Superposition Theorem

[@atriburily1810]

Thank you so much. I found this channel two weeks ago. It has literally made my B.tech EE course interesting.Wish me luck, I am doing my first year this year You've made my life easy. THANK YOU SO MUCH

[@bhagyashririi]

Which other channels did you refer to

[@echoboy45]

​@@bhagyashririi hay 👋🏼 how pass circuits and network theory s3🙂

[@jackie_wa_muranga]

How are you doing now

[@Dineshkumar-xv4xz]

Hearing your voice after a long time please complete these lectures :)

[@landonphemister3941]

Thank you!!!! Reviewing these for my FE exam and totally forgot this concept. Hope you’re doing well in 2021 :)

[@RockstarSham]

Hello

[@supremeleader5516]

What is FE?

[@imsomething2144]

​@@supremeleader5516final exam

[@aryandhakad8495]

I can get perfect notes from you, thanks 😊🤗

[@himanshuchaurasia2427]

You are one of the best channel on this youtube platform i have ever seen for the purpose of study , the way you teach is awesome and really very simple .....thankyou for these concepts .... 👍 And good luck for upcoming lectures ...

[@shravanisd2043]

Happy for you.. got you're channel back 🥳🥳👏

[@swetachaudhary9220]

Thank you so much neso acedemy. Your lectures are literally superbly wonderful. Helping lot to us for understanding any concept. In this stupid theory exam, we can understand concept and write it by your videos. Helping a lot. Can't describe in words.😁😊😊😎🤘

[@MARVELEDITS-124]

Tq my dear sir😊

[@ranasohaib9637]

Respected Sir i listened your voice after a long time but now a time plz to complete the series. i was really shocked by hearing the news of Neso Academy hacked. And Now i am glad it is back i really appreciate your work. Plz complete the whole series Thank you Sir.

[@vinayakayj284]

You deserve million subscribers. No one do this for free. Wish you get healthy and peaceful life 🙏

[@psnjathin8615]

Thank you!!! Reviewing these for my 2rs Amrita PT-1. LY mera dil ka dhadkan

[@UnderratedGamer714]

I am currently in 11th standard, as taking Electronics as a Bifocal subject I thought that this is going to be a hard subject when I didn't understand some concepts in start. Now, I know that everything needs to be practiced and there should be no doubt about that topic in your mind. Thanks for this video.👍

[@qemmm11]

Much appreciated 😊
(v/4)+(v-6)/8=3,
2v+v-6=24,v=10v

[@abhishekshukla9005]

now this is called smooth lecture. no need to show off.

[@manishahalale1678]

Very good explaination!!!Thanks sir❤

[@taka-taktak]

Thank you so much. Your channel is a life saver, you helped me through my electronics courses in Bsc.

[@مريم-ق1ل]

Love from egypt❤❤❤

[@yourbestie4138]

bahut badiya sujeet singh ji

[@kmtazwar8077]

You are the only reason I am going to pass my eee exam😍

[@abhinavpingali2154]

Thank you!!! Reviewing these for my 2rs Amrita PT-1. LY meri jaan

[@sourabhjoshi7522]

I understood the concept easily, thank you sir

[@avinashvishwakarma6488]

very good video for concept clarity and understanding problem solving approach

[@harshitayadav950]

Love from India ❤️🥰

[@pranavJha93]

he is indian

[@LokeshSawarkar-xq7me]

😂

[@akhilakhil2394]

You are awesome . Best teacher with patience .😊

[@Kenneth-iw8jz]

Niceee explanation Sir. Thank youuu ❣️

[@chirantharushka3873]

simply nicely explained thanks sir

[@mohammedisarezwani]

why cant we find the v using mesh theorem?

[@pagadalasumanth7969]

Man u r damn damn amazing the way u explain such heavy topics sooo simply just like thanos snap 🔥🔥🔥

[@kanchasrija192]

Thanks for the video it actually helped me a lot

[@pravallikareddynarala940]

Thankyou so much bro, it was crystal clear

[@ruchithahareendra2973]

Thanks so much!! You explained it in such an easy manner

[@DevRK-xq9mk]

Really helpful video.
Thankyou!!!

[@arki3134]

This was very well explained. Thank you!

[@vinayakagrawal4171]

Thank you so much sir
Really helped a lot

[@LoneWolf25701]

Very nice explanation sir

[@vanshbhatia7890]

very nicely explained ( watching 1 day before exam )

[@nithiyanandham875]

After a long time, I am hearing your voice......❤Hearty❤ Welcome teaching God.....please complete network theory as soon as possible...

[@engineer5085]

Thank you very much sir.

[@sowmyakundeti9966]

Thanq so much sir....love towards Neso

[@shauryasaxena5263]

Tq very much sir 🙏👍 for excellent video

[@rishwanthsaisingirikonda9584]

Thank you bro you made my day........

[@mercy2258]

Thank you Sir for all your efforts, if possible bring lectures on power Electronics also sir

[@pallavipolisetty888]

So clear to undestand.... Tq

[@sword0825]

this is really helpful thank you

[@lakshay6043]

Welcome back. 758k strong.

[@shashikamadushanka4303]

Thank you sir..

[@saadansari4497]

Explaining way❤

[@princepanjiyar1078]

Thank you 💞

[@chaitanyaborude5980]

Excellent 👍

[@aimlessideas1165]

Absolute legend

[@amanmangukiya9928]

Useful for daiict students

[@newinformationhub2.0]

Thanks a lot sir..🎉

[@prebenhamretollefseb530]

Very good, thank you!

[@masked_wolf391]

good job👍

[@subhadepdas9619]

Thank you sir , your channel is more helpful for me ❣️

[@anabildebnath2590]

this is so helpful

[@lunalovegood2766]

Superb!!!!!

[@saikrishnathota5972]

Welcome sir
Please complete network theory sir

[@shravjally4896]

Is he trying to. “Mimic SIRI” ?!.!?!😹😹👌🏼

[@shankiraj7935]

Watching this video one day before exam😢

[@muhammadsamiullah6614]

Thanks To Allah, I see this Video After seeing thousand of time waste video lectures and Also Thanks alot Dear Sir

[@Walirehman16567]

Any diploma student?

[@bba2035]

Thank you bro

[@nisargadk3672]

since current source is open circuited for frst case, same current must flow through 4ohm resistor just like 8ohm resistor na?

[@m.varunreddy7365]

Thanks a lot

[@shaikabid5311]

Thank You

[@YOHANISDESE]

best one

[@munusingh8131]

Anyone from IIT/IIIT/NIT ?

[@ankitabaramn5327]

Nit Agartala

[@vishwarajmurumkar7818]

I'm from symbiosis, better than you peasants

[@samarverma5914]

IIT LONGOWAL

[@GokulanE]

IIT CHENNAI

[@IGMINDS]

Nit trichi

[@tuhinsardar6749]

Thanks

[@Kayumov]

7:34 why you didn't divide 4/4+8? You wrote 8/4+8. Please, explain

[@hasanhan900]

same notation here!!! he solved for I2 probably!! i think that is why you get different answers if you change the current source with voltage source and solve for the voltage with respect to the polarity.

[@continnum_radhe-radhe]

🔥🔥🔥

[@sandyraj2217]

Super👌

[@mathiaskovendy7292]

Using current divider in the last bit, shouldn't it be (3x4)/(8+4)?

[@irvinmosoenyane4389]

that is also my concern

[@tetestoes5188]

No, because we are calculating the voltage in the 4 ohm resistor

[@AdityaSingh-pd9fj]

@@tetestoes5188 yea sl it should be (3x"4")/(8+4)

[@emmanuelnwabuike9475]

Current divider rules state that when two resistors are connected in parallel, the current of the source is multiplied by the other resistor divided by the sum of the resistors

[@rafayali3643]

When you use cdr, then the current for the resistor you are calculating, you have to take another resistor than that

[@madhavkhindri2817]

Can't we use nodal analysis for this? It would be much easy..

[@sourabrao9168]

Any IITRAM students? 😅

[@DEEPAKKUMAR-c2j5i]

RAM?

[@formaltechz]

Any vnrvjiet students 🚩

[@sunkaraugranarasimha802]

Sir please explain another problems in super position theorem

[@EVERYTHING-xu7hg]

This is the problem from the book written by Alexander and matheww...fifth edition ❤️

[@deboor1141]

How we recognise the Circuit which is linear or non linear ?

[@ajitkumarpandit9956]

Yes I am RGPV students

[@udaykiranbade7872]

Sir open circuit means resistance is infinite ?

[@jamesroy9027]

Sir Please complete Computer Network and JAVA series...

[@nesoacademy]

You will get the lectures daily.

[@jamesroy9027]

@@nesoacademy Thanks...

[@tekirohitraj5508]

Any bvrit students

[@iamchiraggupta]

Bpit

[@navvuluKosamOfficial]

Yupp meh!!

[@charithreddy1641]

Mee bro

[@Svecw_girl]

Bvc

[@ElijahWalton-q1z]

Want some B'olofwo'er

[@gkiran931]

Sir please upload network theory chapters from 4th to 10 in neso academy app..

[@gau3463]

Why did you open circuit one and short the other?

[@SanjayS-y3w]

What if , we supposed to find I , do we need to add two current values in the same way

[@phasepanther4423]

So is the voltage in the 8ohm resistor 12v?

[@phasepanther4423]

Or do we have to consider the direction of the current source and voltage source to see that they're in opposition, and therefore have a voltage of 4?

[@nishantgautam7627]

In the step 2, if I replace the current source by a voltage source V= 12v in series with the 4 ohm resistor I get a different answer . Why ??
Also the voltage polarity across 4ohm due to both the sources is different , so should it be v1 - v2 when we do the algebraic sum ?

[@gourav7899]

U probably got 2 as answer.
Its the voltage drop across the resistor.
12-2 will give you 10

[@Dkhaterz]

Anyone from a third tier college 😅

[@solosamuraiz1526]

Did not learn current divider yet. Wish u listed the rule.

[@devAzhar]

Where did the 8/ 8+4 come from. I know that I= V/R the R is 8+ 4
.Where did the division come from?????????????

[@adityavarun1498]

current and voltage division rule

[@naveengouda6697]

Can l get notes for network theory

[@SkajDhj]

VIT-AP

[@Harikrr]

VIT. TN

[@vinayakagrawal4171]

Sir i want to make a project on this topic please please help me

[@Jaanu_moon_06]

Hii guys anyone from Gnits

[@9_______9_______9-i9m]

7:30 pretty sure you applied CDR wrong because it should be Rtotal/Rx(Itotal). If you could clarify i would appreciate this. I'm only watching this video because our teacher is ass

[@aashishsah2110]

🔥❤️

[@kiaranicolebaliwagan9363]

Hello I have a question what if there's 2 voltage source? What shall I do?

[@SillyLittleMe]

if there are two voltage sources,v1 and v2,then first sc v2 and find voltage due to v1 then sc v1 and find voltage due to v2. Follow same steps for current source

[@Happy_Sheoran]

Anyone from DTU

[@eyestracker8922]

Problem 2 te to dependent source dhorei korchenn??

[@somethinglyrical5365]

For first time you have open the circuit and for the second one you have short circuit that
So ho do we know when to do what??

[@SillyLittleMe]

current sources are oc and voltage sources are sc

[@sahilrana8576]

Puri video dekh love day