Circular Motion - Free Formula Sheet: bit.ly/4gIUL3r Physics 1 Final Exam Review: ruclips.net/video/CwkhvFlNFp0/видео.html Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Next Video: ruclips.net/video/G0RikmNonoU/видео.html
I've watched so many of your vids in the past two weeks (prepping for NUPOC phone interview and forgot all my math from college) that I actually hear your voice in my sleep now, thankfully it's a nice voice haha
Normally I don't comment on videos but on you are amazing sir! You were able to explain hard topics in simple terms. Way better than my physic professors. Thank you for your work!
You must be using mastering physics or physics by cutnell. Let's give you super basic examples and then ask you really hard, random questions and tell you that whatever you do to one side of the equation, you have to do to the other while not telling you that you need to know how to do functions of functions and derivatives in the next. Also let's just go with the arbitrary rate of one chapter a week despite chapter 4 being 25 pages because the teacher, who you cant understand, can totally cover that much material in class in a week.
What I did for the asteroid question was I set the masses equal to each other and the radius for x equal to y and half for z. So I isolated the radius for x using mass x ac = centripetal force. So I ended up with 166.6m = rx I then took rx and placed it in my ry for acy and took that acy with a reciprocal of m into its net force equation where the ms canceled each other and I was left with ~6000 N
How bout with this problem? An automobile rounding a level curve of 50m radius. If the coefficient of static friction between tires and the roadbed is 0.75, what is the maximum velocity it must have before it starts to skid?
18:10, why is the y-component of the tension equal to the gravity component? Aren't they going the opposite direction and therefore it will be (-mg) and not (+mg)? :(
For the last question for part B, I got a different answer because I just took half the radius from x which was 12755 m and, so when I plug it into Fc=MV^2/R, I got like 27,706, and he got 27,000 by doing it, why can't the method I used be valid for an answer?
Physics uses the MKS system of units M = meters K = kilograms S =seconds you should always convert your starting units into MKS to get an accurate answer.
Set up a vector r to indicate the position as an object travels around a circle of radius R. Its coordinates are x=R*cos(theta) and y=R*sin(theta), where theta is the angle from the +x direction. We'd like to get the angle theta in terms of speed v and time t. It travels an arc length equal to v*t, and this arc length can convert to an angle in radians, by dividing by radius. Thus: theta = v*t/R Adjust our x and y values accordingly: x = R*cos(v*t/R) y = R*sin(v*t/R) Take the derivative to find the corresponding velocity components, vx and vy: vx = dx/dt vy = dy/dt vx = -R*sin(v*t/R) * v/R vy = R*cos(v*t/R) * v/R vx = -v*sin(v*t/R) vy = v*cos(v*t/R) Take the derivative again to get acceleration: ax = dax/dt ay = day/dt ax = -v*cos(v*t/R) * v/R ay = -v*sin(v*t/R) * v/R Simplify: ax = -v^2/R * cos(v*t/R) ay = -v^2/R * sin(v*t/R) Add up in Pythagorean theorem to get the magnitude of a: |a| = sqrt(ax^2 + ay^2) |a| = v^2/R*sqrt((-cos(v*t/R))^2 + (-sin(v*t/R))^2) The sqrt term equals 1, regardless of what v*t/R equals. Thus we have: |a| = v^2/R
On problem 4, you have a mistake. If x and y are at the same distance, then the gravitational force (ie centripetal force) will be the same. Asteroid Y simply can’t be in a circular orbit at the same distance but a different speed. Otherwise your videos are always fantastic and helpful!
When we stand on a scale and see 140 pounds. Is it mass or weight of the person. We convert kilograms to pounds by multiplying by 2.2 to get weigh ourselves in pounds. Is it pound mass or pound force? I feel it is pound mass, am I right? I buy meat from grocery store and it gives the rate and net weight in pounds. Is it actually mass in pounds?
A merry go round horse is encircling the ride at a speed of 6 m/s. If the diameter of the ride is 18.64 m, how much force is the horse exerting, provided that its mass is 152 kg? Can someone help me with this
A I’m actually homeschooled and I haven’t even been enrolled yet and I’m starting to study, probably on august but i wanted to be super smart so i could wow people with ma brain, That’s literally the whole reason NO, not because i want to succeed in life, NO not because i need it for college, I’m doing it because i wanna act like a damn genius to my family. Loo
I was going to watch this video about centripetal force to the end, but I've already found a flaw at 2 minutes in. Firstly, you said that the rope was a force. That's incorrect because it is actually the resistance to a force, centrifugal force to be exact. Secondly, you then moved onto orbits which can not be scientifically tested and there are no tests to prove anything can "orbit" using any unseen forces. Magnets can not be configured to orbit. No proof of orbiting is available or a centrifugal force. Thirdly, centripetal force is a false conception designed to confuse regurgitating ball Earth proponents because without it heliocenticity falls apart on its face. Google it, they sight tires and ropes as a force, hilarious balltarded dumb garbage is the lie of centripetal force. Centripetal force is actually resistance to centrifugal force, (a real force by the way) or in the case of fluid and gaseous funnels, the centrifugal pressure mediation. Obviously, flat Earth confirmed.
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I've watched so many of your vids in the past two weeks (prepping for NUPOC phone interview and forgot all my math from college) that I actually hear your voice in my sleep now, thankfully it's a nice voice haha
How did the NUPOC process go so far? I have another semester to knock out then I can start applying.
I think so too. My daughter thinks it's "annoying" lol
6:34 FIRST TIME HEARING YOU LAUGH (THOUGH FOR A SECOND)
beautiful
7:05
There's another time he laughs bc he made a calcul mistake 😆
Frankly speaking u explained things better than my lecturer
Long live online education :)
He always does!
He always does it😌👋
Normally I don't comment on videos but on you are amazing sir! You were able to explain hard topics in simple terms. Way better than my physic professors. Thank you for your work!
0:45 the answer to life was just revealed to me. I could not have had a better experience at this moment. Big brain moment right there
I got a 135/125 on my first college physics test because of you.
Kendall Curtis Test must of been easy.
Cooper Stukel class average was an 85/125
Kendall Curtis thats.......pretty good
Wat? How can u get a higher score than the total score
@@redgefleming1535 Bonus question on the back. Most professors try to throw a curve ball to those that test the limits.
You literally taught me physics, THANK YOU a million times!
BRO, WHY HAVE YOU DONE EVERYTHING???? hats of to you dude, jeez
ur videos are helping me so much, i wouldnt be passing if it wasnt for u
7:03 Best Tips That You Never Get from Class.
🤣😂🤣
👌Many Thanks, homes.
u way better than my physics teacher, u explain things alot better
actually your videos are super awesome I got a lot idea from your explanation and I like it so much
Man! you saved my grades thank you so much
.57 seconds described this soooo much better than my book which just keeps repeating "acelleration is towards the center."
I am legit attracted to your teaching method.
6:25 maybe its cause its 2am and im tired but this shit had me dying 😂 “you might actually just fly out the window”
who's behind this voice? i already have a crush on him!!!
wtf
tf
Julio Gonzales
Brain fetish or what
making a joke about flying out of the window on a sharp turn was gold. Jokes only STEM teacher can come up with, so smart :)
Wow ,thx for the free teaching , appreciate it 🤗
2:00 For a second there I thought you were about to rant about the geocentric model like it was 1638.
LMFAOOOOOO
thabk you very much your courses helped me a lot , I watch them all . great work!
This dude really teaching better than my actual teacher
it's really funny while he's explaining about the centripetal force when driving a car. i think he must be laughing too but we could't see him
thank you thank you. i hate physics, organic chemistry is my strength. I also absolutely hate my professor so your help comes a long way!
Thanks Sir we Appreciate you 💪🇵🇬
Great video!
ye-
s
Wow wonderful explanation
6:11 I really like that kind of explanation.
I have a quiz on this today! thank you for your help!
Not even Organic Chemistry Tutor can save me from Physics :(
haha same. good luck!
Trinomials were ok but THIS
You must be using mastering physics or physics by cutnell. Let's give you super basic examples and then ask you really hard, random questions and tell you that whatever you do to one side of the equation, you have to do to the other while not telling you that you need to know how to do functions of functions and derivatives in the next. Also let's just go with the arbitrary rate of one chapter a week despite chapter 4 being 25 pages because the teacher, who you cant understand, can totally cover that much material in class in a week.
@@nicolegaming812 yes D:
-
@@indoororchidsandtropicals358 The accuracy of your comment is actually scary.
I learnt a lot from you thank you
you are literally amazing thank you so much for makign this literally gods work
راجل مظبوط و جدع وتوب التوب احلى تحية من ستيم السادات
You're good man more than my lecture
i like the fact that mark wahlberg making me love physics
I like your videos, Marky Mark- great job.
I like your detailed explanation
U are Good 👍
thank you so much, i am studying to pass the entrance test so that i dont have to take the intro class which is 5 months long
Thank you😊your video has really helped me
What I did for the asteroid question was I set the masses equal to each other and the radius for x equal to y and half for z. So I isolated the radius for x using mass x ac = centripetal force. So I ended up with 166.6m = rx I then took rx and placed it in my ry for acy and took that acy with a reciprocal of m into its net force equation where the ms canceled each other and I was left with ~6000 N
Thank you so much Sir.This is super clear
bless you sir!
u r incredable 💙💙💙💙💙💙
"When the sun orbits the earth..." gotcha right there!
Hi, sir.....I'm not very good at English. So adding subtitles would be good.
Go to the settings of this video tap on the captions and then tap on the auto translate option you can choose a language.
Thank you SO MUCH!!!!
Thank you julio
Thanks more sir!
Good job
Thank you so much
Thank you
Thanks dad
Thank you !!!
4.6 thousandth like! 😮
does the centripetal force always create a perfect circle or is it dependent on the speed of the velocity and gravitational force?
im so eagered to learn but man my brain is melting
y am i paying professors when this is the guy whos teaching me
You pay for your report card. Learning is free.
Hey dude, what happens if we got a spring instead of a rope in the oblique rotation?
@19:12 why was the formula for an object travelling slowly used instead of simpley using the centripetal force formula?
Very nice
At time 18:18. Should R be the radius in the horizontal direction which is L * cos(theta), where L is the length of the rope?
How bout with this problem? An automobile rounding a level curve of 50m radius. If the coefficient of static friction between tires and the roadbed is 0.75, what is the maximum velocity it must have before it starts to skid?
why is Ft_y = mg at 17:09 when it's not at equilibrium?
Flatearthers: 1:59 Ladies and gentlemen, We got them
18:10, why is the y-component of the tension equal to the gravity component? Aren't they going the opposite direction and therefore it will be (-mg) and not (+mg)? :(
because the ball is not moving up and down so that fty-mg=0 so bring mg to other side fty=mg
what if you make a sharp turn with a slow speed or a wide turn with a fast speed.
depending on the numbers, they could have the same amount of force
For the last question for part B, I got a different answer because I just took half the radius from x which was 12755 m and, so when I plug it into Fc=MV^2/R, I got like 27,706, and he got 27,000 by doing it, why can't the method I used be valid for an answer?
Jay Shah different velocities bro
For the last question why can’t I use the formula we’ve been using the whole time directly? I plugged in the values and got the same results as him
For question number two, don't you have to convert kilograms to grams? Or is it ok as it is?
Physics uses the MKS system of units M = meters K = kilograms S =seconds you should always convert your starting units into MKS to get an accurate answer.
@@trentondart3617you are so kind I shall say I had a hard time with this thank you so much
why is fty = mg??
an object of mass 0.2kg is undergoing shm of frequency 6 hz and amplitude of 0.25m,find the maximum speed?
Will Asteroid Y eventually crash on Asteroid X?
How did we come by the Formula Ac=mv^2/r ?
Set up a vector r to indicate the position as an object travels around a circle of radius R. Its coordinates are x=R*cos(theta) and y=R*sin(theta), where theta is the angle from the +x direction.
We'd like to get the angle theta in terms of speed v and time t. It travels an arc length equal to v*t, and this arc length can convert to an angle in radians, by dividing by radius. Thus:
theta = v*t/R
Adjust our x and y values accordingly:
x = R*cos(v*t/R)
y = R*sin(v*t/R)
Take the derivative to find the corresponding velocity components, vx and vy:
vx = dx/dt
vy = dy/dt
vx = -R*sin(v*t/R) * v/R
vy = R*cos(v*t/R) * v/R
vx = -v*sin(v*t/R)
vy = v*cos(v*t/R)
Take the derivative again to get acceleration:
ax = dax/dt
ay = day/dt
ax = -v*cos(v*t/R) * v/R
ay = -v*sin(v*t/R) * v/R
Simplify:
ax = -v^2/R * cos(v*t/R)
ay = -v^2/R * sin(v*t/R)
Add up in Pythagorean theorem to get the magnitude of a:
|a| = sqrt(ax^2 + ay^2)
|a| = v^2/R*sqrt((-cos(v*t/R))^2 + (-sin(v*t/R))^2)
The sqrt term equals 1, regardless of what v*t/R equals. Thus we have:
|a| = v^2/R
@@carultchbrother it's been THREE YEARS
I don't think he needs it anymore.
But I did so thank you
God bless u
On problem 4, you have a mistake. If x and y are at the same distance, then the gravitational force (ie centripetal force) will be the same. Asteroid Y simply can’t be in a circular orbit at the same distance but a different speed. Otherwise your videos are always fantastic and helpful!
When we stand on a scale and see 140 pounds. Is it mass or weight of the person. We convert kilograms to pounds by multiplying by 2.2 to get weigh ourselves in pounds. Is it pound mass or pound force?
I feel it is pound mass, am I right?
I buy meat from grocery store and it gives the rate and net weight in pounds. Is it actually mass in pounds?
A merry go round horse is encircling the ride at a speed of 6 m/s. If the diameter of the ride is 18.64 m, how much force is the horse exerting, provided that its mass is 152 kg?
Can someone help me with this
it's been a week, have you gotten the ans?
@@Dan-sz7qn yes
Don’t mind me, just a 12 year old that isn’t going insane with science
damn and i’m here just starting to study this for my mcat 🤣
A
I’m actually homeschooled and I haven’t even been enrolled yet and I’m starting to study, probably on august but i wanted to be super smart so i could wow people with ma brain, That’s literally the whole reason NO, not because i want to succeed in life, NO not because i need it for college, I’m doing it because i wanna act like a damn genius to my family. Loo
Yooo I am the 100 comment let's gooo
Does anyone know how he came up with 60.4 m/s? because even though I do the example equation just like he did, i keep coming out with 60.3 m/s
The answer is 60.35..and he just approximated it
im gonna go fly off a window thanks JG!
Me watchin this while doing an inertia drift
6:35 haha
Liked
GOD
24:06
I like English language
May the Force be with you.
❤❤❤
I understand the concepts and I know how to preform simple calculations but my professor makes the questions so fucking hard :(
Y’all are in uni learning this? I’m in highschool lmao
I was going to watch this video about centripetal force to the end, but I've already found a flaw at 2 minutes in. Firstly, you said that the rope was a force. That's incorrect because it is actually the resistance to a force, centrifugal force to be exact. Secondly, you then moved onto orbits which can not be scientifically tested and there are no tests to prove anything can "orbit" using any unseen forces. Magnets can not be configured to orbit. No proof of orbiting is available or a centrifugal force.
Thirdly, centripetal force is a false conception designed to confuse regurgitating ball Earth proponents because without it heliocenticity falls apart on its face.
Google it, they sight tires and ropes as a force, hilarious balltarded dumb garbage is the lie of centripetal force.
Centripetal force is actually resistance to centrifugal force, (a real force by the way) or in the case of fluid and gaseous funnels, the centrifugal pressure mediation.
Obviously, flat Earth confirmed.
Can't tell if you are joking.
I want what you are drinking. But later after watching this to the end
Thank you!!!