Superposition Theorem with Dependent Sources

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  • Опубликовано: 11 янв 2025

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  • @divyatripathi4439
    @divyatripathi4439 4 года назад +82

    This is the best channel for an engineering college student. Simply the best!

  • @abdoolsattarcassim6717
    @abdoolsattarcassim6717 3 года назад +9

    This youtube channels layout of teaching is excellent. I love this.

  • @SK-rc7ey
    @SK-rc7ey Год назад +1

    Voice clarity and quality is absolute. Thank you.

  • @sandeeptiwari3655
    @sandeeptiwari3655 4 года назад +13

    Long live sir...... Love you NESO academy......by heart😇😇😇... please keep on uploading network theory lectures

  • @richardfuchs8865
    @richardfuchs8865 Год назад +6

    Your explanations are very clear. I will refer my students to your channel.

  • @azultarmizi
    @azultarmizi 3 года назад +2

    You have a very beautiful handwriting, it helps with the understanding

  • @mihirmishra289
    @mihirmishra289 4 года назад +3

    Jab NESO hai sath toh darne ki kya baat😍

  • @girirajyadav3206
    @girirajyadav3206 3 года назад +7

    Dependent source voltage Must be
    |vx2/2| otherwise there will be confusion in polarity

  • @nitianhostellife.ShivaGupta
    @nitianhostellife.ShivaGupta 2 года назад +1

    best video ever i've got

  • @sammsamm4034
    @sammsamm4034 3 года назад

    Your explanation is very easy to understand. Thank you

  • @nagachaitanyanagachaitanya593
    @nagachaitanyanagachaitanya593 10 месяцев назад +1

    This is best channel for engineer student but i hqve one dought in circuit their is voltage, current and independent voltage source controlled by current source by using super position theorem

  • @somdebsar7378
    @somdebsar7378 4 года назад +2

    Thank you sir for your nice explanation 😊

  • @suheabkhan2546
    @suheabkhan2546 4 года назад +14

    Amazing lecture sir....sir when can we expect datastructures

    • @nesoacademy
      @nesoacademy  4 года назад +7

      The work is in progress, chances are there to start DS from the next month.

    • @ziakamran1692
      @ziakamran1692 3 года назад +5

      @@nesoacademy love u ustad g

  • @krishnakumarmishra3580
    @krishnakumarmishra3580 2 года назад

    Great job... 🙏🙏🙏

  • @harshdadwal3088
    @harshdadwal3088 4 года назад

    Good to see u back

  • @mondalaritra
    @mondalaritra 4 года назад +2

    Thank you sir..

  • @guillaume6373
    @guillaume6373 3 года назад

    Thank you for this video!

  • @adekunleafolabi1040
    @adekunleafolabi1040 4 года назад +1

    Awesome video

  • @pramodkeshari975
    @pramodkeshari975 4 года назад +5

    Sir here in nodal analysis why v=-vx2

  • @snehshah4973
    @snehshah4973 2 года назад +1

    What does v_x=0 exactly mean?
    What does it signify in this circuit?

  • @himanshusingh8693
    @himanshusingh8693 4 года назад

    U r amazing.. Sir..

  • @aravind9054
    @aravind9054 3 года назад +3

    How can u find dependent and independent source

  • @preetichaudhary732
    @preetichaudhary732 4 года назад +31

    According to me Vx2 will be -2/3

    • @250eeejagadeesh4
      @250eeejagadeesh4 4 года назад +7

      sister, i have doubt ,due to1A ,why V=-Vx2

    • @palkisachdeva8246
      @palkisachdeva8246 3 года назад

      Yesss

    • @41.safwansafu85
      @41.safwansafu85 Год назад +2

      @@250eeejagadeesh4 the node have -ve polarity according to the resistor voltage drop i.e Vx

  • @AKSHAY-kx3ln
    @AKSHAY-kx3ln 4 года назад +2

    Sir can you please add operational amplifier in analog electronics series.

  • @Khushi-io7ey
    @Khushi-io7ey 6 месяцев назад

    Sir for finding vx2 can we use current division rule for 1ohm

  • @sanishishakhyriemmujat4777
    @sanishishakhyriemmujat4777 Год назад +1

    For finding V2 why cant we use KVL?

  • @PRAVEENTAMMINAINA
    @PRAVEENTAMMINAINA Год назад

    You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

  • @sudhanshukumar3770
    @sudhanshukumar3770 4 года назад +4

    Sir in how many days network theory will be completed so that it will be benefacial for us in gate 2021.sir please reply as it make us comfortable for plannig purpose🙏

    • @nesoacademy
      @nesoacademy  4 года назад +6

      It is not possible to predict the exact number of days but it will be over before GATE exam. Now we’re more committed to complete the ongoing subjects as soon as possible.

    • @pasvinay
      @pasvinay 2 года назад

      @@nesoacademy Sir, the Network Theory course is still ongoing. Kindly could you let us know when the course would be completed?
      Thank you, Sir

  • @64.preranakumbhare5
    @64.preranakumbhare5 4 года назад

    Thank you so much sir....

  • @dikshaseth862
    @dikshaseth862 4 года назад +5

    Vx1 should be equal to -i1 because the sign of vx1 is negative. See the first ckt of the solution when we are considering only the voltage source. Correct me if I am wrong.

    • @omkarsapte4119
      @omkarsapte4119 4 года назад

      see the polarity of Vx1 it is same along the current tressing direction... If polarity of Vx1 will interchange then you will get Vx1 equals to -i1

  • @QuranTilwatAndTranslation
    @QuranTilwatAndTranslation 4 года назад

    Nice method

    • @an_archy
      @an_archy 2 года назад

      sahi bole sir.

  • @biuhalchatterjee2775
    @biuhalchatterjee2775 4 года назад +2

    Sir in case 2 why V= -Vx2/2? I didn't get the reason of negative sign. Kindly explain. 🙏

    • @nannubedi7773
      @nannubedi7773 4 года назад +1

      because current direction is opposite

    • @leminh3482
      @leminh3482 3 года назад +1

      You can think of it as going from the positive terminal (higher voltage) to the negative terminal (lower voltage) you have a voltage drop of
      V = -Vx2/2 (the current in this case goes from the positive to the negative terminal). If you have the current goes in the opposite direction V = Vx2/2. Hope this will help.

  • @Preethi-z1s
    @Preethi-z1s Месяц назад

    Sir how to know wheteher it is independent or dependent source

  • @NanaBaffour-h1l
    @NanaBaffour-h1l 10 месяцев назад

    Please, how do you locate the independent source

  • @shitposting2234
    @shitposting2234 8 месяцев назад

    i did it using super mesh

  • @manish2747
    @manish2747 4 года назад +2

    1:57 Does someone hear the sound of dogs barking in the background??

  • @raisasultana2077
    @raisasultana2077 10 месяцев назад

    5:41

  • @madhavkhindri2817
    @madhavkhindri2817 4 года назад +4

    By nodal analysis I am getting 4/3 volts

  • @continnum_radhe-radhe
    @continnum_radhe-radhe 2 года назад +1

    🔥🔥🔥

  • @omkarsapte4119
    @omkarsapte4119 4 года назад +1

    Sir can we apply mesh analysis for vx2

    • @AndrewKiethBoggs
      @AndrewKiethBoggs Год назад

      We don't know the voltage across the current source, so we could use super mesh analysis instead.

    • @shitposting2234
      @shitposting2234 8 месяцев назад

      @@AndrewKiethBoggs but us se answer nnahi aa rha mera

  • @simence13
    @simence13 4 года назад +1

    Can we apply Super Mesh analysis here to find Vx2 ?

  • @rudrakshmaurya1061
    @rudrakshmaurya1061 3 года назад

    Can't we apply voltage divder rule when we consider 1v source

  • @qemmm11
    @qemmm11 Год назад

    Much appreciated Sir🫡
    (V-1)/1-(1)+(V-0.5Vx)/1=0....(1)
    V-1-1+V-0.5Vx=0...(1)
    2V-2-0.5Vx=0....(1)
    2(1-Vx)-0.5Vx=2..(1)
    2-2Vx-0.5Vx=2..(1)
    -2.5Vx=0, Vx=0
    V+Vx=1.....(2)
    V=1-Vx...(2)
    (One minute)

  • @yash1152
    @yash1152 Год назад

    what does the diamond symbol mean?

    • @AaronLAB
      @AaronLAB Год назад

      It's an dependent voltage source

    • @yash1152
      @yash1152 Год назад

      @@AaronLAB ohkay, i don't know about them...
      > _"It's an dependent voltage source"_

  • @monicaarmin1508
    @monicaarmin1508 3 года назад +1

    How would i know which source is dependent and which is independent?

    • @kalendemercy1651
      @kalendemercy1651 3 года назад

      Dependent sources always have a standing rhombus with + - sign for a voltage dependent source and an arrow for current dependent source

  • @smartkid5019
    @smartkid5019 Месяц назад

    why is it vx1/2

  • @manjeetsingh2841
    @manjeetsingh2841 3 года назад +2

    sir how V=-Vx2

  • @sahil-of4jb
    @sahil-of4jb 3 года назад

    Wrong method in nodal .. practically not possible all outgoing current in one node

  • @akhilkrishnan3410
    @akhilkrishnan3410 3 года назад

    😌😌❤️

  • @PRAVEENTAMMINAINA
    @PRAVEENTAMMINAINA Год назад

    You

  • @uhhbby_07
    @uhhbby_07 3 месяца назад

    did all this just too find v=0 -_-

  • @digital-zm
    @digital-zm 3 года назад +1

    It was nice if you didn't use video animation. It distracts attention

  • @PRAVEENTAMMINAINA
    @PRAVEENTAMMINAINA Год назад

    You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

  • @PRAVEENTAMMINAINA
    @PRAVEENTAMMINAINA Год назад +1

    You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

    • @davidalbigensechilengi
      @davidalbigensechilengi 5 месяцев назад

      You're right he said that but he actually meant , of which he was correct, that it only becomes the voltage of the node if there's no other branch (resistor for instance) between a nonreference node and the reference node. If there's only a voltage source between a nonreference node and the reference node then the voltage is equal to the voltage of the nonreference node. I hope that will help..

    • @davidalbigensechilengi
      @davidalbigensechilengi 5 месяцев назад

      But for this question there's a resistor as well as a voltage source between a nonreference node and the reference node.

    • @davidalbigensechilengi
      @davidalbigensechilengi 5 месяцев назад

      This is because there's voltage on the source as well as on the resistor. That's how I understood.