to
This was so great! It eliminated the need to review all the videos (that I have already watched several times while learning the concepts), in a compact, "remember these" concepts way. Perfect for day before finals review!
she is doing great, some of us cant afford to pay for you tube videos, for example me, am very poor from the most poor country. so stop influencing her that we should pay for her videos.
This was ABSOLUTELY amazing! Someone in my organic chem group sent this video to the gc and I was happy to watch it! With the situation of COVID my class has been stuck online and it is really hard to understand or ask for help... So, this video really helped out. Thank you!
I know that this is an older video, and I don't know if this channel is really active anymore, but this video is honestly going to be my saving grace for the exam I have tomorrow. Thanks, Leah!!
Thank you so much Leah, You are amazing. Your videos help a lot to understand the difficult concepts of Organic chemistry. I am watching all of them and this video is a summary for many chapters in my textbook. Thanks again and God bless you, wish you all the best Leah!
You are the best. I'm on the chapter of Reactions to Alkenes and it's a huge chapter to read. We have the powerpoint slides but the professor just goes through each slide which makes it hard to understand. Your video pretty much summed up most reactions that we reviewed in class. But now, I have a better understanding.
How do I know if a reaction will do an anti markovnikov addition or a markovinkov addition? Is it just purely memorizing which reaction does what or is there some trick
To understand why any given reaction produces a Markovnikov or anti-Markovnikov product, you must understand something about the reaction mechanism itself. Determining the favored product of the reaction is really all about identifying the reaction intermediate. In short, Markovnikov reactions usually have highly stable carbocation intermediates, while anti-Markovnikov reactions do not show a carbocation intermediate. For more on this, visit my tutorial at leah4sci.com/markovnikov
In this case there is no carbocation intermediate. The nucleophile (H2O) attacks the delta positive carbon on the bromonium. Because there's no true carbocation, no rearrangement
There's no 'free' carbocation in this reaction. Instead it's a partially positive carbon held in place by the bromonium. OH is attracted to the partially positive carbon and IN attacking, breaks the carbon-bromine bond. Without a free carbocation there is no shift
Hello, could you please explain to me the meaning of some substances written on reaction arrows, such as Zn-Hg, Zn(Hg), Zn-H2O, EtOH/H2O, BH3·THF? What do the parentheses (), dot (.), dash (-), and slash (/) signify in these cases?
From a stereochemical perspective, oxymercuration is an anti addition. This has to do with the formation of the mercurinium ion as an intermediate. The nucleophile cannot attack from the same side as the mercury because of steric hindrance. If you’d like to further break down any statements from your textbook, I’d love to do so in my Organic Chemistry Study Hall. For more information, go to studyhall.leah4sci.com/join
Im not sure if you realized but you contradicted yourself for the halohydrin. you mentioned that the halogen goes to the less substituted (markovnikov because more H bonds) but then you said that this is a markovnikov reaction because the solvent without the H adds to the more substituted carbon which is the opposite of markovnikov.
Thanks for watching and for your comment! I do not believe I contradicted myself. Halohydrin formation is a Markovnikov reaction because the nucleophile (in this case, the polar protic solvent) adds to the more substituted carbon. It is the solvent, not the halogen, that adds last in the reaction mechanism. For the complete breakdown of the reaction mechanism, visit leah4sci.com/halohydrin-formation/
Couldn’t believe I just found ur video this is very clear and helpful! I’ve been struggling with the products of these reactions now you’ve cleared my doubts thank you so much
If the pi bond reaches out to attack another atom, it only attaches to ONE of the 2 sp2 carbon atoms. The other will be a carbocation as a result of being abandoned by the bond
I don't have a video dedicated to the nomenclature of molecules with chiral centers. However, you will find these topics addressed in my free Chirality and Stereochemistry series where I walk you through how to identify R and S configurations for chiral molecules. Watch the series at Leah4sci.com/Chirality
everything was purely explained and thnc for clarifying some tricky things. But mem i only have ONE PROBLEM "HOW DO YOU SEE IF YOU AN HYDRIDE SHIFT"??????
Glad I helped clear things up for you. Regarding your questions, a hydride shift can occur in organic chemistry reactions that involve a carbocation intermediate. If such a rearrangement will place the carbocation on a more substituted carbon, then the hydride shift is highly favorable because of its ability to stabilize the intermediate. For more, visit leah4sci.com/hydride-shift-mechanism/
Thank you so much, our professor started this chapter on the last week of class. By watching this video before every class, it allowed me to get more familiar with the material and gradually add the mechanisms behind the results as they were discussed in class.
Thank you! I‘d be interested in hints at why and how a step can go wrong and the risks involved with specific reactions. I understand that is more than is asked in most chemistry education but it is very relevant in daily practice. I really like your colour scheme, we both share a trait 😉
I'm sure it's relevant in daily practice, but alas it is not something I can help with. I'm strictly a pen & paper chemistry tutor, I haven't been in lab for over a decade
Very good but only one question.... In the hydrohalogenation example, isn't the Cl going to go on the C that has the less H, being a Markovnikov reaction? Why does the Cl go on a C that has no pi bonds?
Listen to my explanation in the video one more time. For this example, there is a hydride shift that allows the carbocation to be formed on the more substituted, tertiary carbon. For more on the mechanism of a hydride shift like this one, I invite you to watch the following: ruclips.net/video/cSW9LDxtuoA/видео.html
Hi! I was wondering why there is a hydride shift in the hydrohalogenation, but not any of the others shown given that true same alkene is being used in each mechanism. Doesn’t each alkene reaction exhibit a carbocation intermediate, and if so, why do the other examples not go through a hydride shift?
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/ You can also view my free Alkene Reactions video series and cheat sheet at Leah4sci.com/alkene
I love your videos but I seem to need some background to understand this one because I could not be more lost. What is the prequel to this video? I was following the playlist/series..?
Think of this video as a short summary of all of the other alkene reactions presented in the series. As such, I would watch this video either first (as a preview of what’s to come) or watch it last (as a quick review of everything). For the entire series, in correct order, visit my website at leah4sci.com/alkene-reactions
Actually, no. The formation of the halonium ion intermediate prevents the possibility of a carbocation rearrangement. For more on this reaction, watch my video at ruclips.net/video/S-2CaHDhMfI/видео.html
It depends on the reaction/reagent you're using. For example, in an HBr reaction, the Br gets added on to the side of the pi-bond that is MORE substituted and the H gets added to the less sub carbon (this is Markovnikov addition). In contrast, an HBr reaction using ROOR (peroxide) as a reagent would follow Anti-Markovnikov addition ----> where the H would be placed on the more sub carbon and the Br would go on the LESS sub carbon.
Why do these have catalysts, like a Pd, that doesn't seem to react with anything. Mechanisms are the only aspects I'm stuck on before the finals. Also curious as to why it's in Hydrogenation but not Hydrohalogenation.
I'm sorry, but I don't provide tutoring through RUclips comments. For more help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
My Organic professor is terrible. Reads straight out of the book on an overhead and never works out any problems. Also makes you feel stupid if you ask for help. THANK YOU SO MUCH for these helpful videos. It's hard to teach yourself organic chem out of a textbook.
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
quick question, so these are just different ways/methods in breaking an alkene? because if so, these different ways can also be used with organic synthesis reactions? btw, your videos have helped me so much! so thanks for posting these great videos :)
+Leah4sci In the hydrohalogenation example, organic chem tutor would say that because the C is chiral you can have Cl on the dash and on the wedge, in racemic mix, is that also a thing?
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
To understand, we need to look more closely at the mechanism of the halohydrin formation. There is no carbocation intermediate formed, but rather a halonium ion which stabilizes the positive charge and prevents rearrangement. Check out more on this mechanism by visiting leah4sci.com/halohydrin-formation-alkene-reaction-mechanism/
you're really good but if you just talk a bit slower it will be much better cause i'm arabian and my english isn't pretty good so i needed to pause every 10 sec to realize what you just said.
I appreciate the feedback. I cant help talking fast. Use the RUclips speed feature to slow the videos down to 0.75x so that you can hear everything better
hii, thanks for the video, it was really helpful. but im still a bit confused at the Halohydrin process, according to what u said it should be following mark's rules, but if thats the case, why does the H-shift from tert-C to sec-C doesnt happen to form tert-Carbionium ion, since it would be more stable, and the end product would then be 4bromo 2methyl 2ol butan ?
im currently thinking its because of the intermediate, where both C of the double form form a bond with Br, which gives them the positive partial charge, and the H-shift doesnt like the positive charge so much, but the OH- ion does, thats why the OH-Ion jump right into the sec-C, but wouldnt that make it an anti marks product?
The intermediate is the key here! Rather than having any sort of hydride shift, what we see in this mechanism is the formation of a halonium intermediate where the halogen (in this case, bromine) forms a bridged intermediate across the former pi bond. But even in this bridged intermediate, we see a preference for the partial positive charge to fall on the more substituted position. Therefore, the alcohol comes in and attaches to that more substituted carbocation (the Markovnikov position) in the second step. For more on the mechanism of the halohydrin formation, make sure to see my video at Leah4sci.com/halohydrin
at 4:07 why does it look like both bromines are added to the same side? If the reaction is supposed to proceed with anti stereochemistry doesn't that mean both Br atoms come from opposite faces of the double bond? You only form the trans isomer right?
while you are absolutely correct this version of the product does not show stereochemistry as denoted by the lines rather than dashes and wedges. It does however state 'anti' to remind you that this is an anti addition
4:20- In another video, she explained that this is due to the polar bond formed between the H and O which gives the H a partial positive charge and negates it
Hello leah can you check back the oxidative cleavage with hot KMnO4 in your cheat sheet..? the 2nd products in the cheat sheet gives formic acid (HCOOH) but in your video 11:57 it gives CO2
I'm guessing the CO2 as the 2nd product is correct. After cleavage the unsubstituted carbon should become CO2, monosubstituted become COOH and disubstituted become ketone
Yes, you are absolutely right! Thank you for pointing this out. The correct second product of the oxidative cleavage reaction with KMnO4 would be CO2. A terminal carbon on an alkene will be fully oxidized. Again, thank you! We will correct the alkenes cheat sheet on our site.
Your videos are just mind blowing and amazing. Can you please make videos providing cheat sheets for chapters like carbonyl compound, carboxylic acids, phenols and ethers?
Great video explaining these reactions! My professor tends to lose me by going into too much detail and forgetting that we are not all professionals in OCHEM. This video gives me exactly what I need to know about each reaction in a simplified manner! Thank you!
So many professors forget that the reason they have students is that it is their job to teach chemistry to those who don't yet know it! I'm glad my videos are able to fill in where your professor is unable to
I'm gonna fail my test :(
join the club. i have a borderline failing average and am the top quarter of my class or so.
What did you do?
Big mood
Me too T_T
heyy it’s been two years, did you pass?
This was so great! It eliminated the need to review all the videos (that I have already watched several times while learning the concepts), in a compact, "remember these" concepts way. Perfect for day before finals review!
that was exactly the point! so glad to help
Make sure you try the practice quiz once you feel confident with all the reactions
Life changing so far. Thank you so much! I'm surprised you're providing videos of this quality for free.
she is doing great, some of us cant afford to pay for you tube videos, for example me, am very poor from the most poor country. so stop influencing her that we should pay for her videos.
@@mcmillanbanda6817 yabva....this comment though....tell them
@@mcmillanbanda6817 what country are you from
You're very welcome!
This was ABSOLUTELY amazing! Someone in my organic chem group sent this video to the gc and I was happy to watch it! With the situation of COVID my class has been stuck online and it is really hard to understand or ask for help... So, this video really helped out. Thank you!
Glad it was helpful!
I know that this is an older video, and I don't know if this channel is really active anymore, but this video is honestly going to be my saving grace for the exam I have tomorrow. Thanks, Leah!!
Yes, the channel is still active, I just get behind on my replies sometimes. So glad to help you with your exam!
Just want to express my appreciation to leah4sci, these videos really help me a lot 😊 you're the best 🤟
Happy to hear that!
I shall not fail orgo Chemistry again😭😭
Please don't! Take advantage of all of my free resources: leah4sci.com/syllabus
Leah can you plz explain the syn and anti addition by using cis and trans or E and Z isomers?1 I don't know how to show these effects!
I'm planning to do a video on this soon
Thank you so much Leah, You are amazing. Your videos help a lot to understand the difficult concepts of Organic chemistry. I am watching all of them and this video is a summary for many chapters in my textbook. Thanks again and God bless you, wish you all the best Leah!
You are very welcome! I'm glad the videos help :)
Thank you! God bless you!
You're very welcome
god bless u this is exactly what i needed
Glad I could help!
Thank you so much Leah!! I'm reviewing for the OAT and these videos for a quick recognition of the reactions is SO helpful!
You're so welcome!
:)
Thank god you exist, thank you so much!, you explain it so much better than my lecturer.
You're welcome, happy to clear things up for you!
Didn’t know Zooey Deschanel made orgo videos
Too funny! Thanks :)
You are the best. I'm on the chapter of Reactions to Alkenes and it's a huge chapter to read. We have the powerpoint slides but the professor just goes through each slide which makes it hard to understand. Your video pretty much summed up most reactions that we reviewed in class. But now, I have a better understanding.
That is so nice to hear! Thank you for the feedback. Glad to be of help :)
how can we apply the reaction on the alkene working backwards
Look at the clues you see in the products and ask 'what reaction do I know that will give me this product?' this is how I start
How do I know if a reaction will do an anti markovnikov addition or a markovinkov addition? Is it just purely memorizing which reaction does what or is there some trick
To understand why any given reaction produces a Markovnikov or anti-Markovnikov product, you must understand something about the reaction mechanism itself. Determining the favored product of the reaction is really all about identifying the reaction intermediate. In short, Markovnikov reactions usually have highly stable carbocation intermediates, while anti-Markovnikov reactions do not show a carbocation intermediate. For more on this, visit my tutorial at leah4sci.com/markovnikov
@@Leah4sci thank you, jus wondering do u cover content for organic 2
The video is still very hot despite the fact that it was uploaded 7 years ago. It seems like one uploaded yesterday, thanks 🙏
All thanks to my students who keep watching and making my stuff relevant! You're so welcome. :)
at 4:43 shouldn't the oh group attach to the tertiary carbon because of the stability of the 3° cabocation?
I was thinking the same thing. I expected a hydride shift
In this case there is no carbocation intermediate. The nucleophile (H2O) attacks the delta positive carbon on the bromonium. Because there's no true carbocation, no rearrangement
There's no 'free' carbocation in this reaction. Instead it's a partially positive carbon held in place by the bromonium. OH is attracted to the partially positive carbon and IN attacking, breaks the carbon-bromine bond. Without a free carbocation there is no shift
Hello, could you please explain to me the meaning of some substances written on reaction arrows, such as Zn-Hg, Zn(Hg), Zn-H2O, EtOH/H2O, BH3·THF? What do the parentheses (), dot (.), dash (-), and slash (/) signify in these cases?
Awesome! Keep up your brilliant effort. It's very2 helpful!
Thank you! :)
My textbook (Wade) says that Oxymercuration-Demurcation/Alko... has no stereochemistry, so there's no Anti/Syn
From a stereochemical perspective, oxymercuration is an anti addition. This has to do with the formation of the mercurinium ion as an intermediate. The nucleophile cannot attack from the same side as the mercury because of steric hindrance. If you’d like to further break down any statements from your textbook, I’d love to do so in my Organic Chemistry Study Hall. For more information, go to studyhall.leah4sci.com/join
during Halohydrin i thought a methal shift would occur to place the OH on the more stable carbocation?
at which point in the video?
Thank you Leah for this awesome video and providing the cheat sheet! This is so helpful!
You're very welcome!
Honestly never once liked these overview videos but this one is an exception. Amazing explanation and cheat sheet. Truly helpful!
I'm honored that this video is an exception for you. So glad you gave it a chance and found it helpful.
Im not sure if you realized but you contradicted yourself for the halohydrin. you mentioned that the halogen goes to the less substituted (markovnikov because more H bonds) but then you said that this is a markovnikov reaction because the solvent without the H adds to the more substituted carbon which is the opposite of markovnikov.
Dejure Jones omg I’m so glad you saw that too!
Thanks for watching and for your comment! I do not believe I contradicted myself. Halohydrin formation is a Markovnikov reaction because the nucleophile (in this case, the polar protic solvent) adds to the more substituted carbon. It is the solvent, not the halogen, that adds last in the reaction mechanism. For the complete breakdown of the reaction mechanism, visit leah4sci.com/halohydrin-formation/
So far this been the hardest topic in orgo1 for me thank you very much
You're very welcome, glad I could help!
holy moly... I finally found a video where someone is explaining the reaction in a digestable manner. all is well now.
So happy to help you understand!
Leah, I truly thank you for your videos! You are the O. chem Goddess!!!
Lol you are very welcome!
Couldn’t believe I just found ur video this is very clear and helpful! I’ve been struggling with the products of these reactions now you’ve cleared my doubts thank you so much
You're so welcome!
Love you Leah thank you so much. You cannot imagine how wonderful your talent is and how helpful you are.
Aww, thanks! You are so welcome!
Excellent ,awesome ,fantastic ,fabulous
Thanks so much!
This was an awesome recap ! thank you
You're welcome!
Leah, you are great.
awww! Thank you :)
i love you. thank you so much. this was so cut and dry and to the point
I'm glad you like it!
How do you know when a carbocation will form?
If the pi bond reaches out to attack another atom, it only attaches to ONE of the 2 sp2 carbon atoms. The other will be a carbocation as a result of being abandoned by the bond
You are simply the best m'am .Do you have any lecture on dash wedge nomenclature of organic compounds,I'd look forward seeing it.Thank you very much 🖤
I don't have a video dedicated to the nomenclature of molecules with chiral centers. However, you will find these topics addressed in my free Chirality and Stereochemistry series where I walk you through how to identify R and S configurations for chiral molecules. Watch the series at Leah4sci.com/Chirality
for the last reaction, cyclopropanation an alkene can be reacted with CH2N2/UV light for the same product?
Yes, those are also acceptable reagents for the cyclopropanation of an alkene.
thank you, your video are very helpful.
You're so very welcome, happy to help
everything was purely explained and thnc for clarifying some tricky things. But mem i only have ONE PROBLEM "HOW DO YOU SEE IF YOU AN HYDRIDE SHIFT"??????
Glad I helped clear things up for you. Regarding your questions, a hydride shift can occur in organic chemistry reactions that involve a carbocation intermediate. If such a rearrangement will place the carbocation on a more substituted carbon, then the hydride shift is highly favorable because of its ability to stabilize the intermediate. For more, visit leah4sci.com/hydride-shift-mechanism/
Thank you so much, our professor started this chapter on the last week of class. By watching this video before every class, it allowed me to get more familiar with the material and gradually add the mechanisms behind the results as they were discussed in class.
wow! that's good to know! Thanks for following along. Please make sure to subscribe. You're welcome. :)
Thank you! I‘d be interested in hints at why and how a step can go wrong and the risks involved with specific reactions. I understand that is more than is asked in most chemistry education but it is very relevant in daily practice.
I really like your colour scheme, we both share a trait 😉
I'm sure it's relevant in daily practice, but alas it is not something I can help with. I'm strictly a pen & paper chemistry tutor, I haven't been in lab for over a decade
thanks a ton for these review videos.Helped a lot!
You're welcome, happy to help!
Very good video! straight to the point
Glad you liked it!
Thank you so much very helpfull video
You are very welcome :)
Hi, I really liked the video. Congratulations for your work!
Thank you very much, glad you like it!
Your awesome!!!! Thank you :-)
Aww you're welcome!
I’m here on 5 hours before my repeat exam ….. I think I’m not gonna make it 😢😢😢😢
Oh no, I hope it went better than you expected
Very good but only one question.... In the hydrohalogenation example, isn't the Cl going to go on the C that has the less H, being a Markovnikov reaction? Why does the Cl go on a C that has no pi bonds?
Listen to my explanation in the video one more time. For this example, there is a hydride shift that allows the carbocation to be formed on the more substituted, tertiary carbon. For more on the mechanism of a hydride shift like this one, I invite you to watch the following: ruclips.net/video/cSW9LDxtuoA/видео.html
Hi! I was wondering why there is a hydride shift in the hydrohalogenation, but not any of the others shown given that true same alkene is being used in each mechanism. Doesn’t each alkene reaction exhibit a carbocation intermediate, and if so, why do the other examples not go through a hydride shift?
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
You can also view my free Alkene Reactions video series and cheat sheet at Leah4sci.com/alkene
I love your videos but I seem to need some background to understand this one because I could not be more lost. What is the prequel to this video? I was following the playlist/series..?
Think of this video as a short summary of all of the other alkene reactions presented in the series. As such, I would watch this video either first (as a preview of what’s to come) or watch it last (as a quick review of everything). For the entire series, in correct order, visit my website at leah4sci.com/alkene-reactions
woooooow. um speechless
Glad you like it!
pleasure
In the halohydrogenation 4:32 would there be a carbocation shift towards the tertiary carbon so that OH would be on the more carbon
Actually, no. The formation of the halonium ion intermediate prevents the possibility of a carbocation rearrangement. For more on this reaction, watch my video at ruclips.net/video/S-2CaHDhMfI/видео.html
Hey Leah you are a star girl
Thank you!
thank you for this!! I wish I found it sooner but you're such a lifesaver Leah!
You're welcome! I'm glad you found my resources!
Your videos are a lifesaver thank you so much!!❤
You're so welcome, glad it helped!
My exam is tomorrow and all I have to say is THANK YOU
you're so welcome! How did your exam turn out?
Why does this actually make sense now lol
Mission accomplished! So glad to hear it!
Amazing! God bless you Leah!
Thank you!!
can u xplain markovnikov and anti markovnikov effect?
It depends on the reaction/reagent you're using. For example, in an HBr reaction, the Br gets added on to the side of the pi-bond that is MORE substituted and the H gets added to the less sub carbon (this is Markovnikov addition).
In contrast, an HBr reaction using ROOR (peroxide) as a reagent would follow Anti-Markovnikov addition ----> where the H would be placed on the more sub carbon and the Br would go on the LESS sub carbon.
Yes, I have an entire video on it (new) see it on this page: leah4sci.com/alkene-reactions
thanks you are way better than my teacher, thanks for this video
Happy to help! You're welcome.
Why do these have catalysts, like a Pd, that doesn't seem to react with anything. Mechanisms are the only aspects I'm stuck on before the finals. Also curious as to why it's in Hydrogenation but not Hydrohalogenation.
I'm sorry, but I don't provide tutoring through RUclips comments. For more help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
Your vids are some rare gems !
Aww, thanks for your kind words! I'm so glad you like them!
My Organic professor is terrible. Reads straight out of the book on an overhead and never works out any problems. Also makes you feel stupid if you ask for help. THANK YOU SO MUCH for these helpful videos. It's hard to teach yourself organic chem out of a textbook.
I'm sorry you are having a less than positive experience with your professor!
I'm glad the videos are helping!
The reaction involving metal catalyst is zero order but the ethene hydrogenation is first order ..why??
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
@@Leah4sci it's okay no problem 😊
What a. Lecture!!! Don't stop we want more lecture🙌🙌🙌
Thanks!
third orgo 1 test on this stuff on tuesday, and this was so helpful leah! your videos have gotten me through organic 1!
me right now lol my exam is tuesday and im watching videos for orgo 1 for my third exam
@@suhamoten2060 Me now! Except Coronavirus is giving us an advantage of taking it online now....
honored to be able to help
Really wonderful summary!
Thanks!
I’m so worried about my exam but you sum everything up very clearly. Thank you.
Happy to help! Fingers crossed for your upcoming exam!
quick question, so these are just different ways/methods in breaking an alkene? because if so, these different ways can also be used with organic synthesis reactions? btw, your videos have helped me so much! so thanks for posting these great videos :)
These are the different ways for reacting alkenes, yes
+Leah4sci In the hydrohalogenation example, organic chem tutor would say that because the C is chiral you can have Cl on the dash and on the wedge, in racemic mix, is that also a thing?
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
Thank you for all your help !
You're welcome, happy to help!
4:46 ma'am could you kindly explain why the hydroxyl group didn't go to the more substituted tert carbon next door ?
To understand, we need to look more closely at the mechanism of the halohydrin formation. There is no carbocation intermediate formed, but rather a halonium ion which stabilizes the positive charge and prevents rearrangement. Check out more on this mechanism by visiting leah4sci.com/halohydrin-formation-alkene-reaction-mechanism/
Thanks for sharing this video! I do appreciate the commitment you have given to creating each video.
My pleasure! Thank you for the kind words
you're really good but if you just talk a bit slower it will be much better cause i'm arabian and my english isn't pretty good so i needed to pause every 10 sec to realize what you just said.
I appreciate the feedback. I cant help talking fast. Use the RUclips speed feature to slow the videos down to 0.75x so that you can hear everything better
Whoever said you can't study the night before a final, clearly doesn't know how to study..
All of your studying?! I don't recommend that
hii, thanks for the video, it was really helpful. but im still a bit confused at the Halohydrin process, according to what u said it should be following mark's rules, but if thats the case, why does the H-shift from tert-C to sec-C doesnt happen to form tert-Carbionium ion, since it would be more stable, and the end product would then be 4bromo 2methyl 2ol butan ?
i am having my finals next week and now im going through all of your videos, they are really helpful, thank you so much
im currently thinking its because of the intermediate, where both C of the double form form a bond with Br, which gives them the positive partial charge, and the H-shift doesnt like the positive charge so much, but the OH- ion does, thats why the OH-Ion jump right into the sec-C, but wouldnt that make it an anti marks product?
The intermediate is the key here! Rather than having any sort of hydride shift, what we see in this mechanism is the formation of a halonium intermediate where the halogen (in this case, bromine) forms a bridged intermediate across the former pi bond. But even in this bridged intermediate, we see a preference for the partial positive charge to fall on the more substituted position. Therefore, the alcohol comes in and attaches to that more substituted carbocation (the Markovnikov position) in the second step.
For more on the mechanism of the halohydrin formation, make sure to see my video at Leah4sci.com/halohydrin
@@Leah4sci Thanks for the explaination x)
I had my orgo 1 final today and your videos really helped me a lot !
at 4:07 why does it look like both bromines are added to the same side? If the reaction is supposed to proceed with anti stereochemistry doesn't that mean both Br atoms come from opposite faces of the double bond? You only form the trans isomer right?
while you are absolutely correct this version of the product does not show stereochemistry as denoted by the lines rather than dashes and wedges. It does however state 'anti' to remind you that this is an anti addition
great thank you so much i wish i could find this sooner and save time on understanding other materials! thanks again this saved me
Better late than never though, right? Hope it helped and you're very welcome
4:20- In another video, she explained that this is due to the polar bond formed between the H and O which gives the H a partial positive charge and negates it
Yes, for more on the mechanism of the Halohydrin Formation, make sure to visit Leah4sci.com/Halohydrin.
Thanks for watching!
Great video, thank you!
Glad it helped! You're welcome.
Just the videos I have been looking for!!!🔥🔥🔥😁
Yay!!! So glad you found them!
The Stereochemistry for Oxymercuration is a mixture, not anti addition
That's not how I learned it and I'm happy to be corrected, please show me a resource for this
U r awesome mam😍 ... U teach the way as my teacher taught ne in class... Thanks
It's my pleasure :)
im not kidding when I say you have helped me understand SOO much I cant thank you enough. You make things so much simpler!
Happy to help!
You’re my favorite channel for ochem help, thanks a lot
Wow, thanks! Happy to help!
Hello leah can you check back the oxidative cleavage with hot KMnO4 in your cheat sheet..? the 2nd products in the cheat sheet gives formic acid (HCOOH) but in your video 11:57 it gives CO2
I'm guessing the CO2 as the 2nd product is correct. After cleavage the unsubstituted carbon should become CO2, monosubstituted become COOH and disubstituted become ketone
Yes, you are absolutely right! Thank you for pointing this out. The correct second product of the oxidative cleavage reaction with KMnO4 would be CO2. A terminal carbon on an alkene will be fully oxidized. Again, thank you! We will correct the alkenes cheat sheet on our site.
Your videos are just mind blowing and amazing.
Can you please make videos providing cheat sheets for chapters like carbonyl compound, carboxylic acids, phenols and ethers?
My goal is to eventually cover all organic chemistry reactions
mam, wouldnt it b the tert carbon in halohidrin to hold the OH for markonikovs addition, due to rearrangement,,,,,,,,,,,,
at which point in the video?
halohidrin part where it's markovnikovs addition but there is no rearrangement in the video
I have a quiz today and I now am sure that I would do something on it, lol.
something is better than nothing, right?
thank youso much maam that helped me a lot to revise for my paper day after tomorrow tahnks a lot u almostsaved e wish me luck
Glad I could help!
Can you make a heterocyclic nomenclature anytime soon? Would be really appreciated
I cover that in my naming series here: leah4sci.com/naming
U teach really very good 👌
Thanks!
wow i get it now i was confused since first semester now its clear thanks a lot
You are welcome. I'm glad it helped
Never fails always here during finals week!! Smh
Awesome, glad I can help!
amazingggg :)
Glad you like it!
thanks for making organic chem simple
Aww, you're so very welcome, that's my goal!
It really helpful ... thank you so mach ....
Glad it helped! You're welcome :)
Just awesome 👌..
Glad you think so!