(L-30) Aldol Condensation || with Mechanism || Aldehyde ketones Chemical Rxn. || NEET JEE
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- Опубликовано: 10 сен 2024
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Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️ jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.
Bhai coaching wala jayada nhi fek diya
@@vishugamer5676 😂😂😂
Lol😂
Bohot badiya sir
बस कर पगले रुलाएगा क्या
Sir I got 58/60 in organic chemistry test of KCET exam.
Thank you so much sir.
All was possible only bcaz of u👍👍
Are Bhai party de tbb
Congratulations
Wow congratulations
Congratulations 😃😃
Bro which books did u refer?
You taught this way more better than my PhD professors in university 😃 lots of respect from Pakistan 💚
We learn this in school 🤣🤣🤣🤣🤣,and our competition is way to high,this is considered as trash after JEE exams in college 1st there is whole different thing
@@varnitamishra9491 hehe, we also have to learn this in high school but yeah I never did and always left this topic on choice but in uni's 1st semester, the first topic they taught us was this and I had no choice but to learn🥲🥲
@@Fatimafaisal220 we have no choice to leave any topic in pcm if we are serious jee aspirant
@@varnitamishra9491 what's jee aspirant?
@@Fatimafaisal220 for Engineering
4-Methyl Pent-3-en-2-one ..From Ketone by "Aldol condensation"
Mesityl oxide
@@Honest_Penaldo_fan Hein ?
@@itzpkg what hein? I said the common name of the compound you wrote
@@Honest_Penaldo_fan I was just kidding...dude
Actually Mene 2 Sal phle comment Kiya tha....or 2 sal bad kisi ne reply Diya ...
Kudos to your attention ‼️❤️
@@itzpkg Ok thanks 😂😂... You are appreciated
*Sir, what I like the most about your videos is that, it is short without compromising the major topics and basics...please keep this pattern in future also!👍*
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Sir ketone Wala ho gya ... Answer is 4-methyl pent-3-en-2-one #thank_u_sir
That is my answer too
Nice
Sir
Ketones
Magic
A
Raha
Hai
I got the same!!!
Mera bhi 🥳
Same
Ketone wale hi Gaya sir.
Aldol form is 4-hydroxy 4- methyl pentan-2-one.
After condensation, it is 4-methyl pent-3 -en-2 one.
Ncert
Bas galti nikalo
Sir
@@adityaraj9926 hmm
Yes correct. Thanks for mentioning the answer. I was able to check mine. ☺
We are done in ketone form according to aldol condensation
Have a look on this video too at
ruclips.net/video/z91KRTmXv9g/видео.html
P
P
Hi
Sir I am preparing for GPAT. .and prefer watching your description videos...I love the way you describe sir.....Huge respect....🙏
even after three year no one can beat sir in chemistry
change it 4 man
Change it 5
The ans is 4-methyl pent 3-en 2-one. Sry sir thora late Ho gaya. 😀😀
Same..
Same....
Same to you
yeah same😊😊
same
Hello sir, i m from pakistan.really in love with ur concepts.all my conceps are covered ur amazing.Love from Pakistan💚💚💚
Thankyou so much sir for putting ur immense efforts to teach us! You are the best chemistry teacher across youtube, you work very hard for us! Thankyou again~
#funny
Superb method of teaching.... Love u sir
the ans for aldol condensation of acetons is
( 4-Methyl pent-3-ene-2-one)
ya exactly 👍
Yes sm2u
Same😊
4 hydroxy 4 methyl pentan2one. (Without heating)
After heat:-
4 methyl pent3 en2one.
(CH3)2-C=CH-C=OCH3
Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir
4-methyl pent 3-en 2-one😁😁
Sir my answer.......... 4-methylpent-3en-2one. (aldol condensation product)
4-hydroxy,4-methyl pentane-2-one
Finally sir mujhe aldol aa gya .... maine bahut teachers se smjhne ki kosis ki but .... but aap se behtrrr koi n smjhaye...apne pura concept hi clear kr diya...thanku sir sooo much🙏🙏🙏
Sir it's ans is before condensation 4 hydroxy 4 methyl pent 2 one and after heating answer is 4 methyl pent 3en 2 one....
Book se koi nhi bta dega
(CH3)2-C=CH-CO-CH3
Misityl oxide
@@Crazy_Gamer4855. Now these things don't matter to me, moving forward with coding
Yes sir ho gya... 4 methyl pent-3-en-2-one...
I have done sir and the answer is 4methylPent-3ene-2one.
Thank you sir.
Sir Ketone wala ho gaya. Sir Andol- 4-hydroxy,4-methyl pentan-2-one. And, After Condensation it becomes 4-methyl pent-3-ene-2-one. Sir Ek question h, Condensation k baad Jo product bana kya hum usko generally Enone bol sakte h.
Thanks a lot sir I cracked iit because of you.
Ketone wala ho gya sir ji thank you so much
Srr u r only one ☝whose teaching method is much better for us😍😍 Thankuu so much sr 🙏🙏may God bless uh srr🥰🥰🥰
🥰🥰
Sir the final product is
4-methyl pent 3-en-2one
Thank-you very much sir,👍👍👍
Thanks sir it really works.
Now i am able to work out the questions.
Well explained.
Answer for aldol condensation while using ketone is 4-methyl pent 3-ene 2-anl
Thankyou so much sir and team
Thank you so much sir🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗
🔴आपसे अच्छी केमिस्ट्री अन्य कोई नहीं पढ़ा सकता। 👍☝️😘👏💝
..........Thank you so much dear sir ji 🙏 Love you.
Thank you so much sir board pr smjhane k ly 🙏 ..ap best ho sir🙏❤️
SIR Ketone wala ho gaya.. ans.: 4-METHYLPENT-3-EN-2-ONE...
*THANK YOU SO MUCH SIR😀😀😀😀😀😀😀😀😀😀🤗🤗🤗🤗🤗😊😊😊😊😊😀😀😀😀😀😀😀😀😀*
Product is 4-Methyl pent-3-en-2-one.
Done sir answer is -4-methy pent-3-en-2-one.
Aap mechanism bhut deeply or ache se btate ho
Sir g u r great
I slove all bsc questions because of ure good lecture
Answer of hw question
Mesityl oxide or 4-Methylpent-3-en-2-one
Thank you soo much sir u explained the best nd I was very confused with aldol condensation bt after watching ur video all confusion is gone THANKS AGAIN😀
Loss of hydrogen from alpha position during the loss of water leads to formation of conjugated double bonds which the second reason why hydrogen is released from alpha carbon....nice lecture by the way👍
Experience is the best teacher sir...👌
FOR KETONE PRODUCT IS
4 methyl pent-3 en -2 one
Ans. 4-hydroxy -4-4methyl pentan- 2 one . ... After heat to give :- 4-hydroxy-4-4methyl pent-3- en- 2 one
your every lecture I understand
Love you sir 😍 your way of explaining is too good
Have a look on this video too at
ruclips.net/video/z91KRTmXv9g/видео.html
adol 4hydroxy 4methyl pent-2-one after heat 4methyl pent 3-en -2one
Sah8 hai
Answer 4-methylpent-3-en-2-one
Thank you madejee team for their support to coaching free india
Sir thank u ans is 4methyl pent-3en-2one
Thank you bhiya itna din se head me dard tha reaction clear hi nahi ho rahi thi aapka lecture se sab understand ho gaya thank you once again easiest method aapka sanjana ka
I did my homework sr it was quite simple 😊😊😊
ARMY 💜
Thank you soo much *SIR AND MADE EZEE CHEMISTRY TEAM* for all your hard work...
Sir question is done
Sir question ho gya 👌
🙏Thanks for the effort you make on us, sir
Hey bro can you explain the in dilute naoh is present you know I understand that in naoh oh- is gone for formation of bonding then where is na???
@@DeepakKumar-sf3tuin solution with water
@@DeepakKumar-sf3tuNaOh was base it work was till it gives OH ion not Na
Sir aapki short tricks and mechanism fast samaj me aata h
sir ketone wala ho gaya 4Hydroxy-4methyl-pentan-2-one
after condensation(∆) 4Methyl-pent-3-en-2-one
💞💞I learn alot of concept from u Love from Pakistan ❣️❣️
Thank you made e jee team and thanks a lot sir 👍🏻
Thank you so much sir ❤❤❤lots of love from pakistanis❤❤
Thankyou so much sir ❣️
aap too real guru ji ho
Sir ketone wala ho gya
Answer is 4 Hydroxy- 4 methyl pentenon 2
outstanding brother!Thank you soo much
Completed..
Thankyou so much Sir
bahut aache se samjhaye sir
This is just awesomee ❤️❤️❤️
sir ketone ke bhi ho gaya 😊😊 apne itne ache se pyar se padhaye h toh samaj me aa gaya....Mahadev Aap ko lambi umar de🙏🙏🙏🙏🙏🙏
I cleared my homework and I am waiting for your next interesting video cross aldol.
Sir ans nhi aaya
Ketone -4-methyl pent-3ene-2one
Sir I got 4-methyl pent-3-en-2-one & thank you so much sir 🙂👍
Good presentation sir
You are really a great teacher. You grab our attention very fast. We don't get bore for a single minute during your videos.
Keep it up.☺️👍
Thank you so much sir for this. Sir muje aata Nahi Tha but aab sab yad he and me marck cover by this reaction
Ketone waala ho gya pretty much easy🖤
Sir apke wajah se mujhe organic bahot acche se samajh m ane laga h. Many wishes for your bright future sir . And thankyou once again sir
How did the removal of h and oh occur(mechanism)???
Please like so that sir can see this doubt
By heating 🔥
@@aadil77982 thanks
H in the form of H+ leaves and attacks(retention) on OH and creates H2O+ and it leaves takes electron water gets removed and C- and C+ form a bond .....
This is E1 reaction mechanism
Have a look on this video too at
ruclips.net/video/z91KRTmXv9g/видео.html
For acetone,,,,,,,,4-methyl pent-3-en-2-one ..........
I can do ketone also thnk u sir.. love from Bangladesh 🇧🇩❤️
Sir ketone wala ho gaya
Ans: 4-methyl-pent-3-en-2-one
Thanx sir
Sir ..I got instant motivated when I see u and your hard work...thanku sir for this
Thank YOU❤❤,, i am from Bangladesh
Thank u sir
Now its easy😀
Sir ans is....4 methyl pent-3-ene-2-one...
Ketone Ka aldol condensation karka 1st:aldol product is
4-hydroxy-4-methylpentan-2-one
2nd:enal product is
4-methylpent-3-en-2-one
Ketone product=4-methyl pent-3-en-2-one
Thanks a lot sir
Sir please make çomplete video on coordination compounds 🙏
Bhai ps sir ke lecture dekh le
Good trick sirji........ Thank you sir
Sir can you do a video on Latimer diagram. The question related to it had been asked in NEET 2018
The same machenism for ketones ..thanK You Sir....LOVE from Pakistan
thanku so much sir .......nd whole madeejee family...... nd gooood mrng to u sir...
Sir you are amazing
4 hydroxy 4 methyl pentan 2 one --------------4 methyl pent 3 en 2 one