Uniform Circular Motion Problems

Поделиться
HTML-код
  • Опубликовано: 2 фев 2025

Комментарии • 62

  • @zeri6014
    @zeri6014 2 месяца назад +6

    My physics teacher DOES NOT TEACH and i have to rely on these types of videos every time we have a quiz or a test. YOU are honestly an academic savior we didnt know we needed.

  • @alizo3
    @alizo3 Год назад +28

    one of the best channels on youtube about physics . Thank you Sir

  • @scouterseth
    @scouterseth Год назад +19

    Bro. You are literally crazy good at explaining this stuff. Love the format and love the clarity.

  • @Akshxt_307
    @Akshxt_307 Год назад +13

    preparing for one of the toughest examinations in world (JEE ADVANCED) ,, and your lectures are really helping me bczz most of your videos are included in our syllabus

  • @giannahandayan7900
    @giannahandayan7900 10 месяцев назад +6

    🤗🥺 I was already on the point of giving up on my physics classes until I found this channel. Thank you so much. This means a lot to us students.

  • @tianboqu7469
    @tianboqu7469 Год назад +6

    Finally found a video about the tension in centripetal motion! Thank you so much Physics Ninja!!!

  • @derplerp8412
    @derplerp8412 Год назад +4

    This was the same thing on my physics midterm, thank you so much physics ninja!

    • @PhysicsNinja
      @PhysicsNinja  Год назад +2

      Great news! I love hearing from viewers. I appreciate your comment, it motivates me to make more videos.

  • @Ruby-bj8st
    @Ruby-bj8st Год назад +3

    The same exact problem was on my test! This video was a life saver. Thank you soooo much.

  • @cappmasters7253
    @cappmasters7253 9 месяцев назад +1

    You're the best teacher in the world ,thank u sir

  • @thephysicschannelwithkenny314
    @thephysicschannelwithkenny314 3 года назад +10

    I enjoyed the video. I have not seen too many problems like the second one you did, but it was interesting. Most of the problem I have done on my videos are like the last one you did. Thanks.

    • @PhysicsNinja
      @PhysicsNinja  3 года назад +5

      Thanks Kenny. Nice to meet a fellow physics RUclipsr. I checked out some of your vids. Keep up the good work!

  • @crazyflyingponys
    @crazyflyingponys 7 дней назад

    Thank you so much for your help in these trying times, Adam Sandler.

  • @sonderman8079
    @sonderman8079 10 месяцев назад +2

    That was brilliant. Thanks

  • @KeilanaAbate
    @KeilanaAbate Год назад +12

    why is Tx = Tsintheta and not Tcostheta ?

    • @Smokesounds
      @Smokesounds Год назад +1

      Same question here

    • @MamosebetsiChaoane
      @MamosebetsiChaoane Год назад +8

      Because right angled triangleis formed and Tx is opposite to the theta
      So when using SOH CAH TOA you will find that side as Tsintheta no Tcostheta

    • @NomfundoMagudulela-lf1ck
      @NomfundoMagudulela-lf1ck 9 месяцев назад +3

      Yes that right.... the components depends on an angle

    • @AngeleyeBuddhi
      @AngeleyeBuddhi 8 месяцев назад +1

      Tx equal to sintheta thats correct

    • @MrWood-qd6kr
      @MrWood-qd6kr 8 месяцев назад +1

      Sin theta = centripetal force = x component

  • @konradbrochocki4923
    @konradbrochocki4923 5 месяцев назад

    In the first problem, could you also find the tension by using the negative of mg(since upwards is positive; g should be a negative acceleration) and then applying some trig since we already know our mass and angle of theta? I'm assume that the Ty component of the tension is just the opposite of mg.
    Thanks. Great channel and video!

  • @SbongakonkeZondi-f5q
    @SbongakonkeZondi-f5q 6 месяцев назад

    thank you so much. this topic is really difficult for me but this helped a lot

  • @dhruvalwadhi
    @dhruvalwadhi 3 года назад +4

    Perfect timing! Thank-you so much!

  • @savitarcaptispoba
    @savitarcaptispoba Год назад +1

    why can you just divide two equations like you showed on problem 1 and 2?

  • @lisandrolisandro8100
    @lisandrolisandro8100 Год назад +2

    great video. do more videos like this

  • @vrks1353
    @vrks1353 2 года назад

    Why would the answer for (ii) only take into account equation for m2 when there is also a force labeled T extending from m1? 24:41

  • @maszdauna2518
    @maszdauna2518 2 года назад +1

    This helped me a lot, thank you :)

  • @c4ipl02ankitsengupta9
    @c4ipl02ankitsengupta9 Год назад

    sir, can you please explain an application if the block under the surface is also rotating from problem 3 ???
    please, explain sir.... my test is coming close

  • @Jimmy-de4sj
    @Jimmy-de4sj 10 месяцев назад +1

    Why didn't you use the length in the first problem to find Tx or Ty? Its the hypotenuse so why don't you just find ac that way?

    • @ayeshaajaz1570
      @ayeshaajaz1570 4 месяца назад

      Because it is the length, not the force of tension.

  • @stalerice9470
    @stalerice9470 2 года назад +1

    Thank you so much for this video! It was extremely helpful and saved me a lot of time.

  • @PinkCammy
    @PinkCammy 2 месяца назад

    my guy.... THANK U SO MUCH

  • @MfZeem
    @MfZeem 2 месяца назад

    Can i ask what if the rod is in horizontal axis

  • @barkbarkbark198
    @barkbarkbark198 10 месяцев назад

    Why do people say tension is perpendicular to the bob in horizontal circular motion?

  • @TheRubicon515
    @TheRubicon515 3 месяца назад

    Such a good teacher, but bro, your bookshelf kills me 😭😆

  • @rosalinechirishian5006
    @rosalinechirishian5006 Год назад +1

    i just dont get when the x component equals cos theta and when does it equal to sin theta. is there a fix rule?

    • @astrofpv6656
      @astrofpv6656 Год назад +1

      Build a triangle of your system and remember SOH CAH TOA (ie. sin=opp/hyp)

  • @iamgingerbread6558
    @iamgingerbread6558 6 месяцев назад

    is your velocity accurate in part 2, i keep getting 3.07 m/s

  • @BittuPatel-m6v
    @BittuPatel-m6v 8 месяцев назад

    sry i can be wrong but i think that tx= t cos theta , ty= t son theta [ but you wrote the other way around] can you explain please. thank you

  • @fawlen_eynjuhl
    @fawlen_eynjuhl Год назад +1

    Thanks for this

  • @bdog1365
    @bdog1365 3 месяца назад

    how would you find how many seconds it would take for the puck to do one full revolution?? if there's a video on this can someone send the link??

  • @angelfabian2202
    @angelfabian2202 Год назад +1

    So helpful

  • @yasodha340
    @yasodha340 Год назад

    In problem 2, why the tension value T2 is lesser than T1

  • @doc_tray
    @doc_tray 2 года назад

    Hello, Physics Ninja. Thanks for this awesome video.
    I understood everything explained in the video except for the last thing you mentioned about the mass m2 SPIRALLING DOWN.
    Could you kindly elaborate on that? Why will that mass m2 spiral down if the velocity is less?
    It would be of great help if you assist me with my question or refer me to another video or book for the explanation of my question.
    Thanks!

  • @danmike2305
    @danmike2305 3 месяца назад

    The digrams of physics.

  • @mtado4933
    @mtado4933 2 года назад +1

    You are a god

  • @ezio_g
    @ezio_g Год назад +2

    When people talk about how much they weight they talk about how much kilograms they weight but kilograms are units of mass and weight are in units of force, newtons, because weight is a force. So, why do we refer to weight in units of kilograms instead of using units of newtons. In orher words, If I am 95Kg I should say I weight 931 newtons instead of saying I weight 95Kg. My mass is 95Kg and I weight 931N. Therefore, a scale is a mass measuring device and not a weight scale. When I buy 1kg of tomatos, I'm actually buying 9.8 newtons of tomatos.😮

    • @PhysicsNinja
      @PhysicsNinja  Год назад +1

      People got lazy and decided to drop the little g.

  • @kawsar929
    @kawsar929 Год назад

    Hello there. I found a__c for question 1 to be -9.766679552 m/s^2 and not 0.944 m/s^2

    • @twopoles11
      @twopoles11 Год назад +1

      Check if your calculator is in degrees

  • @flaviocamacho986
    @flaviocamacho986 4 месяца назад

    Thanks for sharing I needed help for the FE exam. I see you are Irish. well if I can boast I kissed the grave of Deloris O'Riordan and claimed her for myself. I took the spirit of Ireland for myself. Contact me if you want to see her grave granted you are aware of the spirit of Ireland. Thanks again and live well my friend.

  • @KokeBroro
    @KokeBroro 11 месяцев назад +1

    Tx is not equal to Tsin

  • @savitarcaptispoba
    @savitarcaptispoba Год назад +2

    :D

  • @JacuelineT
    @JacuelineT 11 месяцев назад

    Xoxo

  • @dbuc4671
    @dbuc4671 Год назад

    Францын ерөнхийлөгч Макрон Улаанбаатарт ирлээ