I searched for this topic and your video came at the top... I understood so well . Even after 8 years ,it is still the best video and best explanation ❤
Timestamps (Powered by Merlin AI) 00:06 - Understanding aldol condensation reaction using acetone. 00:58 - Understanding the formation of beta-hydroxy ketones in aldol condensation. 02:31 - Negative charge interacts to form new sigma bond in aldol condensation. 03:20 - Aldol condensation involves the formation of new sigma bonds and charge transfer. 04:57 - Understanding aldol condensation product formation with alpha hydrogens. 05:39 - Aldol condensation forms new bonds between ketones. 07:19 - Explaining the process of cross aldol condensation in ketones. 08:27 - Explains possibilities in aldol condensation enzyme reactions. 10:00 - Understanding intramolecular aldol condensation reactions. 10:58 - Alpha hydrogen leads to a stable five-membered ring formation.
Wow sir great trick ever i had studied in my life for such a time consuming reaction if i knew this last year it will surely add +4 to my neet 2017 marks
Great sir... Organic made easy by you/// i love the fact that i am learning from one of the best teachers of KOTA and no question of a doubt arises.. THANK YOU
Sure, Go through our app. We have provided a lot of material free of cost i.e. one-shot revision, customized tests, kota notes etc… it will help you to improve your performance.🤞
Very good explanation... Aldol condensation is basically between two aldehyde having alpha hydrogen...so that the product is having AL(aldehyde) and OL(alcohol)... But yes we can cite any example
Sir meant to say that it is easier to attack aldehydes than ketones. This is because aldehydes have less steric hindrance and are also more reactive than ketones because ketones have two alkyl groups which exhibit +I effect on the carbonyl carbon and make it less reactive.
This reaction involves the nucleophilic attack of carbanion, so the species being attacked should be electrophilic. In ketones, due to +I effect of the alkyl groups, the electrophilicity of the carbonyl carbon reduces, hence the nucleophile cannot attack it easily. That's why, it is easier for nucleophilic ketone to attack electrophilic aldehyde, and hence the product formed by the attack of ketone on aldehyde is the major product.
@@niharikamaniayes i do know the reason for easy attack on ald... but my doubt is if aldehyde is easier to attack then how come the two products in which ketone is attacked marked as major? In the first product aldehyde is attacked by ketone so wont it be major?
@@ToijamGhanashyam no? In the first product, the ketone is getting attacked. The alpha carbon gains electrons from the H that it lost and becomes a nucleophile. Then that alpha carbon of aldehyde attacks the carbonyl carbon of ketone. So the ketone is being attacked in the first product, hence it is not major. The ketone that sir has taken here has two alpha carbons so it can launch a nucleophilic attack on the aldehyde from two places, hence two products are formed and those two are major products. I hope I have cleared your confusion :) but you can still ask if not.
If you don't want to get into the mechanism every time and just want to use the trick sir has shown here, you can remember it like this : The species which is losing an H is the attacking species, and the one who is losing an O is the species being attacked
Got so frustrated and lost all hope over this topic after going through every video and not understanding a thing. I can't believe I'm able to get everything right after watching your video. Thank u so much you're the best teacher 😭😭
You’re like the best chemistry teacher eveR!!!!
Bilkul nahi
Stay connected😊
@@kirtanpatel7683 then who
@@kirtanpatel7683 ye boards wali hai kya 😀😀😂😂
Bilkul nhi didi ji
Ab tak ke saare chemistry teachers jo maine dekhe hain, unmein se best ho aap! Keep up the good work!!!
I searched for this topic and your video came at the top... I understood so well . Even after 8 years ,it is still the best video and best explanation ❤
Follow the playlist properly
Sr aaj tk smj ni aaya tha aa tq so much from my heart now I m the student of atp really Sr Asa hi vedio bnaao mjaa aagya 🥰🥰🥰😍😘😘😘
All the best 😊
Thanks alot sir . Im able to get a lot of clarity in organic second year because of your videos
Timestamps (Powered by Merlin AI)
00:06 - Understanding aldol condensation reaction using acetone.
00:58 - Understanding the formation of beta-hydroxy ketones in aldol condensation.
02:31 - Negative charge interacts to form new sigma bond in aldol condensation.
03:20 - Aldol condensation involves the formation of new sigma bonds and charge transfer.
04:57 - Understanding aldol condensation product formation with alpha hydrogens.
05:39 - Aldol condensation forms new bonds between ketones.
07:19 - Explaining the process of cross aldol condensation in ketones.
08:27 - Explains possibilities in aldol condensation enzyme reactions.
10:00 - Understanding intramolecular aldol condensation reactions.
10:58 - Alpha hydrogen leads to a stable five-membered ring formation.
Great....! This trick saved a lot of my time in exams.
❤️🙌
Sir you r the ultimate savior !!! Thankyou!!!
Wow sir great trick ever i had studied in my life for such a time consuming reaction if i knew this last year it will surely add +4 to my neet 2017 marks
@@yuktasingh2708 nice question
@@yuktasingh2708 Did you clear neet?
Great sir... Organic made easy by you/// i love the fact that i am learning from one of the best teachers of KOTA and no question of a doubt arises.. THANK YOU
Sir, in the first question where you explained through trick, which one will be the major product?
Please reply sir!!
Second one(right) is major because alkene shows hyperconjugation and right one has more alpha hydrogens
Sir aldol mai ecb reaction kai liye base hai hi nhi
Bhai perfect smjhate ho
Keep watching 😊
Great 👍🏻👍🏻👍🏻🎉🎉🎉❤❤❤❤
I dont have words for this fantastic teaching
Thats why kota teachers are so famous ❤🎉🎉
yeah video physics walla sir ki playlist me arhe h ?
Ha yaar
Nahi
Tumhara chutya utube
Thank q sir for giving this beautiful understanding ❤
Sir please answer this question...
(Benzaldehyde+Acetaldehyde)in the presence of OH(-) then no. of product will be....
Ans-4
Sir,in the trick shouldn't it be h2o that is removed rather than OH??
Thank you so much sir! From Himachal 🏔
9:59 you said that ketone attacks easier and then telling that the other two products are major ? I'm confused !! please teach in detail
Sure, Go through our app. We have provided a lot of material free of cost i.e. one-shot revision, customized tests, kota notes etc… it will help you to improve your performance.🤞
Ya even I have the same doubt
Me too confused 😐
bhaiya ans mila
@@teharsh459 Jiska alpha H nikalta hai woh attack karta hai. Hope you get it now.
Sir Agar high temperature hai yo E1aur E2 bhi to ho sakta tha E1cb hi kyu hua .
Sir plz Explain .
Very nice explanation sir ❤❤❤🎉🎉🎉🎉
Thank you so much, great video 🙏
Glad it was helpful!
@@atpstarkota wanted to ask if all the mechanisms in OC are important for jee
Love u sir love u 3000 times❤❤❤
11:21
6 member ring mein aur 5 member ring mein kaun jada stable hoga?
6 member.
@@mgri6thfk721 yes.., i edited my comment bro...i was just answering Neelam.
Ty for such a good trick
9:49,the case in which aldehyde is being attacked is only one,but you have said that two products will be major , how sir?
Sir what if there are two long and different aldehydes . One bigger than other R1>R2 , then which will be major product .
Khatranak best academy of organic in world
Good teaching style Sir ji
Really appreciative trick.
Glad you liked it
Sir aap ki wajah se aaj organic bahut strong ho gayi hai..love u sir ❤️❤️
🙌🕉
Absolutely loved the teaching .....I m joining it soon....great faculty sir....🤓
Sir at 7:41alpha h is at the other side also ....so should we consider that....coz then there will be 2 structures....?...plzz answer
Thanks a lot sir ❤
Best channel for revision
Thankuu so so much sir🙏🏻
Thanks 🙏🏻 sir ji
Most pleasurable!!!😊
This is best video in that shortest time....
Isme to sb kuch cover ho gaya
Sir plzz explain in cross aldol attack on ald. is easy is it due to the fact that it is less hindered..
Thank you soooo much sir, you are a lifesaver!! 😭♥️
Padh lo chahe kahi se,
Organic aayegi yahi se! 🎉❤
Salute to your fabulous way of explaining methods and mechanism🎉❤
sirji aldol condensation kee mechanism imp hai ya saare qns short trick se ho jayenge? (wrt jee advanced also)
Sir please use a thicker pen..
It will increase clarity
.. ❤️
Thank you sir for this wonderful trick
Most welcome & stay connected 👍
thank you so much sir you are great teacher
Waoo sir it's osum trick thanks a lot
Thank you so much sir for making organic chemistry so easy.
one of the best aldol condensation trick thank u sir🤗
Thankyou sir!
Sir, how to decide which alpha hydrogen should be removed in aldol condensation
AJit Kumar this doesn't matter ... both can be removed... 2 products will be there
But which is major maity
Aldehydes can be attacked on ketone easily. So, it will be major.
sir please give us a video summarizing all name reactions and things you feel are important to remember
Sir, which is the rate determining step in aldol reaction
The step in which carbonation is forming will be RDS
@@preetkadivar1389 If you don't know better don't message and confused..
RDS→ when New between C-C gets formed
Thanks Sir, for recovery of my last lecture.. 😊😊
Very good explanation... Aldol condensation is basically between two aldehyde having alpha hydrogen...so that the product is having AL(aldehyde) and OL(alcohol)... But yes we can cite any example
To know which hydrogen is acidic b/w 2 alpha carbons we have to check the stability of carbanion no?
sir trick mai apne btaya OH remove karegai ya H2O sir?
Thank you soooooo much sir.This trick is really helpful
no words to describe you,phir bhi u r just ammazing teacher
Does 2 methyl propanal show aldol condensation ?
do I need to know mechanism?
sir 2nd step me anion ne base ki tarah act karke hydrogen kyu nahi
nikala. Voh nucleophyle ke jaise carbon par kyu attack kiya?
Very nice explained
Thank you so much 🙂
Awesome explanation sir
Best lecture forever
very very excellent
Best 👍👍👍👍👍
Thank you 😊
You're welcome 😊
thaNK YOU SO MUCH SIR
Best of luck
9:45 but sir if aldehyde is easier to attack then wont the first one be major???im really confused please help❤
Sir meant to say that it is easier to attack aldehydes than ketones. This is because aldehydes have less steric hindrance and are also more reactive than ketones because ketones have two alkyl groups which exhibit +I effect on the carbonyl carbon and make it less reactive.
This reaction involves the nucleophilic attack of carbanion, so the species being attacked should be electrophilic. In ketones, due to +I effect of the alkyl groups, the electrophilicity of the carbonyl carbon reduces, hence the nucleophile cannot attack it easily. That's why, it is easier for nucleophilic ketone to attack electrophilic aldehyde, and hence the product formed by the attack of ketone on aldehyde is the major product.
@@niharikamaniayes i do know the reason for easy attack on ald... but my doubt is if aldehyde is easier to attack then how come the two products in which ketone is attacked marked as major? In the first product aldehyde is attacked by ketone so wont it be major?
@@ToijamGhanashyam no? In the first product, the ketone is getting attacked. The alpha carbon gains electrons from the H that it lost and becomes a nucleophile. Then that alpha carbon of aldehyde attacks the carbonyl carbon of ketone. So the ketone is being attacked in the first product, hence it is not major.
The ketone that sir has taken here has two alpha carbons so it can launch a nucleophilic attack on the aldehyde from two places, hence two products are formed and those two are major products.
I hope I have cleared your confusion :) but you can still ask if not.
If you don't want to get into the mechanism every time and just want to use the trick sir has shown here, you can remember it like this :
The species which is losing an H is the attacking species, and the one who is losing an O is the species being attacked
Sir I have a doubt, At 4:30 why we'll call it Aldol product , since we are using acetone shouldn't it be ketol product?
5 years ago 💀
hello future @priyadarshinighosh6461
feels so weird
Thank you so much sir
So nice of you
Keep watching 😊
sir benzenal aldol conduction show karta h kya
best aldol video found by luck
Got so frustrated and lost all hope over this topic after going through every video and not understanding a thing. I can't believe I'm able to get everything right after watching your video. Thank u so much you're the best teacher 😭😭
sir e1 cb he to jada substitued double bond kaise bana?
sir you know you save lives thanks a ton
sir where is mixed aldol and cross??
please upload sir..
Cross is there in vid
understood perfectly thanks sir!
Great sir 👌👌👌, you are master of chemistry
Sir: exactly aap ko kaise nikalna he
Me: I am waiting tell fast
Sir: woo aap ko nahi samajnahe
Me:😒😞
Ha...coz sir ne woh part apne lectures me kahi aur sikhaya h.
Superb😍😍
Thanks 🤗
@@atpstarkota sir please make a video on total organic for jee sir..
Sir how to know which will be the major product out of all products???
Just Brilliant!!
Stay connected😊
Twinkle twinkle little star..🔥
ATP super star✨
Diper ki kami hai bas
Thank you very much sir..
Your videos are pretty helpful sir ty
As usual 😀😀...BEAUTIFUL
Thanku sir
Keep watching 😊
sir h2o remove hota hai than oh
nice explanation sir...
Thanks
Isn't 7 membered ring more stable than 5 membered ring due to steric hindrance?
7 membered ring has more strain then 5 membered ring.
Nice explanation 👍👍
Glad, stay connected for more such lectures.👍
Very nice sir
Keep watching 😊
thanks a lot sir...u saved a lot of time for us
Happy to help
sir ek video mein saare name reaction summarise kr dijiye plss..although this was very helpful...thanks
Sir why dilute is used not concentrated.?
Then OH- will *probably* act as a Nu- and attack on C (in C=O)
Nice videos much helpful